How can I select one row from that table http://i.stack.imgur.com/27cu9.jpg where values of 'user_1' and 'user_2' may look like
user_1 user_2
1 2
2 1
In other words I want to select a field that contains 2 users with submitted=1 no matter in which field the value is.
Here is a simple query that does this:
select *
from t
where submitted = 1 and 2 in (user_1, user_2)
If I understood your question, I think you need to JOIN the table on itself if you are trying to return rows that have corresponding users (1,2) and (2,1):
select t1.*
from yourtable t1
join yourtable t2 on
t1.user_1 = t2.user_2 and t1.user_2 = t2.user_1
SQL Fiddle Demo
If however you are just trying to see if user 2 exists in either of the fields, then look at Gordon's post.
Use this:-
select * from tblname as t1, tblname as t2 where
t1.user_1 = t2.user_2 and t1.user_2 = t2.user_1 and t1.user_1<>t1.user_2
EDIT:-
Updated the query so that the rows with the same values do not appear in the result.
Related
first of all i have 1 table in database.
1)tags :
id name
1 theme1=test1
2 theme1=test2
3 theme1=test3
4 theme2=test1
5 theme2=test2
6 theme2=test3
And i have bunch of id of tags in array. like 1,3.
Now,
1)select name from tags where id=1
result: theme1=test1
(now using wildcard)
2)select id from tags where name like 'theme_test1'
result : 1,4
(here 'theme_test1' need to take from query1)
I am getting output proper but need to use 2 query.I want to do this in single query.
Thanks
SELECT id FROM tags WHERE name LIKE (
SELECT CONCAT(SUBSTRING(name,1,5),'__',SUBSTRING(name,8)) FROM tags WHERE id=1
)
Returns 1,4
But Two queries (or a refactor) might be a better option
If you whant to get the id with the same value you can try this:
SELECT t2.* FROM yourtable t1
JOIN youtable t2 on ON t2.name like concat(substr(t1.name,1,5), '%', substr(t1.name,8))
WHERE t1.id=1;
For performance better use this:
SELECT t.id
FROM r
INNER JOIN r AS t ON t.name LIKE CONCAT('theme_=test', SUBSTRING(r.name,-1))
WHERE r.id = '1'
r is your table in this case.
NOTE: this answer isn't valid in case that you have theme1=test1 and theme1=test10 values.
maybe you can use query :
select id from tags where name = (select name from tags where id = 1 ).
You can try that query.
I have two tables first and second.
first Table:
ID NAME ADDRESS
1 test testing address
2 test1 testing address
3 test2 testing address
4 test3 testing address
second Table:
T_ID Partner_id date
1 2 12345678
3 4 32164584
If input T_id is given. Then corresponding Partner_id is taken and it is compared with the ID from first table and corresponding row should be selected.
Can you please tell me.
In php I can write this with two queries but I want it to be in a single query.
Queries in php:
$q=mysqli_query($conn, "SELECT Partner_id from second where T_ID=1");
$qa=mysqli_fetch_array($q);
$w=mysqli_query($conn, "SELECT * from first where ID=$qa[0]");
But, how to combine this two statements?
The specified result can be returned using a query with a join operation.
SELECT f.*
FROM first f
JOIN second s
ON s.Partner_id = f.ID
WHERE s.T_ID=1
Note that there is a potential for this to return more rows that the original, if the first query returns more than one row. (That is, we don't assume that T_ID is unique in second, or that every row with a given T_ID value will have identical values for Partner_id.)
There are other query patterns that will return an equivalent result, but the join operation is the normative pattern.
try to use union ,see this this link
where The SQL UNION operator combines the result of two or more SELECT statements.
SELECT * FROM first WHERE ID IN( SELECT Parent_id FROM second WHERE T_ID = 1 )
or
SELECT * FROM first WHERE ID = ( SELECT Parent_id FROM second WHERE T_ID = 1 )
SELECT * FORM first_table AS f
JOIN second_table AS s
ON s.parent_id =f.id
WHERE s.T_ID = $id
I've got a problem with two mysql tables. I've done some code and I think I am close to the solution, but I'm not sure if this is right.
So here are the two tables:
Table 1: Blogs
Columns: ID, agp_name, agp_url, agp_username, agp_password
Table 2: Keywords
Columns: ID, agp_user_id, agp_order_id, agp_blog_id, agp_keywords, agp_keywords_date
What I want is to get one random row from Table1 based on the following condition: if the agp_keyword match one of the keywords in the last 5 days then do not include into the result.
So far I did this:
SELECT
t1.agp_user_id, t1.agp_order_id, t1.agp_blog_id, t1.agp_keywords, t1.agp_keywords_date, t2.agp_name, t2.agp_url, t2.agp_username, t2.agp_password
FROM table1 AS t1
INNER JOIN (
SELECT ID, agp_name, agp_url, agp_username, agp_password, agp_blogposts
FROM table2
) AS t2 ON t1.agp_blog_id = t2.ID
WHERE
t1.agp_keywords NOT LIKE "%keyword1%" AND
t1.agp_keywords NOT LIKE "%keyword2%" AND
t1.agp_keywords_date BETWEEN (1369440000 AND 1369932432)
ORDER BY RAND() LIMIT 1
However this does not work correctly. Any help will be appreciated.
Try this, your original specifications were a bit confusing :(
SELECT keywords.agp_user_id,
keywords.agp_order_id,
keywords.agp_blog_id,
keywords.agp_keywords,
keywords.agp_keywords_date,
blogs.agp_name,
blogs.agp_url,
blogs.agp_username,
blogs.agp_password
FROM blogs
LEFT JOIN keywords
ON keywords.agp_blog_id = blogs.ID
AND keywords.agp_keywords NOT LIKE "%keyword1%"
AND keywords.agp_keywords NOT LIKE "%keyword2%"
AND FROM_UNIXTIME(keywords.agp_keywords_date) > (DATE_SUB(CURDATE(), INTERVAL 5 DAYS))
ORDER BY RAND() LIMIT 1
I'm very new with SQL and need assistance on how I can accomplish this task using the correct query.
I have 2 tables that I need to use. Table "TB1" has:
id Name
1 bob
2 blow
3 joe
table "TB2" has:
compid property
1 bob
2 blow
I am trying to get which compid is missing in "TB2" and insert it from "TB1"
the query I am doing is:
SELECT id, name from TB1, TB2 where id <> compid
what I get is 2 ouputs of Id 1, and 2, and 3 outputs from id 3. by using php:
for($i=0;$i <= mysql_num_rows($comp)-1; $i++)
{
echo mysql_result($comp, $i, 0)."<br>";
}
and I expected the ouput 3 but instead got this:
1
1
2
2
3
3
3
I understand its comparing all the rows within the table but is there a way to achieve what I am looking for?
Thanks for your time.
You are performing an implicit Cartesian JOIN which results in every row against every other row. You need to specify what attribute JOINs the two tables.
Using implicit syntax (not recommended):
SELECT id, name
FROM TB1, TB2
WHERE id <> compid
AND TB1.Name = TB2.property <-- Column join
Using explicit syntax:
SELECT id, name
FROM TB1
JOIN TB2
ON TB2.property = TB1.Name <-- Column join
WHERE id <> compid
To accomplish your goal you would need something along the lines of:
SELECT TB1.id, TB1.name
FROM TB1
LEFT JOIN TB2
ON TB2.property = TB1.Name
WHERE TB2.compid IS NULL
See it in action
It's best practice to always alias the columns you select to prevent ambiguity.
To select it you can do:
SELECT *
FROM TB1
WHERE id NOT IN (
SELECT compid
FROM TB2
);
There might be an easy solution here, but it seems to have me tripped up. I'm trying to query a table based on an array of values in two columns. Here is the pertinent table structure and sample data
comment table
id, userId, articleId .... etc etc
article table
id, userId .... etc etc
Data: UserIds = 3, 10. ArticleIds = 1, 2
Let's say I'm trying to find all the comments for a particular set of article IDs: 1,2
I can easily use this query
select * from comments WHERE articleId IN(1,2)
However, here is where it gets complex. I have a query that executes prior to the comments query that determines the appropriate article IDs. Those IDs are in an array. Also in an array are the corresponding user IDs for each article.
What I want to do now is query the comments table for only the articles in the array (1,2) AND only for those comments made by the original author (3, 10).
The simple query above will bring back all the comments for articleId 1 and 20. So for example I can't figure out where to add another conditional that says onyl comments for articleId 1, 20 AND corresponding userId, 3, 10.
Any help or suggestions would be much appreciated!
I think the simplest way is to write:
SELECT comments.*
FROM articles
JOIN comments
ON articles.id = comments.articleId
AND articles.userId = comments.userId
WHERE articles.id IN (1, 2)
;
The AND articles.userId = comments.userId clause is what enforces your "only for those comments made by the original author" requirement.
Alternatively, you can use an EXISTS clause:
SELECT *
FROM comments
WHERE articleId IN (1, 2)
AND EXISTS
( SELECT 1
FROM articles
WHERE id = comments.articleId
AND userId = comments.userId
)
;
or a single-row subquery:
SELECT *
FROM comments
WHERE articleId IN (1, 2)
AND userId =
( SELECT userId
FROM articles
WHERE id = comments.articleId
)
;
Have you tried just
select * from comments WHERE articleId IN(1,2) and authorId in (3,10)
If not, please update your question why it's so.
You can add as many IN statements as you want:
select * from comments WHERE articleId IN(1,2) AND userId IN (3,10)
Can't you just make the query that runs first a subquery within your stated query:
SELECT * FROM `comments` WHERE `articleId` IN(1,2) AND `userId` IN (__subquery__)
-- you can use subquery
select * from comments WHERE articleId IN(1,2)
and userId in ( select userId from article where id in (1,2) )