Find the ranking for Concatenated rows in mysql - php

I have a table with concatenated values within both rows, I am therefore uniquely retrieve ranking for each row in the tables.
UPDATE
The other tables has been added to question
NamesTable
NID | Name |
1 | Mu |
2 | Ni |
3 | ices |
GroupTable
GID | GName |
1 | GroupA |
2 | GroupB |
3 | GroupC |
MainTable
| NID | Ages | Group |
| 1 | 84 | 1 |
| 2 | 64 | 1 |
| 3 | 78 | 1 |
| 1 | 63 | 2 |
| 2 | 25 | 2 |
| 3 | 87 | 2 |
| 1 | 43 | 3 |
| 2 | 62 | 3 |
| 3 | 37 | 3 |
Now the first Name is equated to the first age in the table, I am able to equate them using php and foreach statements, Now the problem is with the ranking of the ages per each group. I am ranking the names uniquely on each row or group.
Results which is expected
| Names | Ages | Group | Ranking |
| Mu,Ni,ices | 84,64,78 | 1 | 1,3,2 |
| Mu,Ni,ices | 63,25,87 | 2 | 2,3,1 |
| Mu,Ni,ices | 43,62,37 | 3 | 2,1,3 |
In my quest to solving this, I am using GROUP_CONCAT, and I have been able to come to this level in the below query
SELECT
GROUP_CONCAT(Names) NAMES,
GROUP_CONCAT(Ages) AGES,
GROUP_CONCAT(Group) GROUPS,
GROUP_CONCAT( FIND_IN_SET(Ages, (
SELECT
GROUP_CONCAT( Age ORDER BY Age DESC)
FROM (
SELECT
GROUP_CONCAT(Ages ORDER BY Ages DESC ) Age
FROM
`MainTable` s
GROUP by `Group`
) s
)
)) rank
FROM
`MainTable` c
GROUP by `Group`
This actually gives me the below results.
| Names | Ages | Group | Ranking |
| 1,2,3 | 84,64,78 | 1 | 7,9,8 |
| 1,2,3 | 63,25,87 | 2 | 5,6,4 |
| 1,2,3 | 43,62,37 | 3 | 2,1,3 |
The only problem is that the ranking Values increase from 1 to 9 instead of ranking each row uniquely. Its there any idea that can help me cross over and fix this? I would be grateful for your help. Thanks

Related

MySQL group rows by one column sorting by another column

I'm developing a PHP script, and I have the following table:
+----+-----------+----------+--------------+
| id | id_parent | position | feature |
+----+------------+---------+--------------+
| 1 | 1 | 2 | -B-A-C- |
| 2 | 1 | 3 | -B-C- |
| 3 | 2 | 4 | -C-B- |
| 4 | 3 | 1 | -A-B- |
| 5 | 1 | 6 | -A-C- |
| 6 | 2 | 5 | -C-B- |
| 7 | 2 | 7 | -B-C- |
| 8 | 3 | 8 | -A- |
+----+-----------+----------+--------------+
From this table I would like to select all the rows with "feature" LIKE "%-A-%", but displaying first the result with lowest "position", then all the rows that have same value for column "id_parent" of the first result, then row with the 2nd lowest "position" and all the rows that have same "id_parent" of the result with the 2nd lowest "position", and so on...
So the final result should be:
+----+-----------+----------+--------------+
| id | id_parent | position | feature |
+----+------------+---------+--------------+
| 4 | 3 | 1 | -A-B- |
| 8 | 3 | 8 | -A- |
| 1 | 1 | 2 | -B-A-C- |
| 5 | 1 | 6 | -A-C- |
+----+-----------+----------+--------------+
For some reason I can't explain here I need to have and HAVING clause for selecting the right "feature" value (...HAVING 'feature' LIKE '%-A-%' ...).
Is it possible to make all this with MySQL (possibly without subqueries) or by processing data results with PHP?
Does this help? I've left the last part of the problem as an exercise for the reader...
SELECT a.*
, c.*
FROM my_table a
JOIN
( SELECT id_parent, MIN(position) position FROM my_table WHERE feature = 'a' GROUP BY id_parent ) b
ON b.id_parent = a.id_parent
AND b.position = a.position
JOIN my_table c
ON c.feature = a.feature
AND c.id_parent = a.id_parent;

SELECT records WHERE rows have difference on a specific column

I have a database table campaign_data. I need to select the customer_id where in the campaign there is difference in tariff. How can i do that with MySQL query. Here is some sample data.
SQL Fiddle Schema
| CAMPAIGN_ID | CUSTOMER_ID | CAMPAIGN_NAME | TARIFF |
---------------------------------------------------------
| 1 | 1 | Richmond | 100 |
| 2 | 1 | Sutton Coldfield | 75 |
| 3 | 1 | Putney | 100 |
| 4 | 1 | Kentish Town | 100 |
| 5 | 1 | Woking | 100 |
| 6 | 2 | Chiswick | 90 |
| 7 | 2 | Ealing | 100 |
| 8 | 2 | Camden | 100 |
| 9 | 3 | Croydon | 75 |
| 10 | 3 | Croydon1 | 100 |
| 11 | 3 | Archway | 100 |
| 12 | 4 | Ealing0 | 100 |
| 13 | 4 | Ealing01 | 100 |
| 14 | 4 | Ealing02 | 100 |
| 15 | 4 | Chingford | 100 |
| 16 | 4 | chingford01 | 100 |
Now as you can see customer id 1 , and 3 has different tariffs. I want to select them and leave the customer id 4 because it has campaigns with same tariffs.
Desired Output
| CUSTOMER_ID |
---------------
| 1 |
| 2 |
| 3 |
For clearification you can see customer 1 has 5 records. If in his 5 records the tariff is same (100) i want to avoid but if the tariff is not some as 4 records have 100 and one has 75, i want to select.
SELECT customer_id, count(DISTINCT tariff) as tariffs
FROM campaign_data
GROUP BY customer_id
HAVING tariffs > 1
you looking for this maybe
SELECT customer_id
FROM campaign_data
GROUP BY customer_id
HAVING count(DISTINCT tariff) > 1
http://sqlfiddle.com/#!2/48b6e/31
select
customer_id,
tariff
from campaign_data
group by customer_id
having sum(tariff)/count(tariff) <> tariff;

PHP and MYSQL select with 5 tables and multiple rows as a single array

Would like to get the following as a result from the table structure below (MYSQL + PHP)
array[0][name]1,[desc]red,[title]hero,[desc]strong,[desc2]smells,[img][0]red1,[img][1]red2,[img][2]red3,ext[0].jpg,[ext][1].gif,[ext][2].png,[count][0]253,[count][1]211,[count][2]21,[count][3]121,[dist][0]5,[dist][1]5,[dist][2]12,[dist][3]2,[score][0]2,[score][1]3,[score][2]1,[score][3]5,[score][4]4,[val][0]5,[val][1]1,[val][2]4,[val][3]3,[val][4]4
The problem I have with a simple SELECT, JOIN and GROUP_CONCAT is that the values duplicate after selecting all the images.
I've tried various other ways for example selecting the data by row combined with a foreach loop in PHP, but I end up with lots of duplicates, and it looks very messy.
I also though about splitting it into multiple selects instead of using one, but I really would like to know if it can be done with one select.
Could someone help me with an MYSQL select? Thanks
game
+-----+----------+
| pid | name |
+-----+----------+
| 1 | red |
| 2 | green |
| 3 | blue |
+-----+----------+
detail
+-----+------+--------+-------+--------+
| id | pid | title | desc | desc 2 |
+-----+------+--------+-------+--------+
| 1 | 1 | hero |strong | smells |
| 2 | 2 | prince |nice | tall |
| 3 | 3 | dragon |big | green |
+-----+------+--------+-------+--------+
image
+-----+-----+-----+----+
| id | pid | img |ext |
+-----+-----+-----+----+
| 1 | 1 | red1|.jpg|
| 2 | 1 | red2|.gif|
| 3 | 1 | red3|.png|
+-----+-----+-----+----+
devmap
+-----+-----+-------+------+
| id | pid | count | dist |
+-----+-----+-------+------+
| 1 | 1 | 253 | 5 |
| 2 | 1 | 211 | 5 |
| 3 | 1 | 21 | 12 |
| 4 | 1 | 121 | 2 |
+-----+-----+-------+------+
stats
+-----+-----+-------+------+
| id | pid | scrore| val |
+-----+-----+-------+------+
| 1 | 1 | 2 | 5 |
| 2 | 1 | 3 | 1 |
| 3 | 1 | 1 | 4 |
| 4 | 1 | 5 | 3 |
| 5 | 1 | 4 | 3 |
+-----+-----+-------+------+
When you do a JOIN that involves more than a 1:1 mapping between tables you're going to have duplicate data, and there's no way to get around that in the query.
You can break it out into multiple selects, or you can loop through the result set and pare out whatever duplicate information you don't want.

select data from database Mysql query

tbl_pack_service;
+-------+---------+------------+
| ps_id | pack_id | service_id |
+-------+---------+------------+
| 1 | 1 | 1 |
| 2 | 1 | 2 |
| 3 | 2 | 1 |
| 4 | 2 | 2 |
| 5 | 2 | 3 |
| 6 | 2 | 4 |
| 7 | 2 | 5 |
| 8 | 3 | 1 |
| 9 | 3 | 2 |
| 10 | 3 | 3 |
| 11 | 3 | 4 |
+-------+---------+------------+
ps_id is primary key
i am tying to make dynamic select list in php
i want a mysql query that can give service id which do not match with particular pack_id
like i have service_id 1,2,3,4,5
when i should select pack_id=1 then 3,4,5 should be displayed
and when i should select pack_id=2 then nothing should be displayed as it has all the 5 services.
thanks..
There are a few ways to handle this. The easiest is with a NOT IN subquery:
SELECT DISTINCT service_id
FROM
tbl_pack_service
WHERE service_id NOT IN (SELECT service_id FROM tbl_pack_service WHERE pack_id = 1)

SQL statement to show difference between every user choice and one user choice

Basically I need to create output TOP table where users are arranged by comparing their points with admin's points.
For example:
User3 | 0 //Everything was as admin had.
User5 | 3 //One song had 2 points different from admin and one was off by one
ect.
In my database I have three tables:
Table: rating
+------------+---------+----------+---------+
| rating_id | user_id | song_id | points |
+------------+---------+----------+---------+
| 1 | 1 | 4 | 0 |
| 2 | 1 | 3 | 1 |
| 3 | 3 | 2 | 3 |
| 4 | 4 | 2 | 2 |
| 5 | 2 | 1 | 4 |
Table: songs
+---------------+------------+
| song_name_id | song_name |
+---------------+------------+
| 1 | Song1 |
| 2 | Song2 |
| 3 | Song3 |
| 4 | Song4 |
| 5 | Song5 |
Table: users
+----------+----------+----------+
| id | username | password |
+----------+----------+----------+
| 1 | User1 | passw |
| 2 | User2 | wordp |
| 3 | User3 | somet |
| 4 | User4 | hings |
It should be something like this (not in any programming language):
Compare user_id > 1 with user_id=1 //Let's say that the comparable admin is user_id=1
$result= ABS(user.points-admin.points)++;
And put this to array as:
username => result
Then when I sort this array by result, I can print it as top table - who got the closest result to admin!
I tryed several different solutions but never got the right result.
Can anybody help me?
UPDATE:
Thanks!
With JOIN the result is:
+------------+---------+----------+---------+-----------+
| song_id |song_name| user_id |username |rating_diff|
+------------+---------+----------+---------+-----------+
| 1 | Song1 | 1 | admin | 0 |
| 2 | Song2 | 1 | admin | 0 |
...etc...
With LEFT JOIN the result is:
+------------+---------+----------+---------+-----------+
| song_id |song_name| user_id |username |rating_diff|
+------------+---------+----------+---------+-----------+
| 1 | Song1 | 11 | user2 | NULL |
| 1 | Song1 | 10 | user1 | NULL |
| 1 | Song1 | 12 | user3 | NULL |
| 1 | Song1 | 1 | admin | 0 |
| 2 | Song2 | 11 | user2 | NULL |
| 2 | Song2 | 10 | user1 | NULL |
| 2 | Song2 | 12 | user3 | NULL |
| 2 | Song2 | 1 | admin | 0 |
..etc..
So.. Something is wrong, the rating_diff does not work.
Assuming you want this comparison on a song-by-song basis (instead of a total or average across all songs), try:
select r.song_id,
s.song_name,
r.user_id,
u.username,
abs(r.points - r1.points) rating_diff
from rating r
join songs s on r.song_id = s.song_name_id
join users u on r.user_id = u.id
join rating r1 on r.song_id = r1.song_id and r1.user_id = 1
order by s.song_name, abs(r.points - r1.points)
This should sort the output by the song name, and then by the difference between the admin's points and the users' points. (Change the join on rating r1 to be a left join if you can't guarantee an admin rating for every song.)

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