I am trying to update a patient's record its saying its complete but its not updating phpmyadmin. When I press save and update button it shows Save was successful. Any Ideas ?
<?php
include 'connect.php';
$id1 = $_POST['PatientID']; //Text box the user searches in
mysql_query("UPDATE PatientRecords SET
PatientID = '".$_POST['PatientID']."',
FirstName = '".$_POST['FirstName']."',
LastName = '".$_POST['LastName']."',
DOB = '".$_POST['DOB']."',
IDNumber1 = '".$_POST['IDNumber1']."',
Medication1 = '".$_POST['Medication1']."',
Medication1Dosage = '".$_POST['Medication1Dosage']."',
IDNumber2 = '".$_POST['IDNumber2']."',
Medication2 = '".$_POST['Medication2']."',
Medication2Dosage = '".$_POST['Medication2Dosage']."',
IDNumber3 = '".$_POST['IDNumber3']."',
Medication3 = '".$_POST['Medication3']."',
Medication3Dosage = '".$_POST['Medication3Dosage']."',
MedicalNotes = '".$_POST['MedicalNotes']."'
WHERE PatientID = '$id1');
echo"Patient Information has been updated successfully";
mysql_close($con);
?>
Your query is wrong to begin with. If you're UPDATING an existing row, leave the VALUES (... out and end the query after WHERE PatientID = '$id1'. If you're INSERTING a new row, use INSERT table (column, column, ...) VALUES (value, value, ...) and don't use WHERE.
Related
I am writing a Php 5 and Mysql 5 page counter script. When a student having id as 'visitorid' visits a page having id 'pageid' (both int(11)) the page counter tries to log the visit in 'visitors' database. But counter is not updating in mysql db, instead the visit_counter int(4) turns to 0.Whats wrong with my code? visitdate is datetime.
<?php
$pageid = 101;
$visitorid = 234;
$sql = "SELECT * FROM visitors
WHERE pageid = ".$pageid."
AND visitorid = ".$visitorid;
$temp = mysql_query($sql) or die("Error 1.<br>".mysql_error());
$data = mysql_fetch_array($temp);
// visit_counter is a field in table
if(($data['visit_counter']) != NULL){
echo "Entery exists <br>";
// Tried below version also
$visit = " SET visit_counter = visit_counter+1";
//$visit_counter = $data['visit_counter'];
//$visit = " SET visit_counter = ".$visit_counter++ ;
// Valid SQL
// UPDATE `visitors`
// SET visit_counter = visit_counter+1
// WHERE pageid = 101 and visitorid=234
// This manual sql query updates in phpmyadmin
$sql = "UPDATE visitors ".$visit."
AND visitdate = NOW()
WHERE pageid = ".$pageid."
AND visitorid = ".$visitorid;
$temp = mysql_query($sql) or die("ERROR 3.<br>".mysql_error());
//No error is displayed on above query.
} else {
//first entry
$visit_count = "1";
$sql = "INSERT INTO visitors
(`pageid`,`visitorid`, `visitdate`, `visit_counter`)
VALUES ('".$pageid."','".$visitorid."', NOW(), '".$visit_count."')";
$temp = mysql_query($sql);
//first entry is inserted successfully
//and visit_counter shows 1 as entry.
}
?>
Can anyone tell me whats wrong with this code?
Oh! I got answer by myself. Sometimes just little errors make us go crazy..
I made a mistake in udate query.. rather than using and I should have user a comma instead. .. working well now!
i am updating a single column with many values using comma between them. they are working fine. but if update same column from other user the value inserted by previous users deleted. i want to keep values of previous user also with the insertion of new user value. and i also dont want to repeat the same value again because values i m using are unique ids..
// update student list
$venue = ($_GET['venue']);
$district = ($_GET['dis']);
if(isset($_POST['submit']))
//print_r ($_POST);
{
#$std_list=implode(',',$_POST['std_list']);
if(empty($std_list))
{
$error = 1;
$get_value = "Please select you event students.";
}
else
{
//$query = mysql_query("INSERT INTO events (std_list)
//VALUES('".$std_list."')") or die(mysql_error());
$query = mysql_query("UPDATE events SET std_list='".$std_list."' WHERE
id='".$district."' ") or die(mysql_error());
//echo "$msg";
echo "Students list submitted successfully";
}
}
if any query you can ask again. values i am inserting are integers only. Same integer cant be used by two different users.
try this?
$query = mysql_query("UPDATE events SET std_list = CONCAT( std_list, '".$std_list."') WHERE
id='".$district."' ") or die(mysql_error());
I am trying to issue a mysqli_multi_query, in which my querys are named $query & $query2. Query 1 is a seperate table from query 2. This is a sample of how the code syntax looks like:
$query1 = "INSERT INTO invoices (`id`,`c`) VALUES (NULL, '$client_id')";
$query2 = "UPDATE `customers` SET `a` = `$a`,`b` = `$b` WHERE `customers.id` = $client_id";
the invoices.client_id is the same as the customers.id, and I only want to update customers.id that matches the invoice client_id.
For some odd reason, everything is updated fine into my invoices, but not into my customers. Is my syntax correct?
after our discussion in the chat we figured out the following misstakes:
Your code:
$query2 = "UPDATE customers SET alarmcode = $alarmcode, garagecode = $garagecode, gatecode = $gatecode, liason = $liason, lphone = $lphone WHERE customers.id = '$client_id'";
table-def:
So the problem was not correct encapsulating of strings in the sql statement.
corrected statement was:
$query2 = "UPDATE customers SET alarmcode = '$alarmcode', garagecode = '$garagecode', gatecode = '$gatecode', liason = '$liason', lphone = '$lphone' WHERE id = $client_id";
Okay, so i have a problem here. I solved the updating to a mysql database with just set values. But now i want to let the user put something by use of a textbox to update a row.
this doesnt seem to work
code:
$newfirstname = $_POST['newfirstname'];
//Update the record
$updateQuery = "UPDATE users SET firstname = '".$newfirstname."' WHERE KcID = 2";
mysql_query($updateQuery) or die("Error: ".mysql_error());
//create the query
$query = mysql_query("select * from voskousers");
//return the array and loop through each row
while ($row = mysql_fetch_array($query))
{
?>
It just doesnt update it with the right value, it makes it a blank space in my row.
Is it because you're updating a table called users but then selecting from a table called voskousers?
I'm having problem with inserting in purchase table and updating facility table. Let's say, user made a purchase with product_id and product_quantity.
The query is running. But it inserts twice with the same data and not updating facility table.
When user hit submit, I want to insert product_id and product_quantity into purchase table. And updating facility table with product_id and product_quantity that associated with it.
Here is my code
<?php
include 'dbconn.inc.php';
include 'functions.inc.php';
$sql1 = "SELECT * FROM facilities";
$res = $mysqli->query($sql1);
$facilities = array();
while( $row = $res->fetch_array(MYSQLI_ASSOC) ){
$facilities[]['id'] = $facilities_id;
$facilities[]['product_id'] = $facilities_product_id;
$facilities[]['product_current_quantity'] = $product_current_quantity;
}
$id = $mysqli->real_escape_string ($_POST['id']);
$purchase_id = $mysqli->real_escape_string( $_POST['purchase_id'] );
$facility_id = $mysqli->real_escape_string( $_POST['facility_id'] );
$product_quantity = $mysqli->real_escape_string( $_POST['product_quantity'] );
$sql1 = "UPDATE facilities
SET
`product_current_quantity` = '$product_quantity + $product_current_quantity'
WHERE $facility_id = $facilities_id AND $id = $facilities_product_id ";
$sql = "INSERT INTO purchases
(
`purchase_id`,
`facility_id`,
`product_quantity`,,
`product_id`
)
VALUES
(
'$purchase_id',
'$facility_id',
'$product_quantity',
'$id'
)";
I did some research and I think I need to use triggers. But I never work with triggers before. Any helps would be great. Thank you!
Please execute your query and better use echo statement if you have doubt in query.
use "php.net"
used this code to your updates
product_current_quantity = product_current_quantity + $product_current_quantity
how many number they can add to your product Quantity and they sum the current number.
You have used insert query and update query for the same variable $sql without any condition. If so always your following query only executes.
Then anymore no update only insertion will reflect in your table.
$sql = "INSERT INTO purchases
(
`purchase_id`,
`facility_id`,
`product_quantity`,,
`product_id`
)
VALUES
(
'$purchase_id',
'$facility_id',
'$product_quantity',
'$id'
)";