Okay, so i have a problem here. I solved the updating to a mysql database with just set values. But now i want to let the user put something by use of a textbox to update a row.
this doesnt seem to work
code:
$newfirstname = $_POST['newfirstname'];
//Update the record
$updateQuery = "UPDATE users SET firstname = '".$newfirstname."' WHERE KcID = 2";
mysql_query($updateQuery) or die("Error: ".mysql_error());
//create the query
$query = mysql_query("select * from voskousers");
//return the array and loop through each row
while ($row = mysql_fetch_array($query))
{
?>
It just doesnt update it with the right value, it makes it a blank space in my row.
Is it because you're updating a table called users but then selecting from a table called voskousers?
Related
i am updating a single column with many values using comma between them. they are working fine. but if update same column from other user the value inserted by previous users deleted. i want to keep values of previous user also with the insertion of new user value. and i also dont want to repeat the same value again because values i m using are unique ids..
// update student list
$venue = ($_GET['venue']);
$district = ($_GET['dis']);
if(isset($_POST['submit']))
//print_r ($_POST);
{
#$std_list=implode(',',$_POST['std_list']);
if(empty($std_list))
{
$error = 1;
$get_value = "Please select you event students.";
}
else
{
//$query = mysql_query("INSERT INTO events (std_list)
//VALUES('".$std_list."')") or die(mysql_error());
$query = mysql_query("UPDATE events SET std_list='".$std_list."' WHERE
id='".$district."' ") or die(mysql_error());
//echo "$msg";
echo "Students list submitted successfully";
}
}
if any query you can ask again. values i am inserting are integers only. Same integer cant be used by two different users.
try this?
$query = mysql_query("UPDATE events SET std_list = CONCAT( std_list, '".$std_list."') WHERE
id='".$district."' ") or die(mysql_error());
I have one drop down and lists are aMan, bMan, cMan.I am selecting any one of them from drop down. So whatever I am selecting from drop down I want to update that records according to list. Below update query is updating all my records because i added '$action_points' for each.
For example. If I selected bMan from the drop down then in update table will update only bMan records according to user_id.If I select aMan then update table it will update only aMan with 10.It will not effect on other.
I am getting the issue on update query.Would you help me with update query?
$result = $conn->query($sql_user);
if (isset($result->num_rows) > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$action_type=$row['action_type'];// Value will be aMan,bMan, cMan
$action_points=$row['action_points']; //10, 20, 30
}
}
$sql = "UPDATE man SET aMan='$action_points',bMan='$action_points', cMan='$action_points' where user_id='$user_id'";
$result = $conn->query($sql);
Update table
You are selecting from select drop down it means it will pass the value, that you have either aMan, bMan or cMan.
so you can do it like this,
$action_type = $_GET['action_type'];
$sql = "update man set `$action_type` = '$action_value' where id = $user_id";
Above is an example.
Firstly, you should replace if (isset($result -> num_rows) >0 ) with if(isset($result)) && ($result->num_rows>0)) .The first condition returns the number of rows (which at the least is 0) and then checks if it is set. Thus, isset will always return true, even when $result is not set. The second condition solves this problem
You have the type of list to update, why don't you use it?
For eg:
$result = $conn->query($sql_user);
if(isset($result)) && ($result->num_rows>0)) {
// output data of each row
while($row = $result->fetch_assoc()) {
$action_type=$row['action_type'];// Value will be aMan,bMan, cMan
$action_points=$row['action_points']; //10, 20, 30
}
}
$sql = "UPDATE man SET $action_type = $action_points WHERE user_id='$user_id'";
$result = $conn->query($sql);
This shall automatically update the required column
U should use AND in your query
UPDATE man SET aMan='$action_points' AND bMan='$action_points' AND cMan='$action_points' where user_id='$user_id'"
Or use several update query it means once update aMan row then a query for bMan row and so on.
The issue is because you are updating the three column at a time, you have to make it conditional like:
$action_type=$row['action_type'];// Value will be aMan,bMan, cMan
$action_points=$row['action_points']; //10, 20, 30
$column = '';
if($action_type == 'aMan'){
$column = 'aMan';
}
else if($action_type == 'bMan'){
$column = 'bMan';
}
else if($action_type == 'cMan'){
$column = 'cMan';
}
$sql = "UPDATE man SET ".$column." = '".$action_points."' where user_id='$user_id'";
I have a form that posts data for 2 fields related to specific rows. The form can vary in number of rows for updating dependent on who is using it. However it is not updating any part of the table. If I take the while loop out it will only update the last row. Any suggestions on how to fix it?
foreach($_POST as $k=>$p){ ${$k}=$p; }
if (isset($_POST['Update'])) {
$result = mysql_query("SELECT id, rank FROM accounts WHERE tag='$tag'");
while ($row = mysql_fetch_assoc($result)) {
//Set Variables
$query = "UPDATE accounts SET rank=$rank WHERE id=$m_id";
mysql_query($query);
}
}
you can simply do this:
if (isset($_POST['Update'])) {
$result = mysql_query("UPDATE accounts SET rank=".$_POST['rank']." WHERE tag='".$_POST['tag']."'");
mysql_query($query);
}
better read mysql and php properly.
I am trying to get the last value of a field during a new registration.
before insert data into the table, I want to create a user id number according to the last registered user's id number. to do that I use this:
//to reach the last value of userID field;
$sql = "SELECT userID FROM loto_users ORDER BY userID DESC LIMIT 1";
$result = mysql_query($sql);
while($row = mysql_fetch_array($result))
{
$value = $row['userID'];
echo "$value"; //not resulting here
}
$userID = $value+1;
so, the userID becomes 1.
The weird thing is, I could capable to use exact same code in another php file and works fine.
I would like to say that, rest of the code works fine. No problem with db connections or any other things you can tell me.
Note that: When I run the same query line in the mysql interface, I can get the value I want. I mean $sql line.
Your problem is in this code:
{
$svalue = $row['userID'];
----^
echo "$value"; //not resulting here
}
$userID = $value+1;
Change to $value.
But the right answer is to define userID to be auto-incrementing. That way, the database does the work for you. After inserting the row, you can do:
SELECT LAST_INSERT_ID()
To get the last value.
I solved the problem. Here;
$sql = "SELECT userID FROM loto_users ORDER BY userID DESC LIMIT 1";
$result = mysql_query($sql);
$user_info = $result->fetch_assoc();
$value = intval($user_info["userID"]);
$userID = $value+1;
Thanks everyone.
If you mark the userID field as autoincrement in you mysql table.
You won't need to set the userID and db increase the userID for you. You can get the assigned userID using the mysql_insert_id() function. Here is an example from php.net
mysql_query("INSERT INTO mytable (product) values ('kossu')");
printf("Last inserted record has id %d\n", mysql_insert_id());
Here is another example for your case
mysql_query("INSERT INTO 'loto_users'('username',...) values('usernameValue',...)");
echo "New User id is ".mysql_insert_id();
I want to update some entries in my database, basically I am counting the number of checkboxes that have been selected on the previous page and multiplying them with 25 then adding that value to the current value in the DB.
This is my code:
<?php
if($_POST['code_approve'])
{
for($i=0;$i<count($_POST['checkbox']);$i++)
{
$approval_id = $checkbox[$i];
$checkboxCount = count($_POST['checkbox']);
$countx25 = $checkboxCount * 25;
$sql = "UPDATE table SET status='approved', used='processed' WHERE id='$approval_id'";
$sql2 = "UPDATE members SET balance = balance+'$countx25'";
$result2 = mysql_query($sql2);
$result = mysql_query($sql);
}
if($result)
{
echo "$countx25";
}
}
?>
It seems, that for some reason it is multiplying $countx25 with the number of checkboxes before inserting it into MySQL. This if($result){echo "$countx25";}} always shows me the right value though.
If i select 1 it prints 25, 2 prints 50, 3 prints 75 and so on, but for the MySQL part, if i select 1 it adds 25 to current value, 2 adds 100, 3 adds 225 ?!
What's the error here ?
In your SQL query:
$sql2 = "UPDATE members SET balance = balance+'$countx25'";
You don't tell the database which row to update, so all rows are updated. While you test, you first test once, then again and again, so it might add to fields you don't expect it to. Probably this is your problem.
To specify which row to update, use a WHERE clauseDocs.
To prevent updating the same field more than once, execute the query only once.
As I stated in my comment. You are running this for each checkbox you get via $_POST. Why do you even use the for loop if you use count to count the checkboxes. Remove the for loop and it will work as you intend it to.
The for loop in your code is the problem. I guess here you are trying to use all checkboxes in the previous page, for your code you loop for all the checkboxes, so if there are 4 checkboxes, the for loop will run 4 times. So please identify what you want to do.
This is your code.
<?php
if($_POST['code_approve'])
{
for($i=0;$i<count($_POST['checkbox']);$i++)
{
$approval_id = $checkbox[$i];
$checkboxCount = count($_POST['checkbox']);
$countx25 = $checkboxCount * 25;
$sql = "UPDATE table SET status='approved', used='processed' WHERE id='$approval_id'";
$sql2 = "UPDATE members SET balance = balance+'$countx25'";
$result2 = mysql_query($sql2);
$result = mysql_query($sql);
}
if($result)
{
echo "$countx25";
}
}
?>