select SQL table from php variable - php

Question

I have selected a random table from a list/array and I want to be able to call this random table with the mysqli_query function i.e. select a table dynamically
Here is my code:
<?php
$mysqli=mysqli_connect(HOST,USERNAME,PASSWORD,DATABASE);
// Check connection
if (mysqli_connect_errno($mysqli))
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
// Looks at all prodcuts and selects those that have special offers enabled
// Selects a random table from the array
$tables_special = ["ajbs_products_console" ,"ajbs_products_console_games", "ajbs_products_pc", "ajbs_products_pc_games", "ajbs_products_pc_parts"];
$rtable = $tables_special[floor (rand(0,count($tables_special)-1))];
echo "<p>".$rtable." was selected</p>";
$products = mysqli_query("SELECT * FROM '".$rtable."'");
echo "<p>".$products."</p>";
while($productRow = mysqli_fetch_array($products))
{
if ($productRow['product_specials'] == 1)
{
echo "<table>";
echo "<tr>";
echo "<td rowspan='2'><img src=" . $productRow['product_image'] . "/></td>";
echo "</tr>";
echo "<table border='1'>";
echo "<tr>";
echo "<td>Product Name</td>";
echo "<td>" . $productRow['product_name'] . "</td>";
echo "</tr>";
echo "<tr>";
echo "<td>Description</td>";
echo "<td>" . $productRow['product_description'] . "</td>";
echo "</tr>";
echo "</table>";
}
}
mysqli_close($mysqli);
?>
Im at a loss of why this is not working
Thanks,
Bull

Answer 1

You should not quote table names with single quotes but with backticks, single quotes makes it a string instead of a table name;
Also, the function mysqli_query takes an extra parameter, the connection.
$products = mysqli_query("SELECT * FROM '".$rtable."'");
should be;
$products = mysqli_query($mysqli, "SELECT * FROM `".$rtable."`");

Answer 2

Try
$products = mysqli_query($mysqli, "SELECT * FROM ".$rtable);