PHP outputs the wrongly formatted html table - php

Question

I'm having trouble echoing data into a HTML table.
It comes out like that:
But it should be:
Here's the code. What am I doing wrong?
<?php
$query = $_POST['query'];
$min_length = 1;
if(strlen($query) >= $min_length){ // if query length is more or equal minimum length then
$query = htmlspecialchars($query);
$query = mysql_real_escape_string($query);
$raw_results = mysql_query("SELECT * FROM norse5_proov
WHERE (`model` LIKE '%".$query."%') OR (`year` LIKE '%".$query."%')") or die(mysql_error());
if(mysql_num_rows($raw_results) > 0){ // if one or more rows are returned do following
while($results = mysql_fetch_array($raw_results)){
echo "<table>";
echo "<tr>";
echo "<td>Model name</td>";
echo "<td>Year</td>";
echo "</tr>";
echo "<td>".$results['mudeli_nimetus']."</td>";
echo "<td>".$results['soetusaasta']."</td>";
echo "<br>";
echo "</table>";
}
}
else{
echo "No results";
}
}
?>

Answer 1

The problem is that you keep outputting a new table for each iteration.
Your code should look like this:
<?php
$query = $_POST['query'];
$min_length = 1;
if(strlen($query) >= $min_length){ // if query length is more or equal minimum length then
$query = htmlspecialchars($query);
$query = mysql_real_escape_string($query);
$raw_results = mysql_query("SELECT * FROM norse5_proov
WHERE (`model` LIKE '%".$query."%') OR (`year` LIKE '%".$query."%')") or die(mysql_error());
if(mysql_num_rows($raw_results) > 0){ // if one or more rows are returned do following
echo "<table>"; // Start the table
// Output the table headers
echo "<tr>";
echo "<td>Model name</td>";
echo "<td>Year</td>";
echo "</tr>";
while($results = mysql_fetch_array($raw_results)) {
echo "<tr>";
echo "<td>".$results['mudeli_nimetus']."</td>";
echo "<td>".$results['soetusaasta']."</td>";
echo "<br>";
echo "</tr>";
}
echo "</table>"; // End the table
}
else{
echo "No results";
}
}
?>

Answer 2

just put echo "<table>"; and first tr creation statment out side of while loop and also put closing of table after finishing of while loop and see i am sure it will work.
Try
<?php
echo "<table><tr><td>Model name</td><td>Year</td></tr>";
while($results = mysql_fetch_array($raw_results))
{
echo "<tr><td>".$results['mudeli_nimetus']."</td><td>".$results['soetusaasta']."</td></tr>";
}
echo "</table>";
?>

Answer 3

use this code, you have to first start the table, use while loop to iterate the result, and then close the table.
echo "<table>";
echo "<tr>";
echo "<td>Model name</td>";
echo "<td>Year</td>";
echo "</tr>";
while($results = mysql_fetch_array($raw_results)){
echo "<tr>";
echo "<td>".$results['mudeli_nimetus']."</td>";
echo "<td>".$results['soetusaasta']."</td>";
echo "</tr>";
}
echo "</table>";

Answer 4

Remove table code from while loop and put outside.
echo "<table>";
echo "<tr>";
echo "<td>Model name</td>";
echo "<td>Year</td>";
echo "</tr>";
while($results = mysql_fetch_array($raw_results)){
echo "<tr>";
echo "<td>".$results['mudeli_nimetus']."</td>";
echo "<td>".$results['soetusaasta']."</td>";
echo "</tr>";
}
echo "</table>";

Answer 5

replace your if block, use the following code , hope it may help you
if(mysql_num_rows($raw_results) > 0)
{
echo "<table>";
echo "<tr>";
echo "<td>Model name</td>";
echo "<td>Year</td>";
echo "</tr>";
while($results = mysql_fetch_array($raw_results)){
echo "<tr>";
echo "<td>".$results['mudeli_nimetus']."</td>";
echo "<td>".$results['soetusaasta']."</td>";
echo "</tr>";
}echo "</table>";
}