PHP Database form CSS - php

Question

I have the following code:
<?php
require "dbconn.php";
$register="SELECT * from register WHERE username = '". $_SESSION['username']."'";
$re = $connect->query($register);
$numrow = $re->num_rows;
echo "<table>";
echo "<tr>";
echo"<th>Username</th>";
echo"<th>Forename</th>";
echo"<th>Surname</th>";
echo"<th>Course</th>";
echo"<th>Subject</th>";
echo"<th>Level</th>";
echo"<th>Date</th>";
echo"<th>Time</th>";
echo"</tr>";
$count = 0;
while ($count < $numrow)
{
$row = $re->fetch_assoc();
extract($row);
echo "<tr>";
echo "<td>";
echo $username;
echo "</td>";
echo "<td>";
echo $firstName;
echo "</td>";
echo "<td>";
echo $surname;
echo "</td>";
echo "<td>";
echo $course;
echo "</td>";
echo "<td>";
echo $subject;
echo "</td>";
echo "<td>";
echo $level;
echo "</td>";
echo "<td>";
echo $date;
echo "</td>";
echo "<td>";
echo $time;
echo "</td>";
echo "</tr>";
$count = $count + 1;
}
?>
It shows the records from the database as a form. I have the following button:
<FORM METHOD="LINK" ACTION="register.php">
<INPUT TYPE="submit" VALUE="Go back to register"></INPUT></form>
No matter what DIV I put the button in, or what CSS I give it. The button always stays ABOVE the form from the database and I cannot get it below the table.
Any ideas?

Answer 1

Firstly, you did not close your table with a </table> tag; it's important that you do.
Then there's METHOD="LINK" which doesn't exist and isn't a valid method.
You either want to use method="post" or method="get".
See this answer on Stack about it:
https://stackoverflow.com/a/11582427/