I have a string of varying length taken from a MySQL database and in that string is a value (in bold below):
s:1:"4", s:2:"53", s:3:"7", s:4:"5"
I need a way to find whatever is in quotes following the s:3:. So in this example, it would be 7. I've looked around and I think I need to use the explode function but I am having trouble implementing it. The string may contain multiple values of this in which case I'd like to get them all into an array.
Use preg_match_all() for that:
$str = 's:1:"4", s:2:"53", s:3:"7", s:4:"5"';
if(preg_match_all('/s:3:"(.*?)"/', $str, $matches)) {
var_dump($matches[1]);
}
Non-greedy method, includes multi-lines.
<?php
$str = 's:1:"4", s:2:"53", s:3:"7", s:4:"5"';
if(preg_match_all('!s:3:"([^"]+)"!s', $str, $matches)) {
print_r($matches);
}
?>
Related
I have a little problem in PHP.
$string = "[:string] has [:int] [:string] and [:int] [:string]";
I just wanna modify (probably with str_replace) it with:
$string = "He has 5 apples and 3 bananas";
How could I do that?
(Classic str_replace() will modify all [:int] with the same word,
and is not what I want).
Thank you very much...
You could use the following regex, to capture all groups to replace and then iterate over it.
\[:([^\]]+)\]
Or you can just use preg_replace_callback and pass an desired replace function to it.
$data = [...];
preg_replace_callback('/\[:([^\]]+)\]/', $str, function (&$matches) use ($data) {
return doSomethingWithMatches..
});
I have a server application which looks up where the stress is in Russian words. The end user writes a word жажда. The server downloads a page from another server which contains the stresses indicated with apostrophes for each case/declension like this жа'жда. I need to find that word in the downloaded page.
In Russian the stress is always written after a vowel. I've been using so far a regex that is a grouping of all possible combinations (жа'жда|жажда'). Is there a more elegant solution using just a regex pattern instead of making a PHP script which creates all these combinations?
EDIT:
I have a word жажда
The downloaded page contains the string жа'жда. (notice the
apostrophe, I do not before-hand know where the apostrophe in the
word is)
I want to match the word with apostrophe (жа'жда).
P.S.: So far I have a PHP script creating the string (жа'жда|жажда') used in regex (apostrophe is only after vowels) which matches it. My goal is to get rid of this script and use just regex in case it's possible.
If I understand your question,
have these options (d'isorder|di'sorder|dis'order|diso'rder|disor'der|disord'er|disorde'r|disorder') and one of these is in the downloaded page and I need to find out which one it is
this may suit your needs:
<pre>
<?php
$s = "d'isorder|di'sorder|dis'order|diso'rder|disor'der|disord'er|disorde'r|disorder'|disorde'";
$s = explode("|",$s);
print_r($s);
$matches = preg_grep("#[aeiou]'#", $s);
print_r($matches);
running example: https://eval.in/207282
Uhm... Is this ok with you?
<?php
function find_stresses($word, $haystack) {
$pattern = preg_replace('/[aeiou]/', '\0\'?', $word);
$pattern = "/\b$pattern\b/";
// word = 'disorder', pattern = "diso'?rde'?r"
preg_match_all($pattern, $haystack, $matches);
return $matches[0];
}
$hay = "something diso'rder somethingelse";
find_stresses('disorder', $hay);
// => array(diso'rder)
You didn't specify if there can be more than one match, but if not, you could use preg_match instead of preg_match_all (faster). For example, in Italian language we have àncora and ancòra :P
Obviously if you use preg_match, the result would be a string instead of an array.
Based, on your code, and the requirements that no function is called and disorder is excluded. I think this is what you want. I have added a test vector.
<pre>
<?php
// test code
$downloadedPage = "
there is some disorde'r
there is some disord'er in the example
there is some di'sorder in the example
there also' is some order in the example
there is some disorder in the example
there is some dso'rder in the example
";
$word = 'disorder';
preg_match_all("#".preg_replace("#[aeiou]#", "$0'?", $word)."#iu"
, $downloadedPage
, $result
);
print_r($result);
$result = preg_grep("#'#"
, $result[0]
);
print_r($result);
// the code you need
$word = 'also';
preg_match("#".preg_replace("#[aeiou]#", "$0'?", $word)."#iu"
, $downloadedPage
, $result
);
print_r($result);
$result = preg_grep("#'#"
, $result
);
print_r($result);
Working demo: https://eval.in/207312
I'm trying to find the best way to grab the dynamic substring, but replace all of the content after.
This is what I'm trying to achieve:
{table_telecommunications}
The substring {table_ is always the same, the only that varies is telecommunications}.
I want to grab the word telecommunications so I can do a search on a MySQL table and then replace {table_telecommunications} with the content returned.
I thought of making a strpos and then explode and so on.
But I guess it would be easier with regex, but I have no skills on creating regex.
Could you possibly give me the best way to do this?
Edit: I'm saying possibly regex is the best way because I need to find strings that are in this format, but the second part is variable, just like {table_*}
Use Regex.
<?php
$string = "{table_telecommunications} blabla blabla {table_block}";
preg_match_all("/\{table_(.+?)\}/is", $string, $matches);
$substrings = $matches[1];
print_r($substrings);
?>
if (preg_match('#table_([^}]+)}#', '{table_telecommunications}', $matches)){
echo $matches[1];
}
That's a regex solution. You can do the same with explode:
$parts = explode('table_', '{table_telecommunications}');
echo substr($parts[1], 0, -1);
$input = '{table_telecommunications}';
$table_name = trim(implode('_', array_shift(explode($input, '_'))), '}');
Should be fast, no regex required.
I am using preg_match() to extract pieces of text from a variable, and let's say the variable looks like this:
[htmlcode]This is supposed to be displayed[/htmlcode]
middle text
[htmlcode]This is also supposed to be displayed[/htmlcode]
i want to extract the contents of the [htmlcode]'s and input them into an array. i am doing this by using preg_match().
preg_match('/\[htmlcode\]([^\"]*)\[\/htmlcode\]/ms', $text, $matches);
foreach($matches as $value){
return $value . "<br />";
}
The above code outputs
[htmlcode]This is supposed to be displayed[/htmlcode]middle text[htmlcode]This is also supposed to be displayed[/htmlcode]
instead of
[htmlcode]This is supposed to be displayed[/htmlcode]
[htmlcode]This is also supposed to be displayed[/htmlcode]
and if have offically run out of ideas
As explained already; the * pattern is greedy. Another thing is to use preg_match_all() function. It'll return you a multi-dimension array of matched content.
preg_match_all('#\[htmlcode\]([^\"]*?)\[/htmlcode\]#ms', $text, $matches);
foreach( $matches[1] as $value ) {
And you'll get this: http://codepad.viper-7.com/z2GuSd
A * grouper is greedy, i.e. it will eat everything until last [/htmlcode]. Try replacing * with non-greedy *?.
* is by default greedy, ([^\"]*?) (notice the added ?) should make it lazy.
What do lazy and greedy mean in the context of regular expressions?
Look at this piece of code:
preg_match('/\[htmlcode\]([^\"]*)\[\/htmlcode\]/ms', $text, $matches);
foreach($matches as $value){
return $value . "<br />";
}
Now, if your pattern works fine and all is ok, you should know:
return statement will break all loops and will exit the function.
The first element in matches is the whole match, the whole string. In your case $text
So, what you did is returned the first big string and exited the function.
I suggest you can check for desired results:
$matches[1] and $matches[2]
I am going to parse a log file and I wonder how I can convert such a string:
[5189192e][game]: kill killer='0:Tee' victim='1:nameless tee' weapon=5 special=0
into some kind of array:
$log['5189192e']['game']['killer'] = '0:Tee';
$log['5189192e']['game']['victim'] = '1:nameless tee';
$log['5189192e']['game']['weapon'] = '5';
$log['5189192e']['game']['special'] = '0';
The best way is to use function preg_match_all() and regular expressions.
For example to get 5189192e you need to use expression
/[0-9]{7}e/
This says that the first 7 characters are digits last character is e you can change it to fits any letter
/[0-9]{7}[a-z]+/
it is almost the same but fits every letter in the end
more advanced example with subpatterns and whole details
<?php
$matches = array();
preg_match_all('\[[0-9]{7}e\]\[game]: kill killer=\'([0-9]+):([a-zA-z]+)\' victim=\'([0-9]+):([a-zA-Z ]+)\' weapon=([0-9]+) special=([0-9])+\', $str, $matches);
print_r($matches);
?>
$str is string to be parsed
$matches contains the whole data you needed to be pared like killer id, weapon, name etc.
Using the function preg_match_all() and a regex you will be able to generate an array, which you then just have to organize into your multi-dimensional array:
here's the code:
$log_string = "[5189192e][game]: kill killer='0:Tee' victim='1:nameless tee' weapon=5 special=0";
preg_match_all("/^\[([0-9a-z]*)\]\[([a-z]*)\]: kill (.*)='(.*)' (.*)='(.*)' (.*)=([0-9]*) (.*)=([0-9]*)$/", $log_string, $result);
$log[$result[1][0]][$result[2][0]][$result[3][0]] = $result[4][0];
$log[$result[1][0]][$result[2][0]][$result[5][0]] = $result[6][0];
$log[$result[1][0]][$result[2][0]][$result[7][0]] = $result[8][0];
$log[$result[1][0]][$result[2][0]][$result[9][0]] = $result[10][0];
// $log is your formatted array
You definitely need a regex. Here is the pertaining PHP function and here is a regex syntax reference.