We currently search through a form for contacts, and AJAX is used to display the results from a PHP file below the form (on the same page). The form's onsubmit attribute includes a return:false value to allow the AJAX code to complete.
The results appear 'below the fold' and I'd like the focus to jump down to an ID (#peopleResults) but can't manage this; instead, it stays at the top of the parent page.
Should I be trying something in the actual PHP file or in the AJAX call (to the PHP file) to achieve this?
I already tried <script>window.location.hash = "peopleResults";</script> in the PHP file and referencing results.php#peopleResults in the AJAX call, but neither worked.
Is this possible? I guess I am trying to do the equivalent of appending #peopleResults to the URL upon pressing Submit (without the URL necessary changing)...
I already tried <script>window.location.hash = "peopleResults";</script>
location.hash includes the # – both when reading from it, as well when you set a new value.
So
window.location.hash = "#peopleResults"
would be the correct way to tell the browser to jump to an element with the ID (or anchor name) peopleResults.
I think you want to achieve this please check the fiddle.
This is done without using hash. As you just want to view the result after Ajax.
By this you don't need to change the URL.
Based on the reply to my comment, it would seem you're a little foggy on the AJAX portion too. From the documentation:
$.ajax({
url: "http://fiddle.jshell.net/favicon.png",
beforeSend: function( xhr ) {
xhr.overrideMimeType( "text/plain; charset=x-user-defined" );
}
})
.done(function( data ) {
if ( console && console.log ) {
//this is where you need to add your data to the div
//after the data is in the div, scroll to it.
console.log( "Sample of data:", data.slice( 0, 100 ) );
}
});
You can see, the function where I added the comments is where you need to do the scrolling. After you populate the div (how ever you're doing that), then just use the suggestion Learner Student or phpisuber01 made of scrolling to it:
$("html, body").animate({ scrollTop: $("#peopleResults").scrollTop() }, 1000);
jQuery AJAX documentation: https://api.jquery.com/jQuery.ajax/
jQuery scrollTop documentation: https://api.jquery.com/scrollTop/
Related
I know this has been asked on SO a lot, but I have trawled through the posts for a few hours now and nothing works.
I'm working on a Wordpress blog where the prev/next buttons on a single post page have to load the prev/next post by Ajax. I have written the code (jQuery Ajax) all fine (I think - if you want to improve it, be my guest!), but in each post there a few bits of jQuery that need to work. However, after I click either of the prev/next buttons to move between posts, the jQuery won't work (it works absolutely perfectly when the page is first loaded). I know this is due to the content not being 'connected' to the JS anymore but I'm not sure what to do about it.
Here is my code:
$(".page-feed").on('click', '.post-nav>a', function() {
event.preventDefault ? event.preventDefault() : event.returnValue = false;
var link = $(this).attr('href'); // get the value of the href attribute on the links
$(".post-content").html("Loading...");
$.get(link, function(result) {
$result = $(result);
$content = $result.find(".post-content");
$(".post-content").replaceWith($content);
}, 'html');
});
I know that you're probably going to ask what I've already tried, but if I'm honest, not a lot that would be worth putting here.
The code above is located right at the top of a file called script.js, with all the other JS below it (which doesn't currently work after the Ajax call). The script is started by the standard $(document).ready(function() { statement.
Thanks for any help :)
First, you need to accept the event object as an argument.
$(".page-feed").on('click', '.post-nav>a', function(event) {
Next, by using the jQuery event object, you can simplify the next line because event is normalized by jQuery to work cross-browser.
event.preventDefault();
Now, as far as it working on the first click but not after, that's likely because .page-feed is a dynamic element. You'll need to instead select an element that is an ancestor of .post-content. document is a decent replacement, but it would be better if you picked one more local.
$(document).on('click', '.post-nav>a', function(event) {
I'm using the code below to load the results from a database query in a PHP page:
click me
$('.item > a').click(function(){
var url = $(this).attr('href');
$('.item-popup').fadeIn('slow');
$('.item-content').load(url);
return false;
});
All works fine right now, but the next bit of functionality is a problem. Inside results.php which ajax loads into .item-content, I have another link that is supposed to update and increment click counts for that link, also without refreshing. The functional PHP bits all work fine. My only problem is the jQuery/AJAX aspect of things.
Maybe I'm going about it the wrong way, but what I really want to do is have a page with a container that loads the result of of a database query from a PHP page, but also in that container, I have a link/button whose click count I want to be able to save and update all without refreshing.
EDIT
I guess the most important question I need answering is: When the ajax on index.php loads the content of results.php into the container in index.php, do browsers treat the newly loaded ajax content as part of the parent page (index.php) or is it still treated as a different page loaded into the container like an iFrame?
If say for example it is click event then you need to write
$('input element').on('click',function() {
// write code over here
})
Dont know for sure if you want this, When returning the data in the load function you will have to add a link like this in the resultant HTML which will be clickable:
Now in javascript you need to catch the click event of the link like this:
<script type="text/javascript">
$(function(){
$(".item-content").on("click", ".clickable", function(){
var counter = $(this).data('counter');
var id = $(this).data('id');
$.ajax({
url : //your url here,
data : {'id' : id, 'counter' : counter },
type : 'POST',
success : function(resp){
//update the counter of the current link
$(this).data('counter', parseInt( $(this).data('counter') )+1 );
//whatever here on successfull calling of ajax request
},
error : function(resp){
}
});
});
});
</script>
The below is my code. Div id jp_current_track_title changes automatically when other events occur. I am trying to capture whats gets into the div "Track_title and post it onchange to like.php. as of now i cant figure it out. Im getting something back into the result div but its not posting. What am i doing wrong?
$(document).ready(function() {
$('#track_title').change(function() {
var content = $('#track_title').html();
$.ajax({
url: 'like.php',
type: 'POST',
success: function(info){ $("#result").html(info)
},
data: {
content: content,
}
});
});
});
Instead of detecting changes in jp_current_track_title, can you capture the other events that caused the update to jp_current_track_title? If so, can you get the updated title from there?
You aren't going to get 'change' events when the contents of a div change, it doesn't work like that.
See here:
Fire jQuery event on div change
The main answer mentions how you can track DOMNodeInserted / DOMNodeRemoved / DOMSubtreeModified events, however those don't work in IE.
Your best bet is to use setTimeout() and check the innerHTML of the div on regular intervals to see if the value has changed.
My PHP page
<ul id="upvote-the-image">
<li>Upvote<img src="image.png" /></li>
</ul>
is currently successfully sending variable to javascript
$("#upvote").each(function(index) {
var upthis = $(this).attr("rel");
var plusone = upthis;
$.post("upvote.php", {
'plusone': plusone
});
alert(plusone);
});
(The alert in the code is for testing)
I have multiple images using the rel tag. I would like for each to be able to be upvoted and shown that they are upvoted on the page without loading a new page.
My question, and problem: what is my next step? I would just like to know how to send a value to upvote.php. I know how touse mysql to add an upvote, just not how to send a value to upvote.php, or even if my javascript code opens the page correctly.
thanks
I think you need something like this:
<ul id="upvote-the-image">
<li><span rel="50" id="upvote">Upvote</span><img src="image.png" /></li>
</ul>
<span id="result"></span>
$("#upvote").click(function(index) {
var upthis = $(this).attr("rel");
var oOptions = {
url: upvote.php, //the receiving data page
data: upthis, //the data to the server
complete: function() { $('#result').text('Thanks!') } //the result on the page
};
$.ajax(oOptions);
}
You dont need an anchor, I changed it for a span, you can test asyc connection using F12 in your browser
Your javascript never opens the php page, it just sends data to it, and receives an http header with a response. Your php script should be watching for $_POST['plusone'] and handle database processing accordingly. Your next step would be to write a callback within your $.post function, which I recommend changing to the full ajax function while learning, as it's easier to understand and see all the pieces of what's happening.
$.ajax({
type: 'POST',
url: "upvote.php",
data: {'plusone': plusone},
success: function(IDofSelectedImg){
//function to increment the rel value in the image that was clicked
$(IDofSelectedImg).attr("rel")= upthis +1;
},
});
You'd need some unique identifier for each img element in order to select it, and send it's id to the php script. add a class instead of id for upvote and make the id a uniquely identifiable number that you could target with jquery when you need to increment the rel value. (From the looks of it, It looks like you're putting the value from the rel attribute into the database in the place of the old value.)
A good programming tip here for JQuery, Don't do:
<a href="javascript:return false;"
Instead do something like:
$(function(){
$('#upvote').on('click', function(event){
event.preventDefault();
$.post('upvote.php', {'plusone': $(this).attr('rel')}, function(data){
alert('done and upvoted');
});
});
});
That is a much better way to handle links on your DOM document.
Here are some Doc pages for you to read about that coding I use:
http://api.jquery.com/on/
http://api.jquery.com/jQuery.post/
Those will explain my code to you.
Hope it helps,
Finally, I find some article in http://code.google.com/intl/en/web/ajaxcrawling/docs/getting-started.html msnbc use this method. Thanks for all the friends.
Thanks for your all help. I will study it for myself :-}
Today, I updated my question again, remove all of my code. Maybe my thinking all wrong.
I want make a products show page.
One is index.php, another is search.php (as a jquery box page). index.php has some products catagory lists; each click on product catagory item will pass each value to search.php. search.php will create a mysql query and view products details. It(search.php) also has a search box.(search.php can turn a page to show multiple products; the search result looks similar to a jQuery gallery...).
I need to do any thing in search.php but without refreshing index.php.
I tried many method while I was thinking: Make search.php as an iframe (but can not judge search.php height when it turn page and index.php without refresh); use jquery ajax/json pass value from index.php to search.php, then get back all page's value to index.php. (still met some url rule trouble. php depend on url pass values in search.php, but if the value change, the two page will refresh all. )
so. I think, ask, find, try...
Accidental, I find a site like my request.
in this url, change search word after %3D, only the box page refresh
in this url, change search word after = the page will refresh
I found somthing in its source code, is this the key rules?
<script type="text/javascript">
var fastReplace = function() {
var href = document.location.href;
var siteUrl = window.location.port ? window.location.protocol+'//'+window.location.hostname +':'+window.location.port : window.location.protocol+'//'+window.location.hostname;
var delimiter = href.indexOf('#!') !== -1 ? '#!wallState=' : '#wallState=';
var pieces = href.split(delimiter);
if ( pieces[1] ) {
var pieces2 = pieces[1].split('__');
if ( pieces2[1] && pieces2[1].length > 1) {
window.location.replace( unescape(pieces2[1].replace(/\+/g, " ")));
}
}
}();
</script>
If so. in my condition. one page is index.php. another is search.php.
How to use js make a search url like
index.php#search.php?word=XXX&page=XXX
then how to pass value from one to another and avoid refreshing index.php?
Still waiting for help, waiting for some simple working code, only js, pass value get value.
Thanks to all.
I have read your problem, though I can not write complete code for you (lack of time ) So I can suggest you to what to do for your best practice
use dataType ='json' in jQuery.ajax function and
write json_encode() on B.php
and json_decode() on A.php or $.getJSON()
Alternate:
Read
jQuery.load()
assuming you really want to do something like here: http://powerwall.msnbc.msn.com/
I guess they are using a combination of ajax-requests and something like this: http://tkyk.github.com/jquery-history-plugin/
make shure that the navigation (all links, etc.) in the box works via ajax - check all the links and give them new functionality by js. you can write some function which requests the href url via ajax and then replace the content of your box. ...
function change_box_links(output_area){
output_area.find('a').each(function(){
$(this).bind('click', function(e){
e.preventDefault();
var url = $(this).attr('href');
$.ajax({
url: url,
success: function(data){
output_area.html(data);
//update url in addressbar
change_box_links(output_area);
}
});
});
});
}
it is upgradeable but shell show the main idea...
addendum[2011-05-15]
Get away from thinking you will have two files, that can handle some many "boxes". i mean you can do this but it's worth it.
but to be able to set up your templates like normal html page you could use the above script to parse the ajax requested html pages.
build your html-pages for
viewing the content,
viewing the search result
, etc.
on your main page you have to provide some "box" where you can display what u need. i recommand a div:
<div id="yourbox"></div>
your main page has buttons to display that box with different content, like in the example page you have showed us. if you click one of those a JS will create an ajax call to the desired page:
(here with jquery)
$('#showsearch_button').bind('click', function(){showsearch();});
function show_search() {
$.ajax({
url: 'search.php',
success: function(data){
var output_area = $('#yourbox');
output_area.html(data);
$.address.hash('search');
change_box_links(output_area);
}
});
});
for other buttons you will have similar functions.
the first function (see above) provides that the requested box-content can be written as a normal html page (so you can call it as stand-alone as well). here is the update of it where it also provides the hashtag url changes:
jquery and requireing the history-plugin
function change_box_links(output_area){
output_area.find('a').each(function(){
$(this).bind('click', function(e){
e.preventDefault();
var url = $(this).attr('href');
$.ajax({
url: url,
success: function(data){
output_area.html(data);
var name = url.replace('/\.php/','');
$.address.hash(name);
change_box_links(output_area);
}
});
});
});
}
and you will need some kind of this function, which will bind the back and forward buttons of your browser:
$.address.change(function(event) {
var name = $.address.hash();
switch(name){
case 'search': show_search(); break;
default: alert("page not found: "+name);
}
});
the above code should give an idea of how you can solve your problem. you will have to be very consequnt with filenames if you just copy and past this. again: it is improveable but shell show you the trick ;-)
im not sure that i fully understood what you want, but correct me if i didnt,
i think u need something like a dropdown that once the user select one item some div inside ur page show the result of another page result..
if so u can do it with jquery .load() and here is an example (no need for json)
Step 1:
Index.php
<p>
brand:<select id=jquerybrand>$jquerybrands</select><br />
Model:<select id=jquerycars></select><br />
</p>
<script type=\"text/javascript\">
$(document).ready(function(){
$('#jquerybrand').change(function(){
var value=$(this).value;
var url='api/quick.php?'+this.id+'='+this.value+' option';
$('#jquerycars').load(url);
});
});
</script>
This will simply show 2 dowpdown boxs (can be text or anything u like). and will add a listener to any change in value. once changed it will submit the id of the field and the new value to api/quick.php , then quick.php responce will be loaded into #jquerycars dropdown.
Step 2 quick.php
if(isset($_GET['jquerybrand'])){
$jquerycars="";
require_once("../lib/database.php");
$sql_db = new database();
$l=$sql_db->Item_in_table("car","sheet1","WHERE `brand`='$jquerybrand';");
foreach($l as $l)$jquerycars .="<option>$l</option>";
echo $jquerycars;//response that will replace the old #jquerycars
}
this will confirm that this is a request to get the query result only, then it will do the query and echo the results.
now once the results come back it will replace the old :)
hope it helps :).