Match one or more keywords defined in array [duplicate] - php

Question

Lets say I have an array of bad words:
$badwords = array("one", "two", "three");
And random string:
$string = "some variable text";
How to create this cycle:
if (one or more items from the $badwords array is found in $string)
echo "sorry bad word found";
else
echo "string contains no bad words";
Example:
if $string = "one fine day" or "one fine day two of us did something", user should see sorry bad word found message.
If $string = "fine day", user should see string contains no bad words message.
As I know, you can't preg_match from array. Any advices?

Answer 1

How about this:
$badWords = array('one', 'two', 'three');
$stringToCheck = 'some stringy thing';
// $stringToCheck = 'one stringy thing';
$noBadWordsFound = true;
foreach ($badWords as $badWord) {
if (preg_match("/\b$badWord\b/", $stringToCheck)) {
$noBadWordsFound = false;
break;
}
}
if ($noBadWordsFound) { ... } else { ... }

Answer 2

Why do you want to use preg_match() here?
What about this:
foreach($badwords as $badword)
{
if (strpos($string, $badword) !== false)
echo "sorry bad word found";
else
echo "string contains no bad words";
}
If you need preg_match() for some reasons, you can generate regex pattern dynamically. Something like this:
$pattern = '/(' . implode('|', $badwords) . ')/'; // $pattern = /(one|two|three)/
$result = preg_match($pattern, $string);
HTH

Answer 3

If you want to check each word by exploding the string into words, you can use this:
$badwordsfound = count(array_filter(
explode(" ",$string),
function ($element) use ($badwords) {
if(in_array($element,$badwords))
return true;
}
})) > 0;
if($badwordsfound){
echo "Bad words found";
}else{
echo "String clean";
}
Now, something better came to my mind, how about replacing all the bad words from the array and check if the string stays the same?
$badwords_replace = array_fill(0,count($badwords),"");
$string_clean = str_replace($badwords,$badwords_replace,$string);
if($string_clean == $string) {
echo "no bad words found";
}else{
echo "bad words found";
}

Answer 4

Here is the bad word filter I use and it works great:
private static $bad_name = array("word1", "word2", "word3");
// This will check for exact words only. so "ass" will be found and flagged
// but not "classic"
$badFound = preg_match("/\b(" . implode(self::$bad_name,"|") . ")\b/i", $name_in);
Then I have another variable with select strings to match:
// This will match "ass" as well as "classic" and flag it
private static $forbidden_name = array("word1", "word2", "word3");
$forbiddenFound = preg_match("/(" . implode(self::$forbidden_name,"|") . ")/i", $name_in);
Then I run an if on it:
if ($badFound) {
return FALSE;
} elseif ($forbiddenFound) {
return FALSE;
} else {
return TRUE;
}
Hope this helps. Ask if you need me to clarify anything.