Display images with pagination from mysql - php

Question

I had a php page to display images from a mysql database. It displays all the images uploaded in 1 page one after the other. How can i display 5 or 6 images per page with pagination?
Here is my php page.
<?Php
include("init.php");
include("template/header.php");
?>
<div class="view_albums"><h3> View Albums </h3>;
<?php
$album_id = $_GET['album_id'];
$images = get_images($album_id);
if (empty($images)) {
echo 'There are no images ';
} else {
foreach ($images as $image) {
?> <div class="box"> <?php
echo ' <img class="box1" src="uploads/thumbs/', $image['album'], '/', $image['id'], '.', $image['ext'], '" title="Uploaded on ', date('l F j, Y \a\t g:i A',$image['timestamp']),'"> [delete]';
?> <?php
}
}
?>
</div>
</div>
<?php
include("template/footer.php");
?>

Answer 1

try to use the below pagination function
function genPagination($total,$currentPage,$baseLink,$nextPrev=true,$limit=10)
{
if(!$total OR !$currentPage OR !$baseLink)
{
return false;
}
//Total Number of pages
$totalPages = ceil($total/$limit);
//Text to use after number of pages
$txtPagesAfter = ($totalPages==1)? " page": " pages";
//Start off the list.
$txtPageList = '<br />'.$totalPages.$txtPagesAfter.' : <br />';
//Show only 3 pages before current page(so that we don't have too many pages)
$min = ($page - 3 < $totalPages && $currentPage-3 > 0) ? $currentPage-3 : 1;
//Show only 3 pages after current page(so that we don't have too many pages)
$max = ($page + 3 > $totalPages) ? $totalPages : $currentPage+3;
//Variable for the actual page links
$pageLinks = "";
//Loop to generate the page links
for($i=$min;$i<=$max;$i++)
{
if($currentPage==$i)
{
//Current Page
$pageLinks .= '<b class="selected">'.$i.'</b>';
}
else
{
$pageLinks .= ''.$i.'';
}
}
if($nextPrev)
{
//Next and previous links
$next = ($currentPage + 1 > $totalPages) ? false : 'Next';
$prev = ($currentPage - 1 <= 0 ) ? false : 'Previous';
}
return $txtPageList.$prev.$pageLinks.$next;
}
think it will help you