I have two tables first and second.
first Table:
ID NAME ADDRESS
1 test testing address
2 test1 testing address
3 test2 testing address
4 test3 testing address
second Table:
T_ID Partner_id date
1 2 12345678
3 4 32164584
If input T_id is given. Then corresponding Partner_id is taken and it is compared with the ID from first table and corresponding row should be selected.
Can you please tell me.
In php I can write this with two queries but I want it to be in a single query.
Queries in php:
$q=mysqli_query($conn, "SELECT Partner_id from second where T_ID=1");
$qa=mysqli_fetch_array($q);
$w=mysqli_query($conn, "SELECT * from first where ID=$qa[0]");
But, how to combine this two statements?
The specified result can be returned using a query with a join operation.
SELECT f.*
FROM first f
JOIN second s
ON s.Partner_id = f.ID
WHERE s.T_ID=1
Note that there is a potential for this to return more rows that the original, if the first query returns more than one row. (That is, we don't assume that T_ID is unique in second, or that every row with a given T_ID value will have identical values for Partner_id.)
There are other query patterns that will return an equivalent result, but the join operation is the normative pattern.
try to use union ,see this this link
where The SQL UNION operator combines the result of two or more SELECT statements.
SELECT * FROM first WHERE ID IN( SELECT Parent_id FROM second WHERE T_ID = 1 )
or
SELECT * FROM first WHERE ID = ( SELECT Parent_id FROM second WHERE T_ID = 1 )
SELECT * FORM first_table AS f
JOIN second_table AS s
ON s.parent_id =f.id
WHERE s.T_ID = $id
Related
I have table like this :
user_id field_id value
1 1 toto
2 1 tata
2 2 tata Job
user_id is the id of my users, field_id is the id of the information about the user (name, job, etc.) and value is the value.
I use a searchBar in HTML/PHP with 2 fields : 'name' and 'job'.
When someone search user using this two fields I need to retrieve the user id that matches these two conditions.
My question is :
How to get in SQL all user_id that match with two condition in one like this:
(field_id=1 and value=tata) AND (field_id=2 and value=tata's Job)
Thank you and have a good day !
SQL executes the WHERE logic for each row, not for the entire set. And fields cannot have more than one value. So, you need to use an OR statement instead of an AND to capture both conditions:
Select User_Id, Field_Id, Value
From YourTable
Where (field_id = 1 And value = 'tata')
Or (field_id = 2 And value = 'tata Job')
One method uses aggregation:
select user_id
from t
where (field_id = 1 and value = 'tata') or (field_id = 2 and value = 'tata''s Job')
group by user_id
having count(distinct field_id) = 2;
You can use IN statement, for example: Your table name is users
SELECT user_id
FROM users
WHERE field_id IN (1,2) AND `value` IN ('tata','tata\'s Job')
I would like to get one value instead of all values when they have the same name.
within an sql query. Im using fullcalendar. and have two tables one for the events(evenement) and one for the receiver(evenementontvanger).
evenementontvanger:
id idEvent
1 231
2 231
3 231
evenement:
id title
231 hello
I would like to show only one title not 3
my sql query:
"SELECT
*
FROM
`evenement`
JOIN
`evenementontvanger` ON `evenementontvanger`.`idEvent` = `evenement`.`id`
WHERE
`idEvent` = `evenement`.`id`"
You can use distinct to do so as
SELECT distinct `evenementontvanger`.`idEvent`,`evenement`.`title`
FROM
`evenement`
JOIN
`evenementontvanger` ON `evenementontvanger`.`idEvent` = `evenement`.`id`
WHERE
`idEvent` = `evenement`.`id`;
How ever the above will not bother about idWerknemer and if you want to display them as group use Group_concat as
SELECT `evenementontvanger`.`idEvent`,
`evenement`.`title`,
group_concat(`evenementontvanger`.`idWerknemer`) as `idWerknemer`
FROM
`evenement`
JOIN
`evenementontvanger` ON `evenementontvanger`.`idEvent` = `evenement`.`id`
WHERE
`idEvent` = `evenement`.`id`
Group By `evenementontvanger`.`idEvent`
Check the demo here http://sqlfiddle.com/#!2/290b4/13
Use SELECT DISTINCT on your query to eliminate duplicates :
The ALL and DISTINCT options specify whether duplicate rows should be
returned. ALL (the default) specifies that all matching rows should be
returned, including duplicates. DISTINCT specifies removal of
duplicate rows from the result set. It is an error to specify both
options. DISTINCTROW is a synonym for DISTINCT.
From MySQL docs
use either top 1
OR
select distinct
How can I select one row from that table http://i.stack.imgur.com/27cu9.jpg where values of 'user_1' and 'user_2' may look like
user_1 user_2
1 2
2 1
In other words I want to select a field that contains 2 users with submitted=1 no matter in which field the value is.
Here is a simple query that does this:
select *
from t
where submitted = 1 and 2 in (user_1, user_2)
If I understood your question, I think you need to JOIN the table on itself if you are trying to return rows that have corresponding users (1,2) and (2,1):
select t1.*
from yourtable t1
join yourtable t2 on
t1.user_1 = t2.user_2 and t1.user_2 = t2.user_1
SQL Fiddle Demo
If however you are just trying to see if user 2 exists in either of the fields, then look at Gordon's post.
Use this:-
select * from tblname as t1, tblname as t2 where
t1.user_1 = t2.user_2 and t1.user_2 = t2.user_1 and t1.user_1<>t1.user_2
EDIT:-
Updated the query so that the rows with the same values do not appear in the result.
i am trying to run this query. but it shows either 1 row or give error query result having more than 1 row.
select * from abc where id=(select nameid from xyz where name like '%abc%')
help me.
i am executing a query where i get name, father name and schoolid from table abc. now i want school name from table2 by running another query in it but in all time it shows 1
Use the IN to fetch the more than 1 row:
select * from abc where id IN (select nameid from xyz where name like '%abc%');
EDIT:
select a.*, x.school_name from abc a left join xyz x on a.id = x.nameid where name like '%abc%';
try this with IN to get more then one row
select * from `abc` where id in (select nameid from xyz where name like '%abc%')
This should be
select * from abc where id IN (select nameid from xyz where name like '%abc%')
Use IN mysql clause.
SELECT * FROM abc WHERE id IN (SELECT nameid FROM xyz WHERE name LIKE '%abc%')
because where condition only check for one single value but you were comparing it with array of data returned by subquery.
What you were doin is
if($value = array(1,2,3))
which will always return false so you need to use something which enable you to look into array and give the result.
In other word comparison will only perform on once value like one = one not on one = array('one',two)
so IN clause will do that in MySQL.
I'm very new with SQL and need assistance on how I can accomplish this task using the correct query.
I have 2 tables that I need to use. Table "TB1" has:
id Name
1 bob
2 blow
3 joe
table "TB2" has:
compid property
1 bob
2 blow
I am trying to get which compid is missing in "TB2" and insert it from "TB1"
the query I am doing is:
SELECT id, name from TB1, TB2 where id <> compid
what I get is 2 ouputs of Id 1, and 2, and 3 outputs from id 3. by using php:
for($i=0;$i <= mysql_num_rows($comp)-1; $i++)
{
echo mysql_result($comp, $i, 0)."<br>";
}
and I expected the ouput 3 but instead got this:
1
1
2
2
3
3
3
I understand its comparing all the rows within the table but is there a way to achieve what I am looking for?
Thanks for your time.
You are performing an implicit Cartesian JOIN which results in every row against every other row. You need to specify what attribute JOINs the two tables.
Using implicit syntax (not recommended):
SELECT id, name
FROM TB1, TB2
WHERE id <> compid
AND TB1.Name = TB2.property <-- Column join
Using explicit syntax:
SELECT id, name
FROM TB1
JOIN TB2
ON TB2.property = TB1.Name <-- Column join
WHERE id <> compid
To accomplish your goal you would need something along the lines of:
SELECT TB1.id, TB1.name
FROM TB1
LEFT JOIN TB2
ON TB2.property = TB1.Name
WHERE TB2.compid IS NULL
See it in action
It's best practice to always alias the columns you select to prevent ambiguity.
To select it you can do:
SELECT *
FROM TB1
WHERE id NOT IN (
SELECT compid
FROM TB2
);