I'm calling CHtml::ajaxlink like so:
<?php echo CHtml::ajaxLink('Add to a list',
$this->createUrl('itemList/ajaxadditem'),
array(
'onclick'=>'$("#addToListDialog").dialog("open"); return false;',
'type'=>'POST',
'update'=>'#addToListDialog',
'data' => 'js:{"product_id" : $("#productID").val()}'
),
array('id'=>'showAddToListDialog'));
?>
I don't know how to write the values of the AJAX options array dynamically. I'm using a workaround to get the value using JavaScript, $("#productID").val() and a hidden field.
I want to write something like:
'data' => 'js:{"product_id" : "$model->product_id"}'
But "$model->product_id" is entered as a literal string.
Can anyone give me a way to do this? My method won't actually solve the problem since I need to write this AJAX link multiple times on the fly.
Assuming your $model instance is available, you should be able to append it dynamically like below:
'data' => "js:{'product_id' : '{$model->product_id}'}"
Related
Hi I got trouble in retrieve URL segment CAkephp3 in view. I want to get the ID from current URL.
Lets say my URL is http://localhost/admin/financial_agreements/edit/50
and I want redirect to http://localhost/admin/financial_agreements/do_print/50
simply :
var urlPrint = "<?=$this->Url->build(['controller' => 'financial_agreements', 'action' => 'do_print', 'I NEED ID FROM CURRENT'], true)?>";
I try debug
<?=debug($this->Url->build()); die();?>
But its produce : admin/financial_agreements/edit/50
whats called in 50 ? I need that 50 inside my "url->build" urlPrint
sorry for bad english.
Anyhelp will appreciate.
thanks.
You can use the Request object to get request data (including url parameters) within views.
Try this in your view:
$this->request->getParam('pass') //CakePHP 3.4+
$this->request->params['pass'] // CakePHP 3.3
That will return an array of all non-named parameters that were passed after the action's name in the URL. Example: /mycontroller/myaction/param1/param2. So in this example, $this->request->getParam('pass') will produce an array like: [0 => 'param1', 1 => 'param2'].
Bonus answer: you can also 'name' parameters in the URL, like: /mycontroller/myaction/some_name:some_value. To retrieve this kind of named parameters, you would do the same trick but using: $this->request->getParam('named') (Use the argument 'named' instead of 'pass').
More info:
https://book.cakephp.org/3.0/en/controllers/request-response.html
https://book.cakephp.org/3.0/en/development/routing.html#passed-arguments
Assuming that your edit function follows standard practices, you'll have something like this:
public function edit($id) {
$financialAgreement = $this->FinancialAgreements->get($id);
...
$this->set(compact('financialAgreement'));
}
Then in edit.ctp, you can get the id of the current record very simply as $financialAgreement->id, so your URL will be generated with
$this->Url->build(['controller' => 'financial_agreements', 'action' => 'do_print', $financialAgreement->id], true)
I need to load a view into a view within CodeIgniter, but cant seem to get it to work.
I have a loop. I need to place that loop within multiple views (same data different pages). So I have the loop by itself, as a view, to receive the array from the controller and display the data.
But the issue is the array is not available to the second view, its empty
The second view loads fine, but the array $due_check_data is empty
SO, I've tried many things, but according to the docs I can do something like this:
Controller:
// gather data for view
$view_data = array(
'loop' => $this->load->view('checks/include/due_checks_table', $due_check_data, TRUE),
'check_cats' => $this->check_model->get_check_cats(),
'page_title' => 'Due Checks & Tests'
);
$this->load->view('checks/due_checks',$view_data);
But the array variable $due_check_data is empty
I'm just getting this error, saying the variable is empty?
Message: Undefined variable: due_check_data
You are passing the $view_data array to your view. Then, in your view, you can access only the variables contained in $view_data:
$loop
$check_cats
$page_title
There is no variable due_check_data in the view.
EDIT
The first view is contained in the variable $loop, so you can just print it in the second view (checks/due_checks):
echo $loop;
If you really want to have the $due_check_data array in the second view, why don't you simply pass it?
$view_data = array(
'loop' => $this->load->view('checks/include/due_checks_table', $due_check_data, TRUE),
'check_cats' => $this->check_model->get_check_cats(),
'page_title' => 'Due Checks & Tests',
'due_check_data' => $due_check_data
);
$this->load->view('checks/due_checks',$view_data);
Controller seems has no error. Check out some notices yourself:
<?=$due_check_data?>
This only available in PHP >= 5.4
<? echo $due_check_data; ?>
This only available when you enable short open tag in php.ini file but not recommended
You are missing <?php. Should be something like this
<?php echo $due_check_data; ?>
OK, i managed to solve this by declaring the variables globally, so they are available to all views.
// gather data for view
$view_data = array(
'due_check_data' => $combined_checks,
'check_cats' => $this->check_model->get_check_cats(),
'page_title' => 'Due Checks & Tests'
);
$this->load->vars($view_data);
$this->load->view('checks/due_checks');
i've been using Yii framework for some time now, and i've been really having a good time especially with these widgets that makes the development easier. I'm using Yii bootsrap for my extensions..but i'm having a little trouble understanding how each widget works.
My question is how do i display the widget say a TbDetailView inside a tab?
i basically want to display contents in tab forms..however some of them are in table forms...some are in lists, detailviews etc.
I have this widget :
$this->widget('bootstrap.widgets.TbDetailView',array(
'data'=>$model,
'attributes'=>$attributes1,
));
that i want to put inside a tab
$this->widget('bootstrap.widgets.TbWizard', array(
'tabs' => $tabs,
'type' => 'tabs', // 'tabs' or 'pills'
'options' => array(
'onTabShow' => 'js:function(tab, navigation, index) {
var $total = navigation.find("li").length;
var $current = index+1;
var $percent = ($current/$total) * 100;
$("#wizard-bar > .bar").css({width:$percent+"%"});
}',
),
and my $tabs array is declared like this :
$tabs = array('studydetails' =>
array(
'id'=>'f1study-create-studydetails',
'label' => 'Study Details',
'content' =>//what do i put here?),
...
...);
when i store the widget inside a variable like a $table = $this->widget('boots....);
and use the $table variable for the 'content' parameter i get an error message like:
Object of class TbDetailView could not be converted to string
I don't quite seem to understand how this works...i need help..Thanks :)
You can use a renderPartial() directly in your content, like this:
'content'=>$this->renderPartial('_tabpage1', [] ,true),
Now yii will try to render a file called '_tabpage1.php' which should be in the same folder as the view rendering the wizard. You must return what renderPartial generates instead of rendering it directly, thus set the 3rd parameter to true.
The third parameter that the widget() function takes is used to capture output into a variable like you are trying to do.
from the docs:
public mixed widget(string $className, array $properties=array ( ), boolean $captureOutput=false)
$this->widget('class', array(options), true)
Right now you are capturing the object itself in the variable trying to echo out an object. Echo only works for things that can be cast to a string.
I'm using Yii framework and I want call a PHP function and return a value.
This value has to be appended to a div. I try a lot of things but nothing works. This is more far that I get:
echo CHtml::ajaxSubmitButton('add one more',
CController::createUrl('cadTabelapreco/UpdateFilho'),
array('type'=>'POST',
'data'=>array('item'=>'CadTabelaprecoi',
'i'=>$i,
'complete' => 'function(){
$("#data").append($(this).html());
}',
));
I also try this:
array('type'=>'POST',
'data'=>array('item'=>'CadTabelaprecoi',
'i'=>$i,
'form'=>$form),
'complete' => 'function(ret){
$("#data").append().val(ret);
}',
));
The thing is, if I debug it with Firebug, I see the response and its right, but I can't append the value to the div. How to do that?
echo CHtml::ajaxSubmitButton('add one more',
CController::createUrl('cadTabelapreco/UpdateFilho'),
array('type'=>'POST',
'data'=>array('item'=>'CadTabelaprecoi',
'i'=>$i,
'success' => 'function(data){//pass data to success function
$("#data").empty();//clear div cause if without you'll stack data in your div
$("#data").append(data);//append your url return
}',
));
In your Controller :
public function actionUpdateFilho{
/**
* Do what you need here
*/
echo $result;//form variable string with result wich you want to output(in HTml format wich you need)
}
It's working great for me. Hope this was helpfull.
The problem was the javascript. jQuery's val() returns the value of a input element. If you want to append whatever html or text was returned from the server, the last line should read:
$("#data").append(ret);
Well the title pretty much says it all. I had:
$strata = new Zend_Form_Element_Select('strata');
$strata->setLabel('Select a strata: ')->setMultiOptions($this->stratalist)->setAttrib('onChange', 'this.form.submit()');
Then I need to use some fancy dojo form elements in other forms. So I decided to make them all look the same and did this:
$strata = new Zend_Dojo_Form_Element_FilteringSelect('strata');
$strata->setLabel('Select a strata: ')->setMultiOptions($this->stratalist)->setAttrib('onChange', 'this.form.submit()');
It shows up and looks fine, but the form is not submitted when I change the FilteringSelect. If I look at the HTML that is rendered, sure enough:
<select name="strata" id="strata" onChange="this.form.submit()">
I suspect that Dojo elements cannot or do not work like this. So how do I make this form submit when I change the FilteringSelect?
Here it is:
When defining the form, give it an id:
$this->setName('StrataSelect');
or
$this->setAttrib('id', 'StrataSelect');
Then the onChange event uses getElementById:
$strata = new Zend_Dojo_Form_Element_FilteringSelect('strata');
$strata->setLabel('Select a strata: ')->setMultiOptions($this->stratalist)->setAttrib('onChange', "document.dojo.byId('StrataSelect').submit();");
or
$strata->setLabel('Select a strata: ')->setMultiOptions($this->stratalist)->setAttrib('onChange', "document.getElementById('StrataSelect').submit();");
Why this now works and none of the "old school" submit() calls probably has something to do with dojo handling the onchange event. So submit or this.form are not objects, methods, etc etc etc.
I don't want to put any javascript this form depends on into the view. I want this form to be "portable". So therefore I don't want to use dojo.connect
There are probably better ways to do this. So I'll leave this unanswered for now.
Do you have parseOnLoad enabled? If you're building the form in php you can do this:
$form = new Zend_Form_Dojo();
$form->addElement(
'FilteringSelect',
'myId',
array(
'label' => 'Prerequisite:',
'autocomplete' => true,
'jsId' => 'myJsId',
),
array(), //attributes
array( //your select values
'id1' => 'name1',
'id2' => 'name2',
'id3' => 'name3',
)
);
you might need to set a few attributes on your $form.
try this:
$form->setAttribs( array('jsId'=>'MyFormName') );
Then in your onClick:
MyFormName.submit()
If your form passes validation (presuming you have some), it should submit.