Integrating pagination into mysql query - php

Question

I have the following mysql query and I have added pagination from here:
http://www.tonymarston.net/php-mysql/pagination.html
$DBQuery3 = mysqli_query($dblink, "SELECT * FROM images WHERE project_id = '$FormProjectID'");
if (mysqli_num_rows($DBQuery3) < 1) {
$ProjectContent = '
<p>This project is empty. Upload some files to get started.</p>
';
} else {
//if no page number is set, start at page 1
if (isset($_GET['pageno'])) {
$pageno = $_GET['pageno'];
} else {
$pageno = 1;
}
//This code will count how many rows will satisfy the current query.
$DBQuery3b = mysqli_query($dblink, "SELECT count(*) FROM images WHERE project_id = '$FormProjectID'");
$query_data = mysqli_fetch_row($dblink, $DBQuery3b);
$numrows = $query_data[0];
//This code uses the values in $rows_per_page and $numrows in order to identify the number of the last page.
$rows_per_page = 2;
$lastpage = ceil($numrows/$rows_per_page);
//This code checks that the value of $pageno is an integer between 1 and $lastpage.
$pageno = (int)$pageno;
if ($pageno > $lastpage) {
$pageno = $lastpage;
}
if ($pageno < 1) {
$pageno = 1;
}
//This code will construct the LIMIT clause for the sql SELECT statement.
$limit = 'LIMIT ' .($pageno - 1) * $rows_per_page .',' .$rows_per_page;
$DBQuery3c = "SELECT * FROM images WHERE project_id = $FormProjectID $limit";
$DBQuery3d = mysqli_query($dblink, $DBQuery3c);
//set this variable to empty and so we can latwe loop and keep adding images to it
$ProjectContent ='';
while($row = mysqli_fetch_array($DBQuery3d)) {
$DBImageID = $row['image_id'];
$DBProjectID = $row['project_id'];
$DBImageName = $row['image_name'];
$DBImageDescription = $row['image_description'];
$DBDateCreated = $row['date_created'];
$DBLinkToFile = $row['link_to_file'];
$DBLinkToThumb = $row['link_to_thumbnail'];
$DBGivenName = $row['given_name'];
//if the image was given a name by the user, display it
//otherwise display the generated name
if (strlen($DBGivenName) > 1) {
$FileName = $DBGivenName;
} else {
$FileName = $DBImageName;
}
$ProjectContent .= '
<img src="uploads/'.$DBLinkToThumb.'" width="150px" height="150px" alt="'.$FileName.'" title="'.$FileName.'"/>
';
//Finally we must construct the hyperlinks which will allow the user to select other pages. We will start with the links for any previous pages.
if ($pageno == 1) {
$FirstPrev = " FIRST PREV ";
} else {
$First = " <a href='{$_SERVER['PHP_SELF']}?page=project&id=$FormProjectID&pageno=1'>FIRST</a> ";
$prevpage = $pageno-1;
$Prev = " <a href='{$_SERVER['PHP_SELF']}?page=project&id=$FormProjectID&pageno=$prevpage'>PREV</a> ";
}
//Next we inform the user of his current position in the sequence of available pages.
$PageNumb = " ( Page $pageno of $lastpage ) ";
//This code will provide the links for any following pages.
if ($pageno == $lastpage) {
$NextLast = " NEXT LAST ";
} else {
$nextpage = $pageno+1;
$Next = " <a href='{$_SERVER['PHP_SELF']}?page=project&id=$FormProjectID&pageno=$nextpage'>NEXT</a> ";
$Last = " <a href='{$_SERVER['PHP_SELF']}?page=project&id=$FormProjectID&pageno=$lastpage'>LAST</a> ";
}
}
}
Then in my html I have:
<div id="projectview">
<?php echo $ProjectContent; ?>
<?php echo $FirstPrev; ?>
<?php echo $First; ?>
<?php echo $Prev; ?>
<?php echo $PageNumb; ?>
<?php echo $NextLast; ?>
<?php echo $Next; ?>
<?php echo $Last; ?>
<div class="clear-div"></div>
</div>
This is outputing for example in this case 2 images, but the pagination links look like this:
FIRST PREV ( Page 1 of 0 ) NEXT LAST
Clicking on the links is not cycling through any other images, it still shows the same 2 images.
I can't figure out what I have done wrong here. I don't understand why it says "1 of 0" when clearly there should be more results.