I have MAMP (local hosted SQL,WEB etc server) the database name is :NKTDEBITS the table name is :Insurance and the column on the table is STATECOV. I know I'm close with this but still get a black in the field that should generate the total, anyone got a idea?
<?php
$con=mysqli_connect("localhost","root","root","KNTDebits");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM Insurance");
$result2 = mysqli_query($con,"SELECT * FROM Office");
$result3 = mysqli_query($con,"SELECT * FROM RichmondLocation");
$result4 = mysqli_query($con,"SELECT * FROM DanvilleLocation");
$result5 = mysql_query('SELECT SUM(STATECOV) AS STATECOV_sum FROM Insurance');
echo "<table border='1'>
<tr>
<th>Truck Number</th>
<th>VIN</th>
<th>Make</th>
<th>Model</th>
<th>State Coverage</th>
<th>Comprehinsive Coverage</th>
<th>Property Damage/th>
<th>Personal Injury</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['TNUM'] . "</td>";
echo "<td>" . $row['VIN'] . "</td>";
echo "<td>" . $row['MAKE'] . "</td>";
echo "<td>" . $row['MODEL'] . "</td>";
echo "<td>" . $row['STATECOV'] . "</td>";
echo "<td>" . $row['COMPRE'] . "</td>";
echo "<td>" . $row['PROPDMG'] . "</td>";
echo "<td>" . $row['PRSINJ'] . "</td>";
echo "</tr>";
}
echo "</table>";
//Table 2 Start
str_repeat(' ', 5); // adds 5 spaces
echo "<table border='5'>
<tr>
<th>Richmond</th>
<th>Date</th>
<th>Payment</th>
<th>Payer</th>
</tr>";
while($row3 = mysqli_fetch_array($result3))
{
echo "<tr>";
echo "<td>" . $row3[''] . "</td>";
echo "<td>" . $row3['DATE'] . "</td>";
echo "<td>" . $row3['PAYMENT'] . "</td>";
echo "<td>" . $row3['PAYER'] . "</td>";
echo "</tr>";
}
echo "</table>";
//Table 4 Start
str_repeat(' ', 5); // adds 5 spaces
echo "<table border='5'>
<tr>
<th>Danville</th>
<th>Date</th>
<th>Payment</th>
<th>Payer</th>
</tr>";
while($row4 = mysqli_fetch_array($result4))
{
echo "<tr>";
echo "<td>" . $row4[''] . "</td>";
echo "<td>" . $row4['DATE'] . "</td>";
echo "<td>" . $row4['PAYMENT'] . "</td>";
echo "<td>" . $sum . "</td>";
echo "</tr>";
}
echo "</table>";
//Table 5 Start
echo "<table border='5'>
<tr>
<th>Total</th>
</tr>";
$result = mysql_query('SELECT SUM(STATECOV) AS value_sum FROM Insurance');
$row = mysql_fetch_assoc($result);
$sum = $row['value_sum'];
while($row = mysql_fetch_assoc($result));
{
echo "<tr>";
echo "<td>" . $sum . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
You need a GROUP BY to go along with your SUM. I don;t know enough about you table to let you know what column you should use for this.
You should be handling potential error cases whenn you query the database, as you will quickly see when you are getting database/query errors.
You should also look to use mysqli or PDO instead of the deprecated mysql_* functions.
Related
I have the following PHP/MySql:
$sql = "SELECT * from tblDigest";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
echo "<table><tr>
<th>Diagram</th>
<th>Headcode</th>
<th>Date</th>
<th>Dep Time</th>
<th>Origin</th>
<th>Destination</th>
<th>Arr Time</th>
<th>Booked Traction</th>
<th>Actual Traction</th>
<th>Type</th>
</tr>";
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<tr>";
echo "<td>" . $row["diagram"] . "</td>";
echo "<td>" . $row["headcode"] . "</td>";
echo "<td>" . $row["depDate"] . "</td>";
echo "<td>" . $row["depTime"] . "</td>";
echo "<td>" . $row["origin"] . "</td>";
echo "<td>" . $row["destination"] . "</td>";
echo "<td>" . $row["arrTime"] . "</td>";
echo "<td>" . $row["bookedTraction"] . "</td>";
echo "<td>" . $row["actualTraction"] . "</td>";
echo "<td>" . $row["type"] . "</td>";
echo "</tr>";
}
echo "</table>";
}
I would like to group the results by 'diagram', so that I can display them as an accordion. Is there any easy way to do this?
Failing that, how can I get the value for the first row of the table (so I can have a $diagNo variable and compare $row["diagram"] against that to find out when it has changed.
Sort your results by diagram and watch when its value changes:
$sql = "SELECT * from tblDigest ORDER BY diagram";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
echo "<table><tr>
<th>Diagram</th>
<th>Headcode</th>
<th>Date</th>
<th>Dep Time</th>
<th>Origin</th>
<th>Destination</th>
<th>Arr Time</th>
<th>Booked Traction</th>
<th>Actual Traction</th>
<th>Type</th>
</tr>";
// output data of each row
$oldDiagram = '';
while($row = $result->fetch_assoc()) {
if($oldDiagram == '')
{
// this is the first diagram - create the first accordeon
$oldDiagram = $row['diagram'];
}
elseif($oldDiagram != $row['diagram'])
{
// a new group starts right now - create new accordeon
$oldDiagram = $row['diagram'];
}
echo "<tr>";
echo "<td>" . $row["diagram"] . "</td>";
echo "<td>" . $row["headcode"] . "</td>";
echo "<td>" . $row["depDate"] . "</td>";
echo "<td>" . $row["depTime"] . "</td>";
echo "<td>" . $row["origin"] . "</td>";
echo "<td>" . $row["destination"] . "</td>";
echo "<td>" . $row["arrTime"] . "</td>";
echo "<td>" . $row["bookedTraction"] . "</td>";
echo "<td>" . $row["actualTraction"] . "</td>";
echo "<td>" . $row["type"] . "</td>";
echo "</tr>";
}
echo "</table>";
}
this is my php code for sql query its giving me same value multi time
if (isset($_GET["q"]))
{
$q= $_GET["q"];
$link=mysqli_connect("localhost","root","");
mysqli_select_db($link,"onesports");
$result=mysqli_query($link,"select players.full_name, team.* from players,team where team.team_name='" .$q. " ' and players.team_name=team.team_name ");
echo "<table>
<tr>
<th>Firstname</th>
<th>Lastname</th>
<th>Age</th>
<th>Hometown</th>
<th>Job</th>
</tr>";
while($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<a href=>" . $row['full_name'] . "</a>";
echo "<td>" . $row['image'] . "</td>";
echo "<td>" . $row['team_name'] . "</td>";
echo "<td>" . $row['prov'] . "</td>";
echo "<td>" . $row['city'] . "</td>";
echo "<td>" . $row['captain'] . "</td>";
echo "<td>" . $row['coach'] . "</td>";
echo "</tr>";
}
echo "</table>";
}
else {
echo "no result found.";
}
its giving me this output
enter image description here
i want only player name and remaining value want for one time
You should use INNER JOIN in this case.
just update your code with below code.
$result = mysqli_query($link, "SELECT `players`.full_name,`team`.* FROM `players` INNER JOIN `team` ON `players`.team_name= `team`.team_name AND `team`.team_name='".$q."'");
I have written a PHP script to pull data from a SQL database to display on a webpage. Everything seems fine but when I run the script it throws the error:
Parse error: syntax error, unexpected ')', expecting ';' in db_data.php on line 21
Line 21 is my FOR loop, I have checked the syntax of the loop and it seems to be correct so I can't understand why it is failing.
$result = mysqli_query($con,"SELECT * igi");
echo "<table border='1'>
<tr>
<th>Ref</th>
<th>Nameame</th>
<th>Location</th>
<th>Email</th>
<th>Issue</th>
<th>Urgency</th>
</tr>";
for($row = mysqli_fetch_array($result)){
echo "<tr>";
echo "<td>" . $row['REF'] . "</td>";
echo "<td>" . $row['NAME'] . "</td>";
echo "<td>" . $row['LOCATION'] . "</td>";
echo "<td>" . $row['EMAIL'] . "</td>";
echo "<td>" . $row['ISSUE'] . "</td>";
echo "<td>" . $row['URGENCY'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
Change for to while
<?php
// Missing FROM here vv
$result = mysqli_query($con,"SELECT * FROM igi");
echo "<table border='1'>
<tr>
<th>Ref</th>
<th>Nameame</th>
<th>Location</th>
<th>Email</th>
<th>Issue</th>
<th>Urgency</th>
</tr>";
while($row = mysqli_fetch_array($result)){
echo "<tr>";
echo "<td>" . $row['REF'] . "</td>";
echo "<td>" . $row['NAME'] . "</td>";
echo "<td>" . $row['LOCATION'] . "</td>";
echo "<td>" . $row['EMAIL'] . "</td>";
echo "<td>" . $row['ISSUE'] . "</td>";
echo "<td>" . $row['URGENCY'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
As Anthony Thompson and RJParick says, you have to change for to while. The error you're encountering is due tu for that need 3 params like this :
for($i; $i<10; $i++) {//Note the ; used to separate params.
//do something
}
So your loop would begin like this :
while($row = mysqli_fetch_array($result)){
Another detail, your SQL isn't correct use SELECT * FROM igi instead.
i wanted to ask I would I add up the points of all the drivers in the table produced below by the following code as this only displays points of all the drivers in each row ... There is a table Points which has points, position and a table Drivers having forename, surname.
<?php
session_start();
if ( !isset($_SESSION['loggedin']) ) {
header("Location: login.php");
}
$con=mysqli_connect("xxxxx","xxxxx","xxxxx","xxxx");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT Drivers.forename, Drivers.surname, Teams.name, Teams.engine, Points.points
From Drivers, Teams, Points");
echo "<table border='1'>
<tr>
<th>First name</th>
<th>Last name</th>
<th>Team Name</th>
<th>Engine</th>
<th>Points</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['forename'] . "</td>";
echo "<td>" . $row['surname'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['engine'] . "</td>";
echo "<td>" . $row['points'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
in your code, before the $while
$counter=0
while($row = mysqli_fetch_array($result))
{
$counter += $row['points'];
echo "<tr>";
echo "<td>" . $row['forename'] . "</td>";
echo "<td>" . $row['surname'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['engine'] . "</td>";
echo "<td>" . $row['points'] . "</td>";
echo "</tr>";
}
echo $counter; //echoes sum of points
I'm trying to assign anID to the table I'm generating with PHP but it keeps returning an error. Here is the full code that works fine so far. All I want is to add an 'id' to the table so I can apply css styles to it in the relevant sheet
<?php
$con=mysqli_connect("localhost","<un>","<pw>","monitor");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM presnationalresults ORDER BY Percentage DESC");
echo "<table border='1'>
<tr>
<th>President</th>
<th>Party</th>
<th>Votes</th>
<th>Percentage</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['PresidentName'] . "</td>";
echo "<td>" . $row['PartyCode'] . "</td>";
echo "<td>" . $row['Votes'] . "</td>";
echo "<td>" . $row['Percentage'] . "</td>";
}
echo "</table>";
mysqli_close($con);
Any help? maybe I'm going about it the wrong way?
Please try below block of code . I have added table id and also close </tr> inside while loop
<?php
$con = mysqli_connect("localhost", "<un>", "<pw>", "monitor");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con, "SELECT * FROM presnationalresults ORDER BY Percentage DESC");
echo "<table border='1' id='table-id'>
<tr>
<th>President</th>
<th>Party</th>
<th>Votes</th>
<th>Percentage</th>
</tr>";
while ($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['PresidentName'] . "</td>";
echo "<td>" . $row['PartyCode'] . "</td>";
echo "<td>" . $row['Votes'] . "</td>";
echo "<td>" . $row['Percentage'] . "</td>";
echo "</tr>"; // you forget close tr
}
echo "</table>";
mysqli_close($con);