I am trying to display all records with field_featured = 1 to start at the top of my listing ... and all the others to display at RAND()
So...
SELECT * FROM myTable
If (field_featured = 1 then ORDER BY field_featured) OTHERWISE (ORDER BY RAND() )
How can I do this?
Try this:
ORDER BY (field_fieatured=1) DESC, RAND()
Related
Is possible, and how to ask MySQL for
SELECT * FROM my_table ORDER by row_id DESC LIMIT 8
get the last 8, newest record from my table, with randomized order for PHP showing method
$results = $mysqli->query($query);
while($row = $results->fetch_assoc()) {
echo $row['my_col_name'];
}
Colud I, and where put the rand() in my SQL query?
Without randomize I get last 8 rows ORDERED 10,9,8,7,6,5,4,3
I want to get in the following order:
9,7,5,4,6,10,3,8;
8,7,3,6,10,9,5,4
...
You can place it inside another select:
SELECT * FROM (SELECT * FROM my_table ORDER by row_id DESC LIMIT 8) t ORDER BY RAND()
Use a subquery:
SELECT t.*
FROM (SELECT t.*
FROM my_table t
ORDER by row_id DESC
LIMIT 8
) t
ORDER BY rand();
I have this line:
$query = mysql_query("SELECT * FROM livechat WHERE type='public' ORDER BY id ASC LIMIT 15") ;
And this is for chat, however ASC takes only first ID comments, so it shows only 15 old comments (id1, id2 and so on). If I use DESC instead of ASC, it shows new comments, but in a bad way - newest at the top, since this is a chat, newest comments must be at the bottom.
Try creating a temporary table that contains the last 15 results, and then ordering from that table.
select * from (
select * from livechat where type='public' order by id desc limit 15
) tmp order by tmp.id asc
try like this:
$query = mysql_query("SELECT *
FROM (
SELECT *
FROM livechat
WHERE type='public'
ORDER BY id DESC LIMIT 15
) t
order by t.id") ;
i have a table in mysql with columns: id , view , agree.
i have upload my table's image below:
i want to select 8 rows that greater than others in view column. my condition is agree = 1.
can you tell me how can i do it by mysql query or php.
Select * from table_name WHERE agree = 1 ORDER BY view desc LIMIT 8
Try this:
SELECT * from table
WHERE agree = 1
ORDER BY view DESC
LIMIT 8
use limit and order by
Select * from mytable
where aggree=1
ORDER BY view DESC
LIMIT 8
You can do this:
SELECT *
FROM yourTableName
WHERE agree = 1
ORDER BY view DESC
LIMIT 8
You have to use ORDER BY clause.
SELECT * FROM <TABLE_NAME> WHERE AGREE = 1 ORDER BY VIEW DESC LIMIT 8
Use ORDER BY for DESC or ASC sorting.
and For selection of 8 rows use Limit Data Selections From a MySQL Database
Select * from table_name WHERE agree = 1 ORDER BY view desc LIMIT 8
If you want to take the top 8 'view' values from the table the MySql query for that is:
SELECT * FROM tablename WHERE agree=1 ORDER BY view DESC LIMIT 8;
Note: Replace tablename with the actual name of your table
i have a MySql table that consists of 2 basic things:
The id and a value.
To show that on my page, i need to select, for example, the last 100 rows on reversed order.
So imagine that someone is putting data on it:
Id, value
1, 10
2, 9
3, 21
4, 15
i need, to select the last "3" rows (LIMIT + ORDER Clause), but not like this: 4,3,2 but like this: 2,3,4.
I know how to do that on code, but maybe there is a simple solution for that on Mysql and i don`t know.
Thanks
My SQL Query is like this right now:
SELECT `Data`.`id`, `Data`.`log_id`, `Data`.`value`, `Data`.`created` FROM `control_panel`.`datas` AS `Data` WHERE `Data`.`id` > 1000 AND `Data`.`log_id` = (2) ORDER BY `Data`.`id` DESC LIMIT 100
You need to wrap the first ORDER BY in a subselect which will return a limited selection ordered in descending order, then you can order that result in the outer query in ascending order:
SELECT
a.*
FROM
(
SELECT id, value
FROM tbl
ORDER BY id DESC
LIMIT 3
) a
ORDER BY
a.id
One way to do this would be with a sub-select.
SELECT *
FROM (SELECT * FROM table_name ORDER BY id DESC LIMIT 3) tmp
ORDER BY id ASC
simply
SELECT t.*
(SELECT * FROM table_name
ORDER BY column_name DESC
LIMIT 0,3) t
ORDER BY t.column_name ASC
use DESC to descending order, ASC to increasing order
Simply I have the following
table with records , i want to return randomly 5 records from the last 20 record (order by id desc)
so how we can do it fast
thanks for help.
select * from
(
select * from your_table
order by id desc limit 20
) as lastest_results
order by rand()
limit 5;
Use an inner query to return the last 20, and an outer query to select 5 of them randomly. This may be slow though.
SELECT * FROM (SELECT * FROM table ORDER BY id DESC LIMIT 20) t ORDER BY RAND() LIMIT 5;
This is a slow method but it gets the JOB done:
ORDER BY RAND()
LIMIT 5;
If you are using a large table this can become very slow,
There are multiple alternative that you can read about here
Alternative to order by rand
You need something like
SELECT * FROM table ORDER BY RAND() LIMIT 5;
If you have a time parameter to sort them by for example the last 20 records then use this.
SELECT * FROM table ORDER BY insert_time DESC, RAND() LIMIT 5;
OR
SELECT * FROM table ORDER BY id DESC, RAND() LIMIT 5;