PHP with MYSQL data flow - php

I'm using php with mysql.
I have a large database of mysql containing 365 tables, each day contain a single table and that contains thousand of records for each client in single table.
My problem is that when I'm going to generate the report for multiple clients it doesn't show any thing.
On other hand when I check mysql log it shows queries running on back end, when queries a completed at back end still nothing comes to browser, browser still show process running.
My current code looks like this:
//$ClientList Contains 100 clientIds
//$TableList contains 30 table list
$TotalCount = count($ClientList);
$CountTables = count($TableList);
for($i=0; $i<$TotalCount; $i++) {
for($j=0; $j<$CountTables; $j++) {
$sql = "INSERT INTO TABLEA SELECT * FROM ".$TableList[$j]." WHERE clientid = '".$ClientList[$i]."'";
$rs = mysql_query($sql);
}
}
for($i=0; $i<$TotalCount; $i++) {
$sql = "SELECT * FROM TABLEA";
//STORE IN ARRAY
$rs = mysql_query($sql);
while($ds=mysql_fetch_assoc($rs)) {
$aRRAY[$i] = $ds;
}
}
for($i=0; $i<count($aRRAY); $i++) {
}
But nothing is coming to browser I have also added the settimeout to 0; increased session time, but no results. Any solution to this issuee?

Do not store one million records in a php array:
//$ClientList Contains 100 clientIds
//$TableList contains 30 table list
$TotalCount = count($ClientList);
$CountTables = count($TableList);
for($i=0; $i<$TotalCount; $i++) {
for($j=0; $j<$CountTables; $j++) {
$sql = "INSERT INTO TABLEA SELECT * FROM ".$TableList[$j]." WHERE clientid = '".$ClientList[$i]."'";
$rs = mysql_query($sql);
}
}
//OUTPUT
$sql = "SELECT * FROM TABLEA";
//
$rs = mysql_query($sql);
while($ds=mysql_fetch_assoc($rs)) {
my_output($ds);
}
Also if you are trusting the database to put all your records into TABLEA, why put them into separate tables at all?
//$ClientList Contains 100 clientIds
//$TableList contains 30 table list
$TotalCount = count($ClientList);
$CountTables = count($TableList);
for($i=0; $i<$TotalCount; $i++) {
for($j=0; $j<$CountTables; $j++) {
//OUTPUT
$sql = "SELECT * FROM ".$TableList[$j]." WHERE clientid = '".$ClientList[$i]."'";
//
$rs = mysql_query($sql);
while($ds=mysql_fetch_assoc($rs)) {
my_output($ds);
}
}
}

Related

My for loop only allows one post to be displayed, over and over again

/* To sort the id and limit the post by 40 */
$sql = "SELECT * FROM requests";
$result = $conn->query($sql);
$sqlall= "SELECT * FROM requests ";
$resultall = $conn->query($sqlall);
$i = 0;
if ($result->num_rows > 0) {
// Output data of each row
$idarray= array();
while($row = $result->fetch_assoc()) {
echo "<br>";
// Create an array to store the
// id of the blogs
array_push($idarray,$row['id']);
}
}
else {
echo "0 results";
}
?>
<?php
for($x = 1; $x < 40; $x++) {
// This is the loop to display all the stored blog posts
if(isset($x)) {
$query = mysqli_query(
$conn,"SELECT * FROM `requests`");
$res = mysqli_fetch_array($query);
$email1 = $res['email1'];
$msg1= $res['msg1'];
$subject1 = $res['subject1'];
$name1 = $res['name1'];
$id = $res['id'];
the output is 40 cards reading data from the first row in my database. can anyone help?
I'm using xampp.
This code is to show the loop, but if anyone wants the full code is here
You are storing all the IDs in the array $idarray, but then you don't really use them properly. You loop over them, but you just run SELECT * FROM requests` 40 more times, and always extract the same first row. You never use the ID to change the query.
But it really makes no sense to run lots of separate queries anyway. If you just want the first 40 rows then use MySQL's LIMIT keyword. It usually works best when combined with ORDER BY as well. Something like this:
$sql = "SELECT * FROM requests ORDER BY id LIMIT 40";
$result = $conn->query($sql);
while ($res = $result->fetch_assoc()) {
$email1 = $res['email1'];
$msg1 = $res['msg1'];
$subject1 = $res['subject1'];
$name1 = $res['name1'];
$id = $res['id'];
//example output, just for demo:
echo $email1." ".$msg1." ".$subject1." ".$name1." ".$id;
}
Documentation: https://dev.mysql.com/doc/refman/8.0/en/limit-optimization.html

Update one value at multiple ID's in database table

$upload_files=implode(' ',$_GET['upload_files']);
$upload_user=",".$_GET['upload_user'];
echo $upload_files;
$sql = "UPDATE {$db_pr}files SET userID = CONCAT(userID,'".$upload_user."') WHERE id IN ('".$upload_files."')";
IN takes a comma-delimited string I believe.
try:
$upload_files=implode("','",$_GET['upload_files']);
Well, I got the solution. I used for loop to achieve the result.
$upload_files=$_GET['upload_files'];
$upload_user=",".$_GET['upload_user'];
for ($i = 0, $count = count($upload_files); $i <= $count; $i++) {
$sql = "UPDATE {$db_pr}files SET userID = CONCAT(userID,'".$upload_user."') WHERE id = '".$upload_files[$i]."'";
$result = mysqli_query($mysqli,$sql) or die("Error occurred - tried to update file.");
}
echo "<div class='loginMessage loginSuccess'>Assigned Successfully!!!</div>";

Trying to randomize where a name is inserted into a table using PHP and SQL

What I'm trying to accomplish is randomize elements of an array which contain column names. Then use those randomized columns names to insert a name into a table.
Here is the code I have and its causing a Internal Server Error.
$sql3 = "SELECT * FROM players";
$result3 = $con->query($sql3);
while ($row3 = $result3->fetch_assoc()) {
$num_bracket1 = $row3["num_bracket"];
$name = $row3["name"];
$y = 1;
while ($y <= $num_bracket1) {
shuffle($bracket_array);
shuffle($player_array);
$sql4 = "UPDATE brackets SET ".$player_array[0]."='".$name."' WHERE bracket_num='".$bracket_array[0]"'";
$result4 = $con->query($sql4);
}
}
It's an obvious infinite loop, you forgot to increment $y inside the while and it never ends.

Not able to extract all values of a column in mysql

I am having problem extracting values from a mysql table:
I need to get all values of picname column from a table where uid condition is satisfied.
Now i have two rows where this condition is satisfied but i am getting output only for 1st case. I am not able to get the second row's value. 1st rows value repeats again for second time.
$i = 0;
for($i;$i<2;$i++)
{
$s = "SELECT picname FROM uploaded_data WHERE uid='$uid'";
$que = mysql_query($s,$db);
while($num = mysql_fetch_array($que))
{
echo $name ['picname'];
}
}
Thank You
it should not give you any result you do not have
$name
should be:
$i = 0;
for($i;$i<2;$i++)
{
$s = "SELECT picname FROM uploaded_data WHERE uid='$uid'";
$que = mysql_query($s,$db);
while($num = mysql_fetch_array($que))
{
echo $num['picname'];
}
mysql_free_result($que);
}

Checking to see if a MySQL row is populated

I have a page that writes to a MySQL table. The table has a set amount of rows (24).
I have an $id variable that's set by a rand() function. I basically want to pull the row at that $id, so if $id was 3, I want to pull the third row. Then, I want to check if there is a price set at that row (indicating that the row is being used). If there is no price, I want to keep $id at the value it has been set at and proceed with the query. If there is a price, I want to re-randomize the $id variable, and check again if that row is used up. When it finds an empty row, proceed with the query.
My solution semi-works, but it seems to have a <10% chance of overwriting a used row, for some reason. I want it to never overwrite a used row.
Here's my code:
mysql_select_db("delives0_booklet", $con);
$query = "SELECT * FROM booklet WHERE id = '$id'";
$res = mysql_query($query,$con);
$newId = $id;
while($row = mysql_fetch_array($res))
{
if($row['price'] != 0)
{
do{
$newId = rand(1, 24);
}while($newId == $id);
}
}
$id = $newId;
mysql_query("UPDATE booklet SET price = '$price', advertiser = '$advertiser', image = '$image', monthsRemaining = '$monthsRemaining', availability = 1 WHERE id = '$id'");
Edit
I had the idea to do this. I loop through the table and I put the 'id' of each unfilled spot into an array. Then I pick randomly from that array. However, there seems to be a bug that I can't find, since the array keeps showing as having nothing in it, even after the loop is run, and $i is the correct figure.
mysql_select_db("delives0_booklet", $con);
$query = "SELECT * FROM booklet";
$res = mysql_query($query,$con);
$i = 0;
$isEmpty = array();
while($row = mysql_fetch_array($res))
{
if($row['price'] == 0)
{
$isEmpty[i] = $row['id'];
$i = $i + 1;
}
}
echo $i . " unfilled spots.";
$n = 0;
while($n<$i)
{
echo $isEmpty[$n];
$n = $n + 1;
}
if($i > 0)
{
$id = $isEmpty[rand(0, $i)];
}
if($i == 0)
{
echo 'All spots have been filled.';
}
I think it is a top level logic problem. Because you populate with random ids, you can get duplicate ids, and so when you update "WHERE id = '$id'" you may be picking up rows already populated.
I don't know your goal, but perhaps using an auto-increment id, and dropping rows that you want to get rid of, is the way to go. A rolling set of rows (24 at a time) but with ever increasing ids, would prevent mistaking one for the other.
If I understand the problem correct, this should work:
SELECT *
FROM booklet
WHERE price = 0 OR price IS NULL
ORDER BY RAND()

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