Checking if data is in a table row - php

Question

This is my first post so please bear with me with inputting the code into here. Im trying to output some images to a PDF and need to create a if statement that looks for data with in a row.
$connection = mysql_connect("localhost", "testdb", "********")
or die ("Unable to connect!");
// select database
mysql_select_db("testdb") or die ("Unable to select database!");
// Select all the rows in the test table
$query = "SELECT * FROM test2 WHERE testid=89";
$result = mysql_query($query);
if (!$result) {
die('Invalid query: ' . mysql_error());
}
while ($row= mysql_fetch_array($result)) {
$image = $row[1];
$text = $row[2];
}
That's what I have so far and basically I need something along the line of this:
If (data in row 1) {
print $image;
} else {
print $text;
}

Answer 1

It's hard to say exactly what you're looking for since it isn't very clear, but I think what you're wanting to do is check to see if $image has a value, and if so, display it. If not, display $text instead.
If this is the case use empty(). It will tell you if a variable is empty or not.
if (!empty($image))
{
print $image;
}
else
{
print $text;
}
The following things are considered to be empty:
"" (an empty string)
0 (0 as an integer)
0.0 (0 as a float)
"0" (0 as a string)
NULL
FALSE
array() (an empty array)
$var; (a variable declared, but without a value)

Answer 2

looks like you just need to test for data in $image
if(!empty($image))
{
echo $image;
}
else
{
echo $text;
}

Answer 3

if( !empty($row[1]) ) {
...

Answer 4

Use isset to check variable.
Like
if(isset($images) !='')
{
echo $images;
}

Answer 5

Although you are using old mysql_* functions which are depreciated, you are almost there
$connection = mysql_connect("localhost", "testdb", "********") or die ("Unable to connect!");
// select database
mysql_select_db("testdb") or die ("Unable to select database!");
// Select all the rows in the test table
$query = "SELECT * FROM test2 WHERE testid=89";
$result = mysql_query($query);
if (!$result) {
die('Invalid query: ' . mysql_error());
}
while ($row= mysql_fetch_array($result))
// This will only be called if there is a matching result.
{
echo $row[1];
echo $row[2];
}
Edit: Here is a cut and paste of a section of a query that happen to be open in eclipse:
$arrKPIData = Array();
try{
$dbh = new PDO($this->mySQLAccessData->hostname, $this->mySQLAccessData->username, $this->mySQLAccessData->password);
$stmt = $dbh->query($sql);
$obj = $stmt->setFetchMode(PDO::FETCH_INTO, new kpiData);
$dataCount=0;
foreach($stmt as $kpiData)
{
$arrKPIData[$dataCount]['year']=$kpiData->year;
$arrKPIData[$dataCount]['month']=$kpiData->month;
$arrKPIData[$dataCount]['measure']=$kpiData->kpiMeasure;
$arrKPIData[$dataCount]['var1']=$kpiData->var1;
$arrKPIData[$dataCount]['var2']=$kpiData->var2;
$dataCount++;
unset($stmt);
}
unset($dbh);
}
catch(PDOException $e){
echo 'Error : '.$e->getMessage();
exit();
}
unset($arrKPIData);
I am populating a simple array with data before I cleanse it and convert it into a class further in the code.