This question already has answers here:
How to add http:// if it doesn't exist in the URL
(8 answers)
Closed 9 years ago.
I need a small part of helping, i can't remember the requlare exp. to tell me about its a URL or not, i need to tjeck about its starting whit http:// or not, befures if its not have http:// in start i need to put it into and if its have i need to do nothing.
Hobe sombardy can help me whit this queistion, and thanks a lot for helping.
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Use preg_replace like this
$url = 'http://www.yahoo.com';
echo 'http://' . preg_replace( '~^http://~', '', $url );
Related
This question already has answers here:
PHP, Delete parts of a URL variable [duplicate]
(3 answers)
Closed 4 years ago.
I want to replace '/50' with URL.my URL is
http://localhost/CI/admin/pcustomer/cprofile/50?customer=18267&mobile=&nearby=
I want url as
http://localhost/CI/admin/pcustomer/cprofile?customer=18267&mobile=&nearby=
From that little info in your question, this seems to be the simplest way to achieve "I want to replace '/50' with URL"
$url = str_replace('/50', '', 'http://localhost/CI/admin/pcustomer/cprofile/50?customer=18267&mobile=&nearby=');
This question already has answers here:
How to remove the querystring and get only the URL?
(16 answers)
Closed 8 years ago.
I'm new to PHP and WordPress, and i need to import image from a offshore website with the WordPress function download_URL().
My problem is, i have URL that look like that :
http://www.test/img/FMR.jpg
But i have also URL that look like that :
http://www.test/img/FMR.jpg?Qq_0y12h
And can i have remove everything that is after the .extension if there something?
you can use preg_replace, I did this little example for you.
<?php
$url = "http://www.test/img/FMR.jpg?Qq_0y12h";
echo "url = $url\n\n";
$urlFormatted = preg_replace("/\?.*$/", "", $url);
echo "urlFormatted = $urlFormatted\n";
?>
This question already has answers here:
Get path from URL
(2 answers)
Closed 8 years ago.
Can anyone please tell me how to remove url from a string using PHP
I have this string
src="http://cdn1.vox-cdn.com/uploads/chorus_image/image/34918177/layering__1_.0_standard_90.0.png"
Desired Output:
src="/uploads/chorus_image/image/34918177/layering__1_.0_standard_90.0.png"
You can use the parse_url() buil-in php function for this.
For example:
<?php
$url = 'http://cdn1.vox-cdn.com/uploads/chorus_image/image/34918177/layering__1_.0_standard_90.0.png';
$parsed_url = parse_url($url);
var_dump($parsed_url);
?>
Output:
So, after the url is parsed, the bit you want is found on $parsed_url['path']. Hope this helps.
This question already has answers here:
How do I extract query parameters from a URL string in PHP?
(3 answers)
Closed 8 years ago.
This would be an example:
redirect
dynamic_word can be changed because it is dynamic. When click "redirect", dynamic_word will be extracted. So, how to extract it in redirect.php file ? Thanks !
Use $_GET to get parameters from an URL
<?php
$thatName = $_GET['q'];
echo $thatName;
Result
dynamic_word
If samitha's correct looking answer is incorrect then perhaps you mean you would like to extract the dynamic word from a string.
In that case you could do
<?php
$string = 'http://mywebsite.com/redirect.php&q=dynamic_word';
$ex_stirng = explode('&q=', $string);
$dynamic_word = $ex_string(1);
?>
Or even use the strstr function:
http://www.php.net/manual/en/function.strstr.php
This question already has answers here:
Beautiful way to remove GET-variables with PHP?
(12 answers)
How to remove content from url after question mark. preg_match or preg_replace?
(2 answers)
Closed 8 years ago.
I have this url: http:www.blabla.com/x/x/x/x?username=testuser
I need a string to read this url, but forget everything and including the ? mark.
So it becomes this: http:www.blabla.com/x/x/x/x
The reason for this is because I am making this variable:
$host = $_SERVER['SERVER_NAME'] . $_SERVER['REQUEST_URI'];
And this code:
if($host == "http:www.blabla.com/x/x/x/x") {
echo "lul";
}
But right now, the URL changes depending on what user is on, and it has to execute the echo no matter what user is on.
So I read some reges and preg_match etc. and I just wanted to hear your opinions or advice. How would I accomblish this the best? thanks!
This is too trivial of a task for regex.
$host = $_SERVER['SERVER_NAME'] . explode("?", $_SERVER['REQUEST_URI'], 2)[0];
(Note: this assumes you're up-to-date, or at least using PHP 5.4, for the dereference to work without a temporary variable)
Or if you must omit the get / request section just explode ? and use $host[0]