Search a word in a string using php function - php

Question

When i search for "bank", it should display Bank-List1, Bank-List2 from the following list.
Railway-List, Bank-List1, Bank-List2, Education, Ecommerce, Articles, Railway-List1.
Is there is any php function to display?
I got the output for exact match. But no result for this type of search.
Please help me to find the solution.

Answer 1

you can use stristr
stristr — Case-insensitive strstr()
<?php // Example from PHP.net
$string = 'Hello World!';
if(stristr($string, 'earth') === FALSE) {
echo '"earth" not found in string';
}
// outputs: "earth" not found in string
?>
So for your situation, if your list was in an array named $values
you could do
foreach($values as $value)
{
if(stristr($value, 'bank') !== FALSE)
{
echo $value."<br>";
}
}

Answer 2

You can do it using stristr. This function returns all of haystack starting from and including the first occurrence of needle to the end. Returns the matched sub-string. If needle is not found, returns FALSE.
Here is the complete code:
<?php
$str="Railway-List, Bank-List1, Bank-List2, Education, Ecommerce, Articles, Railway-List1";
$findme="bank";
$tokens= explode(",", $str);
for($i=0;$i<count($tokens);$i++)
{
$trimmed =trim($tokens[$i]);
$pos = stristr($trimmed, $findme);
if ($pos === false) {}
else
{
echo $trimmed.",";
}
}
?>
DEMO

Answer 3

This solution is only valid for this pattern of text is like: word1, word2, word3
<?php
$text = 'Railway-List, Bank-List1, Bank-List2, Education, Ecommerce, Articles, Railway-List1.';
function search_in_text($word, $text){
$parts = explode(", ", $text);
$result = array();
$word = strtolower($word);
foreach($parts as $v){
if(strpos(strtolower($v), $word) !== false){
$result[] = $v;
}
}
if(!empty($result)){
return implode(", ", $result);
}else{
return "not found";
}
}
echo search_in_text("bank", $text);
echo search_in_text("none", $text);
?>
output:
Bank-List1, Bank-List2
not found