How to display checked check boxes together with non-checked ones - php

I have 5 check boxes from which a user can select one or more choices. The selected choices are then updated in database. The user's choices are then displayed/reviewed on another page. However my issue is that I want to show the updated choices together with the non-selected choices when doing a foreach loop in PHP.
These are the 5 check boxes
<input type="checkbox" name="interest[]" value="fishing">Fishing
<input type="checkbox" name="interest[]" value="camping">Camping
<input type="checkbox" name="interest[]" value="hiking">Hiking
<input type="checkbox" name="interest[]" value="swimming">Swimming
<input type="checkbox" name="interest[]" value="running">Running
<br><br>
<input type="submit" name="submit" value="Submit">
Heres the code that updates
if (isset($_POST["submit"])) {
$interestArr = $_POST['interest'];
$interest = new Interest();
$newArr = implode(',', $interestArr);
$interest->updateInterests($id=19, $newArr);
}
Heres the code that displays
<?php
$interest = new Interest();
$interests = $interest->showInterests($userid=19)->interests;
$newArr = explode(',', $interests);
foreach ($newArr as $data) {
echo '<input type="checkbox" name="interest[]" value="'.$data .'" checked>'.$data;
}
The update choices are stored under the interests column in DB like so
fishing,camping,running
And the foreach loop displays them checked check box with the correct corresponding labels.
How can I display the other check boxes that were not selected just so that the user might want to make changes?
Thanks.

Here's a simple example to illustrate the main idea. This code is intended to run in the single script.
The main ideas are:
Use a global list of interests to drive the form.
Keep a separate global list of checked check boxes which you can compare to determine if the checkbox should be checked.
when the form is submitted, populate the list which keeps track of checked items
render the form and compare the list of available checkboxes with checked checkboxes. If item found in both lists, it means that we want to display the checkbox as checked.
index.php
<?php
// Keep this outside of the if statement so the form has access to it.
$availableInterests = [
'fishing',
'camping',
'hiking',
'swimming',
'running',
];
// Keep this outside of the if statement so the form has access to it.
$selectedInterests = [];
if ($_SERVER['REQUEST_METHOD'] === 'POST') {
// Cast the posted interests to an array in case the user submitted an empty list.
// An empty list would be NULL if we didn't cast it.
$selectedInterests = (array)$_POST['interest'];
// foreach $selectedInterests insert into DB...
// Let this code `fall through` to render the form again.
// $selectedInterests is now populated and can be used in to the form below to keep the selected checkboxes checked.
}
?>
<form method="post">
<!-- Using the `global` $availableInterests array to drive our form. -->
<? foreach ($availableInterests as $interest): ?>
<!-- Do we want to render the checkbox as checked? -->
<?php $checked = (in_array($interest, $selectedInterests)) ? ' checked' : ''; ?>
<input type="checkbox"
name="interest[]"
value="<?php echo $interest; ?>"
<?php echo $checked; ?>>
<?php echo ucfirst($interest); ?>
<?php endforeach; ?>
<br><br>
<input type="submit" name="submit" value="Submit">
</form>

Let's suppose you have an array of choice list like :
$choices = ["Fishing", "Camping" , "Hiking","Swimming" , "Running" ]
after the user select their choices
$interests = ["Fishing" , "Running" ];
In your case , the coresponding line is :
$interest = new Interest();
$interests = $interest->showInterests($userid=19)->interests;
$newArr = explode(',', $interests);
Let's suppose that $newArr is equal to $interests in may example.
foreach ($interests as $interest) {
echo 'you have choose '.$interest.PHP_EOL;
}
As result :
you have choose Fishing
you have choose Running
For not selected :
$notInterests = array_diff($choices,$interests);
foreach ($notInterests as $notInterest) {
echo 'you have not choose '.$notInterest.PHP_EOL;
}
As Result :
you have not choose Camping
you have not choose Hiking
you have not choose Swimming
To handle it in one loop :
foreach ($choices as $choice) {
if(in_array($choice,$interests )){
echo'you have choose '.$choice.PHP_EOL ;
}else{
echo 'you have not choose '.$choice.PHP_EOL;
}
}
Hope this help you.

To help others that might be in a similar situation I would like to post what is now a working solution at least for me based on Mohammed Yassine CHABLI's inspiration. Vantiya who was the first to comment really help me appreciate what was to follow. Thanks guys.
<?php
$interest = new Interest();
$interests = $interest->showInterests($userid=19)->interests;
$choices = $interest->showInterests($userid=19)->choices;
$selected = explode(',', $interests);
$choices = explode(',', $choices);
foreach ($choices as $choice) {
if(in_array($choice,$selected )){
echo '<input type="checkbox" name="interest[]" value="'.$choice .'"
checked>'.$choice;
}else{
echo '<input type="checkbox" name="interest[]" value="'.$choice .'"
unchecked>'.$choice;
}
}

Related

How can i post the checkbox with php?

This is my form and categories comes from the database with while loop.
I want to insert the checked inputs only in to database.
How can i detect which checkbox is selected ?
<form action="account.php" method="POST">
<ul class="account-info">
<li>Category1 : <input type="checkbox" value="val1" name="cat1"></li>
<li>Category2 : <input type="checkbox" value="val2" name="cat1"></li>
<li>Category3 : <input type="checkbox" value="val3" name="cat1"></li>
<!-- while continues -->
<li>Category100 : <input type="checkbox" value="val100" name="cat1"></li>
</ul>
<input type="submit" value="submit" />
</form>
In account.php only the check boxes will be posted. As you've named them all the same though, only 1 will be posted, the last checkbox. If you want them to have the same name and come through as an array you need to add [] after the name, like this:
<input type="checkbox" value="val100" name="cat1[]">
Then in your account.php where they are submitted you can do this:
foreach($_POST['cat1'] as $val)
{
echo "$val<br>";
}
That will echo out the values of all the checked boxes.
First off, you have your options set up as if they were radio buttons all having the same name turning into 1 value out of the 3 possible. If you want them to be conventional checkboxes you have to give them separate names.
in your PHP you would check if the array_key_exists for the checkbox name in question, this is how I usually translate the checkbox fields in a form to be easier to use:
<?php
$checked = array(
'cat1' => array_key_exists('cat1', $_POST),
'cat2' => array_key_exists('cat2', $_POST),
'cat3' => array_key_exists('cat3', $_POST)
);
print_r($checked);
exit;
?>
change the name="cat1" to name="cat[1][]"
in your account.php page
foreach($_POST['cat'] as $category){
foreach($category as $value){
echo $value;
}
}
You can check it like that:
This code will check which categories are activated
assuming that your database returns categories from 0 to x
$i = 0;
while(true){
if ($_POST["cat".$i."]) {
//category activated
}
else {
//no category found -> loop ends
break;
}
$i++;
}

php array stored in session

still no solution on this question
So this is what I'm trying to do:
Have a product in a shopping cart with options. the options will be selectable through <input type="checkbox/> And the products are stored based on id's in sessions with php.
Right now I have the candies submitting as an array (like below) But I'm not sure how to add it to that specific product within the session.
My Input for the options is like this:
<?php foreach($options as $option): ?>
<input type="checkbox" name="candies[]" value="<?php echo $option['candy_name']; ?>" /><?php echo $option['candy_name']; ?><br/>
<?php endforeach; ?>
My current code for adding the product to the session is like this:
...
case "add":
$_SESSION['cart'][$product_id]++;
header('location: ../../cart.html');
break;
...
I've also placed $candies = $_GET["candies"]; above the above code to get the options.
How can I make it so the options array is stored in the session for each individual product?
In this image below, you can see what I'm talking about... I am wanting to display each selected option under the options column for the specific product.
this might not be the exact code you are looking for but this should serve as your guide to what you want to achieve.
Let's say you want to get the product options values from you database's productOptions.
$resultSet = mysql_query("SELECT * FROM productOptions");
Now we display the checkboxes to your form based on the result of the query.
while($row = mysql_fetch_assoc($resultSet)){
echo "<input type='checkbox' name='options[]' value='{$row['optionsID']}' />";
}
After displaying the check boxes to our form, we get the checked value from those check boxes that where selected.
if(isset($_POST['yourSubmitButtonName'])){
$productSelected = array();
if(!empty($_POST['options'])){
foreach($_POST['options'] as $options){
$optionsSelected[] = $options;
}
}
}
Now, set the array of options the the $_SESSION variable.
$_SESSION['yourProductID'] = $optionsSelected;
Then we display the options for a product this way
foreach($_SESSION['yourProductID'] as $productOptions){
echo $productOptions;
}
It looks like you've got the correct HTML structure but your code is disjointed. The simplest answer is to do something like this
$_SESSION['cart'][$product_id] = array('options' => $_POST['candies']);
Then you would do something like
foreach($_SESSION['cart'][$product_id]['options'] as $opt) {
echo $opt;
}
Code should look like this first html take checkbox
<form action="sample.php" method="post">
<input type="checkbox" name="candies[]" value="Candy1" />
<input type="checkbox" name="candies[]" value="Candy2" />
<input type="checkbox" name="candies[]" value="Candy3" />
<input type="submit" value="Submit" />
<form>
then session
<?php
session_start();
$result = array();
foreach ( $_POST['candies'] as $key=>$row ) :
$result[$key] = $row[$key];
endforeach;
$_SESSION['candies'] = $result;
print_r($_SESSION['candies']);
?>

Store the array elments based on checkbox checked?

I've got this problem that I can't solve. Partly because I can't explain it with the right terms. I'm new to this so sorry for this clumsy question.
Below you can see an overview of my goal. I am displaying my check boxes in a for loop.
Here I am getting the all values in an array, but I want store the array elements based on the check box checked.
<?php
$j=0;
$arr = Array();
foreach($collection as $data) {
$mageid=$data['mageproductid'];
$products = Mage::getModel('catalog/product')->load($mageid);
$productMediaConfig = Mage::getModel('catalog/product_media_config');
$checkeven=0;
$arr[$j]=$products->getId();
//echo $arr[$j];
$j++;
} ?>
My checkbox code:
<form id="check_all" action="" method="POST" name="check" >
<input type="checkbox" class="multid[]" id="<?php echo $products->getId();?>" value="checked" /> </form>
What do I have to do in order to get checked values in my array? Did I do anything wrong?
Use input name attribute
<input type="checkbox" name="multid[<?php echo $products->getId();?>]" value="checked" />
No in you php code, check if multid[yourProductId] is set, and store them if it is set.
<?php
$j=0;
$arr = Array();
foreach($collection as $data) {
$mageid=$data['mageproductid'];
$products = Mage::getModel('catalog/product')->load($mageid);
$productMediaConfig = Mage::getModel('catalog/product_media_config');
$checkeven=0;
$arr[$j]=$products->getId();
if(!empty($_GET['multid['.$arr[$j].']']))
its checked, do something.
//echo $arr[$j];
$j++;
} ?>
After submiting the form you can get an array of checked products with $_POST['multid']
Can you use javascript? Try this one.
HTML:
<input type="hidden" id="hdnCheckedIDs" value="" />
Before submit, on submit button's client click, Javascript:
var CheckedIDs = "";
for each checkbox
if(document.getelementbyid('multid1').checked)
CheckedIDs = CheckedIDs + document.getelementbyid('multid1').id;
document.getelementbyid('checkboxID') = CheckedIDs;
In PHP, you can use this comma seperated string $_POST['hdnCheckedIDs'] to get the IDs of checked chekboxes.

Populating checkboxlists from database

Is it possible to populate a checkboxlist from the database values? If so, please suggest how to do this.
$query2 = "select * from Products where CategoryID = '$CategoryName' ";
mysql_query($query2) or die(mysql_error());
$array = array();
while($row = mysql_fetch_assoc($query2)){
$array[] = $row;}
foreach($array as $val)
{
if($val =='the checkbox value')
<form>
<input type="checkbox" name="vehicle" value="Bike" /> I have a bike<br />
<input type="checkbox" name="vehicle" value="Car" /> I have a car
</form>
These are the few steps you have to do.
1.Fetch the values from database.
2. Covert the values in array as they are stored as string by (,) separated.
3. Then
foreach($values as $val)
{
if($val =='Bike')
{
$bikeflag = '1';
}
if($val =='Car')
{
$carflag = '1';
}
}
<form>
<input type="checkbox" name="vehicle" value="Bike" <?php if(isset($bikeflag ) =='1'){ ?>checked = checked <?php } ?>/> I have a bike<br />
<input type="checkbox" name="vehicle" value="Car" <?php if(isset($carflag) =='1'){ ?>checked = checked <?php } ?>/> I have a car
</form>
Hopefully this will help you.
Get values from database with the appropriate SQL query
Loop through results echoing out a checkbox element
Caveats
Make sure each one has a unique name unless you want them to be an array. Then use array syntax for their name (e.g. name[])
Make sure to give each one a unique value
Yes, its very much possible:
Fetch the records to be populated with the structure:
Id and value
Provide datasource of the checkedbox list as the fetched structured list as mentioned above.
Now define the value field of the checkboxlist as "Id" and text as "value"

Updating Already Checked Checkboxes in PHP

let's say I have a list of checkboxes that the user selects.
<input type="checkbox" name="utility[]" id="utility[]" value="Water" />Water<br />
<input type="checkbox" name="utility[]" id="utility[]" value="Cable" />Cable<br />
<input type="checkbox" name="utility[]" id="utility[]" value="Electricity" />Electricity<br />
etc...
The user selected Water and it is added to the database. Now the user wants to update the list:
<input type="checkbox" name="utility[]" id="utility[]" value="Water" checked="checked"/>Water<br />
<input type="checkbox" name="utility[]" id="utility[]" value="Cable" />Cable<br />
<input type="checkbox" name="utility[]" id="utility[]" value="Electricity" />Electricity<br />
etc...
How can I check that the utility has already been checked in PHP?
What I've done in the past, to save having hundreds of lines of bloat is this...
First compile all the html in a variable, without any "checked" instances.
$boxes = '';
$boxes .= '<input type="checkbox" name="utility[]" id="utility[]" value="Water" />Water<br />';
$boxes .= '<input type="checkbox" name="utility[]" id="utility[]" value="Cable" />Cable<br />';
$boxes .= '<input type="checkbox" name="utility[]" id="utility[]" value="Electricity" />Electricity<br />';
Now I loop over your array of fields to check. I've provided a sample array here too.
$already_checked = array('Water', 'Electricity');
foreach( $already_checked as $ac ) {
$find = 'value="' . $ac . '"';
$replace = $find . ' checked="checked"';
$boxes = str_replace($find, $replace, $boxes);
}
echo $boxes;
You could do something like this:
<input type="checkbox" name="utility[]" value="Water"
<?= in_array('Water', $utilities) ? 'checked="checked"' : '' ?>"
/>
(The $utilities variable above is a stand-in for something like $_REQUEST['utilities'], depending on how your code is structured.)
Like that?
<input type="checkbox" name="utility[]" id="utility[]" value="Water"
<?php
if(isAlreadyChecked("Water"))
echo "checked=\"checked\""
?>
/>Water<br />
<?php
function isAlreadyChecked(value)
{
//Check if it is already checked and return a boolean
}
?>
I tried every variant of the in_array conditional out there and could NEVER get this to work (checking off the checkboxes whose values had been previously selected and thus inserted into the database). I tried complex queries with table joins and no luck with that either. I finally gave up and generated a display:hidden div that opened the array (which for some odd reason I had to IMPLODE rather than explode) and listed its items as comma-separated text. Then I tossed in a little jQuery indexOf() magic to determine if the value of each checkbox was part of said array or not. Took me 10 minutes flat to do this with jQuery, very simple.
Here's some sample code that is live and working fine:
<div class="categories">
<span class="keywords"><?php $categories = array(); $categories = implode(', ', $keywords); echo $categories ?></span>
<em>Please verify category selections with each update.</em><br/>
<?php
include 'db.php';
$sql = mysqli_query($con,"SELECT * FROM categoriesTable ORDER BY Category_Name ASC");
while ($row = mysqli_fetch_assoc($sql))
{
$key = urldecode($row['Category_Name']);
$id = urlencode($row['catID']);
echo "<input type='checkbox' name='Category_Key[]' value='$id' id='cat_$id' $chk> $key<br/>";
}
?>
</div>
CSS sets that div to invisible:
.keywords { display:none; visibility:hidden; }
and the jQuery portion:
$(document).ready(function() {
$('.categories input').each(function(index,data) {
var str=$('.keywords').text();
var catid = $(this).val();
var chk = str.indexOf(catid);
if (chk >= 0) {
$(this).prop('checked', true);
}
});
});
I hope this helps someone else who is stuck wondering why the in_array conditional is failing them. Since this falls in a twilight zone between data and UI regarding data persistence, I think it's a legit route to take. You have one "echo" statement to generate multiple checkboxes (there are around 40 categories in my situation here) and then a simple jQuery .each() to locate what was selected before and render its corresponding boxes as checked.

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