We have a database of films, and need to select the film with a start and end date within the current week. We have two columns in the SQL table, both of type "date", and are written in the format 2015-01-25 (ISO)(YYYY-MM-DD). We need to select the entry that occurs within the current week. The start date for the film is usually the Friday of the week, and the end date is usually the Sunday of the week. I want to be able to show what the upcoming film for the upcoming weekend will be, no matter what day of the week they check. I have written the following PHP and SQL query, but I'm not getting any data back when I echo the $result.
$date = strtotime("now");
$last = strtotime('next Sunday');
$date = date('Y-m-d',$date);
$last = date('Y-m-d',$last);
$result = mysql_fetch_array(mysql_query("SELECT * FROM campusFilms WHERE startDate BETWEEN $date AND $last"));
Any assistance would be greatly appreciated, and I am happy to elaborate on anything needed. I have searched other StackOverflow questions but none of them quite answered this specific case.
SELECT *
FROM campusFilms
WHERE WEEK('2015-02-05') BETWEEN WEEK(startDate) AND WEEK(endDate);
http://sqlfiddle.com/#!2/476d3/3
This solution cannot use an index so, if performance is an issue, we can look at alternative solutions.
Why not just use YEARWEEK() ?
SELECT whatever_you_need
FROM campusFilms
WHERE YEARWEEK(CURDATE()) BETWEEN YEARWEEK(startDate) AND YEARWEEK(endDate);
yearweek returns the year and week of any given date which will handle multiple years.
If all you care is to find records where startdate is between the Friday and Sunday of the current week, then you don't even need to use PHP to compute dates, you can get mysql to do all the work for you:
SELECT *
FROM campusFilms
WHERE startDate BETWEEN
DATE_ADD(CURDATE(), INTERVAL(-2 + MOD(8-DAYOFWEEK(CURDATE()),7)) DAY)
AND
DATE_ADD(CURDATE(), INTERVAL(MOD(8-DAYOFWEEK(CURDATE()),7)) DAY)
This works regardless of what day of the week it is today. If it's Friday, it'll give you films between today and the day after tomorrow. For Saturdays, it'll give you films between yesterday and tomorrow and for Sundays, it'll give you films between two days ago and today.
Related
I'm trying to create a reservation system for a games library of some sort.
Users should not be allowed to reserve the game for a day before today.
I tried to do this by changing the date chosen by the user for the start of the reservation to a timestamp. Then I would set the date for today, change it to a timestamp and check if the date chosen by the user is less than todays timestamp.
Here is the code:
$timestamp = strtotime($ReservationStart);
$todaystamp = (strtotime('yesterday midnight'));
if ($timestamp < $todaystamp) {
die("The date you've chosen is before today, please choose a valid date");
}
I thought this would work but it this code only stops reservations for 2 days past and behind rather than yesterday and behind.
Any ideas on how to get it to work for yesterday?
What you are looking for is to use midnight rather than yesterday midnight.
$timestamp = strtotime('midnight');
It seems that the strtotime works backwards, so yesterday midnight would be yesterday at 00:00, so it allows all 24 hours of the next day (yesterday) to be allowed to book in.
midnight would go to the current day's midnight (starting at that current date's 00:00.
If you were worried about getting today's midnight, that would be:
$timestamp = strtotime('today midnight');
So it's quite easy to understand once you learn that.
Can somebody help me with my report view problem. I need to view monthly organization report. I do get the report for one month but the problem is it didn't take the first day of the month as the initial. from the day the report has been generate, it is just count 30 days backward. therefore it will take the report for the previous month too since it didn't start from 1 day of every month. this is the code that i used.
SELECT *
FROM aduan_form
WHERE tarikh >= SUBDATE(SYSDATE(), INTERVAL 30 DAYS)
i know there is something wrong with it, i already try to add the format in sysdate() which is :
SELECT *
FROM aduan_form
WHERE tarikh >= SUBDATE(SYSDATE('%Y-%m-01'), INTERVAL 1 MONTH)
but the result still the same. how can i fix this problem?
For Oracle, this would help:
Oracle, Make date time's first day of its month
#MatBailie said: According to http://psoug.org/reference/date_func.html, this should work a dandy...
SELECT TRUNC(yourDateField, 'MONTH') FROM yourTable
I am currently trying to write a little program to track time-off requests for employees. I'm fairly new to MYSQL and PHP, so it's a learning project for me as well. I've run into this problem which I do not seem to be able to figure out.
I want to display time off requests for a given week (Mon-Fri). I've got the requests in a table 'requests', with a 'Starttime' and 'Endtime' in separate fields, both Date/Time.
I can currently easily search and retrieve requests that have either (or both) Starttime or Endtime values that fall within the given ISO week I am looking at (WEEKOFYEAR() ).
What I need to be able to do is search for requests that may include days in the ISO week I am displaying, but not have a Starttime or Endtime during that week.
Example:
Employee takes off Tuesday of Week 24 through Friday of Week 24.
Currently, I would correctly display that the employee was off starting Tuesday and show a return on that Friday, but on Wed and Thursday nothing would be entered.
Employee takes off Friday of Week 30 through Monday of Week 32.
Currently, I would show that employee as not being 'off' during Week 31 because the search would not show a Starttime or Endtime during that week even though they are actually off the entire week. Though the Starttime and Endtime would be noted on the correct days.
Right now, what I do to work around this is run 5 additional queries to check if the date for each day Mon-Fri during Week 31 is contained BETWEEN the Starttime and Endtime of each request in the db.
I hate to run a total of 6 queries to get this information. Is there an easier way to get that information?
I just wrote a calendar app for events and ran into this- how bout something like this:
SELECT * FROM Requests WHERE
Start_Date BETWEEN <first_day_of_week> AND <last_day_of_week>
OR
End_Date BETWEEN <first_day_of_week> AND <last_day_of_week>
OR
<day_of_week_monday> BETWEEN Start_Date AND End_Date
OR
<day_of_week_tuesday> BETWEEN Start_Date AND End_Date
OR
<day_of_week_wedenesday> BETWEEN Start_Date AND End_Date
OR
<day_of_week_thursday> BETWEEN Start_Date AND End_Date
OR
<day_of_week_friday> BETWEEN Start_Date AND End_Date
GROUP BY ID ORDER BY Start_Date ASC, Date ASC
While < value_names > are generated with php via the currently viewed week requested. Should cover your bases.
What format are these dates stored in the DB? Assuming they are using MySQL's DATE format, its pretty easy to do. You can just use comparison operators on the fields and MySQL will do the work for you in one query.
$sql = "SELECT * FROM table WHERE startdate <= $someday AND $someday <= enddate";
Sticking to your week of year way of doing it, you can run a check to see if the current week falls within the range of the starting week off and the ending week off.
SELECT * FROM table WHERE WEEKOFYEAR(Starttime) <= N AND WEEKOFYEAR(Endtime) >= N;
(where N is the week you're displaying)
What you'd want to do, once you get the rows, is parse each day in PHP to see if that day falls between the starttime and endtime.
A good method for that is using:
$start_timestamp = strtotime($row['Starttime']);
$end_timestamp = strtotime($row['Endtime']);
You can use a similar method to get a timestamp of the day you are displaying, and see if it falls between $start_timestamp and $end_timestamp to determine if that day is off.
since you mentioned PHP as the display:
$start=30; //Friday of Week 30
$end=32; //Monday of Week 32
foreach (range($start, $end) as $number) {
echo $number;
}
You would expect to get 30,31,32.
You will have to verify that $start is < $end though as well for December to January weeks.
The range for WEEKOFYEAR() is 1-53. In this case, add 53 to the $end and display mod of $end if greater than 53:
$start=52; //Friday of Week 52, 2009
$end=2; //Monday of Week 2, 2010
If($start>$end) $end+=53;
foreach (range($start, $end) as $number) {
if($number>53){
echo $number%53;}
else{
echo $number;
}
}
You would expect to get 52,53,1,2
Probably need the query to read either like the big one with all the ORs or something like this
WHERE
Starttime <= <value for last day/time of the week>
AND
Endtime >= <value for the first day/time of the week>
That should get all the dates you need that could fall in that week, then you parse the records you get with PHP to find the ones for that actual week... though there may be an easier way to do that.
Before i start id like to say ive posted this question as more of a discussion rather than Problem Question.
In my Database i have news posts lets say with 3 columns (Id, title, date). Wher Id and title are self Explanitory the date is stored in mktime() values, in other words the number of seconds passed since 1 January 1970.
Now what i want to do is build an archive link that will display as such
July 2009
June 2009
March 2009
Feburary 2009
December 2008
Note the months on which there were no posts are not displayed.
Now as an initial thought i was thinking
Start with the last day of the current Month
And get the Value of the First day of the current Month
Do a MySQL COUNT Query/mysql_num_rows for posts that were date >= First_Day_Seconds AND date <= Last_Day_Seconds
Display or put the values in an Array
Do another Query to Check if Any more values are found WHERE date < First_Day_Seconds (break if no rows were found)
Now the above is just something on the top of my head. But if you got any ideas to speed this process up please share.
Will say in advance, date needs to be in mktime format
I would suggest using a database "native" time format, but it works with UNIX timestamps as well.
You can simply do:
SELECT DISTINCT FROM_UNIXTIME(date, '%M %Y') FROM posts;
Optionally with a WHERE clause limiting the dates to past or future dates. Possibly an ORDER clause thrown in for good measure. That should be pretty much all that's needed, let the database do as much work as possible.
If you need more formatting options, select the dates with "%Y-%m" instead and format them in PHP:
date($myCustomFormat, strtotime("$date-01"));
You can use this query to get years
"SELECT *,content_id,COUNT(content_id) AS itemCount FROM content_mast GROUP BY DATE_FORMAT(date_upload,'%Y') DESC";
now use can use this query to get month of that year
$tday = date("Y", $datetime);
$s1="select * from content_mast where DATE_FORMAT(date_upload,'%Y')=$tday";
I need to calculate a difference between a starting date/time and an ending date/time. But, I only want to do this for the 5-day work week (exclude Sat/Sun as days). What is the best way to do this? My thought is that from the date, I'll have to get the day of the week and if it is a weekday, then I add to the accumulator. If it's not, then I don't add anything.
I'm sure someone has done this before, but I couldn't seem to find anything searching. Any links or other help would be very useful.
Many thanks,
Bruce
DAYOFWEEK returns 1 for Sunday and 7 for Saturday. I'm not sure how your schema is set up, but this will perform a TIMEDIFF of two dates that are on a Monday - Friday work week.
select TIMEDIFF(date1,date2) from table
where DAYOFWEEK(date1) not in (1,7) and DAYOFWEEK(date2) not in (1,7)
MySQL DATE/TIME functions
EDIT: From Bruce's comment about holidays. If you have a table full of holiday dates, something like this would work to exclude processing those days:
select TIMEDIFF(date1,date2) from table
where date1 not in (select holiday from holiday_table) and
date2 not in (select holiday from holiday_table) and
DAYOFWEEK(date1) not in (1,7) and DAYOFWEEK(date2) not in (1,7)
NETWORKDAYS() "Returns the number of whole working days between start_date and end_date. Working days exclude weekends and any dates identified in holidays. Use NETWORKDAYS to calculate employee benefits that accrue based on the number of days worked during a specific term." according to the Excel 2007 help file.
The "between" description is a bit inaccurate because it includes the start and end dates, i.e. networkdays(21-01-2010. 22-01-2010) = 2. It also takes no account of times.
Here's a function in PHP that will give the same results. It doesn't work properly if the end date is less than the start date, nor does do anything about holidays (see below the function).
function networkdays($startdate, $enddate)
{
$start_array = getdate(strtotime($startdate));
$end_array = getdate(strtotime($enddate));
// Make appropriate Sundays
$start_sunday = mktime(0, 0, 0, $start_array[mon], $start_array[mday]+(7-$start_array[wday]),$start_array[year]);
$end_sunday = mktime(0, 0, 0, $end_array[mon], $end_array[mday]- $end_array[wday],$end_array[year]);
// Calculate days in the whole weeks
$week_diff = $end_sunday - $start_sunday;
$number_of_weeks = round($week_diff /604800); // 60 seconds * 60 minutes * 24 hours * 7 days = 1 week in seconds
$days_in_whole_weeks = $number_of_weeks * 5;
//Calculate extra days at start and end
//[wday] is 0 (Sunday) to 7 (Saturday)
$days_at_start = 6 - $start_array[wday];
$days_at_end = $end_array[wday];
$total_days = $days_in_whole_weeks + $days_at_start + $days_at_end;
return $total_days;
}
To take holidays into account, you'd have to work out the number of days using this function, then use a query like
Select count (holiday_date) from holidays
where holiday_date between start_date and end_date
and DAYOFWEEK(holiday_date) not in (1,7)
Be careful that there isn't a problem with the end_date being treated as 00:00 (i.e. first thing in the morning) - you may have to condition it to be 23:59:59 so that it works properly. It all depends on how your holidays are stored.
To return the holidays in the same time period and subtract that from the number you first thought of.