php and mysqli prepared update is updating all rows - php

I'm finding that a prepared update using mysqli is updating all the rows in my table instead of the one referenced in the WHERE clause. I'm stumped as for the reason this is happening. I used simplified code below to run as a test, and it still happens. I'm using PHP 5.3.18 and the Client API library version 5.0.96.
$mysqli = new mysqli("localhost", "user", "pass", "db");
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$query = "UPDATE test SET first_name = ? WHERE last_name = ?";
if(!$stmt = $mysqli->prepare($query)) {
die("Unable to prepare<br />");
}
$first = 'test';
$second = 'something';
$stmt->bind_param("ss", $first, $second);
if (!$stmt->execute()) {
die("Could not execute<br />");
}
echo "done";
The query executes, but the first_name is updated for all rows in the table. Yes, there is a last_name with "something." No, the three other test rows do not have the last_name = something.
Is this something wrong with the library? My PHP config? Perhaps not enough sleep? What?
Oh... in addition... if I use a query like
"UPDATE test SET first_name = ? WHERE id = ?"
and update the params to use an id, it works. It only updates the single row. So why can't I use the last_name column in the WHERE clause?

I had the server techs update my server to MySql 5.5 and the issue is now fixed. I'm guessing it had something to do with the library or MySql install.

Related

MYSQLi Creates Database with ? as name

I wrote an Install File for my own CMS which I'm working atm. I changed the SQL statements to make it a bit saver but now nothing works and I can't figure out why...
I change my code from:
$db = new mysqli($_POST['db_ip'], $_POST['db_user'], $_POST['db_key'], '', $_POST['db_port']);
if(!$db) {
exit('Connection error to database');
}
$query = "CREATE DATABASE IF NOT EXISTS $db_name;";
$ergebnis = mysqli_query($db, $abfrage);
to:
$db = new mysqli($_POST['db_ip'], $_POST['db_user'], $_POST['db_key'], '', $_POST['db_port']);
if(!$db) {
exit('Error connecting to database'); //Should be a message a typical user could understand in production
}
$db_name = $_POST['db_name'];
$query = "CREATE DATABASE IF NOT EXISTS ?;";
$stmt->bind_param('s', $db_name);
$stmt = $db->prepare($query);
$stmt->execute();
I even tried:
$db = new mysqli($_POST['db_ip'], $_POST['db_user'], $_POST['db_key'], '', $_POST['db_port']);
if(!$db) {
exit('Error connecting to database'); //Should be a message a typical user could understand in production
}
$db_name = $_POST['db_name'];
$query = mysqli_prepare "CREATE DATABASE IF NOT EXISTS ?;";
mysqli_stmt_bind_param($query, 's', $db_name);
mysqli_stmt_execute($stmt);
mysqli_stmt_close($stmt);
last one added me a database but with the ? as name...
I hoped some one here can help me with that.
Not every SQL statement supports prepared statements. And CREATE DATABASE is one of them.
So, as a general rule, you are supposed to choose the database/table name from the white list.
In your specific case, however, when a user is apparently a database owner, there is not much point in protecting them from SQL injection as they apparently has the database password and can run any SQL statement much more convenient way. So you changed the code for nought. Just revert it back to the regular query() call.
I would only add backticks around the table name so it would always make a correct identifier name. And also may be add a regex validation just in order to avoid a human error.

Escape strings/ inserting in php script

I'm trying to finish a script that connects to two databases, each on a different server, and preforms an update. Basically, the tables being selected from and inserted to are identical: I did a dump/import the other day. The script needs to keep my local table up to date from the remote once since there will be daily records inserted into the remote one and I need to keep it up to date locally.
The key here is that I'm determining the new rows on the remote server by looking at the Auto-incremented Primary key that the tables share, SESSIONID . I'm trying to get my loop below to say, if the id exists in remote server and not local, then insert those records in local server.
I run the below script in powershell by typing php 'filename', and I get both of my successful connection messages, and then I get this message: Incorrect datetime value: '' for column 'ALERTINGTIMESTAMP' at row 1. In this record it's trying to insert, the datetime value is NULL, which the table allows for, however I'm worried it's an issue with escaping characters or something.
How can I modify this to escape properly, or get these records inserted.
Note: Replication and large dump/import/table recreations are not an option for us in this situation. We have several similar scripts to this running and we want to keep the same process here. I'm merely looking to resolve these errors or have someone give me a more efficient way of coding this script, perhaps using a max id or something along those lines.
Here's the script:
ini_set('memory_limit', '256M');
// Create connection
$conn = new mysqli($servername, $username, $password);
$conn2 = new mysqli($servername2, $username2, $password2);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
// Check connection2
if ($conn2->connect_error) {
die("Connection failed: " . $conn2->connect_error);
}
echo "Connected successfully";
$latest_result = $conn2->query("SELECT MAX(`SESSIONID`) FROM `ambition`.`session`");
$latest_row = $latest_result->fetch_row();
$latest_session_id = $latest_row[0];
//Select All rows from the source phone database
$source_data = mysqli_query($conn, "SELECT * FROM `cdrdb`.`session` WHERE `SESSIONID` > $latest_session_id");
// Loop on the results
while($source_item = $source_data->fetch_assoc()) {
// Check if row exists in destination phone database
$row_exists = $conn2->query("SELECT SESSIONID FROM ambition.session WHERE SESSIONID = '".$source_item['SESSIONID']."' ") or die(mysqli_error($conn2));
//if query returns false, rows don't exist with that new ID.
if ($row_exists->num_rows == 0){
//Insert new rows into ambition.session
$conn2->query("INSERT INTO ambition.session (SESSIONID,SESSIONTYPE,CALLINGPARTYNO,FINALLYCALLEDPARTYNO,DIALPLANNAME,TERMINATIONREASONCODE,ISCLEARINGLEGORIGINATING,CREATIONTIMESTAMP,ALERTINGTIMESTAMP,CONNECTTIMESTAMP,DISCONNECTTIMESTAMP,HOLDTIMESECS,LEGTYPE1,LEGTYPE2,INTERNALPARTYTYPE1,INTERNALPARTYTYPE2,SERVICETYPEID1,SERVICETYPEID2,EXTENSIONID1,EXTENSIONID2,LOCATION1,LOCATION2,TRUNKGROUPNAME1,TRUNKGROUPNAME2,SESSIONIDTRANSFEREDFROM,SESSIONIDTRANSFEREDTO,ISTRANSFERINITIATEDBYLEG1,SERVICEEXTENSION1,SERVICEEXTENSION2,SERVICENAME1,SERVICENAME2,MISSEDUSERID2,ISEMERGENCYCALL,NOTABLECALLID,RESPONSIBLEUSEREXTENSIONID,ORIGINALLYCALLEDPARTYNO,ACCOUNTCODE,ACCOUNTCLIENT,ORIGINATINGLEGID,SYSTEMRESTARTNO,PATTERN,HOLDCOUNT,AUXSESSIONTYPE,DEVICEID1,DEVICEID2,ISLEG1ORIGINATING,ISLEG2ORIGINATING,GLOBALCALLID,CADTEMPLATEID,CADTEMPLATEID2,ts,INITIATOR,ACCOUNTNAME,APPNAME,CALLID,CHRTYPE,CALLERNAME,serviceid1,serviceid2)
VALUES ('".$source['SESSIONID']."' ,
'".$source['SESSIONTYPE']."' ,
'".$source['CALLINGPARTYNO']."' ,
'".$source['FINALLYCALLEDPARTYNO']."',
'".$source['DIALPLANNAME']."',
'".$source['TERMINATIONREASONCODE']."',
'".$source['ISCLEARINGLEGORIGINATING']."',
'".$source['CREATIONTIMESTAMP']."',
'".$source['ALERTINGTIMESTAMP']."',
'".$source['CONNECTTIMESTAMP']."',
'".$source['DISCONNECTTIMESTAMP']."',
'".$source['HOLDTIMESECS']."',
'".$source['LEGTYPE1']."',
'".$source['LEGTYPE2']."',
'".$source['INTERNALPARTYTYPE1']."',
'".$source['INTERNALPARTYTYPE2']."',
'".$source['SERVICETYPEID1']."',
'".$source['SERVICETYPEID2']."',
'".$source['EXTENSIONID1']."',
'".$source['EXTENSIONID2']."',
'".$source['LOCATION1']."',
'".$source['LOCATION2']."',
'".$source['TRUNKGROUPNAME1']."',
'".$source['TRUNKGROUPNAME2']."',
'".$source['SESSIONIDTRANSFEREDFROM']."',
'".$source['SESSIONIDTRANSFEREDTO']."',
'".$source['ISTRANSFERINITIATEDBYLEG1']."',
'".$source['SERVICEEXTENSION1']."',
'".$source['SERVICEEXTENSION2']."',
'".$source['SERVICENAME1']."',
'".$source['SERVICENAME2']."',
'".$source['MISSEDUSERID2']."',
'".$source['ISEMERGENCYCALL']."',
'".$source['NOTABLECALLID']."',
'".$source['RESPONSIBLEUSEREXTENSIONID']."',
'".$source['ORIGINALLYCALLEDPARTYNO']."',
'".$source['ACCOUNTCODE']."',
'".$source['ACCOUNTCLIENT']."',
'".$source['ORIGINATINGLEGID']."',
'".$source['SYSTEMRESTARTNO']."',
'".$source['PATTERN']."',
'".$source['HOLDCOUNT']."',
'".$source['AUXSESSIONTYPE']."',
'".$source['DEVICEID1']."',
'".$source['DEVICEID2']."',
'".$source['ISLEG1ORIGINATING']."',
'".$source['ISLEG2ORIGINATING']."',
'".$source['GLOBALCALLID']."',
'".$source['CADTEMPLATEID']."',
'".$source['CADTEMPLATEID2']."',
'".$source['ts']."',
'".$source['INITIATOR']."',
'".$source['ACCOUNTNAME']."',
'".$source['APPNAME']."',
'".$source['CALLID']."',
'".$source['CHRTYPE']."',
'".$source['CALLERNAME']."',
'".$source['serviceid1']."',
'".$source['serviceid2']."')");
}
}
Like Pankaj said, try something like this:
//Insert new rows into ambition.session
$statement = $conn2->prepare('INSERT INTO ambition.session (SESSIONID,SESSIONTYPE,CALLINGPARTYNO,FINALLYCALLEDPARTYNO,DIALPLANNAME,TERMINATIONREASONCODE,ISCLEARINGLEGORIGINATING,CREATIONTIMESTAMP,ALERTINGTIMESTAMP,CONNECTTIMESTAMP,DISCONNECTTIMESTAMP,HOLDTIMESECS,LEGTYPE1,LEGTYPE2,INTERNALPARTYTYPE1,INTERNALPARTYTYPE2,SERVICETYPEID1,SERVICETYPEID2,EXTENSIONID1,EXTENSIONID2,LOCATION1,LOCATION2,TRUNKGROUPNAME1,TRUNKGROUPNAME2,SESSIONIDTRANSFEREDFROM,SESSIONIDTRANSFEREDTO,ISTRANSFERINITIATEDBYLEG1,SERVICEEXTENSION1,SERVICEEXTENSION2,SERVICENAME1,SERVICENAME2,MISSEDUSERID2,ISEMERGENCYCALL,NOTABLECALLID,RESPONSIBLEUSEREXTENSIONID,ORIGINALLYCALLEDPARTYNO,ACCOUNTCODE,ACCOUNTCLIENT,ORIGINATINGLEGID,SYSTEMRESTARTNO,PATTERN,HOLDCOUNT,AUXSESSIONTYPE,DEVICEID1,DEVICEID2,ISLEG1ORIGINATING,ISLEG2ORIGINATING,GLOBALCALLID,CADTEMPLATEID,CADTEMPLATEID2,ts,INITIATOR,ACCOUNTNAME,APPNAME,CALLID,CHRTYPE,CALLERNAME,serviceid1,serviceid2)
VALUES (?, ?, ?, ...);');
$statement->bindParam(1, $source['SESSIONID']);
$statement->bindParam(2, $source['SESSIONTYPE']);
$statement->bindParam(3, $source['CALLINGPARTYNO']);
//...
$statement->execute();
You have to use prepare() function to use parameterized query. Here I have taken example of your query with few parameters you can add yourself with other variables.
$stmt = $conn2->prepare("INSERT INTO ambition.session (SESSIONID,SESSIONTYPE,CALLINGPARTYNO,FINALLYCALLEDPARTYNO) VALUES (:SESSIONID ,:SESSIONTYPE ,:CALLINGPARTYNO ,:FINALLYCALLEDPARTYNO)");
$stmt->bindParam(':SESSIONID', $source['SESSIONID']);
$stmt->bindParam(':SESSIONTYPE', $source['SESSIONTYPE']);
$stmt->bindParam(':CALLINGPARTYNO', $source['CALLINGPARTYNO']);
$stmt->bindParam(':FINALLYCALLEDPARTYNO', $source['FINALLYCALLEDPARTYNO']);
$stmt->execute();
You can checkout this link for more understanding. http://php.net/manual/en/mysqli.prepare.php

Executing mysqli insert query then immediately selecting ID of new row

I've been spending a couple of hours trying to write mysqli queries to insert a new row in a database (with a primary key ID) and then select the ID of the new row. My code as it currently is:
<?php
include('connectionData.php');
$conn = mysqli_connect($server, $user, $pass, $dbname, $port)
or die('Connection error');
if(isset($_POST['submit'])) {
$pnum = $_POST['pnum'];
$phone_insert_text = "INSERT INTO `voterdatabase`.`phone` (`pnum`) VALUES (?)";
$phone_insert_query = $conn->prepare($phone_insert_text);
$phone_insert_query->bind_param('s', $pnum);
$phone_insert_query->execute();
$phone_select_text = "SELECT phone_id FROM voterdatabase.phone WHERE pnum=?";
$phone_select_query = $conn->prepare($phone_select_text);
$phone_select_query->bind_param('s', $pnum);
$phone_select_query->execute();
$phone_select_query->bind_result($phone_id);
echo $phone_id;
?>
$phone_insert_query executes without issue. But $phone_select_query doesn't appear to run at all, as echo $phone_id; has no effect. What might be going on here? I'm able to run the query directly in MySQLWorkbench.
Note that I previously tried doing this in one query using SELECT LAST_INSERT_ID();, but mysqli fails to execute any query containing that.
Please try this
$lastInsertID= mysqli_insert_id($conn);
Use insert_id property:
<?php
include('connectionData.php');
$conn = mysqli_connect($server, $user, $pass, $dbname, $port)
or die('Connection error');
if(isset($_POST['submit'])) {
$pnum = $_POST['pnum'];
$phone_insert_text = "INSERT INTO `voterdatabase`.`phone` (`pnum`) VALUES (?)";
$phone_insert_query = $conn->prepare($phone_insert_text);
$phone_insert_query->bind_param('s', $pnum);
$phone_insert_query->execute();
$phone_id = $conn->insert_id;
echo $phone_id;
?>
If you wish to be able to use the available functions to get the last inserted id, like mysqli_insert_id(), your table must have an AUTO_INCREMENT column. If not you will not get the id.
Also, even if you have the required columns, this will require two calls. To get around this, what you could do is something like create a stored procedure to do your insert for you and return the inserted id from the procedure.

PHP script to update mySQL database

another day another question...
I need to write PHP script to update mySQL database.
For example: updating profile page when user want to change their first name, last name or etc.
Here is my php script so far, it doesn't work. Please help!
<?php
# $db = new MySQLi('localhost','root','','myDB');
if(mysqli_connect_errno()) {
echo 'Connection to database failed:'.mysqli_connect_error();
exit();
}
if (isset($_GET['id'])) {
$id = $db->real_escape_string($_GET['id']);
$First_Name2 = $_POST['First_Name2'];
$query = "UPDATE people SET $First_Name2 = First_Name WHERE `Id` = '$id'";
$result = $db->query($query);
if(! $result)
{
die('Could not update data: ' . mysql_error());
}
echo "Updated data successfully\n";
$db->close();
}
?>
THank you.
Your sql is wrong. Apart from the gaping wide open SQL injection attack vulnerability, you're generating bad sql.
e.g. consider submitting "Fred" as the first name:
$First_Name2 = "Fred";
$query = "UPDATE people SET Fred = First_name WHERE ....";
now you're telling the db to update a field name "Fred" to the value in the "First_Name" field. Your values must be quoted, and reversed:
$query = "UPDATE people SET First_name = '$First_Name2' ...";
You are also mixing the mysqli and mysql DB libraries like a drunk staggering down the street. PHP's db libraries and function/method calls are NOT interchangeable like that.
In short, this code is pure cargo-cult programming.

update mysql database table fields with a single mysqli statement query

I have a database table and i am updating the table columns this way.
$mysqli = new mysqli('localhost', 'root', '', 'db');
if (mysqli_connect_errno()) {
echo 'failed to connect to db.. <br>' . mysqli_connect_errno();
return 'error';
}
$username = $data['username'];
$data['image'] = $this->replace_whitespace($data['image']);
foreach($data as $key=>$value){
$this->query = "UPDATE users SET $key=? WHERE username='$username'";
$this->statement = $mysqli->prepare($this->query);
if($this->statement){
$this->statement->bind_param('s', $value);
$this->statement->execute();
$this->statement->close();
}
}
Is it possible to update more than one table columns in one go. I tried this but in-vain.
$this->query = "UPDATE users SET col1=?, col2=?, col3=? WHERE username='$username'";
$this->statement = $mysqli->prepare($this->query);
if($this->statement){
$this->statement->bind_param('sss', $value1, $value2, $value3);
$this->statement->execute();
$this->statement->close();
}
Is there a better way doing this?
$mysqli = new mysqli('localhost', 'root', '', 'db');
if (mysqli_connect_errno()) {
echo 'failed to connect to db.. <br>' . mysqli_connect_errno();
return 'error';
}
$username = $data['username'];
$this->query = "UPDATE users SET fname=?, lname=?, email=?, tpin=?, image=?, address=? country=?, city=?, state=?, postal=? WHERE username='$username'";
$this->statement = $mysqli->prepare($this->query);
if ($this->statement) {
$this->statement->bind_param('ssssssssss', $data['fname'],$data['lname'],$data['email'],$data['tpin'], $data['file'], $data['address'],$data['country'],$data['city'],$data['state'], $data['post_code']);
$this->statement->execute();
$this->statement->close();
}
This is my real code.
Remove the "," after col3=?
This will fix the syntax error
$this->query = "UPDATE users SET col1=?, col2=?, col3=?, WHERE username='$username'";
You have an extra comma, meaning your SQL is reading "WHERE" as another column and everything gets messed up.
$this->query = "UPDATE users SET col1=?, col2=?, col3=? WHERE username='$username'";
Should work fine.
In response to the comment below, this is the correct way of going about it, so it must be a faulty variable somewhere, what error messages are you getting? (If any)
It could also be that one of the parameters you are binding is not a string. Regardless, we'd need a more in-depth example.
Is it possible to update more than one table columns in one go
Yes. Actually, updating many fields in one query is a very core feature of any DBMS. You can always expect it to be supported.
I tried this but in-vain.
Well, you have to try more, like we all do. After all, it's your job.
Two notes regarding your "real" code:
You have to bind ALL variables in the query, not only some of them
you have to configure mysqli to report errors:
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
I assume it works the same way as putting new values into the database.
Update a row mysql in php

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