I am having problem extracting values from a mysql table:
I need to get all values of picname column from a table where uid condition is satisfied.
Now i have two rows where this condition is satisfied but i am getting output only for 1st case. I am not able to get the second row's value. 1st rows value repeats again for second time.
$i = 0;
for($i;$i<2;$i++)
{
$s = "SELECT picname FROM uploaded_data WHERE uid='$uid'";
$que = mysql_query($s,$db);
while($num = mysql_fetch_array($que))
{
echo $name ['picname'];
}
}
Thank You
it should not give you any result you do not have
$name
should be:
$i = 0;
for($i;$i<2;$i++)
{
$s = "SELECT picname FROM uploaded_data WHERE uid='$uid'";
$que = mysql_query($s,$db);
while($num = mysql_fetch_array($que))
{
echo $num['picname'];
}
mysql_free_result($que);
}
Related
$upload_files=implode(' ',$_GET['upload_files']);
$upload_user=",".$_GET['upload_user'];
echo $upload_files;
$sql = "UPDATE {$db_pr}files SET userID = CONCAT(userID,'".$upload_user."') WHERE id IN ('".$upload_files."')";
IN takes a comma-delimited string I believe.
try:
$upload_files=implode("','",$_GET['upload_files']);
Well, I got the solution. I used for loop to achieve the result.
$upload_files=$_GET['upload_files'];
$upload_user=",".$_GET['upload_user'];
for ($i = 0, $count = count($upload_files); $i <= $count; $i++) {
$sql = "UPDATE {$db_pr}files SET userID = CONCAT(userID,'".$upload_user."') WHERE id = '".$upload_files[$i]."'";
$result = mysqli_query($mysqli,$sql) or die("Error occurred - tried to update file.");
}
echo "<div class='loginMessage loginSuccess'>Assigned Successfully!!!</div>";
I am trying to get the column names and field values from a table for ONE record. If a column name was 'sellers' and the field value was 'Bob', the desired output would be: seller Bob
The output will actually be used for a script like this:
$fields['sellers']->setValue($sellers);
Where 'sellers' is the column name and $sellers is the field value.
There are dozens of columns in the table.
The script below only outputs the column names - not the field values.
Any help is appreciated.
$sql = "SELECT * FROM tbl_pdfform WHERE trans_id = '$trans_id' ";
$sql_result = mysqli_query($db, $sql);
for($i = 0; $i < mysqli_num_fields($sql_result); $i++) {
$field_info = mysqli_fetch_field($sql_result);
$col = "{$field_info->name}";
echo $col . ' ';
while ($row = mysqli_fetch_array($sql_result)) {
$data = $row[$col];
echo $data."<br>";
}
}
Not sure if I exactly understand what you're trying to do but would using mysqli_fetch_assoc() and a foreach loop give your desired result?
$sql = "SELECT * FROM tbl_pdfform WHERE trans_id = '$trans_id' ";
$sql_result = mysqli_query($db, $sql);
$row = mysqli_fetch_assoc($sql_result);
foreach($row as $column => $value) {
echo $column . " " . $value;
}
You should just call mysqli_fetch_array() once, not in a loop for each column. Because every time you call it, it moves to the next row of results, it doesn't re-fetch the old row. Since you only have one row of results, the repeated calls just return false.
$row = mysqli_fetch_array($sql_result);
for($i = 0; $i < mysqli_num_fields($sql_result); $i++) {
$field_info = mysqli_fetch_field($sql_result);
$col = "{$field_info->name}";
echo $col . ' ' . $row[$col];
}
But there isn't really any need to use mysqli_fetch_field() to get the field names. Since $row is an associative array, the field names are just the keys of the array. However, it would be better to use mysqli_fetch_assoc(), because mysqli_fetch_array() returns an array that contains both named and numbered elements; mysqli_fetch_assoc() just returns the named elements. So the answer by WheatBeak is how most would do what you want.
I think that there's a problem with the interpolation.
$sql = "SELECT * FROM tbl_pdfform WHERE trans_id = '$trans_id' ";
Using variables between apostrophes sends the string "$trans_id" in the SQL query instead of the value which $trans_id contains. Try this:
$sql = "SELECT * FROM tbl_pdfform WHERE trans_id = '" . $trans_id . "' ";
What I'm trying to accomplish is randomize elements of an array which contain column names. Then use those randomized columns names to insert a name into a table.
Here is the code I have and its causing a Internal Server Error.
$sql3 = "SELECT * FROM players";
$result3 = $con->query($sql3);
while ($row3 = $result3->fetch_assoc()) {
$num_bracket1 = $row3["num_bracket"];
$name = $row3["name"];
$y = 1;
while ($y <= $num_bracket1) {
shuffle($bracket_array);
shuffle($player_array);
$sql4 = "UPDATE brackets SET ".$player_array[0]."='".$name."' WHERE bracket_num='".$bracket_array[0]"'";
$result4 = $con->query($sql4);
}
}
It's an obvious infinite loop, you forgot to increment $y inside the while and it never ends.
say I have a variable
$id = mt_rand();
how can I query the mysql database to see if the variable exists in the row id, if it does exist then change the variable $id, once the variable is unique to all other stored ids, then insert it into the database?
Thanks you guys.
$con = mysql_connect("<host>","<login>","<pass>");
if ($con) {
mysql_select_db('<schemata>', $con);
$found = false;
while (!$found) {
$idIamSearching = mt_rand();
$query = mysql_query("SELECT count(*) FROM <table> WHERE <idColumnName>='".$idIamSearching."'");
$result = mysql_fetch_row($query);
if ($result[0] > 0) {
mysql_query("INSERT INTO <table> (<column>) VALUES ('".$idIamSearching."')");
$found = true;
}
}
mysql_close($con);
}
Your description is hard to understand, so, this is something that could give you pointers...
'SELECT COUNT(*) as count from table where row_id="'.$variable.'" LIMIT 1'
make sure to escape the variable if it's user input or if it's going to have more than alphanumeric characters
then fetch the row and check if count is 1 or greater than 0
if one, then it exists and try again (in a loop)
although, auto increment on the id field would allow you to avoid this step
$bExists = 0;
while(!$bExists){
// Randomly generate id variable
$result = mysql_query("SELECT * FROM table WHERE id=$id");
if($result){
if(mysql_num_rows($result) > 0){
$bExists = 1;
} else {
// Insert into database
$bExists = 1;
}
}
1 Randomly generate id variable
2 Query database for it
2.1 Result? exit
2.2 No result? Insert
I have a page that writes to a MySQL table. The table has a set amount of rows (24).
I have an $id variable that's set by a rand() function. I basically want to pull the row at that $id, so if $id was 3, I want to pull the third row. Then, I want to check if there is a price set at that row (indicating that the row is being used). If there is no price, I want to keep $id at the value it has been set at and proceed with the query. If there is a price, I want to re-randomize the $id variable, and check again if that row is used up. When it finds an empty row, proceed with the query.
My solution semi-works, but it seems to have a <10% chance of overwriting a used row, for some reason. I want it to never overwrite a used row.
Here's my code:
mysql_select_db("delives0_booklet", $con);
$query = "SELECT * FROM booklet WHERE id = '$id'";
$res = mysql_query($query,$con);
$newId = $id;
while($row = mysql_fetch_array($res))
{
if($row['price'] != 0)
{
do{
$newId = rand(1, 24);
}while($newId == $id);
}
}
$id = $newId;
mysql_query("UPDATE booklet SET price = '$price', advertiser = '$advertiser', image = '$image', monthsRemaining = '$monthsRemaining', availability = 1 WHERE id = '$id'");
Edit
I had the idea to do this. I loop through the table and I put the 'id' of each unfilled spot into an array. Then I pick randomly from that array. However, there seems to be a bug that I can't find, since the array keeps showing as having nothing in it, even after the loop is run, and $i is the correct figure.
mysql_select_db("delives0_booklet", $con);
$query = "SELECT * FROM booklet";
$res = mysql_query($query,$con);
$i = 0;
$isEmpty = array();
while($row = mysql_fetch_array($res))
{
if($row['price'] == 0)
{
$isEmpty[i] = $row['id'];
$i = $i + 1;
}
}
echo $i . " unfilled spots.";
$n = 0;
while($n<$i)
{
echo $isEmpty[$n];
$n = $n + 1;
}
if($i > 0)
{
$id = $isEmpty[rand(0, $i)];
}
if($i == 0)
{
echo 'All spots have been filled.';
}
I think it is a top level logic problem. Because you populate with random ids, you can get duplicate ids, and so when you update "WHERE id = '$id'" you may be picking up rows already populated.
I don't know your goal, but perhaps using an auto-increment id, and dropping rows that you want to get rid of, is the way to go. A rolling set of rows (24 at a time) but with ever increasing ids, would prevent mistaking one for the other.
If I understand the problem correct, this should work:
SELECT *
FROM booklet
WHERE price = 0 OR price IS NULL
ORDER BY RAND()