I have two tables. First one contains first names, second one contains last names. (I could do it with one table with two columnes, but I'm using this way for other reason)
I want to make all possible combinations.
So if there are first names: John, Zed, Marko, and last names: Abbot, Zang I would like to get output like:
JohnAbbot
JohnZagn
ZedAbbot
ZedZang
MarkoAbbot
MarkoZang
I did something similar with For loop and alfanumeric signs. I was able to do it with 6 nested for loops, but I can't get this to work with while loop.
this is the code I use:
$query_name = "SELECT name FROM names";
$results=mysqli_query($connect, $query_name);
$query_surname = "SELECT surname FROM surnames";
$results2=mysqli_query($connect, $query_surname);
while ($row = mysqli_fetch_assoc($results)) {
while ($row2 = mysqli_fetch_assoc($results2)) {
echo $row['name'].$row2['surname']."<br/>";
}
}
with this I got only combinations with 1 name and all surnames.
after I added one more echo in first while loop like this:
while ($row = mysqli_fetch_assoc($results)) {
echo $row['name']."<br/>";
while ($row2 = mysqli_fetch_assoc($results2)) {
echo $row['name'].$row2['surname']."<br/>";
}
}
with this I got:
first name from names table
combinations with first name and all last names (surnames)
all others names
I did not get all the combinations with all names and surnames.
What am I doing wrong?
Thank you in advance
(sorry for my bad english)
That's because fetching is only done once per handle, so when your inner loop reaches the end of records, it will never go back to the first one - as you would need it to - but stay at the end and return false.
If your result sets are not million-row ones, try fetching both only once, then combine the arrays and foreach-loops which will obediently start from the beginning each time:
$a1 = array();while ($row = mysqli_fetch_assoc($results)) $a1[]=$row;
$a2 = array();while ($row = mysqli_fetch_assoc($results)) $a2[]=$row;
foreach($a1 as $row1) {
foreach($a2 as $row2) {
echo $row1['name'].$row2['surname']."<br/>";
}
}
You can do with a simple query
select a.name, b.surname
from names as a
FULL JOIN surnames as b
Related
i have a mysql table the contains an index id, a data entry and 10 other columns called peso1, peso2, peso3...peso10. im trying to get the last 7 peso1 values for a specific id.
like:
$sql = mysql_query("SELECT * FROM table WHERE id='$id_a' ORDER BY data DESC LIMIT 0, 7");
when i try to fetch those values with mysql_fetch_array, i get all values together.
example:
while($line = mysql_fetch_array($sql)) {
echo $line['peso1'];
}
i get all peso1 values from all 7 days together. How can i get it separated?
They will appear all together because you are not separating them as you loop through them.
for example, insert a line break and you will see them on separate lines
while($line = mysql_fetch_array($sql)) {
echo $line['peso1'] ."<br />";
}
You could key it as an array like so
$myArray = array();
$i = 1;
while($line = mysql_fetch_array($sql)) {
$myArray['day'.$i] = $line['peso1'];
$i++;
}
Example use
$myArray['day1'] // returns day one value
$myArray['day2'] // returns day two value
It's not clear what you mean by "separated" so I'm going to assume you want the values as an array. Simply push each row field that you want within your while loop onto an array like this:
$arr = array();
while($line = mysql_fetch_array($sql)) {
$arr[]=$line['peso1'];
}
print_r($arr);//will show your peso1 values as individual array elements
What am I trying to do is collect data from a while loop, store it into a variable. Then later in my code I see if some variable is equal to one of the values in the array and then to echo out the two other column values I got from the while loop but equal to the row that the value came from. I have tried a bunch different things and am so close but cant get it exactly.
while($row = mysql_fetch_assoc($query)){
$team[] .= "{$row['team']}";
$winslosses .= "({$row['wins']} - {$row['losses']})";
}
this returns something like
$team = (bears, badgers, wildcats)
$winslosses = ((42-24), (55-23), (32-21))
Then later in my code I want to see if its equal to a value in the array then echo $winslosses.
if(in_array(bears, $team) ) {echo '$winslosses';}
This shows all the wins and losses from each team. I want it only show me the record of the bears.
Any help would be great.
You can use array_search() to get the index of an item in an array. You can then use that index when querying $winlosses:
$team = array(bears, badgers, wildcats);
$winslosses = array("(42-24)", "(55-23)", "(32-21)");
$key=array_search(bears, $team);
echo $winslosses[$key]
results in:
(42-24)
Your best bet would be to store them in an associative array.
while($row = mysql_fetch_assoc($query)){
$winslosses[$row['team']] = "({$row['wins']} - {$row['losses']})";
}
Hope this helps
Your main problem is that you currently have $winslosses as a string, not an array, so you can't easily pull out the win/loss record for just one team.
There are several ways you could do this. The one that seems easiest to me would be to put it together as one array up front.
Something like...
while($row = mysql_fetch_assoc($query)){
$teams[$row['team']] = "({$row['wins']} - {$row['losses']})";
}
Then later on...
if(array_key_exists("bears",$teams)) {
echo $teams["bears"];
}
Or even better, store the wins/losses as a sub-array, so you have structured data that you can format however you want later on.
while($row = mysql_fetch_assoc($query)){
$teams[$row['team']] = array("wins" => $row['wins'], "losses" => $row['losses']);
}
echo $teams['bears']['wins']; // for example
Use associative array:
while($row = mysql_fetch_assoc($query)){
$team[] = {$row['team']};
$winslosses[$row['team']] = "{$row['wins']} - {$row['losses']}";
}
Then retrieve it like this:
if(in_array(bears, $team) ) {
echo $winslosses['bears'];
}
As a matter of fact, if you do not need the names of the teams in a separate array, you can just use one associative array and then retrieve it.
if (array_key_exists('bears', $winslosses)) {
echo $winslosses['bears'];
}
I'm probably missing something easy, but I seem to be blocked here... I have a MySQL database with two tables and each table has several rows. So the goal is to query the database and display the results in a table, so I start like so:
$query = "SELECT name, email, phone FROM users";
Then I have this PHP code:
$result = mysql_query($query);
Then, I use this to get array:
$row = mysql_fetch_array($result);
At this point, I thought I could simply loop through the $row array and display results in a table. I already have a function to do the looping and displaying of the table, but unfortunately the array seems to be incomplete before it even gets to the function.
To troubleshoot this I use this:
for ($i = 0; $i < count($row); $i++) {
echo $row[$i] . " ";
}
At this point, I only get the first row in the database, and there are 3 others that aren't displaying. Any assistance is much appreciated.
You need to use the following because if you call mysql_fetch_array outside of the loop, you're only returning an array of all the elements in the first row. By setting row to a new row returned by mysql_fetch_array each time the loop goes through, you will iterate through each row instead of whats actually inside the row.
while($row = mysql_fetch_array($result))
{
// This will loop through each row, now use your loop here
}
But the good way is to iterate through each row, as you have only three columns
while($row = mysql_fetch_assoc($result))
{
echo $row['name']." ";
echo $row['email']." ";
}
One common way to loop through results is something like this:
$result = mysql_query($query);
while ($row = mysql_fetch_assoc($result)) {
print_r($row);
// do stuff with $row
}
Check out the examples and comments on PHP.net. You can find everything you need to know there.
I'm trying to figure out the best way to do something like this. Basically what I want to do (in a simple example) would be query the database and return the 3 rows, however if there aren't 3 rows, say there are 0, 1, or 2, then I want to put other data in place of the missing rows.
Say my query returns 2 rows. Then there should be 1 list element returned with other data.
Something like this:
http://i42.tinypic.com/30xhi1f.png
$query = mysql_query("SELECT * FROM posts LIMIT 3");
while($row = mysql_fetch_array($query))
{
print "<li>".$row['post']."</li>";
}
//(this is just to give an idea of what i would likkeee to be able to do
else
{
print "<li>Add something here</li>";
}
You can get the number of items in the resultset with mysql_num_rows. Just build the difference to find out how many items are "missing".
There are three ways I can think of, get the row count with mysql_num_rows, prime an array with three values and replace them as you loop the result set, or count down from three as your work, and finish the count with a second loop, like this:
$result = db_query($query);
$addRows = 3;
while ($row = mysql_fetch_assoc($result){
$addRows--;
// do your stuff
}
while ($addRows-- > 0) {
// do your replacement stuff
}
If you dont find a row, Add extra information accordingly.
$query = mysql_query("SELECT * FROM posts");
for($i=0;$i<3;$i++){
$row = mysql_fetch_array($query);
if($row){
print "<li>".$row['post']."</li>";
}
//(this is just to give an idea of what i would likkeee to be able to do
else{
print "<li>Add something here</li>";
}
}
Assuming you store the rows in an array or somesuch, you can simply do some padding with a while loop (depending how you generate the other data):
while (count($resultList) < 3) {
// add another row
}
I currently have a database like the picture below.
Where there is a query that selects the rows with number1 equaling 1. When using
mysql_fetch_assoc()
in php I am only given the first is there any way to get the second? Like through a dimesional array like
array['number2'][2]
or something similar
Use repeated calls to mysql_fetch_assoc. It's documented right in the PHP manual.
http://php.net/manual/function.mysql-fetch-assoc.php
// While a row of data exists, put that row in $row as an associative array
// Note: If you're expecting just one row, no need to use a loop
// Note: If you put extract($row); inside the following loop, you'll
// then create $userid, $fullname, and $userstatus
while ($row = mysql_fetch_assoc($result)) {
echo $row["userid"];
echo $row["fullname"];
echo $row["userstatus"];
}
If you need to, you can use this to build up a multidimensional array for consumption in other parts of your script.
$Query="select SubCode,SubLongName from subjects where sem=1";
$Subject=mysqli_query($con,$Query);
$i=-1;
while($row = mysqli_fetch_array($Subject))
{
$i++;
$SubjectCode[$i]['SubCode']=$row['SubCode'];
$SubjectCode[$i]['SubLongName']=$row['SubLongName'];
}
Here the while loop will fetch each row.All the columns of the row will be stored in $row variable(array),but when the next iteration happens it will be lost.So we copy the contents of array $row into a multidimensional array called $SubjectCode.contents of each row will be stored in first index of that array.This can be later reused in our script.
(I 'am new to PHP,so if anybody came across this who knows a better way please mention it along with a comment with my name so that I can learn new.)
This is another easy way
$sql_shakil ="SELECT app_id, doctor_id FROM patients WHERE doctor_id = 201 ORDER BY ABS(app_id) ASC";
if ($result = $con->query($sql_shakil)) {
while ($row = $result->fetch_assoc()) {
printf ("%s (%s)\n", $row["app_id"], $row["doctor_id"]);
}
Demo Link
It looks like the complete solution has not been suggested yet
$Query="select SubCode,SubLongName from subjects where sem=1";
$Subject=mysqli_query($con,$Query);
$Rows = array ();
while($row = mysqli_fetch_array($Subject))
{
$Rows [] = $row;
}
The $Rows [] = $row appends the row to the array. The result is a multidimensional array of all rows.