Yii php: Displaying a widget in a Tab - php

i've been using Yii framework for some time now, and i've been really having a good time especially with these widgets that makes the development easier. I'm using Yii bootsrap for my extensions..but i'm having a little trouble understanding how each widget works.
My question is how do i display the widget say a TbDetailView inside a tab?
i basically want to display contents in tab forms..however some of them are in table forms...some are in lists, detailviews etc.
I have this widget :
$this->widget('bootstrap.widgets.TbDetailView',array(
'data'=>$model,
'attributes'=>$attributes1,
));
that i want to put inside a tab
$this->widget('bootstrap.widgets.TbWizard', array(
'tabs' => $tabs,
'type' => 'tabs', // 'tabs' or 'pills'
'options' => array(
'onTabShow' => 'js:function(tab, navigation, index) {
var $total = navigation.find("li").length;
var $current = index+1;
var $percent = ($current/$total) * 100;
$("#wizard-bar > .bar").css({width:$percent+"%"});
}',
),
and my $tabs array is declared like this :
$tabs = array('studydetails' =>
array(
'id'=>'f1study-create-studydetails',
'label' => 'Study Details',
'content' =>//what do i put here?),
...
...);
when i store the widget inside a variable like a $table = $this->widget('boots....);
and use the $table variable for the 'content' parameter i get an error message like:
Object of class TbDetailView could not be converted to string
I don't quite seem to understand how this works...i need help..Thanks :)

You can use a renderPartial() directly in your content, like this:
'content'=>$this->renderPartial('_tabpage1', [] ,true),
Now yii will try to render a file called '_tabpage1.php' which should be in the same folder as the view rendering the wizard. You must return what renderPartial generates instead of rendering it directly, thus set the 3rd parameter to true.

The third parameter that the widget() function takes is used to capture output into a variable like you are trying to do.
from the docs:
public mixed widget(string $className, array $properties=array ( ), boolean $captureOutput=false)
$this->widget('class', array(options), true)
Right now you are capturing the object itself in the variable trying to echo out an object. Echo only works for things that can be cast to a string.

Related

Wordpress page title fxn in echo p

This is probably super simple but I just cant seem to figure it out.
How can I pass the current Wordpress page title into this code?
Below is a snippet from Formidable Forms WP plug-in which basically prints statistics from forms within my website.
In this case, the # of entries for a specific form (55jqi) and a specific field(50) are displayed on the pages, showing how many other people also submitted that form.
Im trying to skip needing to update each page (4,380 pages) with the stats output snippet.. and instead call the current page into the stats display code, to show stats for that particular page being viewed.. using an elementor custom post type template.
I need this:
echo FrmProStatisticsController::stats_shortcode(array('id' => '55jqi', 'type' => 'count', 50 => 'runtz'));
To work like this:
echo FrmProStatisticsController::stats_shortcode(array('id' => '55jqi', 'type' => 'count', 50 => 'single_post_title();'));
Replace the input area ‘Runts’ with the current page title, using
single_post_title()
Or similar.
Any help would be amazing!!
There is also a short code available which works the similarly.
[frm-stats id=55jqi type=count 50="Runtz"]
Formidable Forms Plugin shortcode and php page for reference: https://formidableforms.com/knowledgebase/add-field-totals-and-statistics/#kb-field-filters
You are using single_post_title function in a wrong way. By default, this function will echo the output but in the shortcode, you need to return the output.
This function accepts 2 param: 1: $prefix 2: $display
You need to pass $display as false, which will tell the function to return the value.
so you'll have to make a call like this `single_post_title( '', false )``
and your shortcode call will be like this:
echo FrmProStatisticsController::stats_shortcode(
array(
'id' => '55jqi',
'type' => 'count',
'50' => single_post_title( '', false ),
)
);

CodeIgniter loading a view into a view

I need to load a view into a view within CodeIgniter, but cant seem to get it to work.
I have a loop. I need to place that loop within multiple views (same data different pages). So I have the loop by itself, as a view, to receive the array from the controller and display the data.
But the issue is the array is not available to the second view, its empty
The second view loads fine, but the array $due_check_data is empty
SO, I've tried many things, but according to the docs I can do something like this:
Controller:
// gather data for view
$view_data = array(
'loop' => $this->load->view('checks/include/due_checks_table', $due_check_data, TRUE),
'check_cats' => $this->check_model->get_check_cats(),
'page_title' => 'Due Checks & Tests'
);
$this->load->view('checks/due_checks',$view_data);
But the array variable $due_check_data is empty
I'm just getting this error, saying the variable is empty?
Message: Undefined variable: due_check_data
You are passing the $view_data array to your view. Then, in your view, you can access only the variables contained in $view_data:
$loop
$check_cats
$page_title
There is no variable due_check_data in the view.
EDIT
The first view is contained in the variable $loop, so you can just print it in the second view (checks/due_checks):
echo $loop;
If you really want to have the $due_check_data array in the second view, why don't you simply pass it?
$view_data = array(
'loop' => $this->load->view('checks/include/due_checks_table', $due_check_data, TRUE),
'check_cats' => $this->check_model->get_check_cats(),
'page_title' => 'Due Checks & Tests',
'due_check_data' => $due_check_data
);
$this->load->view('checks/due_checks',$view_data);
Controller seems has no error. Check out some notices yourself:
<?=$due_check_data?>
This only available in PHP >= 5.4
<? echo $due_check_data; ?>
This only available when you enable short open tag in php.ini file but not recommended
You are missing <?php. Should be something like this
<?php echo $due_check_data; ?>
OK, i managed to solve this by declaring the variables globally, so they are available to all views.
// gather data for view
$view_data = array(
'due_check_data' => $combined_checks,
'check_cats' => $this->check_model->get_check_cats(),
'page_title' => 'Due Checks & Tests'
);
$this->load->vars($view_data);
$this->load->view('checks/due_checks');

Drupal 7 collapsible fieldset issues with ajax

I am sending data via ajax to my PHP callback function inside my custom module... Everything is working great. The problem I am having is: the html i am returning and rendering in the ajax complete funciton is composed of fieldsets which wont expand/collapse. Things i have tested :
1). If I render the same html ( fieldsets ) into one of the custom blocks in that same module, they work great, the collapse and expand.
2). I have tried including this inside the callback function,
drupal_add_js('misc/form.js');
drupal_add_js('misc/collapse.js');
inside the fieldset render array,
return array(
'#type' => 'fieldset',
'#title' => t($title),
'#attributes' => array(
'class' => $class,
),
'#attached' => array(
'js' => array(
'misc/form.js',
'misc/collapse.js',
),
),
);
The
$class
variable contains collapsed and collapsible. I have also tried using
#theme => 'fieldset'
Instead of #type => 'fieldset'
the javascript files
misc/collapse.js
misc/form.js
are already being included from a different function inside my module. And looking at the source of the page, are indeed being included to the head of the page.
This has to be related to bringing them in via ajax, I know when you bring elements into the document via ajax, in-order to set events for those new elements you have to use
$(document).on('event', 'class', function(){
//code here
});
and I am wondering if this could be the reason that the fieldsets wont collapse/expand.
If you get data with AJAX with jQuery once you have to use Drupal.behaviors like this:
Drupal.behaviors.MYBEHAVIOR = {
attach: function (context, settings) {
$('MYELEMENT.MYBEHAVIOR', context).once('MYBEHAVIOR', function () {
// Apply the MYBEHAVIOR effect to the elements only once.
});
}
};
See more at the js documentation https://drupal.org/node/756722

CakePHP requestAction() alternative option w/ element

I am in a situation where I am trying to pass a value from a controller action to an element directly.
The only way I know how to do this is with requestAction(), but I don't like using that feature for resource reasons and its not recommended in the manual.
Can anyone shed some light on another method?
Here is what I have now:
Bird Controller action:
function element_array_pass() {
$this->paginate['Bird'] = array(
'fields' => array('id', 'name'),
'contain' => array('id', 'name'),
'order' => 'Bird.id'
);
$bird_elmnt = $this->paginate('Bird');
$this->set(compact('bird_elmnt', $bird_elmnt));
}
dir: views/elements/element_array_pass.ctp
debug($bird_elmnt); // nothing being passed here.
dir: views/birds/index.ctp
I include the element in this file, but the array will not pass.
echo $this->element('element_array_pass',array("bird_elmnt" => $bird_elmnt)); // call to element.
I would like to include this element in my index.ctp with values passed from the action() I included above.
echo $this->element('birds_paginator_element',array('bird_elmnt_var'=>$bird_elmnt_var));
You are able to pass additional data to an element through the 2nd argument of the element() method.
echo $this->element('birds_paginator_element', array(
'bird_elmnt_var' => $bird_elmnt
));
// In element
var_dump($bird_elmnt_var);
Also have a read of this article from Mark Story.

CodeIgniter - Variable scope

I have a controller which I use for a login form. In the view, I have a {error} variable which I want to fill in by using the parser lib, when there is an error. I have a function index() in my controller, controlled by array $init which sets some base variables and the error message to '':
function index()
{
$init = array(
'base_url' => base_url(),
'title' => 'Login',
'error' => ''
);
$this->parser->parse('include/header', $init);
$this->parser->parse('login/index', $init);
$this->parser->parse('include/footer', $init);
}
At the end of my login script, I have the following:
if { // query successful }
else
{
$init['error'] = "fail";
$this->parser->parse('login/index', $init);
}
Now, of course this doesn't work. First of all, it only loads the index view, without header and footer, and it fails at setting the original $init['error'] to (in this case) "fail". I was trying to just call $this->index() with perhaps the array as argument, but I can't seem to figure out how I can pass a new $init['error'] which overrides the original one. Actually, while typing this, it seems to impossible to do what I want to do, as the original value will always override anything new.. since I declare it as nothing ('').
So, is there a way to get my error message in there, or not? And if so, how. If not, how would I go about getting my error message in the right spot? (my view: {error}. I've tried stuff with 'global' to bypass the variable scope but alas, this failed. Thanks a lot in advance.
$init musst be modified before generating your view.
To load your header and footer you can include the following command and the footer's equivalent into your view.
<?php $this->load->view('_header'); ?>
to display errors, you can as well use validation_errors()
if you are using the codeigniter form validation.
if you are using the datamapper orm for codeigniter you can write model validations, and if a query fails due to validation rule violation, you get a proper error message in the ->error property of your model.
Code for your model:
var $validation = array(
'user_name' => array(
'rules' => array('required', 'max_length' => 120),
'label' => 'Name'
)
);
You might try this:
function index() {
$init = array(
'base_url' => base_url(),
'title' => 'Login',
'error' => ''
);
$string = $this->parser->parse('include/header', $init, TRUE);
$string .= $this->parser->parse('login/index', $init, TRUE);
$string .= $this->parser->parse('include/footer', $init, TRUE);
$this->parser->parse_string(string);
}
In parse()you can pass TRUE (boolean) to the third parameter, when you want data returned instead of being sent (immediately) to the output class. By the other hand, the method parse_string works exactly like `parse(), only accepts a string as the first parameter in place of a view file, thus it works in conjunction.

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