I'm in the process to learn PDO. I started changing my database connection from this:
$dbname = "database1";
mysql_connect(
':/Applications/MAMP/tmp/mysql/mysql.sock',
'root',
'root'
) or die( mysql_error());
mysql_select_db($dbname) or die("MySQL Error: " . mysql_error());
to PDO connection:
$username = "root";
$password = "root";
try {
$conn = new PDO('mysql:host=localhost;dbname=database1', $username, $password);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
} catch(PDOException $e) {
echo 'ERROR: ' . $e->getMessage();
}
the connection seems to be working but when I try to login on the website (localhost) it doesn't find my username and password.
Do I need to change all my mysql_query to PDO since I changed the database connection to PDO?
Can I please ask you some reference for a good tutorial to help me during this transition phase?
thanks
Yes you do.
Here is a good PDO tutorial and this one
Related
I have the following code:
<?php
//Step1
$db = mysqli_connect('localhost','root','[mypassword]','users')
or die('Error connecting to MySQL server.');
?>
<html>
<head>
</head>
<body>
<h1>PHP connect to MySQL</h1>
</body>
</html>
I am just trying to connect to my MySQL database. It is administered using phpMyAdmin. I am very unfamiliar with MySQL and I have never used it before. [mypassword] is the password I use to successfully connect to mySQL from the Mac terminal. "users" is a name of a table I have created in phpMyAdmin. I am using cPanel. I keep on getting the error:
Error connecting to mySQL server.
In phpMyAdmin it says Server: localhost:3306. I have tried for a very long time to fix this problem but with no results. What am I doing wrong?
I have also tried the following:
<?php
$servername = "localhost";
$username = "root";
$password = "[myPassword]";
try {
$conn = new PDO("mysql:host=$servername;dbname=users", $username, $password);
// set the PDO error mode to exception
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
echo "Connected successfully";
}
catch(PDOException $e)
{
echo "Connection failed: " . $e->getMessage();
}
?>
After visiting the webpage it says
Connection failed: SQLSTATE[28000] [1045] Access denied for user
'root'#'localhost' (using password: YES)
Be sure that your mySql instance is up. You can download sequelpro and use that to connect to your mySQL. If that doesn't work then its a mysql setting/config that is wrong.
You can try this code
<?php
$servername = "localhost";
$username = "username";
$password = "password";
// Create connection
$conn = mysqli_connect($servername, $username, $password);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
echo "Connected successfully";
?>
How to Connect to mysql using php
Use a try catch to handle errors on the connection proccess, but i strongly advise you to use PDO by alternative from mysqli PDO Book
Use something like this:
<?php
try
{
if ($db = mysqli_connect($hostname_db, $username_db, $password_db))
{
//do something
}
else
{
throw new Exception('Unable to connect');
}
}
catch(Exception $e)
{
echo $e->getMessage();
}
And check if the code print some connection error.
Reference: how to use throw exception in mysql database connect
I am trying to connect to a MySQL database through a php script. It gives me this error from mysql_error(): Access denied for user '#localhost' to database 'userinfo'
userinfo is the database.
my script is this
<?php
$servername = "localhost";
$username = "root";
$password = "'mm'";
$database = "userinfo";
$conn = mysqli_connect($servername, $username, $password);
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
echo "Connected successfully<br>";
mysql_select_db($database) or die(mysql_error());
echo "connected successfully to db:" . $database . "<br>";
?>
you are connecting using
mysqli_
function
and selecting data with
mysql_
avoid using both at the same time. since they're incompatible.
use the mysqli_ alternative instead
mysqli_select_db($conn, $database);
and
mysqli_error($conn)
Please keep in mind this isn't the safest way. But since you have said your learning this it is a start.
<?php
$servername = "localhost";
$username = "root";
$password = "mm";
// Create connection
$conn = new mysqli($servername, $username, $password);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
?>
http://www.w3schools.com/php/php_mysql_connect.asp
To select data from the database
http://www.w3schools.com/php/php_mysql_select.asp
It appeared you where combining the old mysql in php with the new mysqli
I'm trying to learn this stuff. Please be gentle.
Something is wrong here:
$dbhost = "localhost";
$dbname = "something_dbname";
$dbuser = "something_user";
$dbpass = "pwpwpwpw";
$dberror1 = "Could not connect to the database!";
$dbconnected = "you are connected!";
$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ($dberror1);
$select_db = mysql_select_db($dbname . $dbconnected) or die ($dberror1);
where is my mistake? I want $dbconnected to show...
I can just as easily use
echo "hello";
it shows that I connect but I'm trying to get familiar with using multiple variables.
would this be better?
$dbhost = "localhost";
$dbname = "something_dbname";
$dbuser = "something_user";
$dbpass = "pwpwpwpw";
$dberror1 = "Could not connect to the database!";
$dbconnected = "you are connected!";
if ($mysqli = new mysqli($dbhost, $dbuser, $dbpassword, $dbname))
echo $dbconnected;
else die($dberror1);
Right now you are trying to connect to a database called something_dbnameyou are connected. The . concatenates variables into one string.
To fix your immediate problem, try this:
First, define $dbhost - I don't see it in your code.
Then change the last line to this:
$select_db = mysql_select_db($dbname) or die ($dberror1);
Then, just echo $dbconnected;
If you are not connected, the page will have called die, and will never reach the line that echos $dbconnected. If you are connected, the program will proceed to this next line and echo your success message.
Or you can do it more explicitly like this:
if ($select_db = mysql_select_db($dbname))
echo $dbconnected;
else die($dberror1);
To fix the bigger problem, DON'T use mysql_*. Read this for more information.
mysqli or pdo are far better options, and you can accomplish the same task easier, for instance, connecting to a db with mysqli is just:
$mysqli = new mysqli($dbhost, $dbuser, $dbpassword, $dbname);
Or you can do it procedural style, which is closer to your current code. The following snippet is from the php manual, on the page I linked in the comment below.
$link = mysqli_connect($dbhost, $dbuser, $dbpassword, $dbname);
if (!$link) {
die('Connect Error (' . mysqli_connect_errno() . ') '
. mysqli_connect_error());
}
echo 'Success... ' . mysqli_get_host_info($link) . "\n";
mysqli_close($link);
I'd strongly recommend using PDO. The connection string is similar and can be done using:
// I do not see $dbhost defined in your code. Make sure you have it defined first
try {
$conn = new PDO("mysql:host=$dbhost;dbname=$dbname", $dbuser, $dbpass);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
echo $dbconnected; // will print out the connection success message
} catch(PDOException $e) {
echo 'ERROR: ' . $e->getMessage();
}
To answer your question about not using mysql_* functions, you can check out this
I want to connect to mysql database using php and following is my configuration file.
<?php
$host = "localhost";
$db = "payroll"
$username ="root";
$password = "";
mysql_connect ($host,$username,$password);
mysql_select_db($db,$username);
?>
but when I run my program it gives me this error:
SQL error: No database selected SQL errno: 1046
SQL: select language, admin from user where username='admin' and password='abc123'
What's wrong with my code?
You forgot a semicolon here
$db = "payroll";
^--- Here
Don't forget to enable error reporting on your code. This is how you do it.
This(mysql_*) extension is deprecated as of PHP 5.5.0, and will be removed in the future. Instead, the MySQLi or PDO_MySQL extension should be used. Switching to PreparedStatements is even more better to ward off SQL Injection attacks !
Switch to Prepared Statements..
A kickstart example..
<?php
$dsn = 'mysql:dbname=payroll;host=localhost';
$user = 'root';
$password = '';
try
{
$dbh = new PDO($dsn, $user, $password ,array(PDO::MYSQL_ATTR_INIT_COMMAND => 'SET NAMES utf8'));
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
}
catch (PDOException $e)
{
echo 'Connection failed: ' . $e->getMessage();
}
Read more here on PHP Manual
$mysqlhost="localhost"; // MySQL-Host
$mysqluser="user"; // MySQL-User
$mysqlpwd="password"; // Password
$connection=mysql_connect($mysqlhost, $mysqluser, $mysqlpwd) or die
("Couldn´t connect");
$mysqldb="database"; // Your Database
mysql_select_db($mysqldb, $connection) or die("Couldnt select database");
I always use this. Here you get every errormessage you need to find your error.
Try this
<?php
$host = "localhost";
$db = "payroll"
$username ="root";
$password = "";
$con = mysql_connect ($host,$username,$password);
mysql_select_db($db,$con);
?>
If I use the following code, it works:
$con = mysql_connect("localhost","root","");
if (!$con) {
die('Could not connect: ' . mysql_error());
}
But when I do this, it doesn't:
$db_host='localhost';
$db_id='root';
$db_pass='';
$con = mysql_connect($db_host, $db_id, $db_pass);
if (!$con) {
die('Could not connect: ' . mysql_error());
}
Trying to swap (") and (').
mysql_ functions are discouraged for new applicationa you are advised to use mysqli or PDO. The following code uses PDO to connect to database.
//dependant on your setup
$host= "localhost";
$username="XXX";
$password="YYY";
$database="ZZZ";
// connect to the database
try {
$dbh = new PDO("mysql:host=$host;dbname=$database", $username, $password);
//Remainder of code
}
catch(PDOException $e) {
echo "I'm sorry I'm afraid you can't do that.". $e->getMessage() ;// Remove or modify after testing
file_put_contents('PDOErrors.txt',date('[Y-m-d H:i:s]'). $e->getMessage()."\r\n", FILE_APPEND);//Change file name to suit
}
// close the connection
$dbh = null;
try using a script like this
$db_host = 'localhost';
$db_id = 'root';
$db_pass ='';
$con = mysql_connect ($ db_host, $ db_id, $db_pass) or die ('Could not connect:'. mysql_error ());
That code is fine. Review the error log- the problem has to be external to that code.