This question already has answers here:
Get path from URL
(2 answers)
Closed 8 years ago.
Can anyone please tell me how to remove url from a string using PHP
I have this string
src="http://cdn1.vox-cdn.com/uploads/chorus_image/image/34918177/layering__1_.0_standard_90.0.png"
Desired Output:
src="/uploads/chorus_image/image/34918177/layering__1_.0_standard_90.0.png"
You can use the parse_url() buil-in php function for this.
For example:
<?php
$url = 'http://cdn1.vox-cdn.com/uploads/chorus_image/image/34918177/layering__1_.0_standard_90.0.png';
$parsed_url = parse_url($url);
var_dump($parsed_url);
?>
Output:
So, after the url is parsed, the bit you want is found on $parsed_url['path']. Hope this helps.
Related
This question already has answers here:
PHP - parse current URL
(6 answers)
Closed 2 years ago.
How to get a part of string using PHP?
I have a string like this.
https://test-app.com/admin/api/2019-10/orders.json?limit=2&page_info=eyJpZHMiOiIyMDY3MTczMTEzOTg3LDIwNjU0ODU0MzA5MTUsMjA2NTQ3OTI3MDUzMSwyMDYyODE3MzI5MjgzIiwibGFzdF9pZCI6MjA2NTQ4NTQzMDkxNSwibGFzdF92YWx1ZSI6IjIwMjAtMDMtMTcgMTg6MTc6NTkiLCJkaXJlY3Rpb24iOiJuZXh0In0
I want only the link.. like this
orders.json?limit=2&page_info=eyJpZHMiOiIyMDY3MTczMTEzOTg3LDIwNjU0ODU0MzA5MTUsMjA2NTQ3OTI3MDUzMSwyMDYyODE3MzI5MjgzIiwibGFzdF9pZCI6MjA2NTQ4NTQzMDkxNSwibGFzdF92YWx1ZSI6IjIwMjAtMDMtMTcgMTg6MTc6NTkiLCJkaXJlY3Rpb24iOiJuZXh0In0
That's not just a string it's a URL so use URL and path functions:
$parts = parse_url($str);
echo basename($parts['path']).$parts['query'];
This question already has answers here:
How do I replace certain parts of my string?
(5 answers)
Closed 6 years ago.
i have a problem.
I want in php to replace all 'blablabla' with 'bla'(because i hate blablabla). Here's my code:
<?php
$string = 'Dracula always says BlaBlaBla but says he never says BlaBlaBla';
$result = answer to replace here
?>
Thanks
Use srt_replace function to do that like this :
str_replace("BlaBlaBla","bla",$string);
You can use something like this:
str_replace("BlaBlaBla","bla",$string)
Also you can find it here in the docs: http://php.net/manual/en/function.str-replace.php
This question already has answers here:
How to remove the querystring and get only the URL?
(16 answers)
Closed 8 years ago.
I'm new to PHP and WordPress, and i need to import image from a offshore website with the WordPress function download_URL().
My problem is, i have URL that look like that :
http://www.test/img/FMR.jpg
But i have also URL that look like that :
http://www.test/img/FMR.jpg?Qq_0y12h
And can i have remove everything that is after the .extension if there something?
you can use preg_replace, I did this little example for you.
<?php
$url = "http://www.test/img/FMR.jpg?Qq_0y12h";
echo "url = $url\n\n";
$urlFormatted = preg_replace("/\?.*$/", "", $url);
echo "urlFormatted = $urlFormatted\n";
?>
This question already has answers here:
How do I extract query parameters from a URL string in PHP?
(3 answers)
Closed 8 years ago.
This would be an example:
redirect
dynamic_word can be changed because it is dynamic. When click "redirect", dynamic_word will be extracted. So, how to extract it in redirect.php file ? Thanks !
Use $_GET to get parameters from an URL
<?php
$thatName = $_GET['q'];
echo $thatName;
Result
dynamic_word
If samitha's correct looking answer is incorrect then perhaps you mean you would like to extract the dynamic word from a string.
In that case you could do
<?php
$string = 'http://mywebsite.com/redirect.php&q=dynamic_word';
$ex_stirng = explode('&q=', $string);
$dynamic_word = $ex_string(1);
?>
Or even use the strstr function:
http://www.php.net/manual/en/function.strstr.php
This question already has answers here:
How to add http:// if it doesn't exist in the URL
(8 answers)
Closed 9 years ago.
I need a small part of helping, i can't remember the requlare exp. to tell me about its a URL or not, i need to tjeck about its starting whit http:// or not, befures if its not have http:// in start i need to put it into and if its have i need to do nothing.
Hobe sombardy can help me whit this queistion, and thanks a lot for helping.
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Use preg_replace like this
$url = 'http://www.yahoo.com';
echo 'http://' . preg_replace( '~^http://~', '', $url );