Having Trouble Performing a Simple MySql Query - php

Question

I'm very new to PHP and still learning the basics and I'm stuck on an issue I'm hoping someone could help me with.
I have the following code;
$MfgQuery = "SELECT `Mfg` FROM `categories` WHERE `ID` = 10";
if($MfgQueryRun = mysql_query($MfgQuery)) {
if (mysql_num_rows($MfgQueryRun)==NULL){
echo 'No Mfg Results Returned';
} else {
$Mfg = $MfgQueryRun['Mfg'];
echo $Mfg;
}
} else {
echo 'Query Unsuccessful';
}
But for a reason unknown to me I keep getting 'No Mfg Results Returned' but if I copy and paste the query by itself into the MySQL box in PHPMyAdmin it returns a result properly.
What gives??
BTW, Here's exactly what I can insert into PHP MyAdmin's SQL box;
SELECT `Mfg` FROM `categories` WHERE `ID` = 10
and this returns a result but using the code above, it does not.
If anyone wouldn't mind showing me where I went wrong I'd be most appreciative and I thank you in advance

Answer 1

try this
$MfgQuery = "SELECT `Mfg` FROM `categories` WHERE `ID` = 10";
$MfgQueryRun = mysql_query($MfgQuery) ;
$row = mysql_fetch_array($MfgQueryRun) ;
if (mysql_num_rows($MfgQueryRun)== 0 ){
echo 'No Mfg Results Returned';
} else {
$Mfg = $row['Mfg'];
echo $Mfg;
}

Answer 2

Try
$MfgQuery = "SELECT `Mfg` FROM `categories` WHERE `ID` = 10";
$MfgQueryRun = mysql_query($MfgQuery);
if($MfgQueryRun) {
if (mysql_num_rows($MfgQueryRun) == 0){
echo 'No Mfg Results Returned';
} else {
$Mfg = $MfgQueryRun['Mfg'];
echo $Mfg;
}
} else {
echo 'Query Unsuccessful';
}

Answer 3

if (mysql_num_rows($MfgQueryRun)){
echo 'No Mfg Results Returned';
} else {
$Mfg = $MfgQueryRun['Mfg'];
echo $Mfg;
}
Try this remove the NULL in comparison. because mysql_num_rows returns numeric values.

Answer 4

First, you should not use mysql_* functions, they are deprecated (outdated) as of PHP 5.5.0, and will be removed in the future. Use mysqli instead.
Second, you're not testing properly. PHP has no strong types, so a test '== null' does not always do, what you'll expect. See the PHP manual for comparision operators. To test against null, always use is_null().
Third, you're not fetching the data.
Using MySQLi, the code would look similar to this:
$mysqli = new mysqli("example.com", "user", "password", "database");
if ($mysqli->connect_errno != 0) {
echo "Failed to connect to MySQL: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error;
die(); // or return, if in method or function context
}
$result = $mysqli->query("SELECT `Mfg` FROM `categories` WHERE `ID` = 10");
if ($result === false) {
echo "Query failed: (" . $mysqli->errno . ") " . $mysqli->error;
die(); // or return, if in method or function context
}
printf("Select returned %d rows.\n", $result->num_rows);
$row = $result->fetch_assoc();
echo $row['Msg'];
/* free result set */
$result->close();