I have 2 MySQL tables, one of which has a numeric column to orgainise the order I need the items to be displayed:
item_names
menu_id | dish_id | section_id | item_name
--------------------------------------------------
1 | 23 | 2 | Pie
1 | 24 | 2 | Fish
1 | 25 | 3 | Apples
1 | 26 | 2 | Onions
1 | 27 | 2 | Chips
link_extras
extra_id | dish_id | sort
-----------------------------
1 | 23 | 2
2 | 23 | 2
3 | 23 | 2
1 | 24 | 0
5 | 24 | 0
6 | 26 | 3
12 | 26 | 3
1 | 27 | 1
1 | 25 | 0
Basically what I am trying to do is extract each dish with a certain menu_id and section_id from the table item_names and order the output in respect to the sort column in the link_extras table.
so far:
$query="SELECT a.item_name, a.dish_id, b.sort
FROM item_names AS a, link_extras AS b
WHERE a.menu_id='1'
AND a.section_id='2'
AND b.dish_id=a.dish_id
GROUP BY b.dish_id
ORDER BY b.sort";
I am quite new to databases so would appreciate any help. The result I am after is
Fish
Chips
Pie
Onions
Unfortunately just can't get the order correct.
You need to use a simple JOIN
SELECT a.item_name, a.dish_id, b.sort
FROM item_names AS a
JOIN link_extras AS b
ON a.dish_id = b.dish_id
WHERE menu_id = 1
AND section_id = 2
GROUP BY b.dish_id
ORDER BY b.sort
Output:
| ITEM_NAME | DISH_ID | SORT |
------------------------------
| Fish | 24 | 0 |
| Chips | 27 | 1 |
| Pie | 23 | 2 |
| Onions | 26 | 3 |
See this SQLFiddle
SELECT
in.item_name
FROM item_names AS in
LEFT JOIN link_extras AS le
ON le.dish_id = in.dish_id
WHERE in.menu_id = 1
AND in.section_id = 2
ORDER BY le.sort
Demo Here
Output
| ITEM_NAME |
-------------
| Fish |
| Chips |
| Pie |
| Onions |
Related
I have a MySQL database that looks similar to this:
COUPON TABLE
| id | coupon_id | host | away |guess |skor |status|
+----+-----------+-----------+-------------+---------+------+------+
| 1 | 22 | Barcelona | Real Madrid | 1 |2-1 | 1 |
| 2 | 22 | Celtic | Porto | 2 |1-0 | 2 |
| 3 | 23 | Barcelona | Real Madrid | 1 |2-1 | 1 |
| 4 | 23 | M city | Chelsea | 1 |4-1 | 1 |
COUPONS TABLE
| id | user | Copuonstatus
+----+------------+-------------+
| 22 | Admin | 0 |
| 23 | Roberto | 0 |
I need to sort the results in a table that looks like this:
COUPONS TABLE
| id | user | Copuonstatus
+----+------------+-------------+
| 22 | Admin | 2 |
| 23 | Roberto | 1 |
NOTE :
Copuonstatus= default value 0
status = 0 waiting
status = 1 win
status = 2 los
im query try,
I could not
or update INNER JOIN use?
$q=$db->prepare("SELECT * FROM coupons INNER JOIN coupon ON
coupon.coupon_id = coupons.id AND coupon.status=2");
$q->execute();
$sss=$q->fetchAll(PDO::FETCH_GROUP);
if ( $sss > 0){
$db->exec("UPDATE coupons SET coupon_status = 2 FROM coupons ON
coupon.coupon_id = coupons.id WHERE coupons.Copuonstatus=0 ");}
UPDATE
coupons AS A
INNER JOIN coupon AS B ON A.id = B.coupon_id
SET
coupon_status = 2
WHERE
A.Copuonstatus = 0
Hope it help
there is 4 table
team
---------------
id | teamname |
1 | lal |
2 | sobuj |
member
-----------------------
id | membername| team |
1 | sagor | 1 |
2 | sumon | 1 |
dps
---------------------------------------------------
id | member| team | deposit | refund | ddate |
1 | 1 | 1 | 100 | 12 | 2016-09-01 |
2 | 2 | 1 | 120 | 34 | 2016-09-01 |
3 | 1 | 1 | 130 | 22 | 2016-09-01 |
4 | 3 | 1 | 120 | 0 | 2016-09-01 |
mvs
----------------------------------------------------
id | member| team | mvs_total| refund | ddate |
1 | 1 | 1 | 100 | 12 | 2016-09-01 |
2 | 2 | 1 | 120 | 34 | 2016-09-01 |
3 | 1 | 1 | 130 | 22 | 2016-09-01 |
4 | 3 | 1 | 120 | 0 | 2016-09-01 |
here is my query:
$result=mysql_query(select * from member where team='1');
$row=mysql_fetch_array($result);
do{
$aresult=mysql_query(select sum(deposit)-sum(refund)as balance from dps where member='$row[id]');
$arow=mysql_fetch_array($aresult);
echo $arow[balance];
$bresult=mysql_query(select sum(mvs_total)as mvs_balance from mvs where member='$row[id]' and date1<='2016-09-01');
$brow=mysql_fetch_array($bresult);
echo $brow[mvs_total];
} while($row=mysql_fetch_array($result));
its taking too much time how to avoid sub query or how can i save time advice plz Thanks in advance.
First thing I notice in your table structure is that repetition of column.
E.g. team column not require in dps and mcs table, because from member column [connect to member table] you can easily find dps or mvs is under which team.
For your current problem you can use following query.
SELECT member.id,
member.membername,
Sum(dps.deposit) - Sum(dps.refund) AS balance,
Sum(mvs.mvs_total) AS mvs_balance,
Sum(loan.deposit) - Sum(loan.withdraw) AS balance,
Sum(loan.deposit2) - Sum(loan.withdraw2) AS balance2,
Sum(loan.total) - Sum(loan.lpay) AS outsstanding
FROM member AS member
LEFT JOIN dps AS dps
ON dps.member = member.id
LEFT JOIN mvs AS mvs
ON mvs.member = member.id
LEFT JOIN loan AS loan
ON loan.member = member.id
WHERE member.team = 1
AND mvs.ddate <= '2016-09-01'
-- AND loan.team = '10'
-- AND loan.cs = 'Core'
GROUP BY member.id
I have a table with concatenated values within both rows, I am therefore uniquely retrieve ranking for each row in the tables.
UPDATE
The other tables has been added to question
NamesTable
NID | Name |
1 | Mu |
2 | Ni |
3 | ices |
GroupTable
GID | GName |
1 | GroupA |
2 | GroupB |
3 | GroupC |
MainTable
| NID | Ages | Group |
| 1 | 84 | 1 |
| 2 | 64 | 1 |
| 3 | 78 | 1 |
| 1 | 63 | 2 |
| 2 | 25 | 2 |
| 3 | 87 | 2 |
| 1 | 43 | 3 |
| 2 | 62 | 3 |
| 3 | 37 | 3 |
Now the first Name is equated to the first age in the table, I am able to equate them using php and foreach statements, Now the problem is with the ranking of the ages per each group. I am ranking the names uniquely on each row or group.
Results which is expected
| Names | Ages | Group | Ranking |
| Mu,Ni,ices | 84,64,78 | 1 | 1,3,2 |
| Mu,Ni,ices | 63,25,87 | 2 | 2,3,1 |
| Mu,Ni,ices | 43,62,37 | 3 | 2,1,3 |
In my quest to solving this, I am using GROUP_CONCAT, and I have been able to come to this level in the below query
SELECT
GROUP_CONCAT(Names) NAMES,
GROUP_CONCAT(Ages) AGES,
GROUP_CONCAT(Group) GROUPS,
GROUP_CONCAT( FIND_IN_SET(Ages, (
SELECT
GROUP_CONCAT( Age ORDER BY Age DESC)
FROM (
SELECT
GROUP_CONCAT(Ages ORDER BY Ages DESC ) Age
FROM
`MainTable` s
GROUP by `Group`
) s
)
)) rank
FROM
`MainTable` c
GROUP by `Group`
This actually gives me the below results.
| Names | Ages | Group | Ranking |
| 1,2,3 | 84,64,78 | 1 | 7,9,8 |
| 1,2,3 | 63,25,87 | 2 | 5,6,4 |
| 1,2,3 | 43,62,37 | 3 | 2,1,3 |
The only problem is that the ranking Values increase from 1 to 9 instead of ranking each row uniquely. Its there any idea that can help me cross over and fix this? I would be grateful for your help. Thanks
I have a database table campaign_data. I need to select the customer_id where in the campaign there is difference in tariff. How can i do that with MySQL query. Here is some sample data.
SQL Fiddle Schema
| CAMPAIGN_ID | CUSTOMER_ID | CAMPAIGN_NAME | TARIFF |
---------------------------------------------------------
| 1 | 1 | Richmond | 100 |
| 2 | 1 | Sutton Coldfield | 75 |
| 3 | 1 | Putney | 100 |
| 4 | 1 | Kentish Town | 100 |
| 5 | 1 | Woking | 100 |
| 6 | 2 | Chiswick | 90 |
| 7 | 2 | Ealing | 100 |
| 8 | 2 | Camden | 100 |
| 9 | 3 | Croydon | 75 |
| 10 | 3 | Croydon1 | 100 |
| 11 | 3 | Archway | 100 |
| 12 | 4 | Ealing0 | 100 |
| 13 | 4 | Ealing01 | 100 |
| 14 | 4 | Ealing02 | 100 |
| 15 | 4 | Chingford | 100 |
| 16 | 4 | chingford01 | 100 |
Now as you can see customer id 1 , and 3 has different tariffs. I want to select them and leave the customer id 4 because it has campaigns with same tariffs.
Desired Output
| CUSTOMER_ID |
---------------
| 1 |
| 2 |
| 3 |
For clearification you can see customer 1 has 5 records. If in his 5 records the tariff is same (100) i want to avoid but if the tariff is not some as 4 records have 100 and one has 75, i want to select.
SELECT customer_id, count(DISTINCT tariff) as tariffs
FROM campaign_data
GROUP BY customer_id
HAVING tariffs > 1
you looking for this maybe
SELECT customer_id
FROM campaign_data
GROUP BY customer_id
HAVING count(DISTINCT tariff) > 1
http://sqlfiddle.com/#!2/48b6e/31
select
customer_id,
tariff
from campaign_data
group by customer_id
having sum(tariff)/count(tariff) <> tariff;
I want to find the three most sold products every day and
show them together with number of sales.
However if there are more than one product sharing the same
number of sales I just want to tell how many products got this
ranking.
I have two tables
Products:
+-----+---------+
| Pid | Product |
+-----+---------+
| 1 | Moon |
| 2 | Sun |
| 3 | Venus |
| 4 | Mars |
+-----+---------+
SalesRows:
+-----+---------+------------+
| Pid | No_sold | Sales_date |
+-----+---------+------------+
| 1 | 1 | 2013-01-01 |
| 2 | 5 | 2013-01-01 |
| 3 | 2 | 2013-01-01 |
| 2 | 2 | 2013-01-01 |
+-----+---------+------------+
Should give:
+------+--------------+-------+
| Rank | Product | Sales |
+------+--------------+-------+
| 1 | Sun | 7 |
| 2 | Venus | 2 |
| 3 | Moon | 1 |
+------+--------------+-------+
However this sales data:
SalesRows:
+-----+---------+------------+
| Pid | No_sold | Sales_date |
+-----+---------+------------+
| 1 | 1 | 2013-01-01 |
| 2 | 5 | 2013-01-01 |
| 3 | 2 | 2013-01-01 |
| 2 | 2 | 2013-01-01 |
| 4 | 1 | 2013-01-01 |
+-----+---------+------------+
Should give:
+------+--------------+-------+
| Rank | Product | Sales |
+------+--------------+-------+
| 1 | Sun | 7 |
| 2 | Venus | 2 |
| 3 | *2 products* | 1 |
+------+--------------+-------+
Any suggestions how to solve this last part?
This query may help you.
SELECT #rownum := #rownum + 1 rownum,
t.*
FROM (SELECT #rownum:=0) r,
(select case when indicator = 1 then Product
else concat( indicator, ' Products') end as Product, sales from (Select *, count(sales) as indicator from (SELECT Product,SUM(No_sold) AS sales FROM SalesRows
JOIN Products ON Products.Pid = SalesRows.Pid
WHERE Sales_date = curdate()
GROUP BY SalesRows.Pid ) a group by sales Order by sales desc) a) t
Try this :
SELECT Product,SUM(No_sold) AS sales FROM SalesRows
LEFT JOIN Products ON Products.Pid = SalesRows.Pid
WHERE Sales_date = '".$today."'
GROUP BY Pid