RegEx for hashtag separated string - php

I have bunch of strings like this:
a#aax1aay222b#bbx4bby555bbz6c#mmm1d#ara1e#abc
And what I need to do is to split them up based on the hashtag position to something like this:
Array
(
[0] => A
[1] => AAX1AAY222
[2] => B
[3] => BBX4BBY555BBZ6
[4] => C
[5] => MMM1
[6] => D
[7] => ARA1
[8] => E
[9] => ABC
)
So, as you see the character right behind the hashtag is captured plus everything after the hashtag just right before the next char+hashtag.
I've the following RegEx which works fine only when I have a numeric value in the end of each part.
Here is the RegEx set up:
preg_split('/([A-Z])+#/', $text, 0, PREG_SPLIT_NO_EMPTY | PREG_SPLIT_DELIM_CAPTURE);
And it works fine with something like this:
C#mmm1D#ara1
But, if I change it to this (removing the numbers):
C#mmmD#ara
Then it will be the result, which is not good:
Array
(
[0] => C
[1] => D
)
I've looked at this question and this one also, which are similar but none of them worked for me.
So, my question is why does it work only if it has followed by a number? and how I can solve it?
Here you can see some of them sample strings which I have:
a#123b#abcc#def456 // A:123, B:ABC, C:DEF456
a#abc1def2efg3b#abcdefc#8 // A:ABC1DEF2EFG3, B:ABCDEF, C:8
a#abcdef123b#5c#xyz789 // A:ABCDEF123, B:5, C:XYZ789
P.S. Strings are case-insensitive.
P.P.S. If you ever thinking what the hell are these strings, they are user submitted answers to a questionnaire, and I can't do anything on them like refactoring as they are already stored and just need to be proceed.
Why Not Using explode?
If you look at my examples you will see that I need to capture the character right before the # as well. If you think it's possible with explode() please post the output as well, thanks!
Update
Should we focus on why /([A-Z])+#/ works only if numbers included? thanks.

Instead of using preg_split(), decide what you want to match instead:
A set of "words" if followed by either <any-char># or <end-of-string>.
A character if immediately followed by #.
$str = 'a#aax1aay222b#bbx4bby555bbz6c#mmm1d#ara1e#abc';
preg_match_all('/\w+(?=.#|$)|\w(?=#)/', $str, $matches);
Demo
This expression uses two look-ahead assertions. The results are in $matches[0].
Update
Another way of looking at it would be this:
preg_match_all('/(\w)#(\w+)(?=\w#|$)/', $str, $matches);
print_r(array_combine($matches[1], $matches[2]));
Each entry starts with a single character, followed by a hash, followed by X characters until either the end of the string is encountered or the start of a next entry.
The output is this:
Array
(
[a] => aax1aay222
[b] => bbx4bby555bbz6
[c] => mmm1
[d] => ara1
[e] => abc
)

If you still want to use preg_split you can remove the + and it might work as expected:
'/([A-Z])#/i'
Since then you only match the hashtag and ONE alpha character before, and not all them.
Example: http://codepad.viper-7.com/z1kFDb
Edit: Added a case-insensitive flag i in the pattern.

Use explode() rather than Regexp
$tmpArray = explode("#","a#aax1aay222b#bbx4bby555bbz6c#mmm1d#ara1e#abc");
$myArray = array();
for($i = 0; $i < count($tmpArray) - 1; $i++) {
if (substr($tmpArray[$i],0,-1)) $myArray[] = substr($tmpArray[$i],0,-1);
if (substr($tmpArray[$i],-1)) $myArray[] = substr($tmpArray[$i],-1);
}
if (count($tmpArray) && $tmpArray[count($tmpArray) - 1]) $myArray[] = $tmpArray[count($tmpArray) - 1];
edit: I updated my answer to reflect better reading the questions

You can use explode() function that will split the string except the hash signs, like stated in the answers given before.
$myArray = explode("#",$string);
For the string 'a#aax1aay222b#bbx4bby555bbz6c#mmm1d#ara1e#abc' this returns something like
$myarray = array('a', 'aax1aay22b', 'bbx4bby555bbz6c' ....);
All you need now is to take the last character of each string in array as another item.
$copy = array();
foreach($myArray as $item){
$beginning = substr($item,0,strlen($item)-1); // this takes all characters except the last one
$ending = substr($item,-1); // this takes the last one
$copy[] = $beginning;
$copy[] = $ending;
} // end foreach
This is an example, not tested.
EDIT
Instead of substr($item,0,strlen($item)-1); you might use substr($item,0,-1);.

Related

Extract multiples strings from one variable by using preg_match

I'm having troubles extracting several strings between tags from a variable, in order to echo them inside a span individually.
Thing is, the tags in question are determined by a variable, here is what it looks like :
<?php
$string = "[en_UK]english1[/en_UK][en_UK]english2[/en_UK][fr_FR]francais1[/fr_FR][fr_FR]francais2[/fr_FR][fr_FR]francais3[/fr_FR]";
$lang = "en_UK";
preg_match("/(.[$lang]), (.[\/$lang])/", $string, $outputs_list);
foreach ($outputs_list as $output) {
echo "<span>".$output."/span>";
}
// in this exemple I want to output :
// <span>english1</span>
// <span>english2</span>
?>
It's my first time using preg_match and after trying so many differents things I'm kinda lost right now.
Basically I want to extract every strings contained between the tags [$lang] and [/$lang] (in my exemple $lang = "en_UK" but it will be determined by the user's cookies.
I'd like some help figuring this out if possible,
Thanks
[] in a regular expression makes a character class. I'm not sure what you're trying to do with the .s and , either. Your regex currently says:
Any single character, an e, n, _, U, or K, a , and space, and again any single character, an e, n, _, U, K, but this time also allowing /.
Regex demo: https://regex101.com/r/8pmy89/2
I also believe you were grouping the wrong value. The () go around what you want to capture, know as a capture group.
I think the regex you want is:
\[$lang\](.+?)\[\/$lang\]
Regex demo: https://regex101.com/r/8pmy89/3
PHP Usage:
$string = "[en_UK]english1[/en_UK][en_UK]english2[/en_UK][fr_FR]francais1[/fr_FR][fr_FR]francais2[/fr_FR][fr_FR]francais3[/fr_FR]";
$lang = "en_UK";
preg_match_all("/\[$lang\](.+?)\[\/$lang\]/", $string, $outputs_list);
foreach ($outputs_list[1] as $output) {
echo "<span>".$output."/span>";
}
PHP demo: https://eval.in/686086
Preg_match vs. preg_match_all
Preg_match only returns the first match(es) of a regex. Preg_match_all returns all matches of the regex. The 0 index has what the full regex matched. All subsequent indexes are each capture groups, e.g. 1 is the first capture group.
Simple Demo: https://eval.in/686116
$string = '12345';
preg_match('/(\d)/', $string, $match);
print_r($match);
preg_match_all('/(\d)/', $string, $match);
print_r($match);
Output:
Array
(
[0] => 1
[1] => 1
)
^ is preg_match, below is the preg_match_all
Array
(
[0] => Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 4
[4] => 5
)
[1] => Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 4
[4] => 5
)
)
I made little late to post this answer. #chris already answered your question, so i made the solution broad which might help other users who may have different requirements.
<?php
$string = "[en_UK]english1[/en_UK][en_UK]english2[/en_UK][fr_FR]francais1[/fr_FR][fr_FR]francais2[/fr_FR][fr_FR]francais3[/fr_FR]";
$lang = "en_UK";
echo "User Language -";
preg_match_all("/\[$lang\](.+?)\[\/$lang\]/", $string, $outputs_list);
foreach ($outputs_list[1] as $output) {
echo "<span>".$output.",</span>";
}
echo "<br/>All languages - ";
//if all lang
preg_match_all("/[a-zA-Z0-9]{3,}/", $string, $outputs_list);
foreach ($outputs_list[0] as $output) {
echo "<span>".$output.",</span>";
}
echo "<br/>Type of lang - ";
//for showing all type of lang
preg_match_all("/(\[[a-zA-Z_]+\])*/", $string, $outputs_list);
foreach ($outputs_list[1] as $output) {
echo "<span>".$output."</span>";
}
?>
OUTPUT
User Language -english1,english2,
All languages - english1,english2,francais1,francais2,francais3,
Type of lang - [en_UK][en_UK][fr_FR][fr_FR][fr_FR]

How to numerically sort an array like this: ['11--2017 name.png','1--2016 name.png','2--1999 name.png']

Am I correct that character precedence would order these like this:
1--2016 name.png, 11--2017 name.png, 2--1999 name.png
Numerically, however, they would be like this:
1--2016 name.png, 2--1999 name.png, 11--2017 name.png
That is, if I'm looking at the first numbers alone. How do you numerically sort an array with strings like this? Namely, integers appended with "--".
It's important to note that these "strings" are actually pathnames which cannot be renamed. See glob for more information.
Edit, after modified question:
After your edit, obviously all answers in this thread are wrong. Also, you don't have to only copy-and-paste a piece of code, but to read entire answer. Sure enough, in my original answer, I say:
if you have a value like “12--3”, it will be sorted like “123”
So, you could see right away that your real case is not coherent with provided sample.
This second solution will sort an array by number at start of given basename path followed by two dashes. It will be applicable on following cases:
String Will be sorted by
------------------------------ -----------------
/Absolute/Path/12-- 12
/Absolute/Path/12--2001.png 12
/12--2001.png 12
12--2001.png 12
a12--2001.png a12--2001.png
-12--2001.png -12--2001.png
Having this array:
[
'/path/to/image/1--2016 name.png',
'/path/to/image/11--2017.png',
'/path/to/image/2--1999.png'
]
You can replace regular expression patter of above original solution with this pattern:
~^(.*/)?(\d+)--[^/]*$~
And above array will be sorted in this way:
Array
(
[0] => /path/to/image/1--2016 name.png
[1] => /path/to/image/2--1999.png
[2] => /path/to/image/11--2017.png
)
eval.in demo
Pattern explanation:
~
^ # Start of string
(.*/)? # Group 1 (optional): zero-ore-more characters followed by a slash
(\d+) # Group 2: one-or-more digits
-- # two dashes
[^/]* # zero-or-more characters, except slash
$ # End of string
~
In the future, take a look at How to create a Minimal, Complete, and Verifiable example
Original answer (for original question):
There are surely many ways to obtain your result. Using usort and preg_replace:
$array = ['11--','23--','1--'];
usort
(
$array,
function( $a, $b )
{
return preg_replace( '~[^\d]~', '', $a ) - preg_replace( '~[^\d]~', '', $b );
}
);
$array now is:
Array
(
[0] => 1--
[1] => 11--
[2] => 23--
)
Above solution will sort your array deleting1 all not digits characters.
So, if you have a value like 12--3, it will be sorted like 123. Consequently, it doesn't work on not-integer or negative numbers.
1 Actually, the original array values are not changed.
If you wanted a quick fix to getting this done, you could:
$strings = array('5--', '2--', '11--');
$newStrings = array();
foreach ($strings as $string) {
$stringNew = str_replace('--', '', $string);
array_push($newStrings, $stringNew);
}
sort($newStrings);
$doneArray = array();
foreach ($newStrings as $newString) {
array_push($doneArray, $newString.'--');
}
// $doneArray is the new array full of the sorted strings.
I didn't really bother with the variable names, but that's a nice way to do it.
natsort
See here.
I'm not sure how glob sorts things as they come in, but I thought that sort would have ordered them correctly, but natsort will do the trick.

preg match to get text after # symbol and before next space using php

I need help to find out the strings from a text which starts with # and till the next immediate space by preg_match in php
Ex : I want to get #string from this line as separate.
In this example, I need to extract "#string" alone from this line.
Could any body help me to find out the solutions for this.
Thanks in advance!
PHP and Python are not the same in regard to searches. If you've already used a function like strip_tags on your capture, then something like this might work better than the Python example provided in one of the other answers since we can also use look-around assertions.
<?php
$string = <<<EOT
I want to get #string from this line as separate.
In this example, I need to extract "#string" alone from this line.
#maybe the username is at the front.
Or it could be at the end #whynot, right!
dog#cat.com would be an e-mail address and should not match.
EOT;
echo $string."<br>";
preg_match_all('~(?<=[\s])#[^\s.,!?]+~',$string,$matches);
print_r($matches);
?>
Output results
Array
(
[0] => Array
(
[0] => #string
[1] => #maybe
[2] => #whynot
)
)
Update
If you're pulling straight from the HTML stream itself, looking at the Twitter HTML it's formatted like this however:
<s>#</s><b>UserName</b>
So to match a username from the html stream you would match with the following:
<?php
$string = <<<EOT
<s>#</s><b>Nancy</b> what are you on about?
I want to get <s>#</s><b>string</b> from this line as separate. In this example, I need to extract "#string" alone from this line.
<s>#</s><b>maybe</b> the username is at the front.
Or it could be at the end <s>#</s><b>WhyNot</b>, right!
dog#cat.com would be an e-mail address and should not match.
EOT;
$matchpattern = '~(<s>(#)</s><b\>([^<]+)</b>)~';
preg_match_all($matchpattern,$string,$matches);
$users = array();
foreach ($matches[0] as $username){
$cleanUsername = strip_tags($username);
$users[]=$cleanUsername;
}
print_r($users);
Output
Array
(
[0] => #Nancy
[1] => #string
[2] => #maybe
[3] => #WhyNot
)
Just do simply:
preg_match('/#\S+/', $string, $matches);
The result is in $matches[0]

PHP Parsing text to extract two numbers

The text is similar to this: +1191–1405 Holy Damage The numbers can change as well as the Damage type. Like +777-1444 Fire Damage ect.
What I want to do is extract the two numbers. So from the first example I want 1191 and 1405 and I need them to be integers not strings.
I've read up on preg_ stuff and such a bit and can do simple searches and parsing but i'm not quite at this level. I'm guessing I need to extract whatever numbers that are after + but before -, and after - discarding everything else.
Use this:
preg_match('/\+(\d+)-(\d+)/', $text, $match);
Now $match[1] contains the first number, $match[2] contains the second number.
Because I hate pattern matching and avoid it whenever possible:
function getNumbersFromString($str){
$splt = explode(' ', $str); // split by spaces
$sub = substr($splt[0], 1); // get rid of leading +
return explode('-', $sub); // return split by -
}
// Array ( [0] => 777 [1] => 1444 )
print_r(getNumbersFromString('+777-1444 Fire Damage'));
// Array ( [0] => 1191 [1] => 1405 )
print_r(getNumbersFromString('+1191-1405 Holy Damage'));

Adding Character between numbers

I have an integer $client_version=1000 I do need to add dots between every number in this integer so it looks like 1.0.0.0 and save it in new variable as string.
How can I do this?
Easy enough:
$client_version = 1000;
$dotted = join(".",str_split($client_version));
Note that this will always split it so that there is only one character between the dots. If you want something like 1.00.0, you'll need to change your question to explain more about what you're trying to do and what patterns you need.
PHP offers the function array str_split ( string $string [, int $split_length = 1 ] ) to convert a string to a character-array or blocks of characters.
In your case, invoking str_split((string)1000, 1) or str_split((string)1000) will result in:
Array
(
[0] => 1
[1] => 0
[2] => 0
[3] => 0
)
Code:
implode('.',str_split((string)1000))
Result: 1.0.0.0
For a more general, yet less well known approach, based on Regular Expression see this gist and this tangentially related topic on SO.
Code:
preg_match_all('/(.{1})/', (string)1000, $matches);
echo implode('.', $matches[0]);
Result: 1.0.0.0
Use str_split to get an array of chars and then implode them.
$client_version = 1000;
$client_version_chars = str_split($client_version);
$client_version_with_dots = implode('.', $client_version_chars);

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