Im new in PHP and I have create a table (bookstore) really look like this
no_id | author | id_book | id_topic | quote | comments | no_page
id_book and id_topic have another table eg
table for book
:
id_book | book_name
table for topic
:
id_topic | topic_name
I made this sql statement for show the output in my system,but my problem is the system show only one output when submit a keyword. even though there are few similar word in the database.
"SELECT a.*, b.book_name
FROM bookstore AS a
LEFT JOIN book AS b ON a.id_book=b.id_book
WHERE quote LIKE '%".
can anyone help me how to show all match quote? i am so confuse *_*
Edit:
This is my php code.
$colname_Recordset1 = "-1";
if (isset($_GET['quote'])) {
$colname_Recordset1 = $_GET['quote'];
}
mysql_select_db($database_config, $config);
$query_Recordset1 = "SELECT a.*, b.book_name FROM bookstore a
LEFT OUTER JOIN book b ON a.id_book = b.id_book
WHERE a.quote LIKE '%'". $colname_Recordset1."%%'";
$Recordset1 = mysql_query($query_Recordset1, $config)
or die(mysql_error());
$row_Recordset1 = mysql_fetch_assoc($Recordset1);
$totalRows_Recordset1 = mysql_num_rows($Recordset1);
I think, if I understand correctly, that your query should be more like:
SELECT a.*, b.book_name
FROM bookstore a
LEFT OUTER JOIN book b ON a.id_book = b.id_book
WHERE a.quote LIKE '%'
If you are still getting a single result (where you know there is more than one result), you need to post the PHP code you are using to extract records from the DB.
You should fetch the result like this, reference http://www.php.net/manual/en/function.mysql-fetch-assoc.php
while ($row = mysql_fetch_assoc($Recordset1)) {
print_r($row);
}
and you should escape the user input with mysql_escape_string, the full php code
mysql_select_db($database_config, $config);
$filter = '';
if (isset($_GET['quote'])) {
$filter = " WHERE a.quote LIKE '%" . mysql_escape_string($_GET['quote']) . "%'";
}
$result = mysql_query(
"SELECT a.*, b.book_name FROM bookstore a
LEFT OUTER JOIN book b ON a.id_book = b.id_book" . $filter,
$config
) or die(mysql_error());
while ($row = mysql_fetch_assoc($result)) {
// If you need to output table, put the code here
print_r($row);
}
Related
First loop table
user_id | fname | lname
1 | first | emp
2 | second| emp
3 | third | emp
Second loop table
shift_id | employee_id
1 | 1
2 | 2
3 | 2
if($employees)
{
foreach ($employees as $employee)
{
if($employee['user_id'] == $shift['employee_id'])
{
echo ucwords($employee['fname']. ' ' .$employee['lname']);
}
}
}
I am getting the right result but I think there is some better way of writing this.
You can use joins in table. Left join means that the user line has to exists (because: LEFT) and the shifts enty is optional.
SELECT user.user_id, user.fname, user.lname, shifts.shift_id
FROM yourUserTable AS user
LEFT JOIN yourShiftsTable AS shifts ON(user.user_id = shifts.employee_id)
Now you get it in your initial array, as if you'd select it as one row from a table and no longer need to do tricks in PHP to combine information. If you can, always try to get the database to manage data, it does that way faster than PHP can.
Please note, the query could be a little off, I just wrote this out of the top of my head.
Just some test code I whipped up to test this from the information provided for this "Demonstration Code".
Note: I have used the mysqli class for the database (instantiating $db ) and have excluded the SQL Table setup.
What you would have had is something along the lines of this...
Case 1 - The original
$db = new mysqli('localhost', 'root', 'test', 'phptutorials_st26');
echo '<h2>Create $employees </h2>';
$query = "SELECT * FROM users";
$result = $db->query($query);
$employees = $result->fetch_all(MYSQL_ASSOC);
var_dump($employees);
echo '<h2>Create $shifts </h2>';
$query = "SELECT * FROM shifts";
$result = $db->query($query);
$shifts = $result->fetch_all(MYSQL_ASSOC);
var_dump($shifts);
echo '<h2>Using foreach on $employees and $shifts</h2>';
if ($employees) {
foreach ($employees as $employee) {
foreach ($shifts as $shift) {
if ($employee['user_id'] == $shift['employee_id']) {
echo ucwords($employee['fname'] . ' ' . $employee['lname']);
echo '<br>';
}
}
}
}
The Result from the above is
First Emp
Second Emp
Second Emp
Case 2 - Using a Join
Well using a join, as everyone has already stated, is the way to go...
$sql = "SELECT u.user_id, u.fname, u.lname, s.shift_id
FROM users AS u
JOIN shifts AS s ON(u.user_id = s.employee_id)
";
$result = $db->query($sql);
$employees = $result->fetch_all(MYSQL_ASSOC);
// To see what comes out because we always check things.
var_dump($joined_result);
(Don't ask me why I love using very abbreviated aliases for the table names! It's just "a thing".)
Then your "loop" simply becomes...
echo '<h2>Using foreach on join</h2>';
foreach ($employees as $employee) {
echo ucwords($employee['fname'] . ' ' . $employee['lname']);
echo '<br>';
}
And the result is...
First Emp
Second Emp
Second Emp
Case 2 - has reduced the code and only requires 1 Trip to the Database.
Does that help you any?
You could do it this way also. Its a little shorter.
SELECT TABLE1.FNAME, TABLE1.LNAME, TABLE2.EMPLOYEE_ID
FROM TABLE1, TABLE2
WHERE TABLE1.USER_ID = TABLE2.EMPLOYEE_ID;
I have been scratching my head for a very long time about this PHP code. I am trying to achieve something like
->Get each status
->Get each user in user's friends list
->Display status' from each user that is in the user's friends list
and repeat until there is no more. I have been looking for a solution for more a few days and it is really bugging me. Here is the code I tried:
EDIT: posted schema as requested
https://kjf-tech.net/files/schema.png
<?php
$connect = new MySQLi($DBhost,$DBuser,$DBpass,$DBname);
$querya = "SELECT * FROM statuses ORDER BY `id` DESC";
$result = mysqli_query($connect, $querya);
$ALLDATA = array();
$DBcon2 = new MySQLi($DBhost,$DBuser,$DBpass,$DBname);
if ($DBcon2->connect_errno) {
die("ERROR : -> ".$DBcon2->connect_error);
}
while ($record = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
array_push($ALLDATA, $record);
$queryb = "SELECT * FROM friendslist WHERE idOfPerson1='".$record['idOfUser']."' OR idOfPerson2='".$record['idOfUser']."' OR idOfPerson2='".$userRow['user_id']."' OR idOfPerson1='".$userRow['user_id']."' ORDER BY `id` DESC";
$result2 = mysqli_query($connect, $queryb);
$ALLDATA2 = array();
while ($record2 = mysqli_fetch_array($result2, MYSQLI_ASSOC)) {
array_push($ALLDATA2, $record2);
if($record['idOfUser'] == $userRow['user_id']) {
echo '<div>You Posted on '.$record['whenPosted'].'<br />'.$record['content'].'</div>';
}
elseif($record2['idOfPerson1'] == $userRow['user_id']) {
$query2 = $DBcon2->query("SELECT * FROM tbl_users WHERE user_id='".$record2['idOfPerson2']."'");
$userRow2=$query2->fetch_array();
echo '<div>'.$userRow2['username'].' Posted on '.$record['whenPosted'].'<br />'.$record['content'].'</div>';
}
elseif($record2['idOfPerson2'] == $userRow['user_id']) {
$query2 = $DBcon2->query("SELECT * FROM tbl_users WHERE user_id='".$record2['idOfPerson1']."'");
$userRow2=$query2->fetch_array();
echo '<div>'.$userRow2['username'].' Posted on '.$record['whenPosted'].'<br />'.$record['content'].'</div>';
}
}
mysqli_free_result($result2);
}
$DBcon2->close();
mysqli_free_result($result);
?>
Your schema looks good, but let's take another look at the relations. I'm going to rename some of the columns for convenience.
Users:
+- user_id
| user_name
|
|
| Friendships:
| fid
+- user_id
| friend_id --------+
| friendship_start |
| |
| |
| Statuses: |
| sid |
+- user_id ----------+
post_date
content
If you just wanted to find statuses of your friends, the query would look thus:
SELECT statuses.content
FROM friendships, statuses
WHERE friendship.user_id=? AND
friendships.friend_id = statuses.user_id
You would, of course, bind the appropriate user_id value when you ->prepare() the statement.
(See http://php.net/manual/en/mysqli.prepare.php for the proper way to do sql. You don't ever want to do something like mysql_query("select * from table where id=".$_POST['id']) because it's open to SQL injection)
Unfortunately, though, this does not include your own status in the query results. We'll have to do a little more work on the query...
SELECT statuses.content
FROM friendships, statuses
WHERE
( friends.user_id = ? AND
friends.friend_id = stuatuses.user_id )
OR
statuses.user_id = ?
ORDER BY statuses.post_date DESC
So far, so good... but we don't have the names nor the post date. The post date is easy, just add that to the select:
SELECT statuses.content, statuses.post_date
To add the name, we have to get data from Users also.
SELECT users.user_name, statuses.content, statuses.post_date
FROM users, friendships, statuses
WHERE
users.user_id = ? AND
(
( users.user_id = friendships.user_id AND
friendships.friend_id = statuses.user_id )
OR
statuses.user_id = users.user_id
)
ORDER BY statuses.post_date DESC
And there you have it; the database does all the work for you. No need for nested queries and such. This will just give you the simple list to print on your page. Please keep in mind that this is off the top of my head, so you may have to tweak it if I overlooked something.
I am working on a webpage that displays list of shops. I have 2 tables, shops and shops_sched.
+-shops-+
| id | title |
+-------------shops_sched-------------+
| id | shops_id | start_date | end_date |
Basically, the program displays the list of shops from the shops table, but if a value from shops.id is found # shops_sched.shops_id the page must output shops.title + 'coming soon'.
I understand this will be easy if I just place the date fields inside the table shops but due to programming restrictions I can't. I'm working on an existing project and I'm trying to minimize changes to existing functions. I can create new PHP functions if necessary though.
In addition, I need to get all the entries from the shops table. The Program needs to return all shops.title but for those shops whose id is found # shops_sched.shops_id, the program will have to return shops.title + "Coming Soon".
must output shops.title + 'coming soon'.
So do it like this:
$shops.title = "Donut-John";
echo $shops.title." coming soon";
To join the shops and shops_sched table
$query = SELECT `title` FROM `shops` JOIN `shops_sched` ON `shops`.`id` = `shops_sched`.`shops_id` WHERE `shops_sched`.`shop_id` = 5;
$result = mysql_query($query);
while($row = mysql_fetch_array($result) {
echo $row['title'] . 'coming soon';
}
For more about join you also can refer the following link
https://dev.mysql.com/doc/refman/5.0/en/join.html
http://www.tutorialspoint.com/mysql/mysql-using-joins.htm
Join the two tables :
SELECT shops.title
FROM shops INNER JOIN shops_sched ON shops.id = shops_sched.shops_id
The query should return only the the shops inside shops_sched
EDIT :
If I understood your question, try this :
SELECT shops.title, shops_sched.id
FROM shops LEFT JOIN shops_sched ON shops.id = shops_sched.shops_id
This will return all the titles, and the shops_sched.shops_id if shops.id = shops_sched.shops_id. In the other case, the hops_sched.shops_id will be null
Then you fetch the rows and if the second row is not null, print title + coming soon
Sample code : (Something like this)
$query = "SELECT `title`, 'shops_id' FROM `shops` LEFT JOIN `shops_sched` ON `shops`.`id` = `shops_sched`.`shops_id` WHERE `shops_sched`.`shop_id`";
$result = mysql_query($query);
while($row = mysql_fetch_array($result) {
if($row['shops_id'] != "")
{
echo $row['title'] . ' coming soon';
}
else
{
echo $row['title'];
}
}
I'm very new to PHP/MYSQL and find this quite difficult to explain, so hopefully someone will understand what I'm trying to do. I have a database that collects information on artists and songs. I want to be able to link the artists to the song and display the "credit" with the song information.
I have a database with tables similar to this:
Artist
| artist_id, artist_name
Credits
| credit_id, credit_name
Song
| song_id, song_name
Credit_To_Artist
| credit_id, artist_id, song_id
Example data:
Artist
| 2, Peter Mark
Artist
| 5, Mette Christiansen
Credits
| 1, Producer
Credits
| 2, Writer
Credits
| 3, Vocalist
Song
| 23, The Game
Credit_To_Artist
| 1, 2, 23
Credit_To_Artist
| 2, 2, 23
Credit_To_Artist
| 3, 5, 23
I have created a page "song.php" that displays information on each song using mysql_real_escape_string to get the song ID from the URL:
$id = mysql_real_escape_string($_GET['id']);
if (!$id) {
die('Please provide an id!');
}
$query = "SELECT * FROM `Credit_To_Artist` AS c2a
INNER JOIN `Credits` AS cr ON cr.credit_id = c2a.credit_id
LEFT OUTER JOIN `Artist` AS a ON a.artist_id = c2a.artist_id
LEFT OUTER JOIN `Song` AS s ON s.song_id = c2a.song_id
WHERE c2a.song_id = $id";
$res = mysql_query($query);
$row = mysql_fetch_assoc($res);
The issue I'm having is I want to be able to list all of the artists linked to that song, and all of their credits in brackets next to it. Since there are more than one artist linked to each song, and most of them have more than one credit (producer, writer, vocalist etc), I have no idea how to write a loop function that shows both of these. Below is my attempt to show what I mean, although it obviously doesn't work:
while ($row = mysql_fetch_array($res)) {
$artist = $row[artist_name];
echo "$artist";
while ($row = mysql_fetch_array($res)) {
$credit = $row[credit_name];
echo "$credit";
}
echo "<br />";
}
This is what I'd ideally like to achieve from the example data above:
Song: The Game
Credits: Peter Mark (Producer, Writer)
Mette Christiansen (Vocalist)
You have two options:
GROUP_CONCAT(..)
You can use GROUP_CONCAT(..). This mysql function groups values in a column that are in each group. You would alter the sql to group by artist_id in this case.
SELECT a.artist_name as aname, GROUP_CONCAT(c.credit_name) as credits
FROM Credits_To_Artist as c2a
JOIN Artist as a ON c2a.artist_id = a.artist_id
JOIN Credits as c ON c2a.credit_id = c.credit_id
GROUP BY c2a.credit_id
Your rows would look like:
Array( "aname" => "name",
"credits" => "function 1,function 2" )
The biggest problem with GROUP_CONCAT is that if you have to concat a lot of values together, it might exceed the maximum width of the row. This does not seem to be the case for your problem. You would not need a loop with this approach.
Adding to array
If you keep the query as it is, you have a row for each 'credit'. You can prepare your data by adding it to an Array, then use implode(..) in php to add commas.
$artists = Array();
while( $row = mysql_fetch_array($res) ) {
$artist = $row[artist_name];
$credit = $row[credit_name];
if( !array_key_exists( $artist, $artists ) ) {
$artists[$artist] = Array();
}
$artists[$artist][] = $credit;
}
foreach( $artists as $artist => $creditarr ) {
$credits = implode( ", ", $creditarr );
echo "{$artist} ({$credits})<br>";
}
You'll find that preparing your data in an array will sometimes be much faster than writing a query that does the same thing. I would probably choose the latter solution.
Let's start with the tables, here is what i think you should do
artist | id, name
song | id, title
credit | id, credit
song_artists | id, song_id, artist_id
credit_to_artists | id, song_artists_id, credit_id
Should be the way to handle the kind of relationship you want.
And here is the PHP code, it might not be the most efficient one, but it will do the job
$query = "SELECT * FROM song_artists WHERE song_id = $id_from_link";
$result = mysql_query($query);
while($row = mysql_fetch_array($result))
{
$artistQuery = "SELECT * from artist WHERE id = {$row['artist_id']}";
$artistResult = mysql_query($artistQuery);
while($artistRow = mysql_fetch_array($artistResult))
{
echo "The Artist: " . $artistRow['name'];
}
echo $songArtistId;
$creditToArtistQuery = "SELECT * FROM credit_to_artists WHERE song_artists_id = {$row['id']}";
$creditToArtistResult = mysql_query($creditToArtistQuery);
if(mysql_num_rows($creditToArtistResult)>0)
{
echo " { ";
$isFirstCredit = true;
while($creditToArtistRow = mysql_fetch_array($creditToArtistResult))
{
$creditQuery = "SELECT * FROM credit WHERE id = {$creditToArtistRow['credit_id']}";
$creditResult = mysql_query($creditQuery);
while($creditRow = mysql_fetch_array($creditResult))
{
if($isFirstCredit)
{
echo $creditRow['credit'];
$isFirstCredit = false;
}
else
{
echo ", " .$creditRow['credit'];
}
}
}
echo " } <br />";
}
}
I am trying to query five tables. I am able to query one of the tables with
$query = "SELECT * FROM Stats_player WHERE player='$user'";
However, when I try to query another table with
$query = "SELECT * FROM Stats_player, Stats_block WHERE player='$user'";
the website breaks. Here is the code I am using to echo the data on the screen
<?php
if ($result = $mysqli->query($query)) {
echo "<img src=\"https://minotar.net/avatar/{$user}/100\"><h1>{$user}</h1><br/>";
while ($row = $result->fetch_assoc()) {
//variables
$play_time = $row['playtime']/3600;
$play_time = round($play_time, 1);
$xpgained = $row['xpgained'];
$damagetaken = $row['damagetaken'];
$toolsbroken = $row['toolsbroken'];
$itemscrafted = $row['itemscrafted'];
$itemseaten = $row['omnomnom'];
$commandsused = $row['commandsdone'];
$teleports = $row['teleports'];
$itemspickedup = $row['itempickups'];
$itemsdroped = $row['itemdrops'];
$lastseen = date("F j, Y ", strtotime($row['lastjoin']));
//end of variables
echo "<p>Time on Server: {$play_time} HRS</p>";
echo "<p>Last Seen: {$lastseen}";
echo "<p>Commands Used: {$commandsused}";
echo "<p>XP Gained: {$xpgained}";
echo "<p>Blocks broken: {$row['blockID']}"; //this is data from the table Stats_block
}
$result->free();
}
$mysqli->close();
?>
Any ideas on how I might do this?
Table structor of Stats_player:
| counter | player | Playtime |
Stats_block is:
| counter | player | blockID |
$query = "SELECT * FROM Stats_player, Stats_block WHERE player='$user'"
That's very likely wrong. You should use a JOIN operator.
Here, you are just doing a cartesian products of the two tables, that's hardly what you want. And that may overrun your resource (memory etc.) if the tables have a lot of rows.
Something like
$query = "SELECT * FROM Stats_player p, Stats_block b
WHERE p.block_id = b.id AND p.player='$user'"
or
$query = "SELECT * FROM Stats_player p INNER JOIN Stats_block b ON p.block_id = b.id
WHERE p.player='$user'"
or maybe LEFT OUTER JOIN...
The exact query will depend on your schema.
Without seeing the structure of both tables, something like this could work.
SELECT columnList
FROM Stats_player a
LEFT JOIN Stats_block b ON b.player = a.player
WHERE a.player = '$user'
Have you tried something like this:
SELECT
table1.field1, table1.field2, table2.field1, table2.field2
FROM
table1, table2
WHERE
table1.field1 = " " and table2.field1 = " ";