Im building a search engine from scratch.
It scans many different tables in multiple databases.
It searches through only the specified columns.
The search words are explode()'ed case of multiple words search
It iterates with a foreach through the tables.
I'm having trouble structuring the code base with LIMIT. I want it to show only DISTINCT.
For example if I search Joe Schmoe my code will search for first = joe and then for last = schmoe, and it will display a result for each search. But I want it to display only one result for the two searches.
<?php
echo "<h1>Search Results</h1>";
echo "<table style='width: 100%;'>";
$a = $_GET["q"];
$b = explode(" ", $a);
include 'db_connect3.php';
mysql_select_db("db440035579", $con);
foreach($b as $c){
$sql="SELECT * FROM users WHERE first LIKE '%$c%' || last LIKE '%$c%'";
$result = mysql_query($sql);
while($row = mysql_fetch_array($result))
{
echo "<a href='applications.php?act=search&uid=$row[7]'>$row[5], $row[4]</a>";
}
}
mysql_close($con);
?>
First of all http://bobby-tables.com/
Secondly, plugging in PDO takes only a few lines of code.
Thirdly, FULL TEXT SEARCH is much better.
And finally:
Use a array microcaching. I assume $row[0] is the user.id. That way you only get one item per ID
$cache = array();
foreach($b as $c){
$sql="SELECT * FROM users WHERE first LIKE '%$c%' || last LIKE '%$c%'";
$result = mysql_query($sql);
while($row = mysql_fetch_array($result)){
$cache[$row[0]] = $row;
}
}
foreach($cache as $row){
echo "<a href='applications.php?act=search&uid=$row[7]'>$row[5], $row[4]</a>";
}
Related
I have two tables. First one contains first names, second one contains last names. (I could do it with one table with two columnes, but I'm using this way for other reason)
I want to make all possible combinations.
So if there are first names: John, Zed, Marko, and last names: Abbot, Zang I would like to get output like:
JohnAbbot
JohnZagn
ZedAbbot
ZedZang
MarkoAbbot
MarkoZang
I did something similar with For loop and alfanumeric signs. I was able to do it with 6 nested for loops, but I can't get this to work with while loop.
this is the code I use:
$query_name = "SELECT name FROM names";
$results=mysqli_query($connect, $query_name);
$query_surname = "SELECT surname FROM surnames";
$results2=mysqli_query($connect, $query_surname);
while ($row = mysqli_fetch_assoc($results)) {
while ($row2 = mysqli_fetch_assoc($results2)) {
echo $row['name'].$row2['surname']."<br/>";
}
}
with this I got only combinations with 1 name and all surnames.
after I added one more echo in first while loop like this:
while ($row = mysqli_fetch_assoc($results)) {
echo $row['name']."<br/>";
while ($row2 = mysqli_fetch_assoc($results2)) {
echo $row['name'].$row2['surname']."<br/>";
}
}
with this I got:
first name from names table
combinations with first name and all last names (surnames)
all others names
I did not get all the combinations with all names and surnames.
What am I doing wrong?
Thank you in advance
(sorry for my bad english)
That's because fetching is only done once per handle, so when your inner loop reaches the end of records, it will never go back to the first one - as you would need it to - but stay at the end and return false.
If your result sets are not million-row ones, try fetching both only once, then combine the arrays and foreach-loops which will obediently start from the beginning each time:
$a1 = array();while ($row = mysqli_fetch_assoc($results)) $a1[]=$row;
$a2 = array();while ($row = mysqli_fetch_assoc($results)) $a2[]=$row;
foreach($a1 as $row1) {
foreach($a2 as $row2) {
echo $row1['name'].$row2['surname']."<br/>";
}
}
You can do with a simple query
select a.name, b.surname
from names as a
FULL JOIN surnames as b
Okay essentially what I'm trying to achieve is to combine the first query with the second one the trouble I'm having is that I'm unable to array out the results from the first query to then use in the second one. Here is my first query what this achieves is that it selects all the room subjects from my users which typically look like this, welcome to my #room hope you #enjoy once is selects one it will then strip the subject of the words and will only keep the hash-tags for example it will keep #room and #enjoy once its goes through and selects all the hash-tags from all of the room subjects it will then order them from how frequent they are used among subjects of all users.
$sql = mysql_query("SELECT subject FROM `users`");
$row = mysql_fetch_array($sql);
$freqDist = [];
foreach($results as $row)
{
$words = explode(" ", $row);
foreach($words as $w)
{
if (array_key_exists($w, $freqDist))
$freqDist[$w]++;
else
$freqDist[$w] = 1;
}
}
arsort($freqDist);
foreach($freqDist as $word => $count)
{
if (strpos($word, '#') !== FALSE)
echo "$word: $count\n";
else
echo "$word: does not contain hashtag, DROPPED\n";
}
Now what I'm trying to achieve here is that I'm trying to array out the results from the above query so then I can perform an action on each hash-tag which is grabbed from above. Below I have included the code and essentially the problem I face lies solely on this line $all = array("hashtag1", "hashtag2", "hashtag3"); as what I'm trying to achieve is instead of typing in directly the hash-tags I want to perform the action on I would want them to be grabbed via using the above query.
$all = array("hashtag1", "hashtag2", "hashtag3");
$trending = $all;
foreach($trending as $tags)
{
$sql = mysql_query("SELECT * FROM `users` WHERE `subject` LIKE '%$tags%'");
$sums = mysql_query("SELECT SUM(viewers) AS viewers FROM `users` WHERE `subject` LIKE '%$tags%'");
$num_rows = mysql_num_rows($sql);
$row = mysql_fetch_assoc($sql);
$sum = mysql_fetch_assoc($sums);
}
So again just to outline my problem I'm trying to grab the results from the first query and use them as an array with the second query. I apologise for the length of this question I just assumed it would help you better understand my question.
As per my understanding, you want to store the hashtag value in an array. if so then just update your foreach()
$hashWord = array();
foreach($freqDist as $word => $count)
{
if (strpos($word, '#') !== FALSE)
echo "$word: $count\n";
$hashWord[] = $word;
else
echo "$word: does not contain hashtag, DROPPED\n";
}
Hi I would like to compare two tables from two different databases.
Select from the first database
$sql= mysqli_query ("SELECT * FROM emasa.staff_detail");
$row = mysqli_fetch_array($sql);
Select from the second database
$sql2 = mysqli_query ("SELECT * FROM employee");
$row2 = mysqli_fetch_array($sql2);
Then I compare the two table
if ($row['icnum'] == $row2['emp_ic'])
{
echo "Data already exist in both database.";
}
else
{
while ($row = mysqli_fetch_assoc($sql))
{
echo "<td align='center' height='30'>" . $row ['name'] . "</td>";
echo "<td align='center'>" .$row['icnum'] . "</td>";
}
}
But my problem is it only compares the first row in the database.
My output should only display the staff name that is not available in the other database. However, this is my output.
Based on the output it only compares the first row. So how do I change my code so that it compares the whole row. Please help me, thank you!
You're not looping through the results of the query. You're simply getting back the first row and going with that.
Ex:
$sql= mysqli_query ("SELECT * FROM emasa.staff_detail");
This is returning a result set which you then need to use
$row = mysqli_fetch_array($sql);
to get the actual values. The problem comes when
$row = mysqli_fetch_array($sql);
by itself only gives you one row.
Solution 1
You must use code like this:
while($row = mysqli_fetch_array($sql))
{
//Do some comparison
}
Since you're going to have to loop through two different result sets, you're going to have to do a loop within a loop, build an array of results and then loop through the results afterwards to output your HTML.
Ex:
while($row = mysqli_fetch_array($sql))
{
while($row2 = mysqli_fetch_array($sql2))
{
if ($row['icnum'] == $row2['emp_ic'])
{
//add to array of equal data
}
else
{
//add to array of not equal data
}
}
}
foreach($array as $not_equal_or_equal_data)
{
//output your desired HTML
}
Solution 2
Depending on what you actually care about, you could do a sql statement like this
$sql = "
SELECT
*
FROM
emasa.staff_detail AS sd
JOIN db2.employee AS e
ON sd.icnum = e.emp_ic";
This would return all the rows where those two columns were equal
$search = htmlspecialchars($_GET["s"]);
if(isset($_GET['s'])) {
// id index exists
$wordarray = explode(" ",$search);
$stringsearch = implode('%',$wordarray);
echo $stringsearch;
echo ",";
$result = mysqli_fetch_array($conn->query("SELECT ID FROM table WHERE title LIKE '%$stringsearch%';"));
if (!empty($result)) {
echo sizeof($result);
echo ",";
Database has 3 rows with titles test,pest,nest with corresponding id's 1,2,3. when i request domain.com/?s=est
it echos something like this
est,2,
Now when i checked $result[0] and $result[1], $result[0] echoed 1 and $result[1] didn't echo anything. When I use foreach function, it is taking only value of $result[0]
and $result should be array of all the three indexes.
I cannot find any mistake,
when i type the same command in sql console it works, somebody help me, thanks in advance.
The problem is, if you're expecting multiple rows, then don't do this:
$result = mysqli_fetch_array($conn->query("SELECT ID FROM table WHERE title LIKE '%$stringsearch%';"));
This only fetches the first row, you need to loop it to advance the next pointer and get the next following row set:
$result = $conn->query("SELECT ID FROM table WHERE title LIKE '%$stringsearch%' ");
while($row = $result->fetch_array()) {
echo $row[0] . '<br/>';
// or $row['ID'];
}
Sidenote: Consider using prepared statements instead, since mysqli already supports this.
I have a small problem and since I am very new to all this stuff, I was not successful on googling it, because I dont know the exact definitions for what I am looking for.
I have got a very simple database and I am getting all rows by this:
while($row = mysql_fetch_array($result)){
echo $row['id']. " - ". $row['name'];
echo "<br />";
}
Now, my question is: how do I filter the 2nd result? I thought something like this could work, but it doesnt:
$name2= $row['name'][2];
Is it even possible? Or do I have to write another mysql query (something like SELECT .. WHERE id = "2") to get the name value in the second row?
What I am trying to is following:
-get all data from the database (with the "while loop"), but than individually display certain results on my page. For instance echo("name in second row") and echo("id of first row") and so on.
If you would rather work with a full set of results instead of looping through them only once, you can put the whole result set to an array:
$row = array();
while( $row[] = mysql_fetch_array( $result ) );
Now you can access individual records using the first index, for example the name field of the second row is in $row[ 2 ][ 'name' ].
$result = mysql_query("SELECT * FROM ... WHERE 1=1");
while($row = mysql_fetch_array($result)){
/*This will loop arround all the Table*/
if($row['id'] == 2){
/*You can filtere here*/
}
echo $row['id']. " - ". $row['name'];
echo "<br />";
}
$counter = 0;
while($row = mysql_fetch_array($result)){
$counter++;
if($counter == 2){
echo $row['id']. " - ". $row['name'];
echo "<br />";
}
}
This While loop will automatically fetch all the records from the database.If you want to get any other field then you will only need to use for this.
Depends on what you want to do. mysql_fetch_array() fetches the current row to which the resource pointer is pointing right now. This means that you don't have $row['name'][2]; at all. On each iteration of the while loop you have all the columns from your query in the $row array, you don't get all rows from the query in the array at once. If you need just this one row, then yes - add a WHERE clause to the query, don't retrieve the other rows if you don't need them. If you need all rows, but you wanna do something special when you get the second row, then you have to add a counter that checks which row you are currently working with. I.e.:
$count = 0;
while($row = mysql_fetch_array($result)){
if(++$count == 2)
{
//do stuff
}
}
Yes, ideally you have to write another sql query to filter your results. If you had :
SELECT * FROM Employes
then you can filter it with :
SELECT * FROM Employes WHERE Name="Paul";
if you want every names that start with a P, you can achieve this with :
SELECT * FROM Employes WHERE Name LIKE "P%";
The main reason to use a sql query to filter your data is that the database manager systems like MySQL/MSSQL/Oracle/etc are highly optimized and they're way faster than a server-side condition block in PHP.
If you want to be able to use 2 consecutive results in one loop, you can store the results of the first loop, and then loop through.
$initial = true;
$storedId = '';
while($row = mysql_fetch_array($result)) {
$storedId = $row['id'];
if($initial) {
$initial = false;
continue;
}
echo $storedId . $row['name'];
}
This only works for consecutive things though.Please excuse the syntax errors, i haven't programmed in PHP for a very long time...
If you always want the second row, no matter how many rows you have in the database you should modify your query thus:
SELECT * FROM theTable LIMIT 1, 1;
See: http://dev.mysql.com/doc/refman/5.5/en/select.html
I used the code from the answer and slightly modified it. Thought I would share.
$result = mysql_query( "SELECT name FROM category;", db_connect() );
$myrow = array();
while ($myrow[] = mysql_fetch_array( $result, MYSQLI_ASSOC )) {}
$num = mysql_num_rows($result);
Example usage
echo "You're viewing " . $myrow[$view_cat]['name'] . "from a total of " . $num;