I'm trying to write to a json file, and want to be able to overwrite an object if certain fields match. Right now, I have code that gets whats currently in the JSON file, but that just adds the latest object to the end of it. What I need to do is that if the message fields match, then I need to replace the entry with the newer one. Know what I mean?
Thanks for the help!
PHP:
$file = file_get_contents('test.json');
$data = json_decode($file);
unset($file);//prevent memory leaks for large json.
//insert data here
$data[] = array("message" => $name, "latitude" => $lat, "longitude" => $lon, "it" => $it);
//save the file
file_put_contents('test.json',json_encode($data));
echo json_encode($data);
unset($data);//release memory
You can use array_filter to find the element with the matching name and update it in place. This will not remove any existing duplicates for you, though.
$datum = array_filter($data, function (&$elem) use ($name, $lat, $lon, $it) {
if ($elem['message'] === $name) {
$elem = array('message' => $name /* snip */)
return true;
}
});
if (!$datum) { /* append array */ }
assuming I understand correctly, you only need to check if two elements in your $data array are equal, based on the message. Easiest way to do that is use the key of the data array, and reset it afterwards. so something similar to :
$file = file_get_contents('test.json');
$data = json_decode($file);
unset($file);//prevent memory leaks for large json.
//insert data here
$data[$message] = array("message" => $name, "latitude" => $lat, "longitude" => $lon, "it" => $it);
//save the file
$data = array_values($data);
file_put_contents('test.json',json_encode($data));
echo json_encode($data);
unset($data);//release memory
this will increase memory consumption, so you can use md5() for the keys instead to keep it low.
If you use json_decode($string, true), you will get either an associative or numeric array. This array can be manipulated with standard php array methods.
$array = json_decode($string, true);
if(md5($data['message']) != md5($newMessage)) {
$array['message'] = $newMessage;
}
I used an md5, because i don't know how the message is structured.
Related
I send the following data to my php file via ajax:
JSON.stringify({test1: '1', test2: '2'})
I would like to write this data to my JSON FILE content.json containing an empty array
[]
I only want to add the content though if it is not there, yet. This is my PHP code:
$jsonStringObject = file_get_contents("php://input");
$phpObject = json_decode($jsonStringObject);
$newJsonStringObject = json_encode($phpObject);
header('Content-Type: application/json');
$jsonString = file_get_contents('content.json');
$data = (array) json_decode($jsonString, true);
if (in_array($phpObject, $data) === false){
$data[] = $phpObject;
}
$newJsonString = json_encode($data);
file_put_contents('content.json', $newJsonString);
It almost works. Something is wrong with the way the data is added to the array because when I call the function for the first time, it updates content.json to
[null,{"test1":"1","test2":"2"}]
On calling the function again, it adds the object again despite the if-statement:
[null,{"test1":"1","test2":"2"},{"test1":"1","test2":"2"},{"test1":"1","test2":"2"}]
Can anyone help me to spot the mistake?
You're comparing apples and oranges (or rather objects to arrays).
Make sure you decode all json as arrays:
$jsonStringObject = file_get_contents("php://input");
// Added true as second argument to get it bas as an array
$phpObject = json_decode($jsonStringObject, true);
$jsonString = file_get_contents('content.json');
// Removed the (array) since the second argument literally means "return as array"
$data = json_decode($jsonString, true);
if (in_array($phpObject, $data) === false){
$data[] = $phpObject;
}
$newJsonString = json_encode($data);
file_put_contents('content.json', $newJsonString);
Demo: https://3v4l.org/rnCn5
So I'm trying to figure out why I get a NULL value in my .json file after I try to write the array to it. It only happens with the 'array_push' line after creating a new file. If there is a .json file already there with a value in it, it'll write to it correctly. The only thing I could guess was the file is missing the '{' and '}' in it upon creation.
I've got a small work around so far, but not sure that this is the right way to do it. Can someone tell me if this is good or bad?
Just to clarify, the .json document only holds the vault of NULL, there are no array elements or anything in the file besides the word NULL.
//CHECK IF FILE EXISTS, ELSE CREATE IT
$log_filename = "./site_files/logs/error-404-log.json";
if(!file_exists($log_filename)) {
touch($log_filename);
//LINE BELOW IS MY WORK AROUND, I'M NOT SURE IF THIS IS THE RIGHT WAY
file_put_contents($log_filename, json_encode(json_decode("{}")));
echo "$log_filename was created. <br />";
}
$log_array = array();
$new_data = array(
'current_date_stamp' => $current_date_stamp,
'current_page_trail' => $current_page_trail
);
$json_data = file_get_contents($log_filename);
if($log_array != "") { $log_array = json_decode($json_data, true); }
//WHEN CREATING A NEW FILE, ARRAY_PUSH GIVES ERROR
array_push($log_array, $new_data);
$json_data = json_encode($log_array, JSON_PRETTY_PRINT);
file_put_contents($log_filename, $json_data);
$log_filename = "error-404-log.json"; // establish the path/to/filename.json
if (file_exists($log_filename)) { // if path/to/filename.json exists
$json = file_get_contents($log_filename); // access PRETTY json string
echo "pre-existing data: <div><pre>$json</pre></div><br>"; // display json string
$array = json_decode($json, true); // decode to prepare for new data
}
// data always maintains the same structure: an array of 2-element arrays
$array[] = [
'current_date_stamp' => date('Y-m-d H:i:s'),
'current_page_trail' => "foo"
];
// create/update the file
$new_json = json_encode($array, JSON_PRETTY_PRINT); // re-encode updated array data
echo "new data: <div><pre>$new_json</pre></div>"; // display new json string
file_put_contents($log_filename, $new_json); // create or overwrite file
Your code is failing because you are comparing $log_array with an empty string, this condition will always pass because this array will never be an empty string. In the if statement you decode the contents of the file, when the file has no content this will be an empty string and it will return NULL, after this you write this NULL value to your file. If you check if $json_data is an empty string your code should work, I would also recommend doing it like this:
$log_array = array();
$new_data = array(
'current_date_stamp' => $current_date_stamp,
'current_page_trail' => $current_page_trail
);
$json_data = file_get_contents($log_filename);
if($json_data != "") {
$log_array = json_decode($json_data, true);
//WHEN CREATING A NEW FILE, ARRAY_PUSH GIVES ERROR
array_push($log_array, $new_data);
$json_data = json_encode($log_array, JSON_PRETTY_PRINT);
file_put_contents($log_filename, $json_data);
}
This is better since if the string is empty all other actions are irrelevant.
I have a sample JSON Array labeled sample.txt that is sent from a sweepstakes form that captures a user's name and e-mail. I'm using WooBox so the JSON Array sends information over by each entry, so there are two entries here: http://pastebin.ca/3409546
On a previous question, I was told to break the ][ so that JSON_ENCODE can figure the separate entries. I would like to capture just the name and e-mail and import the array to my e-mail database (campaign monitor).
My question is: How do I add JSON variable labels to an array? If you see my code, I have tried to use the label $email. Is this the correct form or should it be email[0] with a for loop?
$url = 'http://www.mywebsite.com/sweeps/test.txt';
$content = file_get_contents($url);
$json = json_decode($content,true);
$tmp = explode('][', $json_string);
if (!count($tmp)) {
$json = json_decode($json_string);
var_dump($json);
} else {
foreach ($tmp as $json_part) {
$json = json_decode('['.rtrim(ltrim($json_string, '['), ']').']');
var_dump($json);
}
}
require_once 'csrest_general.php';
require_once 'csrest_subscribers.php';
$auth = array(
'api_key' => 'xxxxxxxxxxxxxxx');
$wrap = new CS_REST_Subscribers('xxxxxxxxxx', $auth);
$result = $wrap->add($json(
'EmailAddress' => $email,
'Name' => $custom_3_first,
'Resubscribe' => false
));
https://github.com/campaignmonitor/createsend-php/blob/master/samples/subscriber/add.php
This should have been fairly easy: if you have a JSON string and you call json_decode($string, true) on it, you get its equivalent in a PHP variable, plain and simple. From there, you can access it like you would any PHP array, object, etc.
The problem is, you don't have a proper JSON string. You have a string that looks like JSON, but isn't valid JSON. Run it through a linter and you'll see what I mean.
PHP doesn't know what to do with your supposed JSON, so you have to resort to manual parsing, which is not a path I would recommend. Still, you were almost there.
require_once 'csrest_general.php';
require_once 'csrest_subscribers.php';
$auth = array('api_key' => 'xxxxxxxxxxxxxxx');
$wrap = new CS_REST_Subscribers('xxxxxxxxxx', $auth);
$url = 'http://www.mywebsite.com/sweeps/test.txt';
$content = file_get_contents($url);
$tmp = explode('][', $content);
foreach ($tmp as $json_part) {
$user = json_decode('['.rtrim(ltrim($json_string, '['), ']').']', true);
$result = $wrap->add(array(
'EmailAddress' => $user->email,
'Name' => $user->fullname,
'Resubscribe' => true
));
}
I want to retrieve array value.
This is my array value:
overlay.txt:
{"title":"sss","description":"sss","code":"sss"}
{"title":"trtr","description":"trtr","code":"tyrytr"}
{"title":"ret54","description":"56tr","code":"ty76"}
{"title":"rgfdg","description":"dfgdfg","code":"dfgdfg"}
{"title":"asfafdsf","description":"sdfsdf","code":"sdfsdfsdf"}
This is my code: but this is not working.why?
How to retrieve value from overlay.txt file.
I did not get all title value.
I do not known how to get title value from overlay.txt
The $title is showing empty.
Where I want to change in my code to get $title value.
$info = array();
$folder_name = $this->input->post('folder_name');
$info['title'] = $this->input->post('title');
$info['description'] = $this->input->post('description');
$info['code'] = $this->input->post('code');
$json = json_encode($info);
$file = "./videos/overlay.txt";
$fd = fopen($file, "a"); // a for append, append text to file
fwrite($fd, $json);
fclose($fd);
$filecon = file_get_contents('./videos/overlay.txt', true);
$this->load->view('includes/overlays',$filecon);
//overlays page;
foreach($filecon as $files)
{
$title=$files['title'];
echo $title;
}
You're encoding your array to JSON, so at some point you need to decode it again into a PHP array. Since you actually have several JSON objects in the file, you need to decode each one individually. Assuming it's always one JSON object per line, this'll do:
$jsonObjects = file('overlay.txt', FILE_IGNORE_NEW_LINES);
foreach ($jsonObjects as $json) {
$array = json_decode($json, true);
echo $array['title'];
...
}
This will very quickly break if there are line breaks within the serialized JSON, e.g.:
{"title":"ret54","description":"foo
bar","code":"ty76"}
That way of storing the data is not very reliable.
make overlay.txt fully json format:
[
{"title":"sss","description":"sss","code":"sss"},
{"title":"trtr","description":"trtr","code":"tyrytr"},
...
]
and try this:
$raw = file_get_contents('./videos/overlay.txt', true);
$this->load->view('includes/overlays', array("filecon" => json_decode($raw)));
overlay page:
<?php
foreach($filecon as $files) {
echo $files['title'];
}
?>
If you want to use $filecon in view file,
set an array which has the key "filecon" in $this->load->view()'s second argument.
http://codeigniter.com/user_guide/general/views.html
CREATE TABLE Posts
{
id INT PRIMARY KEY AUTO_INCREMENT,
title VARCHAR(200),
url VARCHAR(200)
}
json.php code
<?php
$sql=mysql_query("select * from Posts limit 20");
echo '{"posts": [';
while($row=mysql_fetch_array($sql))
{
$title=$row['title'];
$url=$row['url'];
echo '
{
"title":"'.$title.'",
"url":"'.$url.'"
},';
}
echo ']}';
?>
I have to generate results.json file.
To generate JSON in PHP, you need only one function, json_encode().
When working with database, you need to get all the rows into array first. Here is a sample code for mysqli
$sql="select * from Posts limit 20";
$result = $db->query($sql);
$posts = $result->fetch_all(MYSQLI_ASSOC);
then you can either use this array directly or make it part of another array:
echo json_encode($posts);
// or
$response = json_encode([
'posts' => $posts,
]);
if you need to save it in a file then just use file_put_contents()
file_put_contents('myfile.json', json_encode($posts));
Use this:
$json_data = json_encode($posts);
file_put_contents('myfile.json', $json_data);
You can create the myfile.json before you run the script.But its not compulsory if you have full sudo privileges(read/write permissions(For of you on Mac).
Here is a working Example:
<?php
// data stored in an array called posts
$posts = Array (
"0" => Array (
"id" => "01",
"title" => "Hello",
),
"1" => Array (
"id" => "02",
"title" => "Yoyo",
),
"2" => Array (
"id" => "03",
"title" => "I like Apples",
)
);
// encode array to json
$json = json_encode($posts);
$bytes = file_put_contents("myfile.json", $json); //generate json file
echo "Here is the myfile data $bytes.";
?>
Insert your fetched values into an array instead of echoing.
Use file_put_contents() and insert json_encode($rows) into that file, if $rows is your data.
If you're pulling dynamic records it's better to have 1 php file that creates a json representation and not create a file each time.
my_json.php
$array = array(
'title' => $title,
'url' => $url
);
echo json_encode($array);
Then in your script set the path to the file my_json.php
Here i have mentioned the simple syntex for create json file and print the array value inside the json file in pretty manner.
$array = array('name' => $name,'id' => $id,'url' => $url);
$fp = fopen('results.json', 'w');
fwrite($fp, json_encode($array, JSON_PRETTY_PRINT)); // here it will print the array pretty
fclose($fp);
Hope it will works for you....
You can simply use json_encode function of php and save file with file handling functions such as fopen and fwrite.
First, you need to decode it :
$jsonString = file_get_contents('jsonFile.json');
$data = json_decode($jsonString, true);
Then change the data :
$data[0]['activity_name'] = "TENNIS";
// or if you want to change all entries with activity_code "1"
foreach ($data as $key => $entry) {
if ($entry['activity_code'] == '1') {
$data[$key]['activity_name'] = "TENNIS";
}
}
Then re-encode it and save it back in the file:
$newJsonString = json_encode($data);
file_put_contents('jsonFile.json', $newJsonString);
copy
Use PHP's json methods to create the json then write it to a file with fwrite.