I am sending parameter to a page itself on keyup event.
I am sending a parameter though ajax like url:"http://localhost/application/views/pages/users/tags.php?tagfilter=lif",
and getting its value in a javascript function ('/instruction/showtags/<?php if( isset($_GET['tagfilter']) && $_GET['tagfilter'] == "") {echo $_GET['tagfilter'];} ?> ', {
I checked,my console , its showing no errors & no warning.
But i am sure its either not sending parameter or it may be its not getting the parameter.
Please let me know , why my parameter is not sending ? Is the way of writing ajax code is correct?
If you could not understand my question, then please let me know, i will try to explain it in some other way.
Full Source code:
tags.php
<input placeholder="Search" id="tagfilter" name="tagfilter" type="text"/>
Jquery/ajax function
<script type="text/javascript">
$(document).ready(function() {
$('#tagfilter').keyup(function(e){
// alert("called");
$.ajax({
url:"http://localhost/application/views/pages/users/tags.php?
tagfilter=lif",
type:"get",
success: function(){
}
});
});
});
</script>
My Infinite scroll js file, including in the same page
<script>
(function($) {
$.fn.scrollPagination = function(options) {
var settings = {
nop : 10, // The number of posts per scroll to be loaded
offset : 0, // Initial offset, begins at 0 in this case
error : 'No More Data To Display!', // When the user reaches the end this is the message that is
// displayed. You can change this if you want.
delay : 500, // When you scroll down the posts will load after a delayed amount of time.
// This is mainly for usability concerns. You can alter this as you see fit
scroll : true // The main bit, if set to false posts will not load as the user scrolls.
// but will still load if the user clicks.
}
.............................
.............................
.............................
Update:
What exactly i am trying to do?
I have implemented a infinite scroll with jquery. When my page loads, it call my controller, and from from controller it takes data and display it in my view page.
Now , i plan to put search on this page with infinite scroll.
I have a textbox, from this textbox i am trying to do search on keyup event.
I am trying with this logic. If you have any better logic, please share with me,because i am struggling from long time to implement this.
Ok. I don't know your structure so what I have is few tips.
First: you need to know that javascript processing is much faster than PHP as long as JS is a Client Side language when PHP is Server Side language. so try to keep your php data in javascript vars like this:
var seg3 = "<?php echo $this->uri->segment(3) ?>";
$.post("/instruction/showtags/" + seg3, {...etc
then for your safety just try to check whether you need all the url not just part of it ( depends on CI configuration ) so your code can come up like this
var seg3 = "<?php echo $this->uri->segment(3) ?>";
var myurl = "<?php echo site_url('casting/send_email'); ?>" + seg3;
$.post(myurl, {...etc
And be sure not to use $_GET.
Second, make sure you're sending the segment and it's there. you can always use the
console.log() in javascript to keep up with the data and see if it's empty or not.
whether you want it on keyup or keydown or whatever it will be the same.
and if you are using json make sure to add it as the last arg to your $.post() method you can see the jquery api for it.
You check if $_GET['tagfilter'] == "", and only if the string is empty you print it.
so it should be:
<?php if( isset($_GET['tagfilter']) && $_GET['tagfilter'] != "") { echo $_GET['tagfilter'];} ?>
Related
We currently search through a form for contacts, and AJAX is used to display the results from a PHP file below the form (on the same page). The form's onsubmit attribute includes a return:false value to allow the AJAX code to complete.
The results appear 'below the fold' and I'd like the focus to jump down to an ID (#peopleResults) but can't manage this; instead, it stays at the top of the parent page.
Should I be trying something in the actual PHP file or in the AJAX call (to the PHP file) to achieve this?
I already tried <script>window.location.hash = "peopleResults";</script> in the PHP file and referencing results.php#peopleResults in the AJAX call, but neither worked.
Is this possible? I guess I am trying to do the equivalent of appending #peopleResults to the URL upon pressing Submit (without the URL necessary changing)...
I already tried <script>window.location.hash = "peopleResults";</script>
location.hash includes the # – both when reading from it, as well when you set a new value.
So
window.location.hash = "#peopleResults"
would be the correct way to tell the browser to jump to an element with the ID (or anchor name) peopleResults.
I think you want to achieve this please check the fiddle.
This is done without using hash. As you just want to view the result after Ajax.
By this you don't need to change the URL.
Based on the reply to my comment, it would seem you're a little foggy on the AJAX portion too. From the documentation:
$.ajax({
url: "http://fiddle.jshell.net/favicon.png",
beforeSend: function( xhr ) {
xhr.overrideMimeType( "text/plain; charset=x-user-defined" );
}
})
.done(function( data ) {
if ( console && console.log ) {
//this is where you need to add your data to the div
//after the data is in the div, scroll to it.
console.log( "Sample of data:", data.slice( 0, 100 ) );
}
});
You can see, the function where I added the comments is where you need to do the scrolling. After you populate the div (how ever you're doing that), then just use the suggestion Learner Student or phpisuber01 made of scrolling to it:
$("html, body").animate({ scrollTop: $("#peopleResults").scrollTop() }, 1000);
jQuery AJAX documentation: https://api.jquery.com/jQuery.ajax/
jQuery scrollTop documentation: https://api.jquery.com/scrollTop/
I have a label called price, and this label automatically updates its value every two seconds from the server. Also I have a button or link, which increases this price in database when I do click. The problem is how save the data without redirect to the same page.
My code:
<?php
echo $this->html->link('Increase price', array('controller' => 'example', 'action' => 'increase_price', $param1), array ('id' => 'btPrice'));
?>
And in ExampleController the code is
function increase_price($param1)
{
$this->autoRender = false; //Don't want a view
$example = $this->Example->findById($param1);
$example ['Example ']['price'] = $example ['Example ']['price'] + 1;
$this->Example->save($example );
}
The price is increased but cakePhp is asking me for a view, and if I do autoRender=false then my page will be blank and I want to stay on the same page.
I don't know if this is a CakePhp question or if is Jquery question. In both cases, I appreciate your help
if you don't wanna reload the page to do this, you need to use Ajax..since you've already got unique id for this, what you need to do is use Jquery Ajax to handle this.
first download jquery lib and put it into your app/webroot/js folder and load it
http://jquery.com/download/ download Jquery lib here
then you can do:
<script>
$( document ).ready(function() {
//do sth when click on #btPrice
$('#btPrice').click(function(){
$.ajax({
type:"POST",
//the function u wanna call
url:"<?php echo $this->webroot;?>example/increase_price/",
/* data you wanna pass, as your $param1 is serverSide variable,
you need to first assign to js variable then you can pass:
var param1 = '<?php echo $param1;?>';*/
data:{increase_price:param1},
success:function(data)
{
//update your div
}
});
});
});
</script>
Also you have to modify your increase_price function
As we are passing increse_price as parameter in ajax call and method is post, in your function, you have to use $_POST['increase_price'] to catch it then assign to another variable
eg: $param1 = $_POST['increase_price']; then you can use it..
Should do the trick for you
The normal flow is that when you click on a link, the browser requests a new page from the server and then renders the contents.
If you want to change something in the DOM from the client's side you need Javascript.
With the use of Javascript you can skip the complete page reload because you can request the exact information you need and then update the DOM with it. This is known as AJAX.
While you can do AJAX with plain Javascript it is usually much easier to use a Javascript framework like jQuery to make things easier.
Finally, I find some article in http://code.google.com/intl/en/web/ajaxcrawling/docs/getting-started.html msnbc use this method. Thanks for all the friends.
Thanks for your all help. I will study it for myself :-}
Today, I updated my question again, remove all of my code. Maybe my thinking all wrong.
I want make a products show page.
One is index.php, another is search.php (as a jquery box page). index.php has some products catagory lists; each click on product catagory item will pass each value to search.php. search.php will create a mysql query and view products details. It(search.php) also has a search box.(search.php can turn a page to show multiple products; the search result looks similar to a jQuery gallery...).
I need to do any thing in search.php but without refreshing index.php.
I tried many method while I was thinking: Make search.php as an iframe (but can not judge search.php height when it turn page and index.php without refresh); use jquery ajax/json pass value from index.php to search.php, then get back all page's value to index.php. (still met some url rule trouble. php depend on url pass values in search.php, but if the value change, the two page will refresh all. )
so. I think, ask, find, try...
Accidental, I find a site like my request.
in this url, change search word after %3D, only the box page refresh
in this url, change search word after = the page will refresh
I found somthing in its source code, is this the key rules?
<script type="text/javascript">
var fastReplace = function() {
var href = document.location.href;
var siteUrl = window.location.port ? window.location.protocol+'//'+window.location.hostname +':'+window.location.port : window.location.protocol+'//'+window.location.hostname;
var delimiter = href.indexOf('#!') !== -1 ? '#!wallState=' : '#wallState=';
var pieces = href.split(delimiter);
if ( pieces[1] ) {
var pieces2 = pieces[1].split('__');
if ( pieces2[1] && pieces2[1].length > 1) {
window.location.replace( unescape(pieces2[1].replace(/\+/g, " ")));
}
}
}();
</script>
If so. in my condition. one page is index.php. another is search.php.
How to use js make a search url like
index.php#search.php?word=XXX&page=XXX
then how to pass value from one to another and avoid refreshing index.php?
Still waiting for help, waiting for some simple working code, only js, pass value get value.
Thanks to all.
I have read your problem, though I can not write complete code for you (lack of time ) So I can suggest you to what to do for your best practice
use dataType ='json' in jQuery.ajax function and
write json_encode() on B.php
and json_decode() on A.php or $.getJSON()
Alternate:
Read
jQuery.load()
assuming you really want to do something like here: http://powerwall.msnbc.msn.com/
I guess they are using a combination of ajax-requests and something like this: http://tkyk.github.com/jquery-history-plugin/
make shure that the navigation (all links, etc.) in the box works via ajax - check all the links and give them new functionality by js. you can write some function which requests the href url via ajax and then replace the content of your box. ...
function change_box_links(output_area){
output_area.find('a').each(function(){
$(this).bind('click', function(e){
e.preventDefault();
var url = $(this).attr('href');
$.ajax({
url: url,
success: function(data){
output_area.html(data);
//update url in addressbar
change_box_links(output_area);
}
});
});
});
}
it is upgradeable but shell show the main idea...
addendum[2011-05-15]
Get away from thinking you will have two files, that can handle some many "boxes". i mean you can do this but it's worth it.
but to be able to set up your templates like normal html page you could use the above script to parse the ajax requested html pages.
build your html-pages for
viewing the content,
viewing the search result
, etc.
on your main page you have to provide some "box" where you can display what u need. i recommand a div:
<div id="yourbox"></div>
your main page has buttons to display that box with different content, like in the example page you have showed us. if you click one of those a JS will create an ajax call to the desired page:
(here with jquery)
$('#showsearch_button').bind('click', function(){showsearch();});
function show_search() {
$.ajax({
url: 'search.php',
success: function(data){
var output_area = $('#yourbox');
output_area.html(data);
$.address.hash('search');
change_box_links(output_area);
}
});
});
for other buttons you will have similar functions.
the first function (see above) provides that the requested box-content can be written as a normal html page (so you can call it as stand-alone as well). here is the update of it where it also provides the hashtag url changes:
jquery and requireing the history-plugin
function change_box_links(output_area){
output_area.find('a').each(function(){
$(this).bind('click', function(e){
e.preventDefault();
var url = $(this).attr('href');
$.ajax({
url: url,
success: function(data){
output_area.html(data);
var name = url.replace('/\.php/','');
$.address.hash(name);
change_box_links(output_area);
}
});
});
});
}
and you will need some kind of this function, which will bind the back and forward buttons of your browser:
$.address.change(function(event) {
var name = $.address.hash();
switch(name){
case 'search': show_search(); break;
default: alert("page not found: "+name);
}
});
the above code should give an idea of how you can solve your problem. you will have to be very consequnt with filenames if you just copy and past this. again: it is improveable but shell show you the trick ;-)
im not sure that i fully understood what you want, but correct me if i didnt,
i think u need something like a dropdown that once the user select one item some div inside ur page show the result of another page result..
if so u can do it with jquery .load() and here is an example (no need for json)
Step 1:
Index.php
<p>
brand:<select id=jquerybrand>$jquerybrands</select><br />
Model:<select id=jquerycars></select><br />
</p>
<script type=\"text/javascript\">
$(document).ready(function(){
$('#jquerybrand').change(function(){
var value=$(this).value;
var url='api/quick.php?'+this.id+'='+this.value+' option';
$('#jquerycars').load(url);
});
});
</script>
This will simply show 2 dowpdown boxs (can be text or anything u like). and will add a listener to any change in value. once changed it will submit the id of the field and the new value to api/quick.php , then quick.php responce will be loaded into #jquerycars dropdown.
Step 2 quick.php
if(isset($_GET['jquerybrand'])){
$jquerycars="";
require_once("../lib/database.php");
$sql_db = new database();
$l=$sql_db->Item_in_table("car","sheet1","WHERE `brand`='$jquerybrand';");
foreach($l as $l)$jquerycars .="<option>$l</option>";
echo $jquerycars;//response that will replace the old #jquerycars
}
this will confirm that this is a request to get the query result only, then it will do the query and echo the results.
now once the results come back it will replace the old :)
hope it helps :).
I'm building a website which has a page that users can add content to, and they can rearrange the divs to whichever position and size they want. I'd like to have a save button which saves the current position of each div; however, I don't want the page to refresh each time (I'm also going to have an auto-save, which will have to save the information in the background).
I can't figure out how to post the data to the server though, without causing the page to reload. I figure I need some kind of AJAX request, but can't find anything that tells me how to do that (all the AJAX examples I can find seem to be about reading data from the server). I think I'm just starting to go round in circles now, but I can't get my head around this at all - I know it's probably not a hard thing to do, but I keep getting confused by the different examples.
So, first of all, is this the best way to do it? And, if so, can someone point me to a straightforward example of posting data via AJAX? I'm already using jQuery, so can use that for the Ajax as well.
Thanks.
Super simple AJAX with jQuery:
$.ajax({
url: '/save-the-stuff-url',
type: 'POST',
data: {
// information about your divs, etc.
'foo' : 'bar'
},
success: function(response) {
// if the AJAX call completes successfully, this function will get called.
alert('POST successful!');
}
});
Give it a shot!
Here, try this for AJAX:
$.post("example.php", {
from : "ajax", // put some info in these - they are the params
time : "2pm",
data : "save"
},
function(data) { // callback function - data always passed to it
$("#success").html(data); // do something with that data
}
);
And put this somewhere:
<span id='success'></span>
And then, try this example for example.php:
<?php
if(isset($_POST['from']) and $_POST['from'] == 'ajax'){
echo "<span style='color: green;'>Saved!</span>";
}
else {
echo "<span style='color: red;'>Failure!</span>";
}
?>
And then just modify these to fit your needs, probably changing the file of target. Whatever the script outputs is what is given to the ajax request. This means that if this was my PHP script:
<?php echo "Aloha!"; ?>
And this was my javascript:
$("#output").load("myScript.php");
Then #output would have "Aloha!" in it.
Hope this helps!
Please go through the Jquery site for various examples of post.
HTH
and the jQuery docs pages are a great way to learn jQuery.. the page for post is http://docs.jquery.com/Post
you may also want to look at jQuery draggables if you're not using that yet..
http://docs.jquery.com/UI/API/1.8/Draggable
you can fire a save tied to your draggable object being let go rather easily with
$( ".selector" ).draggable({
stop: function(event, ui) { ... }
});
I have a function which loads some content when executed...
IE...
function load_product(product_id) {
$.ajax({
type: 'GET',
url: 'product_image.php',
data: 'product_id='+product_id+'',
success: function(data) {
$('#product_image').html(data);
}
});
}
That works great. But say I want to create a link to a page, so that then something triggers to load up the dynamic content?
IE I link to a page, say
www.blah.com/?product=1
and a few 'divs' on the page that load up different things dynamically for product #1.
The way I currently do it is by doing something:
<?php
if($_REQUEST['product_id']) {
echo '
<script type="text/javascript">
$(document).ready(function(){
load_product(' . $_REQUEST['product_id'] . ');
});
</script>
';
}
And I put that somewhere on the new page being loaded. It works. But is there a better way?
I do something similar but using YepNope.js.
<script>
var hasProduct = <?php echo isset($_REQUEST['product']) ? 'true' : 'false' ?>
yepnope({
test : hasProduct,
yep : 'js_file_to_load.js',
});
</script>
Then you can store all you main js in an external file. This has the added advantage over your method in that, I don't have to load the external scripts for every request just in case $_REQUEST['product'] is set.
You can do this all in JavaScript.
Use 'location.search' to give you the query part of the current URL...
for example, if the url is "www.blah.com/?product=1" then location.search returns "?product=1". Then you can just use split('=') to get part number. Of course, you can also just get the whole URL using 'location.href'... doesn't really matter.
var productNum = parseInt(location.search.split('=')[1]);
You would probably want more checks in there, but that's the basic idea.