Retrieve POST checkbox data from form if they exist - php

Hello knowledgeable people. I am having trouble retrieving checkbox data from form. I have a site in which user can add checkboxes themselves, so I am writing them out like this:
<table style="padding:10px;">
<?php
$query_boolean = $DB->prepare("SELECT * FROM moduls WHERE type='boolean'") or die(mysql_error());
$query_boolean->execute();
while (($row = $query_boolean->fetch()) != false)
{
?>
<tr>
<td>
<?php echo $row->name ?>:
</td>
<td>
<?php
$s = "";
$s .= sprintf('<input type="checkbox" class="textbox" name="boolean_%s" value="yes">%s', $row->id, Yes);
$s .= sprintf('<input type="checkbox" class="textbox" name="boolean_%s" value="no">%s', $row->id, No);
echo $s;
?>
</td>
</tr>
<?php
}
?>
</table>
Now I have an advanced search in which I have to chech through every checkbox to see what has been selected (ether none, Yes, No, or both). How can I get the info from every checkbox in variables? Thank you so much!

To get POST data from checkboxes they must have attribute
checked="checked"
EDIT:
If you have 2 checkbox as this..
<input type="checkbox" checked="checked" class="textbox" name="boolean_yes" value="yes">
<input type="checkbox" class="textbox" name="boolean_no" value="no">
When you submit your form the checkbox with attribute checked will be sent as POST and the one without checked attribute will not be sent..
if(isset($_POST['search'])) {
$all_checked = array();
foreach($_POST as $key=>$value){
if(strpos($key, "boolean_") > -1){
$all_checked[$key] = $value;
}
}
var_dump($all_checked);
}
This way you will get inside $all_checked array all marked boxes.. All others checboxes are not marked!

if you want to get checkbox value then use checkbox name as array
<input type="checkbox" name="email1[]" value="">
an get it on another page by
<?php
$var2 = $_POST['email1'];
$v=implode(",",$var2);
echo $v;
?>
try it

Related

How to display checked check boxes together with non-checked ones

I have 5 check boxes from which a user can select one or more choices. The selected choices are then updated in database. The user's choices are then displayed/reviewed on another page. However my issue is that I want to show the updated choices together with the non-selected choices when doing a foreach loop in PHP.
These are the 5 check boxes
<input type="checkbox" name="interest[]" value="fishing">Fishing
<input type="checkbox" name="interest[]" value="camping">Camping
<input type="checkbox" name="interest[]" value="hiking">Hiking
<input type="checkbox" name="interest[]" value="swimming">Swimming
<input type="checkbox" name="interest[]" value="running">Running
<br><br>
<input type="submit" name="submit" value="Submit">
Heres the code that updates
if (isset($_POST["submit"])) {
$interestArr = $_POST['interest'];
$interest = new Interest();
$newArr = implode(',', $interestArr);
$interest->updateInterests($id=19, $newArr);
}
Heres the code that displays
<?php
$interest = new Interest();
$interests = $interest->showInterests($userid=19)->interests;
$newArr = explode(',', $interests);
foreach ($newArr as $data) {
echo '<input type="checkbox" name="interest[]" value="'.$data .'" checked>'.$data;
}
The update choices are stored under the interests column in DB like so
fishing,camping,running
And the foreach loop displays them checked check box with the correct corresponding labels.
How can I display the other check boxes that were not selected just so that the user might want to make changes?
Thanks.
Here's a simple example to illustrate the main idea. This code is intended to run in the single script.
The main ideas are:
Use a global list of interests to drive the form.
Keep a separate global list of checked check boxes which you can compare to determine if the checkbox should be checked.
when the form is submitted, populate the list which keeps track of checked items
render the form and compare the list of available checkboxes with checked checkboxes. If item found in both lists, it means that we want to display the checkbox as checked.
index.php
<?php
// Keep this outside of the if statement so the form has access to it.
$availableInterests = [
'fishing',
'camping',
'hiking',
'swimming',
'running',
];
// Keep this outside of the if statement so the form has access to it.
$selectedInterests = [];
if ($_SERVER['REQUEST_METHOD'] === 'POST') {
// Cast the posted interests to an array in case the user submitted an empty list.
// An empty list would be NULL if we didn't cast it.
$selectedInterests = (array)$_POST['interest'];
// foreach $selectedInterests insert into DB...
// Let this code `fall through` to render the form again.
// $selectedInterests is now populated and can be used in to the form below to keep the selected checkboxes checked.
}
?>
<form method="post">
<!-- Using the `global` $availableInterests array to drive our form. -->
<? foreach ($availableInterests as $interest): ?>
<!-- Do we want to render the checkbox as checked? -->
<?php $checked = (in_array($interest, $selectedInterests)) ? ' checked' : ''; ?>
<input type="checkbox"
name="interest[]"
value="<?php echo $interest; ?>"
<?php echo $checked; ?>>
<?php echo ucfirst($interest); ?>
<?php endforeach; ?>
<br><br>
<input type="submit" name="submit" value="Submit">
</form>
Let's suppose you have an array of choice list like :
$choices = ["Fishing", "Camping" , "Hiking","Swimming" , "Running" ]
after the user select their choices
$interests = ["Fishing" , "Running" ];
In your case , the coresponding line is :
$interest = new Interest();
$interests = $interest->showInterests($userid=19)->interests;
$newArr = explode(',', $interests);
Let's suppose that $newArr is equal to $interests in may example.
foreach ($interests as $interest) {
echo 'you have choose '.$interest.PHP_EOL;
}
As result :
you have choose Fishing
you have choose Running
For not selected :
$notInterests = array_diff($choices,$interests);
foreach ($notInterests as $notInterest) {
echo 'you have not choose '.$notInterest.PHP_EOL;
}
As Result :
you have not choose Camping
you have not choose Hiking
you have not choose Swimming
To handle it in one loop :
foreach ($choices as $choice) {
if(in_array($choice,$interests )){
echo'you have choose '.$choice.PHP_EOL ;
}else{
echo 'you have not choose '.$choice.PHP_EOL;
}
}
Hope this help you.
To help others that might be in a similar situation I would like to post what is now a working solution at least for me based on Mohammed Yassine CHABLI's inspiration. Vantiya who was the first to comment really help me appreciate what was to follow. Thanks guys.
<?php
$interest = new Interest();
$interests = $interest->showInterests($userid=19)->interests;
$choices = $interest->showInterests($userid=19)->choices;
$selected = explode(',', $interests);
$choices = explode(',', $choices);
foreach ($choices as $choice) {
if(in_array($choice,$selected )){
echo '<input type="checkbox" name="interest[]" value="'.$choice .'"
checked>'.$choice;
}else{
echo '<input type="checkbox" name="interest[]" value="'.$choice .'"
unchecked>'.$choice;
}
}

how to insert values from checkbox to MYSQL Database?

<table width="200" border="0">
<tr>
<td><p>
<?php while($row1 = mysql_fetch_array($res)){ ?>
<label>
<input type="checkbox" name="module" value="<?php echo $row1['MID']?>" id="<?php echo $row1['MID']?>">
<?php echo $row1['ModuleName']?></label>
<br>
<?php }?>
</p></td>
</tr>
</table>
I use this code to outout the checkboxes,and the checkboxes appear allright.
I m not sure about how,the data can be saved to the MYSL table.
the table i drew is in the form:
student_module{studentID,ModuleID}
what is the code i should write to enter the data to that table.
One student can enroll to many modules.
Using ajax functionality:
By clicking on checkbox collect the value of studentID and ModuleID and pass to the ajax method and then in your server end page, you can update db record.
Without ajax functionality
Post the form when user clicking on checkbox or put a save button below to submit the form on a PHP page and then you can collect all your values and update db accordingly.
<input type="checkbox" name="chk1[]" value="" ><?php echo $row1['ModuleName']?>
if(isset($_POST['submit']))
{
$checkbox1 = $_POST['chk1'];
$selected_checkbox = "";
foreach ($checkbox1 as $checkbox1)
{
$selected_checkbox .= $checkbox1 . ", ";
}
$selected_checkbox = substr($selected_checkbox, 0, -2);
// now here in your insert query take mid='".$selected_checkbox."';
}

Looping through an array of checkbox

I have a form with rows which are populated from a table. Each row has a "checkbox" which the user can check or not.
When the form is submitted I want to be able to read which checkbox have been selected and insert the result in to a data table.
My code so far
FORM:
<form method="post" name="form1" action="<?php echo $editFormAction; ?>">
<table
<?php do { ?>
<tr>
<td>input type="text" name="InspectRoomNo" value="<?php print $row_InspectItems['AuditItemNo']; ?>"></td>
<td>php echo $row_InspectItems['AuditItem']; ?>td>
<td>input name="check[]" type="checkbox" ></td>
</tr>
<?php } while ($row_InspectItems = mysql_fetch_assoc($InspectItems)); ?>
<input type="submit" value="Insert record">
</table>
The insert: fetchs $Items from table
while($row = mysql_fetch_assoc($Items))
{
$array[] = $row['AuditItem'];
}
foreach($array as $id) {
$AuditItemID = mysql_real_escape_string($id);
if(isset($_POST['check'])){
$Checked = mysql_real_escape_string($_POST['check'][$row]);
}
}
The problem I am having is the returned values for all the checkbox is true, even if a checkbox was not selected.
Can anyone help me sort this issue.
Many thanks.
Do it like this:
if(!empty($_POST['check'])) {
foreach($_POST['check'] as $check) {
echo $check;
}
}
You should put the item id inside the checkbox name:
<td><input name="check[<?= $row_InspectItems['AuditItem']; ?>]" type="checkbox" /></td>
Then, you can simply iterate over it:
foreach ($_POST['check'] as $id => $value) {
// do stuff with your database
}
I'm assuming than whomever runs this script is trusted, because it would be easy to forge the list of ids; make sure the current user has permissions to update those records.
What is happening, is that only selected checkboxes get sent to the server, so you will see that your $_POST['check'] array (this is an array!) is smaller than the number of items you have displayed on the screen.
You should add your ID's so that you know what checkboxes got checked and adapt your php processing code to handle an array instead of a single value.
You are also overwriting your InspectRoomNo every row, so you should use an array there as well.
The form side would look something like:
<td><input type="text" name="InspectRoomNo[<?php echo row_InspectItems['AuditItemNo']; ?>]" value="<?php print row_InspectItems['AuditItemNo']; ?>"></td>
<td><?php echo $row_InspectItems['AuditItem']; ?></td>
<td><input name="check[<?php echo row_InspectItems['AuditItemNo']; ?>]" type="checkbox" ></td>

PHP - How to submit a form containing input fields that point to different MySQL rows

I am setting up a form using this PHP that loops through all records a user may have:
<?php foreach ($items as $row): ?>
<tr>
<td>
<?php echo form_hidden('id', $row->id); ?>
</td>
<td>
<?php echo '<strong>' . $row->name . '</strong>'; ?>
</td>
<td>
<?php echo form_input('number', $number); ?>
</td>
<td>
<?php echo form_input('registry', $registry); ?>
</td>
<td>
<?php echo form_checkbox('OK', $ok, $ok); ?>
</td>
</tr>
<?php endforeach; ?>
This gives me a form with the following look:
The idea here is that each row belongs to a unique ID/row in the database, and I would like to allow the user to edit all on the same page/form, using a single submit button.
What would be the best way of implementing this?
When this data is submitted, there should be a way of looping through each packet of information (from each user) in my controller. Would this be done via ajax/json?
This does not use codeigntier, but you should be familiar with the general technique before attempting to use CI to shortcut this process. Codeigniter will help you with rendering the form elements, performing validation, escaping your input and performing your query - but it will only help you (do anything) if you understand the basic principles involved. Hope this helps
MARKUP
<form action="/process.php">
<div>
<h2>GORDON</h2>
<input type="text" name="user[1][number]" /> <!-- The number corresponds to the row id -->
<input type="text" name="user[1][registry]" />
<input type="checkbox" name="user[1][ok]" value="1" />
</div>
<div>
<h2>ANDY</h2>
<input type="text" name="user[242][number]" />
<input type="text" name="user[242][registry]" />
<input type="checkbox" name="user[242][ok]" value="1" />
</div>
<div>
<h2>STEWART</h2>
<input type="text" name="user[11][number]" />
<input type="text" name="user[11][registry]" />
<input type="checkbox" name="user[11][ok]" value="1" />
</div>
<input type="submit" />
PHP
$users = $_REQUEST['user'];
foreach ($users as $rowId => $info){
// YOU SHOULD MAKE SURE TO CLEAN YOUR INPUT - THIS IS A GUESS AT WHAT YOUR DATA TYPES MIGHT BE
$id = (int) $rowId;
$number = (int) $info['number'];
$registry = mysql_real_escape_string($info['registry']);
$ok = (int) ($info['ok']);
$q = "UPDATE user SET number = $number, registry = '$registry', ok = $ok WHERE id = $id";
mysql_query($q);
// You may want to check that the above query was sucessful and log any errors etc.
}
There's no need to use ajax mate.
For each put a hidden input with the ID of the row in this format:
<input type="hidden" name="id[<?= $row->id ?>]" value="<?= $row->id ?>" ?>
Do the same for each element in the tr, i.e. name them as
name="number[<?= $row->$id ?>]"
name="registry[<?=$row->$id ?>]"
name="ok[<?=$row->$id ?>]"
and once you post the FORM you can iterate each row with:
foreach ($_POST['id'] as $key => $value) {
echo $_POST['name'][$key];
}
You need to set up input-names as array-names, so you will send the whole form and may iterate over the entries.
e.g.
<?php
echo form_input('userdata[' . $row->id . '][number]', $number);
?>
which would possibly create an
<input name="userdata[1][number]" />
(I don't know where those form-functions came from…)
This will result in an array $_POST['userdata'] which may be iterated via:
foreach($_POST['userdata'] as $userId => $userInputFields)
{
$user = new User($userId);
$user->number = $userInputFields['number'];
// …
}

How to receive a batch of checkbox data in PHP?

The key code is:
while ($row= mysql_fetch_array($result, MYSQL_ASSOC))
{ $id=$row[id];
$html=<<<html
<tr><td>
<input style="float:left" type="checkbox" name="mycheckbox[]" value="$id">
<span style="float:left">$row[content]</span>
<span style="color:black;float:right">$row[submitter]</span></td></tr>
html;
echo $html;
}
There are many checkboxes.
How to receive these checkbox values in another PHP file?
You know, you need to name these checkboxes so a PHP file can receive these values on the other side. But how to name these checkboxes? If I name 1,2, 3,...,how can I associate them with $row[id]?
You need to give them names - you can either do it like this:
<input style="float:left" type="checkbox" id="$id" name="$id" value="true">
or like this to get an array:
<input style="float:left" type="checkbox" id="$id" name="myBoxes[$id]" value="true">
You can then check isset($_POST[$id]) or isset($_POST['myBoxes'][$id])
Name your checkboxes so you can easily identify them.
eg
$CheckBoxHTML = "<input type='checkbox' name='check_$row[id]' value='YES'>Check This";
then in your recieving php file you can find all checkboxes by
foreach ($_POST as $key => $value)
{
if (strpos($key,'check_') !== false)
{
list($tmp, $ID) = split('_', $key);
$CheckedValues[] = $ID;
}
}
That will pull out all your checked ids.

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