I have this code, is working in all the tester I'm using for regex, but later, in my real php code it doesn't work. What I want is to replace the number in the link for something else
$value='/something.html?helperid=252';
//patern
$patternHelperId='/(?<=helperid=)\d{1,}/';
//replace
preg_replace($patternHelperId, "mynewreplacement", $value);
//debug
echo "\n$value\n";// /something.html?helperid=252????? aggain???
What's wrong??
You should assign the result of preg_replace back to $value, like this:
$value = preg_replace($patternHelperId, "mynewreplacement", $value);
And, as a sidenote, \d{1,} can be replaced with \d+.
preg_replace returns the result. It does not modify the variable in-place
You have forgotten to take the result of the preg_replace function:
$newValue = preg_replace($patternHelperId, "mynewreplacement", $value);
echo "\n$newvalue\n";
A better pattern:
$patternHelperId='/helperid=\K\d++/';
Related
i've a little problem.
I want to check the numer of post like this:
http://xxx.xxxxxx.net/episodio/168
this is part of my code, only need the number check:
[...]
if(preg_match('#^http://horadeaventura.enlatino.net/episodio/[0-9]',trim($url))){
[...]
Can help me?
Thanks!
If you want to do it with preg_match:
$url = 'http://horadeaventura.enlatino.net/episodio/168';
if(preg_match('#^http://horadeaventura.enlatino.net/episodio/([0-9]+)#',trim($url), $matches)){
$post = $matches[1];
echo $post;
}
So, basically: I added an end delimiter (#), changed "[0-9]" to "([0-9])+", added ", $matches" to capture the matches. Of course it can be done better and using other options than preg_match. But I wanted to make your snippet work - not rewrite it.
If you don't have your heart set on using preg_match(), you could do
$string = "http://xxx.xxxxxx.net/episodio/168";
$array = explode("/", $string);
echo end($array);
which will output
168
this is assuming the number you are looking for will always be the last section of the url string
Or, you can just check for number, on last position:
if(preg_match('#[0-9]+$#',trim($url),$match)){
print_r($match);
}
I am using preg_match() to extract pieces of text from a variable, and let's say the variable looks like this:
[htmlcode]This is supposed to be displayed[/htmlcode]
middle text
[htmlcode]This is also supposed to be displayed[/htmlcode]
i want to extract the contents of the [htmlcode]'s and input them into an array. i am doing this by using preg_match().
preg_match('/\[htmlcode\]([^\"]*)\[\/htmlcode\]/ms', $text, $matches);
foreach($matches as $value){
return $value . "<br />";
}
The above code outputs
[htmlcode]This is supposed to be displayed[/htmlcode]middle text[htmlcode]This is also supposed to be displayed[/htmlcode]
instead of
[htmlcode]This is supposed to be displayed[/htmlcode]
[htmlcode]This is also supposed to be displayed[/htmlcode]
and if have offically run out of ideas
As explained already; the * pattern is greedy. Another thing is to use preg_match_all() function. It'll return you a multi-dimension array of matched content.
preg_match_all('#\[htmlcode\]([^\"]*?)\[/htmlcode\]#ms', $text, $matches);
foreach( $matches[1] as $value ) {
And you'll get this: http://codepad.viper-7.com/z2GuSd
A * grouper is greedy, i.e. it will eat everything until last [/htmlcode]. Try replacing * with non-greedy *?.
* is by default greedy, ([^\"]*?) (notice the added ?) should make it lazy.
What do lazy and greedy mean in the context of regular expressions?
Look at this piece of code:
preg_match('/\[htmlcode\]([^\"]*)\[\/htmlcode\]/ms', $text, $matches);
foreach($matches as $value){
return $value . "<br />";
}
Now, if your pattern works fine and all is ok, you should know:
return statement will break all loops and will exit the function.
The first element in matches is the whole match, the whole string. In your case $text
So, what you did is returned the first big string and exited the function.
I suggest you can check for desired results:
$matches[1] and $matches[2]
I have the following in a variable, |MyString|
I want to strip the leading | and the ending | returning MyString
What is the quickest and non intensive way of doing this?
Easiest way is probably
$result = trim($input, '|');
http://docs.php.net/trim
e.g.
<?php
$in = '|MyString|';
$result = trim($in, '|');
echo $result;
prints MyString
Checkout the str_replace function in PHP http://php.net/manual/en/function.str-replace.php
this should remove all '|' characters:
str_replace('|','',$myString)
You may be able to use a regular expression to only remove the first and last '|' or alternatively using the String trim() function may also work:
http://www.php.net/manual/en/function.trim.php
So, something like this:
$trimmedMyString = trim($myString, "|");
Worth trying anyway.
Basically from a database I am getting data that is formatted like this nameofproject101 Now this could continue to increase so eventually it could be nameofproject1001 my question is how can I trim off the number and just get the name of the project. I thought about using substr but since I dont know the length always I cant really do that. Since the numbers differ I dont think I can use str_replace is there any way to accomplish this?
It sounds like something is way off about your database scheme. You should probably try to do refactor/normalize your scheme.
But in the meantime, you can use rtrim() to trim all numbers off of the right side.
$val = rtrim($val, '0123456789');
Examples
Input Output
nameofproject1001 nameofproject
nameofproject nameofproject
n4me0fproj3ct1001 n4me0fproj3ct
for string like, project12V123, It is better to do this
$text = `project12V123`;
$text = preg_replace('/([\w]+)([^0-9])([0-9])+$/', '$1$2', $text);
Will return:
Project12V
or use rtrim:
$text = rtrim($text,'0123456789');
You should definitely use regular expressions:
$fullname = "nameofproject101";
preg_match("/([a-z]+)([0-9]+)/i", $fullname, $matches);
$name = $matches[1];
$number = $matches[2];
echo "'$fullname' is '$name' followed by '$number'";
preg_replace('/[^a-z]/i', '', $string);
Would it be possible to make a regex that reads {variable} like <?php echo $variable ?> in PHP files?
Thanks
Remy
The PHP manual already provides a regular expression for variable names:
[a-zA-Z_\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*
You just have to alter it to this:
\{[a-zA-Z_\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*\}
And you’re done.
Edit You should be aware that a simple sequential replacment of such occurrences as Ross proposed can cause some unwanted behavior when for example a substitution also contains such variables.
So you should better parse the code and replace those variables separately. An example:
$tokens = preg_split('/(\{[a-zA-Z_\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*\})/', $string, -1, PREG_SPLIT_DELIM_CAPTURE);
for ($i=1, $n=count($tokens); $i<$n; $i+=2) {
$name = substr($tokens[$i], 1, -1);
if (isset($variables[$name])) {
$tokens[$i] = $variables[$name];
} else {
// Error: variable missing
}
}
$string = implode('', $tokens);
It sounds like you're trying to do some template variable replacement ;)
I'd advise collecting your variables first, in an array for example, and then use something like:
// Variables are stored in $vars which is an array
foreach ($vars as $name => $value) {
$str = str_replace('{' . $name . '}', $value, $str);
}
{Not actually an answer, but need clarification}
Could you expand your question? Are you wanting to apply a regex to the contents of $variable?
The following line should replace all occurences of the string '{variable}' with the value of the global variable $variable:
$mystring = preg_replace_callback(
'/\{([a-zA-Z][\w\d]+)\}/',
create_function('$matches', 'return $GLOBALS[$matches[1]];'),
$mystring);
Edit: Replace the regex used here by the one mentioned by Gumbo to precisely catch all possible PHP variable names.
(in comments) i want to be able to type {variable}
instead of <?php echo $variable ?>
Primitive approach: You could use an external program (e.g. a Python script) to preprocess your files, making the following regex substitution:
"{([a-zA-Z_\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*)}"
with
"<?php echo $\g<1> ?>"
Better approach: Write a macro in your IDE or code editor to automatically make the substitution for you.