i want to update query from array.the problem is when i ran the code, the updated data in the database just the first data..
example..
the array consist of integer type = [1,2]
when i ran the code, the data in the database just ran the first data (only 1)..how can i fix this?
PHP file
$query_edit_paket = "select nama_menu from menu where id_menu = 149 ";
$query_exec_edit_paket = mysql_query($query_edit_paket) or die(mysql_error());
$nama_menu_query = reset(mysql_fetch_assoc($query_exec_edit_paket));
$_fbexclude = mysql_query("select id_paket from detail_paket where menu_paket = '$nama_menu_query' ");
$fbexcludearray = array();
while ($row = mysql_fetch_assoc($_fbexclude)) {
$fbexcludearray[] = $row['id_paket'];
}
$excludes = implode(',', $fbexcludearray);
echo $excludes;
for($i=0;$i<count($excludes);$i++)
{
if($excludes != "")
{
$strSQL = "update paket set ketersediaan_paket ='kosong' ";
$strSQL .="WHERE id_paket = '$excludes' ";
$objQuery = mysql_query($strSQL);
}
}
thanks!!
Try using IN
change
$strSQL .="WHERE id_paket = '$excludes' ";
to
$foo = '';
for($i=0; $i < count($fbexcludearray); $i++){
$foo.= $i == 0? $fbexcludearray[$i]: ','.$fbexcludearray[$i];
}
$strSQL .="WHERE id_paket IN ($foo) ";
If you were to print your $strSQL you would see that your query would be something like this
update paket set ketersediaan_paket ='kosong' WHERE id_paket = '1,2'
Which is not the query you want. What you want is more something like this
update paket set ketersediaan_paket ='kosong' WHERE id_paket = '1' OR WHERE id_paket = '2'
So you need to restructure your for loop or change your query.
Related
$frame_type = '';
$ret = mysqli_query($con, "select * from products where status='1' AND frame_type = '$frame_type' ");
while ($row = mysqli_fetch_array($ret)) {
$emparray[] = $row;
}
Get All Rows If The $frame_type Is Empty I am trying this way but i get zero rows , How to fix that Where $frame_type has value then send to query else not
There are a some of things that is wrong with your question (code). But if you only want answer. Just copy this
$frame_type = '';
$query = "select * from products where status='1' ";
// strlen has value
if(strlen($frame_type)) {
$query .= "AND frame_type = '$frame_type'";
}
$ret = mysqli_query($con, $query);
while ($row = mysqli_fetch_array($ret)) {
$emparray[] = $row;
}
PS: It's never a safe idea to pass everything to the query. Use prepared statement if you can.
I am trying to get the key value from the multidimensinal array which I have created using .The Array snapshot is given after the Code.
Below is my PHP code-
$selectTicket = "select ticketID from ticketusermapping where userID=$userID and distanceofticket <=$miles;";
$rsTicket = mysqli_query($link,$selectTicket);
$numOfTicket = mysqli_num_rows($rsTicket);
if($numOfTicket > 0){
$allRowData = array();
while($row = mysqli_fetch_assoc($rsTicket)){
$allRowData[] = $row;
}
$key = 'array(1)[ticketID]';
$QueryStr = "SELECT * FROM ticket WHERE ticketID IN (".implode(',', array_keys($key)).")";
Array Snapshot-
I need the tickedID value from this array . Like the first one is 49 .
Please help.
change your code like
$selectTicket = "select ticketID from ticketusermapping where userID=$userID and distanceofticket <=$miles;";
$rsTicket = mysqli_query($link, $selectTicket);
$numOfTicket = mysqli_num_rows($rsTicket);
if ($numOfTicket > 0) {
$allRowData = array();
while ($row = mysqli_fetch_assoc($rsTicket)) {
$allRowData[] = $row['ticketID'];
}
$QueryStr = "SELECT * FROM ticket WHERE ticketID IN (" . implode(',', $allRowData) . ")";
$ids = array_column( $allRowData, 'ticketID'); //this will take all ids as new array
$QueryStr = "SELECT * FROM ticket WHERE ticketID IN (".implode(',', $ids).")";
You should do a single query using JOIN for this:
$query = "
SELECT t.*
FROM ticket t
JOIN ticketusermapping tum
ON t.ticketID = tum.ticketID
AND tum.userID = '$userID'
AND tum.distanceofticket <= '$miles'
";
$stmt = mysqli_query($link, $query);
$numOfTickets = mysqli_num_rows($stmt);
while($row = mysqli_fetch_assoc($stmt)){
var_dump($row); // here will be the ticket data
}
Following is my code,
$result1 = "SELECT emp_id FROM employee where manager_id=".$userID;
$array = mysql_query($result1);
$cnt = 0;
while ($row = mysql_fetch_array($array)) {
"emp_id: " . $row[0];
$myArrayOfemp_id[$cnt] = $row[0];
$cnt++;
}
var_dump($myArrayOfemp_id);
$sql = "SELECT emp_id FROM emp_leaves WHERE emp_id='$myArrayOfemp_id' ORDER BY apply_date DESC";
$result = mysql_query($sql);
$total_results = mysql_num_rows($result);
When I'am trying to use $myArrayOfemp_id variable in $sql query, It shows that error:
Array to string conversion in..
How can I fix it?
You are trying to convert an array into a string in the following line:
$sql = "SELECT emp_id FROM emp_leaves
WHERE emp_id='$myArrayOfemp_id' ORDER BY apply_date DESC";
$myArrayOfemp_id is an array. That previous line of code should be changed to:
$sql = "SELECT emp_id FROM emp_leaves
WHERE emp_id={$myArrayOfemp_id[0]} ORDER BY apply_date DESC";
I placed 0 inside {$myArrayOfemp_id[0]} because I'm not sure what value want to use that is inside the array.
Edited:
After discussing what the user wanted in the question, it seems the user wanted to use all the values inside the array in the sql statement, so here is a solution for that specific case:
$sql = "SELECT emp_id FROM emp_leaves
WHERE ";
foreach ($myArrayOfemp_id as $value)
{
$sql .= " emp_id={$value) || ";
}
$sql .= "1=2";
$result = mysql_query($sql);
$total_results = mysql_num_rows($result);
$sql = "SELECT emp_id FROM emp_leaves WHERE emp_id in
(SELECT GROUP_CONCAT(emp_id) FROM employee where manager_id=".$userID.")
ORDER BY apply_date DESC";
$result = mysql_query($sql);
$total_results = mysql_num_rows($result);
just change your query like above might solve your problem.
you can remove following code now. :)
$result1 = "SELECT emp_id FROM employee where manager_id=".$userID;
$array = mysql_query($result1);
$cnt = 0;
while ($row = mysql_fetch_array($array)) {
"emp_id: " . $row[0];
$myArrayOfemp_id[$cnt] = $row[0];
$cnt++;
}
var_dump($myArrayOfemp_id);
How to loop php using ref data from mysql ?
work flow :
Loop If column 'xxx' == ''
{
$sql = "SELECT * FROM table WHERE xxx == '' order by id desc";
$result = mysql_query($sql);
$datas=mysql_fetch_array($result);{
$id = stripslashes(str_replace('\r\n', '<br>',($datas['id'])));
}
$sql = "UPDATE table SET xxx = 'test' WHERE id = '$id' ";
$dbQuery = mysql_query($sql);'
}
ypur query is confusing. why would you store ids with html in them? regardless, this should work
$sql = "SELECT * FROM table WHERE xxx != '' "; //ORDER BY will not work since ids are not int
$result = mysql_query($sql);
while ($row = mysql_fetch_array($result){
$id = stripslashes(str_replace('\r\n', '<br>',($row['id'])));
$sql = "UPDATE table SET xxx = 'test' WHERE id = '$id' ";
$dbQuery = mysql_query($sql);'
}
Quick Question;
$sql = mysql_query("SELECT * FROM cronjobs WHERE status = 0 ");
while($cronjob = mysql_fetch_array($sql)){
if($cronjob['suid'] != $cronjob['cuid']){
//echo 'not equal<br>';
$set = 0;
$sid = $cronjob['sid'];
$suid = $cronjob['suid'];
$cuid = $cronjob['cuid'];
$set = notify($sid, $suid, $cuid);
if($set==1){
//echo 'notified<br>';
$sql = "UPDATE cronjobs SET status = '1' WHERE id='".$cronjob['id']."'";
if(mysql_query($sql)){
echo '1<br>';
$set = 0;
}
}
}
}
}
notify() will return 1 (numeric)
The problem is only one iteration of the while loop is executed even though there are more records. I don't know what's wrong here. Help me out pls.
Please change inner $sql variable name to something else..outer $sql and inner one are making conflict
$sql = mysql_query("SELECT * FROM cronjobs WHERE status = 0 ");
while($cronjob = mysql_fetch_array($sql)){
if($cronjob['suid'] != $cronjob['cuid']){
//echo 'not equal<br>';
$set = 0;
$sid = $cronjob['sid'];
$suid = $cronjob['suid'];
$cuid = $cronjob['cuid'];
$set = notify($sid, $suid, $cuid);
if($set==1){
//echo 'notified<br>';
$sql_2 = "UPDATE cronjobs SET status = '1' WHERE id='".$cronjob['id']."'";
if(mysql_query($sql_2)){
echo '1<br>';
$set = 0;
}
}
}
}
}
Just an observation:
Because you have:
$sql = mysql_query("SELECT * FROM cronjobs WHERE status = 0 ");
while($cronjob = mysql_fetch_array($sql)){
Its going to execute the Query EVERY SINGLE time it goes through the loop. If you have a 100 rows, its going to execute 100 times. If you do this instead, then it executes only once.
$sql = mysql_query("SELECT * FROM cronjobs WHERE status = 0 ");
$res = mysql_fetch_array($sql);
while($cronjob = $res){
It wouldnt have conflicted either!
It is clearly an issue that occurs when you have the same variable for query ($query)
and Result Object ($result).try different name for mysql_query() inside the WHILE Loop.