I recently made a code that updates my posts on my blog. It worked perfectly on localhost. But when i uploaded it online it did not work any more. The weird thing is it doesn't even display a error so i have no idea where to look. Can someone please help me ?
require('config.php');
$query = "SELECT * FROM project ORDER BY idproject DESC";
$result = mysqli_query($verbinding, $query ) or die (mysqli_error('kan geen verbinding maken met de database'));
if(isset($_POST['editBut'])){
$editTitle = $_POST['editName'];
$editThis = mysqli_query($verbinding, "SELECT * FROM project WHERE title = '".$editTitle."'");
$values = mysqli_fetch_assoc($editThis);
}
if(isset($_POST['update'])){
$editedTitle = $_POST['newTitle'];
$editedText = $_POST['newTekst'];
$oldTitle = $_POST['oldTitle'];
$date = $_POST['datum'];
$updater = mysqli_query($verbinding, "UPDATE Project SET title='".$editedTitle."', content='".$editedText."' WHERE title='".$oldTitle."' AND datum='".$date."'");
echo $updater;
header('location:editPost.php?id=1');
}
if(isset($_GET['id'])){
echo 'post has been succesfully updated';
}
<?php if(isset($_POST['editBut'])){ ?>
<form action="" method="post">
Title: <input type="text" name="newTitle" value="<?php echo $values['title'] ?>"><br>
Text: <textarea type="text" name="newTekst" id="newTekst"><?php echo $values['content'] ?></textarea><br>
<input type="hidden" value="<?php echo $values['title'] ?>" name="oldTitle">
<input type="hidden" value="<?php echo $values['datum'] ?>" name="datum">
<input type="submit" name="update" value="Edit post">
</form>
<?php } else { ?>
<p>Find the post you want to edit:</p>
<form action="" method="post">
<select name="editName">
<?php
while ($row = mysqli_fetch_assoc($result)) {
?> <option value="<?php echo $row['title'] ?>"><?php echo $row['title'] ?></option>
<?php } ?>
</select>
<input type="submit" name="editBut" value="Choose">
</form>
<?php } ?>
In update query replace your table name with small letter.
replace Project with project
Related
I'm trying to call the old values to be edited. What part am I wrong at?
<?php
if (isset($_GET['edit'])) {
$id = $_GET['edit'];
$update = true;
$record = mysqli_query($db, "SELECT * FROM bookinfo WHERE BookNo='$BookNo'");
if (mysqli_num_rows($record) == 1 ) {
$n = mysqli_fetch_array($record);
$BookNo = $n['BookNo'];
$ISBN = $n['ISBN'];
$title = $n['title'];
$author = $n['author'];
$publisher = $n['publisher'];
$status = $n['status'];
$cost = $n['cost'];
}
}
?>
<a href="viewBook.php?edit=<?php echo $row['BookNo']; ?>" class="edit_btn" >Edit</a>
</td>
<?php
if (isset($_GET['edit'])) { ?>
<form method="post" action = "viewBook.php">
<input type="hidden" name="BookNo" value="<?php echo $BookNo; ?>">
<input type="text" name="ISBN" value="<?php echo $ISBN; ?>">
<input type="text" name="title" value="<?php echo $title; ?>">
<input type="text" name="author" value="<?php echo $author; ?>">
<input type="text" name="publisher" value="<?php echo $publisher; ?>">
<input type="text" name="status" value="<?php echo $status; ?>">
<input type="text" name="cost" value="<?php echo $cost; ?>">
<?php if ($update == true): ?>
<button class="btn" type="submit" name="update" style="background: #556B2F;" >update</button>
<?php else: ?>
<button class="btn" type="submit" name="save" >Save</button>
<?php endif ?>
<?php } ?>
</form>
So far, what it does is, when the user clicks the edit button, it just shows 6 text fields. I thought by doing what I did, it was supposed to show the details already filled in the textbox.
When you do
$record = mysqli_query($db, "SELECT * FROM bookinfo WHERE BookNo='$BookNo'");
$BookNo is not defined.
maybe you wanted to do something like this:
$id = $_GET['edit'];
$update = true;
$record = mysqli_query($db, "SELECT * FROM bookinfo WHERE BookNo='$id'");
<form method="post" action = "viewBook.php">
your form method is "post" but you are checking $_GET You must check $_POST
if (isset($_GET['edit']))
you are passing value in $id And using $BookNo which not define.
only 6 input field will be show because first one is using hidden property.
<input type="hidden" name="BookNo" value="<?php echo $BookNo; ?>">
when you click on submit button data will be receive by $_POST
I am creating a simple CRUD application that will be used as a blog. For the edit page, I want to have a dropdown menu with the blog titles of each post. When an option/blog post is selected, I want it to populate the "Title" and "Message" fields, so it can then be edited and saved to the database.
I got it to retrieve the titles of the blog posts, but I am struggling to make it populate the "Title" and "Message" fields so it can be edited when the option is selected.
I have 4 rows in my database: row[0] is the title, row[1] is the message, row[2] is the timestamp and row[3] is the ID.
Thanks guys. I appreciate it.
<form action="edit.php" id="myform" method="post" autocomplete=off>
<input type="hidden" name="action" value="show">
<p><label>Entry:</label><select name="blog">
<?php
$result = mysqli_query($con, "SELECT * FROM blog");
while ($row = mysqli_fetch_array($result)) {
$chosen = $row['bid'];
}
if (isset($_GET['blog'])) {
$id = $_GET['blog'];
$result = mysqli_query($con, "SELECT * FROM blog WHERE bid='$id'");
$row = mysqli_fetch_array($result);
}
$result = mysqli_query($con, "SELECT * FROM blog");
while ($row = mysqli_fetch_array($result)) {
$id = $row['bid'];
$title = $row['title'];
$selected = '';
if ($id == $chosen) {
$selected = "selected='selected'";
}
echo "<option value='$id' $selected>$title</option>\n";
}
?>
</select></p>
<p><label>Title:</label> <input type="text" id="newtitle" name="newtitle" value="<?php echo $row[0]; ?>"></p>
<p><label>Message:</label> <input type="text" id="newmessage" name="newmessage" value="<?php echo $row[1]; ?>"></p>
<p><input type="hidden" name="id" value="<?php echo $row[3]; ?>"></p>
<br><p><input type="submit" name="submit" value="Submit"></p>
</form>
I have managed to somewhat figure out the answer on my own. It's probably not the most ideal way of doing it, but for anyone else potentially stuck on this - here is my code:
The only issue I'm having now is figuring out how to keep my option selected.
<form action="edit.php" id="myform" method="post" autocomplete=off>
<input type="hidden" name="action" value="show">
<p><label>Entry:</label><select name="blog" onchange="window.location.href = blog.options[selectedIndex].value">
<option selected disabled>Select One</option>
<?php
$result = mysqli_query($con, "SELECT * FROM blog");
while ($row = mysqli_fetch_array($result)) {
$id = $row['bid'];
$title = $row['title'];
echo "<option value='edit.php?edit=$row[bid]'>$title</option>\n";
}
if (isset($_GET['edit'])) {
$id = $_GET['edit'];
$result = mysqli_query($con, "SELECT * FROM blog WHERE bid='$id'");
$row = mysqli_fetch_array($result);
}
?>
</select></p>
<p><label>Title:</label> <input type="text" id="newtitle" name="newtitle" value="<?php echo $row[0]; ?>"></p>
<p><label>Message:</label> <input type="text" id="newmessage" name="newmessage" value="<?php echo $row[1]; ?>"></p>
<p><input type="hidden" name="id" value="<?php echo $row[3]; ?>"></p>
<br><p><input type="submit" name="submit" value="Submit"></p>
</form>
I am working on a project and would like to give the user per-determined values when updating a record.
Here is my code so far.
<?php
// if there are any errors, display them
if ($error != '')
{
echo '<div style="padding:4px; border:1px solid red; color:red;">'.$error.'</div>';
}
?>
<form action="" method="post">
<input type="hidden" name="id" value="<?php echo $id; ?>"/>
<div>
<p><strong>ID:</strong> <?php echo $id; ?></p>
<strong>School Name:</strong> <input type="text" name="Name" value="<?php echo $Name; ?>"/><br/><br>
<strong>Status:</strong> <input type="text" name="Status" value="<?php echo $Status; ?>"/><br/><br>
<strong>Comments:</strong> <input type="text" name="Comments" value="<?php echo $Comments; ?>"/><br/><br>
<strong>Type:</strong> <input type="text" name="Type" value="<?php echo $Type; ?>"/><br/><br>
<input type="submit" name="submit" value="Submit">
</div>
</form>
</body>
</html>
<?php
}
// connect to the database
include('connect-db.php');
// check if the form has been submitted. If it has, process the form and save it to the database
if (isset($_POST['submit']))
{
// confirm that the 'id' value is a valid integer before getting the form data
if (is_numeric($_POST['id']))
{
// get form data, making sure it is valid
$id = $_POST['id'];
$Name = mysql_real_escape_string(htmlspecialchars($_POST['Name']));
$Status = mysql_real_escape_string(htmlspecialchars($_POST['Status']));
$Comments = mysql_real_escape_string(htmlspecialchars($_POST['Comments']));
$Type = mysql_real_escape_string(htmlspecialchars($_POST['Type']));
// check that firstname/lastname fields are both filled in
if ($Name == '' || $Type == '')
{
// generate error message
$error = 'ERROR: Please fill in all required fields!';
//error, display form
renderForm($id, $Name, $Status, $Comments, $Type, $error);
}
else
{
// save the data to the database
mysql_query("UPDATE Schools SET Name='$Name', Status='$Status', Comments='$Comments', Type='$Type' WHERE id='$id'")
or die(mysql_error());
// once saved, redirect back to the view page
header("Location: view.php");
}
}
else
{
// if the 'id' isn't valid, display an error
echo 'Error!';
}
}
else
// if the form hasn't been submitted, get the data from the db and display the form
{
// get the 'id' value from the URL (if it exists), making sure that it is valid (checing that it is numeric/larger than 0)
if (isset($_GET['id']) && is_numeric($_GET['id']) && $_GET['id'] > 0)
{
// query db
$id = $_GET['id'];
$result = mysql_query("SELECT * FROM Schools WHERE id=$id")
or die(mysql_error());
$row = mysql_fetch_array($result);
// check that the 'id' matches up with a row in the databse
if($row)
{
// get data from db
$Name = $row['Name'];
$Status = $row['Status'];
$Comments = $row['Comments'];
$Type = $row['Type'];
// show form
renderForm($id, $Name, $Status, $Comments, $Type, '');
}
else
// if no match, display result
{
echo "No results!";
}
}
else
// if the 'id' in the URL isn't valid, or if there is no 'id' value, display an error
{
echo 'Error!';
}
}
?>
I am wanting to replace the status text filed with a drop down list of options.
Replace your <input by <select :
<form action="" method="post">
<input type="hidden" name="id" value="<?php echo $id; ?>"/>
<div>
<p><strong>ID:</strong> <?php echo $id; ?></p>
<strong>School Name:</strong> <input type="text" name="Name" value="<?php echo $Name; ?>"/><br/><br>
<!-- <strong>Status:</strong> <input type="text" name="Status" value="<?php echo $Status; ?>"/><br/><br>-->
<strong>Status:</strong> <select name="Status">
<option value="1">Status 1</option>
<option value="2">Status 2</option>
</select>
<strong>Comments:</strong> <input type="text" name="Comments" value="<?php echo $Comments; ?>"/><br/><br>
<strong>Type:</strong> <input type="text" name="Type" value="<?php echo $Type; ?>"/><br/><br>
<input type="submit" name="submit" value="Submit">
</div>
</form>
If your statuses are in a table, fill the <select> with a query :
<form action="" method="post">
<input type="hidden" name="id" value="<?php echo $id; ?>"/>
<div>
<p><strong>ID:</strong> <?php echo $id; ?></p>
<strong>School Name:</strong> <input type="text" name="Name" value="<?php echo $Name; ?>"/><br/><br>
<!-- <strong>Status:</strong> <input type="text" name="Status" value="<?php echo $Status; ?>"/><br/><br>-->
<strong>Status:</strong> <select name="Status">
<?php
$result = mysql_query("SELECT * FROM tbl_status",$cnx);
while ( $row = mysql_fetch_array($result) )
echo "<option value='" . $row["id"] . "'>" . $row["text"] . "</option>";
?>
</select>
<strong>Comments:</strong> <input type="text" name="Comments" value="<?php echo $Comments; ?>"/><br/><br>
<strong>Type:</strong> <input type="text" name="Type" value="<?php echo $Type; ?>"/><br/><br>
<input type="submit" name="submit" value="Submit">
</div>
</form>
You could use the html <datalist> or the <select> tag.
I hope I could help.
First of all you need to switch from mysql_* to mysqli_* as it going to get removed in php 7.0 I'm using this function i created and it might help you
here is the php code
function GetOptions($request)
{
global $con;
$sql = "SELECT * FROM data GROUP BY $request ORDER BY $request";
$sql_result = mysqli_query($con, $sql) or die('request "Could not execute SQL query" ' . $sql);
while ($row = mysqli_fetch_assoc($sql_result)) {
echo "<option value='" . $row["$request"] . "'" . ($row["$request"] == $_REQUEST["$request"] ? " selected" : "") . ">" . $row["$request"] . "$x</option>";
}
}
and the html code goes like
<label>genre</label>
<select name="genre">
<option value="all">all</option>
<?php
GetOptions("genre");
?>
</select>
I'm making a site where the owner has to be able to update their events, but my update code isnt working even though im 99% sure I havent made any errors.
First the form where you press update:
<?php
$sql = "SELECT * FROM events ORDER BY id ASC";
$res = $objCon->query($sql) or die('fejl i query:'.mysqli_error($objCon));
while($row=$res->fetch_array()) {
$id = $row['id'];
echo "<div class='eventpost'>";
echo "<div class='dato'>";
echo $row['id'];
echo "</div>";
echo "<p class='overskrift'>";
echo "<a href='update.php?id=$id'>RET </a>";
echo "<a href='code_delete.php?id=$id'>SLET</a>";
echo $row['overskrift'];
echo "</p>";
echo "</div>";
}
?>
then the update form:
<form action="code_update.php" method="POST">
<label>Dato:<br>
<input type="text" name="dag" value="<?php echo $data['dag']; ?>"></label>
<label>Månede:<br>
<input type="text" name="month" value="<?php echo $data['month']; ?>"></label>
<label>Overskrift:<br>
<input type="text" name="overskrift" value="<?php echo $data['overskrift']; ?>"></label>
<label>Tekst:<br>
<input type="text" name="tekst" value="<?php echo $data['tekst']; ?>"></label>
<input type="hidden" name="id" value="<? echo $id; ?>">
<input type="submit" value="Opret">
</form>
and finally the update code
<?php
session_start();
if($_SESSION['auth'] == 2){
include('incl_db.php');
$id = $_POST['id'];
$overskrift = $_POST['overskrift'];
$dag = $_POST['dag'];
$month = $_POST['month'];
$tekst = $_POST['tekst'];
$sql = "UPDATE events SET overskrift='$overskrift', dag='$dag', month='$month', tekst='$tekst' WHERE id='$id'";
$res = $objCon->query($sql);
header('location:events.php');
}else{
header('location:index.php');
}
?>
Probably shorthand tags are disabled in your php version.So try changing this
<input type="hidden" name="id" value="<? echo $id; ?>">
to this
<input type="hidden" name="id" value="<?php echo $id; ?>">
You can check this answer for more.
Hi there I'm quite new to PHP
I have this problem:
I would like to POST a multiple choice + a hidden field from a form:
<?php
if (isset($_SESSION['nickname']))
{
$result = mysql_query("SELECT * FROM users");
$teamsCount = ceil(mysql_num_rows($result)/2);
for ($i=1; $i<=$teamsCount; $i++)
{
// TEST: echo $i . " TeamsCount er: " . $teamsCount. "<br>";
?>
Team <? echo $i; ?>
<form name="addTeam" action="buildTeams.php" method="POST">
<input type="hidden" name="hiddenField" value="<?php $i; ?>" />
<select name="teams[]" multiple="multiple" size="<?php echo mysql_num_rows($result); ?>">
<?php
$query = mysql_query("SELECT * FROM users");
while ($row=mysql_fetch_array($query))
{
$id=$row["ID"];
$nick=$row["Nick"];
?>
<option value="<?php echo $id; ?>"><?php echo ucfirst($nick); ?></option>
<?php
}
?>
</select>
<input type="submit" value="Make them teams!!" />
</form>
<?php
}
}
?>
I think you have an error in this line:
<input type="hidden" name="hiddenField" value="<?php $i ?>" />
It should be
<input type="hidden" name="hiddenField" value="<?php echo $i ?>" />
Edit:
Put the team id in the select name. Example:
<select name="teams[<?=$i?>][]">
And in PHP do:
foreach ($_POST['teams'] as $team_id => $choices)
I think you should check $_POST['hiddenField'] to obtain hidden value