Pre-Populate Form with Dropdown Menu in PHP/MySQL? - php

I am creating a simple CRUD application that will be used as a blog. For the edit page, I want to have a dropdown menu with the blog titles of each post. When an option/blog post is selected, I want it to populate the "Title" and "Message" fields, so it can then be edited and saved to the database.
I got it to retrieve the titles of the blog posts, but I am struggling to make it populate the "Title" and "Message" fields so it can be edited when the option is selected.
I have 4 rows in my database: row[0] is the title, row[1] is the message, row[2] is the timestamp and row[3] is the ID.
Thanks guys. I appreciate it.
<form action="edit.php" id="myform" method="post" autocomplete=off>
<input type="hidden" name="action" value="show">
<p><label>Entry:</label><select name="blog">
<?php
$result = mysqli_query($con, "SELECT * FROM blog");
while ($row = mysqli_fetch_array($result)) {
$chosen = $row['bid'];
}
if (isset($_GET['blog'])) {
$id = $_GET['blog'];
$result = mysqli_query($con, "SELECT * FROM blog WHERE bid='$id'");
$row = mysqli_fetch_array($result);
}
$result = mysqli_query($con, "SELECT * FROM blog");
while ($row = mysqli_fetch_array($result)) {
$id = $row['bid'];
$title = $row['title'];
$selected = '';
if ($id == $chosen) {
$selected = "selected='selected'";
}
echo "<option value='$id' $selected>$title</option>\n";
}
?>
</select></p>
<p><label>Title:</label> <input type="text" id="newtitle" name="newtitle" value="<?php echo $row[0]; ?>"></p>
<p><label>Message:</label> <input type="text" id="newmessage" name="newmessage" value="<?php echo $row[1]; ?>"></p>
<p><input type="hidden" name="id" value="<?php echo $row[3]; ?>"></p>
<br><p><input type="submit" name="submit" value="Submit"></p>
</form>

I have managed to somewhat figure out the answer on my own. It's probably not the most ideal way of doing it, but for anyone else potentially stuck on this - here is my code:
The only issue I'm having now is figuring out how to keep my option selected.
<form action="edit.php" id="myform" method="post" autocomplete=off>
<input type="hidden" name="action" value="show">
<p><label>Entry:</label><select name="blog" onchange="window.location.href = blog.options[selectedIndex].value">
<option selected disabled>Select One</option>
<?php
$result = mysqli_query($con, "SELECT * FROM blog");
while ($row = mysqli_fetch_array($result)) {
$id = $row['bid'];
$title = $row['title'];
echo "<option value='edit.php?edit=$row[bid]'>$title</option>\n";
}
if (isset($_GET['edit'])) {
$id = $_GET['edit'];
$result = mysqli_query($con, "SELECT * FROM blog WHERE bid='$id'");
$row = mysqli_fetch_array($result);
}
?>
</select></p>
<p><label>Title:</label> <input type="text" id="newtitle" name="newtitle" value="<?php echo $row[0]; ?>"></p>
<p><label>Message:</label> <input type="text" id="newmessage" name="newmessage" value="<?php echo $row[1]; ?>"></p>
<p><input type="hidden" name="id" value="<?php echo $row[3]; ?>"></p>
<br><p><input type="submit" name="submit" value="Submit"></p>
</form>

Related

Old values not appearing in text field when called

I'm trying to call the old values to be edited. What part am I wrong at?
<?php
if (isset($_GET['edit'])) {
$id = $_GET['edit'];
$update = true;
$record = mysqli_query($db, "SELECT * FROM bookinfo WHERE BookNo='$BookNo'");
if (mysqli_num_rows($record) == 1 ) {
$n = mysqli_fetch_array($record);
$BookNo = $n['BookNo'];
$ISBN = $n['ISBN'];
$title = $n['title'];
$author = $n['author'];
$publisher = $n['publisher'];
$status = $n['status'];
$cost = $n['cost'];
}
}
?>
<a href="viewBook.php?edit=<?php echo $row['BookNo']; ?>" class="edit_btn" >Edit</a>
</td>
<?php
if (isset($_GET['edit'])) { ?>
<form method="post" action = "viewBook.php">
<input type="hidden" name="BookNo" value="<?php echo $BookNo; ?>">
<input type="text" name="ISBN" value="<?php echo $ISBN; ?>">
<input type="text" name="title" value="<?php echo $title; ?>">
<input type="text" name="author" value="<?php echo $author; ?>">
<input type="text" name="publisher" value="<?php echo $publisher; ?>">
<input type="text" name="status" value="<?php echo $status; ?>">
<input type="text" name="cost" value="<?php echo $cost; ?>">
<?php if ($update == true): ?>
<button class="btn" type="submit" name="update" style="background: #556B2F;" >update</button>
<?php else: ?>
<button class="btn" type="submit" name="save" >Save</button>
<?php endif ?>
<?php } ?>
</form>
So far, what it does is, when the user clicks the edit button, it just shows 6 text fields. I thought by doing what I did, it was supposed to show the details already filled in the textbox.
When you do
$record = mysqli_query($db, "SELECT * FROM bookinfo WHERE BookNo='$BookNo'");
$BookNo is not defined.
maybe you wanted to do something like this:
$id = $_GET['edit'];
$update = true;
$record = mysqli_query($db, "SELECT * FROM bookinfo WHERE BookNo='$id'");
<form method="post" action = "viewBook.php">
your form method is "post" but you are checking $_GET You must check $_POST
if (isset($_GET['edit']))
you are passing value in $id And using $BookNo which not define.
only 6 input field will be show because first one is using hidden property.
<input type="hidden" name="BookNo" value="<?php echo $BookNo; ?>">
when you click on submit button data will be receive by $_POST

How to add to this update SQL statement and make a drop down list too for it

Okay i have this SQL statement for update which works find but I want to add locations which is in te_venue table after adding the location into sql i want for locations to be a drop down list which user can pick one location from list and when clicked on update it should update.
This is the php code that I have already (I need to add location into this)
<?php
$eventID = $_GET['id'];
if(isset($_POST['submit']))
{
$title = $_POST['title'];
$startdate = $_POST['startdate'];
$enddate = $_POST['enddate'];
$price = $_POST['price'];
$description = $_POST['description'];
$sql = "UPDATE te_events SET eventTitle='$title',eventStartDate='$startdate',eventEndDate='$enddate',eventPrice='$price',eventDescription='$description' WHERE eventID=$eventID";
if ($conn->query($sql) === TRUE)
{
header('Location:edit.php');
}
else
{
echo "Error updating record";
}
}
$sql = "SELECT * FROM te_events where eventID='$eventID'";
$result = $conn->query($sql);
while($row = $result->fetch_assoc())
{
$eventTitle = $row['eventTitle'];
$eventDescription = $row['eventDescription'];
$eventStartDate = $row['eventStartDate'];
$eventEndDate = $row['eventEndDate'];
$eventPrice = $row['eventPrice'];
}
?>
And this is where i want to have a drop down list for location.
<form method="post" action="">
<label for="title">Title</label><br/>
<input type="text" name="title" required/ value="<?php echo $eventTitle; ?>"><br/>
<label for="startdate">Start Date</label><br/>
<input type="date" name="startdate" required/ value="<?php echo $eventStartDate; ?>"><br/>
<label for="enddate">End Date</label><br/>
<input type="date" name="enddate" required/ value="<?php echo $eventEndDate; ?>"><br/>
<label for="price">Price (£)</label><br/>
<input type="number" step="any" name="price" required/ value="<?php echo $eventPrice; ?>"><br/>
<label for="description">Description</label><br/>
<textarea name="description" cols="55" rows="5"><?php echo $eventDescription; ?></textarea><br/>
<input type="submit" name="submit" value="Update" class="button">
</form>
Here is a screenshot of my tables too it might help.
https://postimg.org/image/6ui8nsi55/
Do you want something like this? Getting the location from te_venue and adding the results to a select?
<select>
<?php
$sql = "SELECT location FROM te_venue";
$result = $conn->query($sql);
while($row = $result->fetch_assoc())
}
?>
<option value="<?php echo $row['location'];?>"><?php echo $row['location'];?> </option>
<?php
}
?>
</select>
<label for="location">Choose a location: </label>
<select class="form-control" name="location">
<option value="London">London</option>
<option value="Paris">Paris</option>
<option value="Rome">Rome</option>
<option value="Berlin">Berlin</option>
<option value="Moscow">Moscow</option>
</select>

How to Edit a MySQL Data base from a PHP Site

I have built a database named "artStore" and a table within that database named "inventory". I've been able to figure out how to create a new entry to the database, but I'm trying to create a page that can edit those entries.
Here is "inventory" the table I created:
$sql = "CREATE TABLE inventory (
id INT(6) AUTO_INCREMENT PRIMARY KEY,
product VARCHAR(30),
category VARCHAR(30),
seller VARCHAR(30)
)";
Here is what I'm currently trying:
<?php
$resultProduct = "product";
$resultCategory = "category";
$resultSeller = "seller";
if ($result->num_rows > 0) {
while ($row = $result->fetch_assoc()) {
$resultProduct = $row["product"];
$resultCategory = $row["category"];
$resultSeller = $row["seller"];
}
} else {
echo "No Results";
}
?>
<form action="update.php" method="POST">
<label for="product">Product</label>
<input id="product" type="text" name="product" value="<?php echo $resultProduct; ?>">
<br>
<label for="category">Category:</label>
<input id="category" type="text" name="category" value="<?php echo $resultCategory; ?>">
<br>
<label for="seller">Seller:</label>
<input id="seller" type="text" name="seller" value="<?php echo $resultSeller; ?>">
<br>
<input id="id" type="text" name="id" value="<?php echo $resultId; ?>" style="display:none;">
<input type="submit" value="Update My Record">
</form>
What I'm trying in update.php
$product = $_POST['product'];
$category = $_POST['category'];
$seller = $_POST['seller'];
$sql = "INSERT INTO inventory (product, category, seller) VALUES ('$product', '$category', '$seller')";
if ($connection->query($sql) === true) {
echo "Inserted Successfully";
} else {
echo "Error occured in the insert: " . $connection->error;
}
$connection->close();
Try the below code I added hidden field on form and changes on your sql query
<?php
$resultProduct = "product";
$resultCategory = "category";
$resultSeller = "seller";
if ($result->num_rows > 0) {
while ($row = $result->fetch_assoc()) {
$resultProduct = $row["product"];
$resultCategory = $row["category"];
$resultSeller = $row["seller"];
$resultId = $row["id"];
}
} else {
echo "No Results";
}
?>
<form action="update.php" method="POST">
<input type="text" name="update_id" value="<?php echo $resultId; ?>">
<label for="product">Product</label>
<input id="product" type="text" name="product" value="<?php echo $resultProduct; ?>">
<br>
<label for="category">Category:</label>
<input id="category" type="text" name="category" value="<?php echo $resultCategory; ?>">
<br>
<label for="seller">Seller:</label>
<input id="seller" type="text" name="seller" value="<?php echo $resultSeller; ?>">
<br>
<input id="id" type="text" name="id" value="<?php echo $resultId; ?>" style="display:none;">
<input type="submit" value="Update My Record">
</form>
In update.php
$product = $_POST['product'];
$category = $_POST['category'];
$seller = $_POST['seller'];
$updateId = $_POST['update_id'];
$sql = "UPDATE inventory set product = '$product',category='$category',seller='$seller' WHERE id = '$updateId'";
<?php
$resultProduct = "product";
$resultCategory = "category";
$resultSeller = "seller";
$resultId = "product_id";
if ($result->num_rows > 0) {
while ($row = $result->fetch_assoc()) {
$resultProduct = $row["product"];
$resultCategory = $row["category"];
$resultSeller = $row["seller"];
$resultid = $row["id"];
}
} else {
echo "No Results";
}
?>
You were using $resultId in the form but you have not declared and assigned a value to it in the loop.
<form action="update.php" method="POST">
<input id="id" type="hidden" name="id" value="<?php echo $resultId; ?>">
<label for="product">Product</label>
<input id="product" type="text" name="product" value="<?php echo $resultProduct; ?>">
<br>
<label for="category">Category:</label>
<input id="category" type="text" name="category" value="<?php echo $resultCategory; ?>">
<br>
<label for="seller">Seller:</label>
<input id="seller" type="text" name="seller" value="<?php echo $resultSeller; ?>">
<br>
<input type="submit" value="Update My Record">
</form>
<!-- Instead of passing the ID in textbox with display: none you can pass it directly in hidden -->
<?php
$product = $_POST['product'];
$category = $_POST['category'];
$seller = $_POST['seller'];
$product_id = $_POST['id'];
if($product_id!='')//MEANS WE HAVE TO UPDATE THE RECORD
{
// UPDATE QUERY WILL UPDATE THE SAME RECORD ONLY MATCHING THE UNIQUE PRODUCT ID
$sql = "UPDATE inventory SET product = '$product', category = '$category', seller = '$seller' WHERE id = '$product_id' LIMIT 1";
if ($connection->query($sql) === true) {
echo "Updated Successfully";
} else {
echo "Error occured in the insert: " . $connection->error;
}
}
else// If id is blank it means you have a new record
{
$sql = "INSERT INTO inventory (product, category, seller) VALUES ('$product', '$category', '$seller')";
if ($connection->query($sql) === true) {
echo "Inserted Successfully";
} else {
echo "Error occured in the insert: " . $connection->error;
}
}
$connection->close();
?>

check box issue during editing in php

This is advertisement query
INSERT into advertise_management(advertisement_name,adv_code) values('".$adv_name."','".$adv_code."')
post management:
<input type="text" name="post_name" value="<?php if(isset($post_value)){ echo $post_value['post_name'];} else { echo ''; }?>" required="required">
<?php $res= mysql_query("select * from advertise_management ");
while($result= mysql_fetch_array($res)){
$adv=$result['advertisement_name'];
{ ?>
<input type="checkbox" value="<?php echo $adv?>" name="post_adv[]">
<?php } ?>
Post Management insert query :
$post_name = $_POST['post_name'];
$post_adv1 = $_POST['post_adv'];
$post_adv = implode(",", $post_adv1);
$post_id = $_POST['post_id'];
$res = mysql_query("INSERT into post_managment(post_name,post_adv) values('".$post_name."','".$post_adv."')") or die(mysql_error());
Post management edit :
$result = mysql_query("SELECT * FROM post_managment where post_id='$pid'");
$post_value = mysql_fetch_array($result);
><input type="text" name="post_name" value="<?php if(isset($post_value)){ echo $post_value['post_name'];} else { echo ''; }?>" required="required">
<?php $res= mysql_query("select * from advertise_management ");
while($result= mysql_fetch_array($res)){
$adv=$result['advertisement_name'];
{ ?>
<input type="checkbox" value="<?php echo $adv?>" name="post_adv[]">
<?php } ?>
<input type="submit" value="" id="create"><input type="reset" value="" id="cancel">
I want to return the values that is checked and the values that is not checked.
The browser normally won't send anything for checkboxes that aren't checked. You can work around this by also rendering a hidden input () with the same name and a different value. Make sure it's output right before the checkbox.

Updating Post not working

I recently made a code that updates my posts on my blog. It worked perfectly on localhost. But when i uploaded it online it did not work any more. The weird thing is it doesn't even display a error so i have no idea where to look. Can someone please help me ?
require('config.php');
$query = "SELECT * FROM project ORDER BY idproject DESC";
$result = mysqli_query($verbinding, $query ) or die (mysqli_error('kan geen verbinding maken met de database'));
if(isset($_POST['editBut'])){
$editTitle = $_POST['editName'];
$editThis = mysqli_query($verbinding, "SELECT * FROM project WHERE title = '".$editTitle."'");
$values = mysqli_fetch_assoc($editThis);
}
if(isset($_POST['update'])){
$editedTitle = $_POST['newTitle'];
$editedText = $_POST['newTekst'];
$oldTitle = $_POST['oldTitle'];
$date = $_POST['datum'];
$updater = mysqli_query($verbinding, "UPDATE Project SET title='".$editedTitle."', content='".$editedText."' WHERE title='".$oldTitle."' AND datum='".$date."'");
echo $updater;
header('location:editPost.php?id=1');
}
if(isset($_GET['id'])){
echo 'post has been succesfully updated';
}
<?php if(isset($_POST['editBut'])){ ?>
<form action="" method="post">
Title: <input type="text" name="newTitle" value="<?php echo $values['title'] ?>"><br>
Text: <textarea type="text" name="newTekst" id="newTekst"><?php echo $values['content'] ?></textarea><br>
<input type="hidden" value="<?php echo $values['title'] ?>" name="oldTitle">
<input type="hidden" value="<?php echo $values['datum'] ?>" name="datum">
<input type="submit" name="update" value="Edit post">
</form>
<?php } else { ?>
<p>Find the post you want to edit:</p>
<form action="" method="post">
<select name="editName">
<?php
while ($row = mysqli_fetch_assoc($result)) {
?> <option value="<?php echo $row['title'] ?>"><?php echo $row['title'] ?></option>
<?php } ?>
</select>
<input type="submit" name="editBut" value="Choose">
</form>
<?php } ?>
In update query replace your table name with small letter.
replace Project with project

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