For loop not working in PHP script - php

Question

I have written a PHP script to pull data from a SQL database to display on a webpage. Everything seems fine but when I run the script it throws the error:
Parse error: syntax error, unexpected ')', expecting ';' in db_data.php on line 21
Line 21 is my FOR loop, I have checked the syntax of the loop and it seems to be correct so I can't understand why it is failing.
$result = mysqli_query($con,"SELECT * igi");
echo "<table border='1'>
<tr>
<th>Ref</th>
<th>Nameame</th>
<th>Location</th>
<th>Email</th>
<th>Issue</th>
<th>Urgency</th>
</tr>";
for($row = mysqli_fetch_array($result)){
echo "<tr>";
echo "<td>" . $row['REF'] . "</td>";
echo "<td>" . $row['NAME'] . "</td>";
echo "<td>" . $row['LOCATION'] . "</td>";
echo "<td>" . $row['EMAIL'] . "</td>";
echo "<td>" . $row['ISSUE'] . "</td>";
echo "<td>" . $row['URGENCY'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);

Answer 1

Change for to while
<?php
// Missing FROM here vv
$result = mysqli_query($con,"SELECT * FROM igi");
echo "<table border='1'>
<tr>
<th>Ref</th>
<th>Nameame</th>
<th>Location</th>
<th>Email</th>
<th>Issue</th>
<th>Urgency</th>
</tr>";
while($row = mysqli_fetch_array($result)){
echo "<tr>";
echo "<td>" . $row['REF'] . "</td>";
echo "<td>" . $row['NAME'] . "</td>";
echo "<td>" . $row['LOCATION'] . "</td>";
echo "<td>" . $row['EMAIL'] . "</td>";
echo "<td>" . $row['ISSUE'] . "</td>";
echo "<td>" . $row['URGENCY'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);

Answer 2

As Anthony Thompson and RJParick says, you have to change for to while. The error you're encountering is due tu for that need 3 params like this :
for($i; $i<10; $i++) {//Note the ; used to separate params.
//do something
}
So your loop would begin like this :
while($row = mysqli_fetch_array($result)){
Another detail, your SQL isn't correct use SELECT * FROM igi instead.