I am trying to find a way to select the row from database which the dates are between yesterday 5p.m. and today 4:59p.m.
The database are filled with orders and I am trying to make it display all the orders starting from yesterday's 5p.m. till today's 4:59p.m. I have to make it display those entries everyday so that my client is able to know what had been ordered today until the cut-off time.
I had found a few but only display time from 0000 - 23:59 while what I need is 17:00 - 16:59.
Is there any way to do so?
EDIT:
The query that I had so far:
"SELECT date FROM xcart_orders WHERE date between '".strtotime(date("F j, Y", time() - 60 * 60 * 24))."' and '".strtotime(date('F j, Y'))."'"
This will return me result between now and yesterday. E.g. Currently is 12PM, it will return me the results from yesterday 12PM till now(12PM).
HOWEVER, what I want is it will always show me the result from yesterday 5PM till today 4:59PM. This is necessary as my client is doing e-commerce and the cut-off time for delivery is 5PM. Hence, he needs to consolidate the orders from last cut-off time to current cut-off time.
My apologies for forgetting to inform about this; the date in the database is in UNIX time stamp, hence, my query has 'strtotime'.
Sorry causing confusion, my English isn't good.
Regards,
FT
Check this and try
$yesterday= date("Y-m-d", time()-86400)." 00:00:00";
$yesterday2= date("Y-m-d", time()-86400)." 23:59:59";
Change the time if you like
Try this
SELECT x FROM y WHERE date between '2014-05-07 08:00' and date_add('2014-05-07 08:00', INTERVAL 1 DAY)
The result should be every data you select from date 2014-05-07 8am to 2017-05-08 7.59am
Hope it helps. =)
Related
I'm trying to create a reservation system for a games library of some sort.
Users should not be allowed to reserve the game for a day before today.
I tried to do this by changing the date chosen by the user for the start of the reservation to a timestamp. Then I would set the date for today, change it to a timestamp and check if the date chosen by the user is less than todays timestamp.
Here is the code:
$timestamp = strtotime($ReservationStart);
$todaystamp = (strtotime('yesterday midnight'));
if ($timestamp < $todaystamp) {
die("The date you've chosen is before today, please choose a valid date");
}
I thought this would work but it this code only stops reservations for 2 days past and behind rather than yesterday and behind.
Any ideas on how to get it to work for yesterday?
What you are looking for is to use midnight rather than yesterday midnight.
$timestamp = strtotime('midnight');
It seems that the strtotime works backwards, so yesterday midnight would be yesterday at 00:00, so it allows all 24 hours of the next day (yesterday) to be allowed to book in.
midnight would go to the current day's midnight (starting at that current date's 00:00.
If you were worried about getting today's midnight, that would be:
$timestamp = strtotime('today midnight');
So it's quite easy to understand once you learn that.
We have a database of films, and need to select the film with a start and end date within the current week. We have two columns in the SQL table, both of type "date", and are written in the format 2015-01-25 (ISO)(YYYY-MM-DD). We need to select the entry that occurs within the current week. The start date for the film is usually the Friday of the week, and the end date is usually the Sunday of the week. I want to be able to show what the upcoming film for the upcoming weekend will be, no matter what day of the week they check. I have written the following PHP and SQL query, but I'm not getting any data back when I echo the $result.
$date = strtotime("now");
$last = strtotime('next Sunday');
$date = date('Y-m-d',$date);
$last = date('Y-m-d',$last);
$result = mysql_fetch_array(mysql_query("SELECT * FROM campusFilms WHERE startDate BETWEEN $date AND $last"));
Any assistance would be greatly appreciated, and I am happy to elaborate on anything needed. I have searched other StackOverflow questions but none of them quite answered this specific case.
SELECT *
FROM campusFilms
WHERE WEEK('2015-02-05') BETWEEN WEEK(startDate) AND WEEK(endDate);
http://sqlfiddle.com/#!2/476d3/3
This solution cannot use an index so, if performance is an issue, we can look at alternative solutions.
Why not just use YEARWEEK() ?
SELECT whatever_you_need
FROM campusFilms
WHERE YEARWEEK(CURDATE()) BETWEEN YEARWEEK(startDate) AND YEARWEEK(endDate);
yearweek returns the year and week of any given date which will handle multiple years.
If all you care is to find records where startdate is between the Friday and Sunday of the current week, then you don't even need to use PHP to compute dates, you can get mysql to do all the work for you:
SELECT *
FROM campusFilms
WHERE startDate BETWEEN
DATE_ADD(CURDATE(), INTERVAL(-2 + MOD(8-DAYOFWEEK(CURDATE()),7)) DAY)
AND
DATE_ADD(CURDATE(), INTERVAL(MOD(8-DAYOFWEEK(CURDATE()),7)) DAY)
This works regardless of what day of the week it is today. If it's Friday, it'll give you films between today and the day after tomorrow. For Saturdays, it'll give you films between yesterday and tomorrow and for Sundays, it'll give you films between two days ago and today.
I am retrieving data from a table and show the total SUM of entries. What I want to do is to show the total SUM of entries made on today's date, yesterday and this month. The table is using the unix timestamp format (e.g. 1351771856 for example).
Currently I am using this line to show todays results:
AND comment_date > UNIX_TIMESTAMP() - 24 * 3600";
but that gives me just the entries for the last 24 hours.
Example: So let's say its Friday, 17:00 PM - it gives me the count from Thursday 17:00 PM to Friday 17:00 PM
What I want is to get the results for
Thursday 00:00:00 - 23:59:59 (yesterday in this case)
the results for today (00:00:00 - 23:59:59)
and last week, results that start on Monday, 00:00:00 until "today" (in this case Friday).
I couldn't find a way in the MySQL documentation to achieve this.
This mysql code should work for you:
// Today
AND DATE(from_unixtime(comment_date)) = CURRENT_DATE
// Yesterday
AND DATE(from_unixtime(comment_date)) = DATE_SUB(CURRENT_DATE,INTERVAL 1 DAY)
// This week
AND YEARWEEK(from_unixtime(comment_date), 1) = YEARWEEK(CURRENT_DATE, 1)
// This month
AND YEAR(from_unixtime(comment_date)) = YEAR(CURRENT_DATE)
AND MONTH(from_unixtime(comment_date)) = MONTH(CURRENT_DATE)
Simply use this:
AND comment_date > date_sub(current_date, interval 1 day)
See my answer here, I think it's quite related.
Pull records from orders table for the current week
Consider getting intimate with MySQL's GROUP BY. You will most likely need to know this if you use MySQL.
I am trying to create a custom MySQL for use with the Expression Engine CMS. The purpose of the query is to display events that are happening today or in the future.
The problem is that the EE field type that allows you to put in the date and converts it into a unix timestamp. If I pick the 26th July it puts in the date value "25th July 23:00".
As you see from my query below it almost works but I need to add 24 hours onto the values that are used in the conditional part of the statement. I want events that occur on the day "for example today 25th July" to be displayed up until 23:00 hours that day then be removed.
I almost have it I am just stuck on how to add 24 hours to the conditional.
SELECT t.entry_id,
t.title,
t.url_title,
d.field_id_13 AS event_lineup,
d.field_id_14 AS event_details,
d.field_id_15 AS event_day,
d.field_id_16 AS event_flyer_front,
d.field_id_17 AS event_flyer_back,
d.field_id_18 AS event_facebook,
d.field_id_12 AS event_date
FROM `exp_weblog_titles` AS t
NATURAL JOIN `exp_weblog_data` AS d
WHERE d.weblog_id = 5
AND CAST(d.field_id_12 AS UNSIGNED) >= (unix_timestamp(Now()))
ORDER BY d.field_id_12 ASC
What I think might be happening is your timestamps get adjusted for the time zone, and that adjustment is configured differently in the CMS and on the server.
I need to calculate a difference between a starting date/time and an ending date/time. But, I only want to do this for the 5-day work week (exclude Sat/Sun as days). What is the best way to do this? My thought is that from the date, I'll have to get the day of the week and if it is a weekday, then I add to the accumulator. If it's not, then I don't add anything.
I'm sure someone has done this before, but I couldn't seem to find anything searching. Any links or other help would be very useful.
Many thanks,
Bruce
DAYOFWEEK returns 1 for Sunday and 7 for Saturday. I'm not sure how your schema is set up, but this will perform a TIMEDIFF of two dates that are on a Monday - Friday work week.
select TIMEDIFF(date1,date2) from table
where DAYOFWEEK(date1) not in (1,7) and DAYOFWEEK(date2) not in (1,7)
MySQL DATE/TIME functions
EDIT: From Bruce's comment about holidays. If you have a table full of holiday dates, something like this would work to exclude processing those days:
select TIMEDIFF(date1,date2) from table
where date1 not in (select holiday from holiday_table) and
date2 not in (select holiday from holiday_table) and
DAYOFWEEK(date1) not in (1,7) and DAYOFWEEK(date2) not in (1,7)
NETWORKDAYS() "Returns the number of whole working days between start_date and end_date. Working days exclude weekends and any dates identified in holidays. Use NETWORKDAYS to calculate employee benefits that accrue based on the number of days worked during a specific term." according to the Excel 2007 help file.
The "between" description is a bit inaccurate because it includes the start and end dates, i.e. networkdays(21-01-2010. 22-01-2010) = 2. It also takes no account of times.
Here's a function in PHP that will give the same results. It doesn't work properly if the end date is less than the start date, nor does do anything about holidays (see below the function).
function networkdays($startdate, $enddate)
{
$start_array = getdate(strtotime($startdate));
$end_array = getdate(strtotime($enddate));
// Make appropriate Sundays
$start_sunday = mktime(0, 0, 0, $start_array[mon], $start_array[mday]+(7-$start_array[wday]),$start_array[year]);
$end_sunday = mktime(0, 0, 0, $end_array[mon], $end_array[mday]- $end_array[wday],$end_array[year]);
// Calculate days in the whole weeks
$week_diff = $end_sunday - $start_sunday;
$number_of_weeks = round($week_diff /604800); // 60 seconds * 60 minutes * 24 hours * 7 days = 1 week in seconds
$days_in_whole_weeks = $number_of_weeks * 5;
//Calculate extra days at start and end
//[wday] is 0 (Sunday) to 7 (Saturday)
$days_at_start = 6 - $start_array[wday];
$days_at_end = $end_array[wday];
$total_days = $days_in_whole_weeks + $days_at_start + $days_at_end;
return $total_days;
}
To take holidays into account, you'd have to work out the number of days using this function, then use a query like
Select count (holiday_date) from holidays
where holiday_date between start_date and end_date
and DAYOFWEEK(holiday_date) not in (1,7)
Be careful that there isn't a problem with the end_date being treated as 00:00 (i.e. first thing in the morning) - you may have to condition it to be 23:59:59 so that it works properly. It all depends on how your holidays are stored.
To return the holidays in the same time period and subtract that from the number you first thought of.