deleting a row with a particular id in while loop - php

<?php
$sql = "SELECT * from movieinfo";
$sql_data = mysqli_query($db,$sql);
echo "<table>";
echo "<tr>";
echo "<td><b>Movie Name</b></td>";
echo"<td><center><b>Delete</b></center></td>";
echo"</tr>";
while($row = mysqli_fetch_array($sql_data,MYSQLI_ASSOC)) {
echo "<tr>";
echo "<td style='color:white'>";
echo $row['title'];
echo "<td><center><a href='adminpage.php?mid={$row['movieid']}'><button
class='contact100-form-btn' name='deletem'>Delete Movie</button></a>
</center></td>";
$_SESSION['delete'] = $row['movieid'];
echo "<td>";
echo"</tr>";
}
echo "</table>";
?>
if (isset($_POST['deletem'])) {
$delete=$_SESSION['delete'];
$query6 = "DELETE FROM movieinfo WHERE movieid=$delete";
mysqli_query($db, $query6);
}
i need to delete the particular row with the id selected so i am storing in session the id and deleting it but when i press on the deleting button it deletes the last row only its because session is storing all the id's because of loop how should i fix it?

<?php
$sql = "SELECT * from movieinfo";
$sql_data = mysqli_query($db,$sql);
echo "<table>";
echo "<tr>";
echo "<td><b>Movie Name</b></td>";
echo"<td><center><b>Delete</b></center></td>";
echo"</tr>";
while($row = mysqli_fetch_array($sql_data,MYSQLI_ASSOC)) {
echo "<tr>";
echo "<td style='color:white'>";
echo $row['title'];
**echo "</td>";
$mid = isset($_GET['mid']) ? $_GET['mid'] : '';
$del = "DELETE FROM movieinfo WHERE movieid=$mid";
mysqli_query($db, $del);
{
echo "<td><center><a href='adminpage.php?mid={$row['movieid']}'><button
class='contact100-form-btn' name='deletem'>Delete Movie</button></a>
</center></td>";
}
echo"</tr>";
}
echo "</table>";
?>

Related

php results 2 table on page instead of one with all data

I've made a script for a search mysql table, and instead of one table with more rows, he return me on results page one table for each person.
This is my results code by id from the search script. and returns table for each person
$id = $_GET['id'];
$sql = "select * from wp_certificari WHERE id = '{$id}'";
$rst = mysql_query($sql);
while($a_row = mysql_fetch_assoc($rst)) {
echo "<center>\n";
echo "<b>Detalii Certificat:</b>";
echo "<table border='1'>";
echo"<thead>";
echo "<th>Denumire certificare</th>";
echo "<th>Serie si numar certificare</th>";
echo "<th>Data certificarii</th>";
echo "<th>Valabilitate certificare</th>";
echo "<th>Sector Financiar</th></tr>";
echo"</thead>";
echo "<td class='lalign'>{$a_row['nume']}</td>" ;
echo "<td class='lalign'>{$a_row['serie_numar']}</td>" ;
echo "<td class='lalign'>{$a_row['data']}</td>" ;
echo "<td class='lalign'>{$a_row['valabilitate']}</td>" ;
echo "<td class='lalign'>{$a_row['sector_financiar']}</td></tr>" ;
echo"</table>";
echo "</center>\n";}
You need to write your table and table head html outside your while loop Add mysql_num_rows to check empty result and add mysql_real_escape_string to Escapes special characters in a string for use in an SQL statement
$id = $_GET['id'];
$id=mysql_real_escape_string($id);
$sql = "select * from wp_certificari WHERE id = '{$id}'";
$rst = mysql_query($sql);
$row=mysql_num_rows($rst);
if($row>0){
//outside while loop
echo "<center>\n";
echo "<b>Detalii Certificat:</b>";
echo "<table border='1'>";
echo"<thead>";
echo "<th>Denumire certificare</th>";
echo "<th>Serie si numar certificare</th>";
echo "<th>Data certificarii</th>";
echo "<th>Valabilitate certificare</th>";
echo "<th>Sector Financiar</th>";
echo"</thead>";
while($a_row = mysql_fetch_assoc($rst)) {
echo "<tr><td class='lalign'>{$a_row['nume']}</td>" ;
echo "<td class='lalign'>{$a_row['serie_numar']}</td>" ;
echo "<td class='lalign'>{$a_row['data']}</td>" ;
echo "<td class='lalign'>{$a_row['valabilitate']}</td>" ;
echo "<td class='lalign'>{$a_row['sector_financiar']}</td></tr>" ;
}
//outside while loop
echo"</table>";
echo "</center>\n";
}
Note:- Don't use mysql because it is deprecated instead use mysqli or
PDO
To prevent sql injection check this link How can I prevent SQL-injection in PHP?
You have to get table part outside from while loop.
$id = $_GET['id'];
$sql = "select * from wp_certificari WHERE id = '{$id}'";
$rst = mysql_query($sql);
echo "<center>\n";
echo "<b>Detalii Certificat:</b>";
echo "<table border='1'>";
echo "<thead>";
echo "<tr>";
echo "<th>Denumire certificare</th>";
echo "<th>Serie si numar certificare</th>";
echo "<th>Data certificarii</th>";
echo "<th>Valabilitate certificare</th>";
echo "<th>Sector Financiar</th></tr>";
echo "</thead><tbody>";
while($a_row = mysql_fetch_assoc($rst)) {
echo "<tr>";
echo "<td class='lalign'>{$a_row['nume']}</td>" ;
echo "<td class='lalign'>{$a_row['serie_numar']}</td>" ;
echo "<td class='lalign'>{$a_row['data']}</td>" ;
echo "<td class='lalign'>{$a_row['valabilitate']}</td>" ;
echo "<td class='lalign'>{$a_row['sector_financiar']}</td></tr>";
}
echo"</tbody></table>";
echo "</center>\n";

Finding library details based on user search input - using LIMIT and OFFSET

Basically I have 4 fields in a form. I want to the user search for books in a library by either title, or by author or both. I also want the user to set the length of the list of items and from the starting point, these are not restrictions though the user does not have to specify.
Here is the code:
require_once __DIR__.'/config.php';
session_start();
$dbh = new PDO('mysql:host=' . DB_HOST . ';dbname=' . DB_USERNAME, DB_USERNAME, DB_PASSWORD);
$title = $_GET["title"];
$authors = $_GET["authors"];
$st = $_GET["start"];
$ln = $_GET["length"];
$stmt = $dbh->prepare("SELECT title, authors, description, price FROM books WHERE title = :title LIMIT :length OFFSET :start");
$stmt->execute(array(':title' => $title,':start' => $st,':length' => $ln));
while ($row = $stmt->fetch(PDO::FETCH_ASSOC))
{
$title = $row['title'];
$authors = $row['authors'];
$description = $row['description'];
$price = $row['price'];
}
echo "<table>";
echo "<tr>";
echo "<td>Title</td>";
echo "<td>$title</td>";
echo "</tr>";
echo "<tr>";
echo "<td>Authors</td>";
echo "<td>$authors</td>";
echo "</tr>";
echo "<tr>";
echo "<td>Description</td>";
echo "<td>$description</td>";
echo "</tr>";
echo "<tr>";
echo "<td>Price</td>";
echo "<td>$price</td>";
echo "</tr>";
echo "</table>";
So far it literally just returns me what I have typed in the input - so nothing much at all! Does anyone know how I can do this?
Adapt your code this way:
echo "<table>";
while ($row = $stmt->fetch(PDO::FETCH_ASSOC))
{
$title = $row['title'];
$authors = $row['authors'];
$description = $row['description'];
$price = $row['price'];
echo "<tr>";
echo "<td>Title</td>";
echo "<td>$title</td>";
echo "</tr>";
echo "<tr>";
echo "<td>Authors</td>";
echo "<td>$authors</td>";
echo "</tr>";
echo "<tr>";
echo "<td>Description</td>";
echo "<td>$description</td>";
echo "</tr>";
echo "<tr>";
echo "<td>Price</td>";
echo "<td>$price</td>";
echo "</tr>";
}
echo "</table>";
to print all the rows returned by the query. Your code was printing just the last row.

Displaying Multiple Rows with two tables

I'm not that good in programming PHP, and still learning from it.
Here's my problem, I need to display the result of rows from two different tables, had researched things and tried but all failed.
Hope someone could give some advice with my line of code.
$query = "SELECT tblparent.*, tblchild.* FROM tblparent, tblchild* FROM tblparent";
$num_results = $result->num_rows;
$result = $mysqli->query( $query );
if( $num_results ){
echo "<center><table border='1' id='members'>";
echo "<tr>";
echo "<th>Parent ID</th>";
echo "<th>Parent Firstname</th>";
echo "<th>Parent Lastname</th>";
echo "<th>Parent Middlename</th>";
echo "<th>Child ID</th>";
echo "<th>Child Firstname</th>";
echo "<th>Child Middlename</th>";
echo "<th>Child Lastname</th>";
echo "<th>Action</th>";
echo "</tr>";
while( $row = $result->fetch_assoc() ){
extract($row);
echo "<tr>";
echo "<td>{$Parent_ID}</td>";
echo "<td>{$PFname}</td>";
echo "<td>{$PLname}</td>";
echo "<td>{$PMname}</td>";
echo "<td>{$Child_ID}</td>";
echo "<td>{$CFname}</td>";
echo "<td>{$CMname}</td>";
echo "<td>{$CLname}</td>";
echo "<td>";
echo "<a href='#' onclick='delete_mem( {$Parent_ID} );'>Delete</a>";
echo "</td>";
echo "</tr>";
}
echo "</table>";
}
else{
echo "No records found.";
}
$result->free();
$mysqli->close();
I see two mistakes:
you should satisfy the right order of statements, $result should be
before $num_results assigment.
it seems that there is a mistake in your SQL query.
You need to adjust the following code, I am assuming that tblparent has an id and tblchild has a relation to tblparent id as parent_id:
$query = "SELECT tblparent.*, tblchild.* FROM tblparent, tblchild WHERE tblparent.id = tblchild.parent_id";
$result = $mysqli->query( $query );
$num_results = $result->num_rows;

how to select two columns from two tables in mysql

I am trying to execute this query but i got error " Undefined index:
lname".I want to count row from one column(fname) from table a and
select column(lname) from other table b. so please help me.
$result = mysql_query("SELECT COUNT(fname),lname FROM a,b");
while ($row = mysql_fetch_array($result))
{
echo "<tr><td>";
echo $row['lname'];
echo "</td>";
echo "<td>";
echo $row['COUNT(fname)'];
echo "</td></tr>";
}
If you still get an error you can try to fetch both separately:
$result = mysql_query("SELECT COUNT(fname) FROM a");
while ($row = mysql_fetch_array($result))
{
echo "<tr><td>";
echo $row['COUNT(fname)'];
echo "</td></tr>";
}
$result1 = mysql_query("SELECT lname FROM b");
while ($row = mysql_fetch_array($result1))
{
echo "<tr><td>";
echo $row['lname'];
echo "</td></tr>";
}
You need to use an alias. Use this:
$result = mysql_query("SELECT COUNT(fname) AS countfname,lname FROM a,b");
while ($row = mysql_fetch_array($result))
{
echo "<tr><td>";
echo $row['lname'];
echo "</td>";
echo "<td>";
echo $row['countfname'];
echo "</td></tr>";
}
Try this code:
$result = mysql_query("SELECT COUNT(a.fname) as fname,b.lname as lname FROM a,b");
while ($row = mysql_fetch_array($result))
{
echo "<tr><td>";
echo $row['lname'];
echo "</td>";
echo "<td>";
echo $row['COUNT(fname)'];
echo "</td></tr>";
}

Add an extra table every time the row is updated

I basically have an input system where people enter data and the data is printed in a specific order in a HTML table.
I have some code which works fine below except that every time the row is updated, the table is edited instead adding a new table with the data. Also when i refresh the data disappears?
My code is below:
$query = "SELECT * FROM rumours";
$query = mysql_query($query) or die('MySQL Query Error: ' . mysql_error( $connect ));
while ($row = mysql_fetch_assoc($query)) {
$id = $row['id'];
$band = $row['band'];
$title = $row['Title'];
$description = $row['description'];
}
$sql="INSERT INTO rumours (band, Title, description)
VALUES
('$_POST[firstname]','$_POST[lastname]','$_POST[age]')";
if (!mysql_query($sql,$connect))
{
die('Error: ' . mysql_error());
}
if (mysql_query($sql, $connect)) {
echo "<table border='1'>";
echo "<tr>";
echo "<td> $title </td>";
echo "</tr>";
echo "<tr>";
echo "<td class = 'td1'> $description </td>";
echo "</tr>";
echo "</table>";
}
echo "1 record added";
mysql_close($connect);
You are only generating the table from the inserted db rows, not all of the db rows in the db table. To do that, you have to echo the table code for each of the found rows as well:
$query = "SELECT * FROM rumours";
$query = mysql_query($query) or die('MySQL Query Error: ' . mysql_error( $connect ));
while ($row = mysql_fetch_assoc($query)) {
$id = $row['id'];
$band = $row['band'];
$title = $row['Title'];
$description = $row['description'];
echo "<table border='1'>";
echo "<tr>";
echo "<td> $title </td>";
echo "</tr>";
echo "<tr>";
echo "<td class = 'td1'> $description </td>";
echo "</tr>";
echo "</table>";
}
$sql="INSERT INTO rumours (band, Title, description)
VALUES
('$_POST[firstname]','$_POST[lastname]','$_POST[age]')";
/* ... Code truncated to save space */

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