Object not Found 404 Error [duplicate] - php

Question

This question already has answers here:
Object Not Found error for simple php script
(4 answers)
Closed 9 years ago.
This code returns me a 404 Object Not Found error that I could not solve by modifying the code. And I don't know whether it's a code problem or a localhost problem. I need this to be running for my Final Year Project. Please help. Thanks a lot guys.
<?php
session_start();
require "dbc.php";
echo "<center>";
echo "<img src='web_header.jpg'/>";
echo "</center>";
if($_SESSION['admin_username'])
{
echo "Hello : ".$_SESSION['admin_username'];
echo "<p><a href ='admin_panel.php'>Admin Main</a> || <a href='manage_patients.php'>Manage Patients</a> || <a href ='manage_doctor.php'>Manage Doctors</a> || <a href ='mail_form.php'>Send Email</a> || <a href='logout.php'>Logout</a> ";
echo "<title>Manage Patients</title>";
echo "<h2>Manage Patients</h2>";
$query = mysql_query("SELECT * FROM users");
$numrows = mysql_num_rows($query);
if ($numrows != 0)
{
echo "<table width='1285' height='102' border='1'>";
echo "<tr><th>ID</th><th>Name</th><th>IC Number</th><th>Address</th><th>Mobile Number</th><th>E-mail Address</th><th>Doctor ID</th></tr>";
while ($rows = mysql_fetch_assoc($query))
{
echo "<tr>";
echo "<td width='57' height='33'>";
echo "<center>";
echo $rows['id'];
echo "</center>";
echo "</td>";
echo "<td width='173'>";
echo $rows['name'];
echo "</td>";
echo "<td width='113'>";
echo "<center>";
echo $rows['icnum'];
echo "</center>";
echo "</td>";
echo "<td width='622'>";
echo $rows['address'];
echo "</td>";
echo "<td width='110'>";
echo "<center>";
echo $rows['mobile'];
echo "</center>";
echo "</td>";
echo "<td width='170'>";
echo "<center>";
echo $rows['email'];
echo "</center>";
echo "</td>";
echo "<td width='90'>";
echo "<center>";
echo $rows['docID'];
echo "</center>";
echo "</td>";
echo "</tr>";
}
echo "</table>";
echo"<br>";
echo"</br>";
echo "<form action = 'manage_patients.php method=POST'>";
echo "<p>Assign Doctor ID : ";
echo "<input type='text' name='assign_id' value='Insert Doctor ID Here'>";
echo " for Patient ID : ";
echo "<input type='text' name='id' value='Insert Patient ID Here'></p>";
echo "<input type= 'submit' name='submit' value='Assign Now'>";
echo "</form>";
if (isset($_POST['submit']))
{
require "dbc.php";
$name = mysql_real_escape_string($_POST['assign_id']);
$id = mysql_real_escape_string($_POST['id']);
$query = mysql_query("UPDATE users SET docID='$assign_id' WHERE id='$id'");
echo "Doctor ID Successfully Assigned for Patient ID : $name ";
echo "<p>Refresh page to view changes.</p>";
}
}
}
else
{
header("location:index.html");
}
?>

Answer 1

change this
<form action = 'manage_patients.php method=POST'>
to
<form action = 'manage_patients.php' method='POST'>

Answer 2

If you are getting a 404 Error, it means that the page could not be found. So it is most likely not a problem with your code (that would give you a 500 Server Error). Instead you most likely have used the wrong URL.

Answer 3

<form action = 'manage_patients.php method=POST'>
I find this line of yours a bit suspiscious