PHP imagick get all images from tiff - php

Question

I am trying to load a tiff file and count the number or images and then then dispaly each image as a PNG thumbnail.
The count part is ok it counts 6 which is the correct number of pages in that tif, the code then lists 6 of the same image which is the the first page of the tiff. Cant workout if there is a problem with my loop or I am simply not using the imagick functions correctly.
Can anyone help
<?php
$image2 = new Imagick('http://mysite.org.uk/tiftest/2.tif');
/* Create the object */
$image = new Imagick('http://mysite.org.uk/tiftest/2.tif');
$count = $image->getNumberImages();
echo "<h3 style=\"font: bold 12pt Arial\">Total Number of Images Extracted ".
"from the TIF : ".$image->getNumberImages()."</h3>";
for ($x = 1;$x <= $image->getNumberImages();$x++) {
$image->pingImage( $image2 );
$image->readImageFile( $image2 );
$image->setImageFormat( 'png' );
$image->thumbnailImage(100, 0);
echo "<img id='" . $x . "' src='data:image/png;base64,".base64_encode($image)."' />"; } ?>

Answer 1

You will have to move to the previous image using $image->previousImage()
Iterate over the number of images backwards and move to the previous image to get all of them, might also be able to use while ($image->hasPreviousImage()) {} construct
Oh, and dont use readImageFile, you already have the image in-memory.

Answer 2

I sussed it !!
Here is the code to get all the sepearte pages out of the tif and display them as PNG's :
<?php
/* Create the object */
$image = new Imagick('http://mysite.o.uk/tiftest/1.tif');
$count = $image->getNumberImages();
echo "<h3 style=\"font: bold 12pt Arial\">Total Number of Images Extracted ".
"from the TIF : ".$image->getNumberImages()."</h3>";
$x =0;
foreach ( $image as $image ) {
$x++;
$image->setImageFormat( 'png' );
$image->thumbnailImage(150, 120);
echo "<img id='" . $x . "' src='data:image/png;base64,".base64_encode($image)."' />";
}
?>
However now I need to know how to display them as true PNG's without using base63 encoding, any ideas ???