I am new to mysqli and I am trying to output a simple query into an HTML table.
I get three blank cells returned but nothing inside of them.
I tried looking around here to find this and maybe my search skills aren't up to par, so either nobody else got stuck here, or I can't search for squat!
Anyway, this is my code:
<?php
$mysqli = new mysqli("localhost", "webuser", "mysecretpassword", "userdb");
/* check connection */
if ($mysqli->connect_errno)
{
printf("Connect failed: %s\n", $mysqli->connect_error);
exit();
}
/* Select queries return a resultset */
if ( $result = $mysqli->query("select first_name, last_name, last_activity_date from users order by first_name" ) )
{
$finfo = $result->fetch_fields();
foreach ( $finfo as $val )
{
echo "<tr>\n";
echo "<td>$val->first_name</td>\n";
echo "<td>$val->last_name</td>\n";
echo "<td>$val->last_activity_date</td>\n";
echo "</tr>\n";
}
$result->close();
}
$mysqli->close();
?>
While I have seen other examples using printf() I am not familiar with its syntax since I am not used to C style printf since I had used the echo style previously on my old database transactions.
Any help is greatly appreciated here. Thanks!
Try this
foreach ( $finfo as $val )
{
echo "<tr>\n";
echo "<td>" . $val->first_name . "</td>\n";
echo "<td>" . $val->last_name . "</td>\n";
echo "<td>" . $val->last_activity_date . "</td>\n";
echo "</tr>\n";
}
if ( $result = $mysqli->query("select first_name, last_name, last_activity_date from worker order by first_name" ) )
{
while ( $val = $result->fetch_object() )
{
echo "<tr>\n";
echo "<td>" . $val->first_name . "</td>\n";
echo "<td>" . $val->last_name . "</td>\n";
echo "<td>" . $val->last_activity_date . "</td>\n";
echo "</tr>\n";
}
$result->close();
}
It's not about the foreach or while loop, fetch_fields does not return the query result but the meta data about the columns of the query result (such as name, length, type etc)
You should also get a PHP warning as well on $val->first_name since this object member isn't defined.
Related
I'm trying to create a dynamic header on Name which gives the user the ability to sort by ASC or DESC, the results is from the 'register'-table in MySQL. I have tried a couple of codings, but it hasn't given the correct result as of now. Hope anyone is able to help me :)
I have tried making another variable, but I couldn't manage to create the correct one.
<?php
$sql = "SELECT * FROM register";
if($sqlData = mysqli_query($db, $sql)) {
if(mysqli_num_rows($sqlData) > 0) {
echo "<table border ='1' bgcolor='#FFF' width='100%'>";
echo "<tr>";
echo "<th><a href='overview.php?order=name'>Name</a></th>";
echo "<th>Score</th>";
echo "</tr>";
while($row = mysqli_fetch_array($sqlData)) {
echo "<tr>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['score'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_free_result($sqlData);
} else{
echo "No results in DB";
}
} else{
echo "Error couldn't connect $sql. " . mysqli_error($db);
}
mysqli_close($db);
?>
Hm, that's not a good idea to sort table using MySQL each time user clicked on the table's header.
I suggest you to use javascript for it. Example
I am trying to get the column names and data from a table using mysqli and php. Any help is appreciated.
I know how to do this in java by more or less this code:
String [] header= new String[numberOfColumns-1];
//Code to get column names in header array
String table = "<table><tr>"
for(int i=0;i<numberOfColumns-1;i++){
table= table + "<td>" + header[i] + </td>;
}
table = table + </tr>;
while(result.next()!=null){
table = table + <tr>
for (int j = 0 ; j < numberOfColumns-1 ; j++){
table = table + <td> + result.getString[j] + </td>
}
table = table + </tr>
}
But i have no idea how to do it in php. Each table is different but what i have to far for the one table:
include("config.php");
session_start();
$sql = ($_POST['q']);
$result = mysqli_query($db,$sql);
echo "<tr>";
echo "<td>First Name</td>";
echo "<td>Last Name</td>";
echo "<td>Date of Birth</td>";
echo "<td>Contact Details</td>";
echo "</tr>";
while($rowitem = mysqli_fetch_array($result,MYSQLI_ASSOC)){
echo "<tr>";
echo "<td>" . $rowitem['fname'] . "</td>";
echo "<td>" . $rowitem['lname'] . "</td>";
echo "<td>" . $rowitem['dob'] . "</td>";
echo "<td>" . $rowitem['contact'] . "</td>";*/
echo "</tr>";
}
echo "</table>"; //end table tag
EDIT: Is the implementation of the fetch_fields correct?
include("config.php");
session_start();
$sql = ($_POST['q']);
$result = mysqli_query($db,$sql);
$finfo = mysqli_fetch_fields($result);
echo "<tr>";
foreach ($finfo as $val) {
echo "<td>" . $val->name . "</td>"
}
echo "</tr>";
while($rowitem = mysqli_fetch_array($result,MYSQLI_ASSOC)){
echo "<tr>";
for($x =0; $x < count($finfo);$x++){
echo "<td>" . $rowitem[$x] . "/td";
}
echo "</tr>";
}
echo "</table>";
EDIT 2: Database Connection.php
<<?php
include("config.php");
session_start();
$sql = ($_GET['q']);
$result = mysqli_query($db,$sql);
echo "<table border='1' class='table_info'>";
$finfo = mysqli_fetch_fields($result);
echo "<tr>";
foreach ($finfo as $val) {
echo "<td>" . $val->name . "</td>";
}
echo "</tr>";
while($rowitem = mysqli_fetch_array($result,MYSQLI_ASSOC)){
echo "<tr>";
foreach ($row as $value) { (line 18)
echo "<td>" . $value . "</td>";
}
echo "</tr>";
}
echo "</table>"; //end table tag
?>
Error:
Notice: Undefined variable: row in databaseConnection.php on line 18
Warning: Invalid argument supplied for foreach() in databaseConnection.php on line 18
You can call mysqli_fetch_fields on the $result object, and retrieve the name property for each object in the returned array. See documentation for examples.
There are a couple ways to do this:
Use array_keys() to grab the names of the keys from an associative array:
$rowitem = mysqli_fetch_array($result, MYSQLI_ASSOC);
$header = array_keys($rowitem);
Use mysqli_fetch_fields() to grab the field objects, and parse out the names into an array using array_map():
// Helper function to use in array_map
// (For PHP < 5.3. If >= 5.3.0, use the second version)
function getFieldName($field) { return $field->name; }
// For PHP < 5.3:
$header = array_map("getFieldName", mysqli_fetch_fields($result));
// For PHP >= 5.3.0:
$header = array_map(function($o) { return $o->name; }, mysqli_fetch_fields($result));
As mentioned you can use $result->fetch_fields() to get the field information from the result and this includes the name of each field.
For what you're trying to acheive this code should work for pretty much any table/query:
<?php
/* Connect to mysql */
$mysqli = new mysqli("localhost", "username", "password", "database");
/* Check connection */
if ($mysqli->connect_errno) {
printf("Connect failed: %s\n", $mysqli->connect_error);
exit();
}
/* Your query */
$query = "SELECT * from table";
if ($result = $mysqli->query($query)) {
/* Output HTML table */
echo "<table border='1'>";
/* Get field information for all returned columns */
$finfo = $result->fetch_fields();
/* Output each column name in first table row */
echo "<tr>";
foreach ($finfo as $val) {
echo "<td>".$val->name."</td>";
}
echo "</tr>";
/* Fetch the result and output each row into a table row */
while($row = mysqli_fetch_array($result, MYSQLI_NUM)) {
echo "<tr>";
foreach ($row as $value) {
echo "<td>" . $value . "</td>";
}
echo "</tr>";
}
$result->free();
echo "</table>";
}
$mysqli->close();
(Obviously you should never query a database from a $_POST variable without some serious sanitisation of the input, but I'll assume that was just for your convenience.)
You can Echo in a table..
$result = mysqli_query($db,$sql)
if (!$result) {
die("Query to show fields from table failed");
}
$fields_num = mysqli_num_fields($result);
echo "<table border='1'><tr>";
// printing table headers
for($i=0; $i<$fields_num; $i++)
{
$field = mysqli_fetch_field($result);
echo "<td>{$field->name}</td>";
}
echo "</tr>\n";
// printing table rows
while($row = mysqli_fetch_row($result))
{
echo "<tr>";
// $row is array... foreach( .. ) puts every element
// of $row to $cell variable
foreach($row as $cell)
echo "<td>$cell</td>";
echo "</tr>\n";
}
mysqli_free_result($result);`
I am trying to pass a variable from a page to another page so that i can display more information on the other page by getting the idea. I am not really sure what is going wrong and because I use bluemix it doesn`t display an error it just gives me the page 500 error. Here is my code:
<?php
$strsql = "select id, name, problem, urgency, technology from idea WHERE status='saved'";
if ($result = $mysqli->query($strsql)) {
// printf("<br>Select returned %d rows.\n", $result->num_rows);
} else {
//Could be many reasons, but most likely the table isn't created yet. init.php will create the table.
echo "<b>Can't query the database, did you <a href = init.php>Create the table</a> yet?</b>";
}
?>
<?php
echo "<tr>\n";
while ($property = mysqli_fetch_field($result)) {
echo '<th>' . $property->name . "</th>\n"; //the headings
}
echo "</tr>\n";
while ( $row = mysqli_fetch_row ( $result ) ) {
$idea_id= $row['id'];
echo "<tr>\n";
for($i = 0; $i < mysqli_num_fields ( $result ); $i ++) {
echo '<td>' . "$row[$i]" . '</td>';
}
echo "</tr>\n";
}
$result->close();
mysqli_close();
?>
There's a small bug in your code. Your echo <a href ="... line should be like this,
echo '<td>' . $row[$i] . '</td>';
I have created an sql database(with phpmyadmin) filled with measurements from which I want to call data between two dates( the user selects the DATE by entering in the HTML forms the "FROM" and "TO" date) and display them in a table.
Additionally I have put, under my html forms, some checkboxes and by checking them you can restrict the amount of data displayed.
Each checkbox represent a column of my database; so along with the date and hour column, anything that is checked is displayed(if none is checked then everything is displayed).
So far I managed to write a php script that connects to the database, display everything when none of my checkboxes is checked and also managed to put in order one of my checkboxes.
Problem: The data that I call for are been displayed twice.
Question: I want to have four checkboxes.
Do I need to write an sql query for every possible combination or there is an easier way?
<?php
# FileName="Connection_php_mysql.htm"
# Type="MYSQL"
# HTTP="true"
$hostname_Database_Test = "localhost";
$database_Database_Test = "database_test";
$table_name = "solar_irradiance";
$username_Database_Test = "root";
$password_Database_Test = "";
$Database_Test = mysql_pconnect($hostname_Database_Test, $username_Database_Test, $password_Database_Test) or trigger_error(mysql_error(),E_USER_ERROR);
//HTML forms -> variables
$fromdate = $_POST['fyear'];
$todate = $_POST['toyear'];
//DNI CHECKBOX + ALL
$dna="SELECT DATE, Local_Time_Decimal, DNI FROM $database_Database_Test.$table_name where DATE>=\"$fromdate\" AND DATE<=\"$todate\"";
$tmp ="SELECT * FROM $database_Database_Test.$table_name where DATE>=\"$fromdate\" AND DATE<=\"$todate\"";
$entry=$_POST['dni'];
if (empty($entry))
{
$result = mysql_query($tmp);
echo
"<table border='1' style='width:300px'>
<tr>
<th>DATE</th>
<th>Local_Time_Decimal</th>
<th>Solar_time_decimal</th>
<th>GHI</th>
<th>DiffuseHI</th>
<th>zenith_angle</th>
<th>DNI</th>
";
while( $row = mysql_fetch_assoc($result))
{
echo "<tr>";
echo "<td>" . $row['DATE'] . "</td>";
echo "<td>" . $row['Local_Time_Decimal'] . "</td>";
echo "<td>" . $row['Solar_Time_Decimal'] . "</td>";
echo "<td>" . $row['GHI'] . "</td>";
echo "<td>" . $row['DiffuseHI'] . "</td>";
echo "<td>" . $row['Zenith_Angle'] . "</td>";
echo "<td>" . $row['DNI'] . "</td>";
echo "</tr>";
}
echo '</table>';}
else
{
$result= mysql_query($dna);
echo
"<table border='1' style='width:300px'>
<tr>
<th>DATE</th>
<th>Local_Time_Decimal</th>
<th>DNI</th>
";
while($row = mysql_fetch_assoc($result))
{
echo "<tr>";
echo "<td>" . $row['DATE'] . "</td>";
echo "<td>" . $row['Local_Time_Decimal']."</td>";
echo "<td>" . $row['DNI'] . "</td>";
echo "</tr>";
}
echo '</table>';
}
if($result){
echo "Successful";
}
else{
echo "Enter correct dates";
}
?>
<?php
mysql_close();
?>
Try to create your checkbox like below:
Solar_Time_Decimal<checkbox name='columns[]' value='1'>
GHI<checkbox name='columns[]' value='2'>
DiffuseHI<checkbox name='columns[]' value='3'>
Zenith_Angle<checkbox name='columns[]' value='4'>
DNI<checkbox name='columns[]' value='5'>
And try to hange your PHP code to this:
<?php
//HTML forms -> variables
$fromdate = isset($_POST['fyear']) ? $_POST['fyear'] : data("d/m/Y");
$todate = isset($_POST['toyear']) ? $_POST['toyear'] : data("d/m/Y");
$all = false;
$column_names = array('1' => 'Solar_Time_Decimal', '2'=>'GHI', '3'=>'DiffuseHI', '4'=>'Zenith_Angle','5'=>'DNI');
$column_entries = isset($_POST['columns']) ? $_POST['columns'] : array();
$sql_columns = array();
foreach($column_entries as $i) {
if(array_key_exists($i, $column_names)) {
$sql_columns[] = $column_names[$i];
}
}
if (empty($sql_columns)) {
$all = true;
$sql_columns[] = "*";
} else {
$sql_columns[] = "DATE,Local_Time_Decimal";
}
//DNI CHECKBOX + ALL
$tmp ="SELECT ".implode(",", $sql_columns)." FROM $database_Database_Test.$table_name where DATE>=\"$fromdate\" AND DATE<=\"$todate\"";
$result = mysql_query($tmp);
echo "<table border='1' style='width:300px'>
<tr>
<th>DATE</th>
<th>Local_Time_Decimal</th>";
foreach($column_names as $k => $v) {
if($all || (is_array($column_entries) && in_array($k, $column_entries)))
echo "<th>$v</th>";
}
echo "</tr>";
while( $row = mysql_fetch_assoc($result))
{
echo "<tr>";
echo "<td>" . $row['DATE'] . "</td>";
echo "<td>" . $row['Local_Time_Decimal'] . "</td>";
foreach($column_names as $k => $v) {
if($all || (is_array($column_entries) && in_array($k, $column_entries))) {
echo "<th>".$row[$v]."</th>";
}
}
echo "</tr>";
}
echo '</table>';
if($result){
echo "Successful";
}
else{
echo "Enter correct dates";
}
?>
<?php
mysql_close();?>
This solution consider your particular table columns but if your wish a generic solution you can try to use this SQL too:
$sql_names = "SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_SCHEMA = '$database_Database_Test' AND TABLE_NAME = '$table_name'";
and use the result to construct the $column_names array.
Solution for your problem : Change the mysql_fetch_assoc with mysql_fetch_array
If you have the same problem try to print your result with print_r
Answer : Use the bit datatype in mysql for store and read your checkboxes.
When you're receiving thr value from the database then you can use
in the parameter checked you can use the php code as exist :
$value = ...get the value from db ( 1 or 0 )
echo '<input type="checkbox" name="thename" value="thevalue" '.($value==1?'checked=checked'.'').'/>';
I have selected a random table from a list/array and I want to be able to call this random table with the mysqli_query function i.e. select a table dynamically
Here is my code:
<?php
$mysqli=mysqli_connect(HOST,USERNAME,PASSWORD,DATABASE);
// Check connection
if (mysqli_connect_errno($mysqli))
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
// Looks at all prodcuts and selects those that have special offers enabled
// Selects a random table from the array
$tables_special = ["ajbs_products_console" ,"ajbs_products_console_games", "ajbs_products_pc", "ajbs_products_pc_games", "ajbs_products_pc_parts"];
$rtable = $tables_special[floor (rand(0,count($tables_special)-1))];
echo "<p>".$rtable." was selected</p>";
$products = mysqli_query("SELECT * FROM '".$rtable."'");
echo "<p>".$products."</p>";
while($productRow = mysqli_fetch_array($products))
{
if ($productRow['product_specials'] == 1)
{
echo "<table>";
echo "<tr>";
echo "<td rowspan='2'><img src=" . $productRow['product_image'] . "/></td>";
echo "</tr>";
echo "<table border='1'>";
echo "<tr>";
echo "<td>Product Name</td>";
echo "<td>" . $productRow['product_name'] . "</td>";
echo "</tr>";
echo "<tr>";
echo "<td>Description</td>";
echo "<td>" . $productRow['product_description'] . "</td>";
echo "</tr>";
echo "</table>";
}
}
mysqli_close($mysqli);
?>
Im at a loss of why this is not working
Thanks,
Bull
You should not quote table names with single quotes but with backticks, single quotes makes it a string instead of a table name;
Also, the function mysqli_query takes an extra parameter, the connection.
$products = mysqli_query("SELECT * FROM '".$rtable."'");
should be;
$products = mysqli_query($mysqli, "SELECT * FROM `".$rtable."`");
Try
$products = mysqli_query($mysqli, "SELECT * FROM ".$rtable);