i have a MySql table that consists of 2 basic things:
The id and a value.
To show that on my page, i need to select, for example, the last 100 rows on reversed order.
So imagine that someone is putting data on it:
Id, value
1, 10
2, 9
3, 21
4, 15
i need, to select the last "3" rows (LIMIT + ORDER Clause), but not like this: 4,3,2 but like this: 2,3,4.
I know how to do that on code, but maybe there is a simple solution for that on Mysql and i don`t know.
Thanks
My SQL Query is like this right now:
SELECT `Data`.`id`, `Data`.`log_id`, `Data`.`value`, `Data`.`created` FROM `control_panel`.`datas` AS `Data` WHERE `Data`.`id` > 1000 AND `Data`.`log_id` = (2) ORDER BY `Data`.`id` DESC LIMIT 100
You need to wrap the first ORDER BY in a subselect which will return a limited selection ordered in descending order, then you can order that result in the outer query in ascending order:
SELECT
a.*
FROM
(
SELECT id, value
FROM tbl
ORDER BY id DESC
LIMIT 3
) a
ORDER BY
a.id
One way to do this would be with a sub-select.
SELECT *
FROM (SELECT * FROM table_name ORDER BY id DESC LIMIT 3) tmp
ORDER BY id ASC
simply
SELECT t.*
(SELECT * FROM table_name
ORDER BY column_name DESC
LIMIT 0,3) t
ORDER BY t.column_name ASC
use DESC to descending order, ASC to increasing order
Related
I need to get data from MySQL table in ascending order but zero values come last and randomly
Right now this is my order by condition.This is not working
ORDER BY sortorder=0 RAND(),sortorder
Use conditional ordering
select *
from table
order by column > 0 desc, column asc, rand()
Add rand() at the end
Demo
Or you could use union
(select * from table where column > 0 order by column asc)
union all
(select * from table where column = 0 order by rand())
Demo
If you want to get data from mysql randomly and zero values come last. You may want to try the following:
SELECT * FROM table ORDER BY `column` = 0, rand();
I want to select last 5 records from first 50 records in the table, currently i have following query, somebody tell me best way to select these records without calculating the limit and offset?
SELECT id FROM table WHERE enabled=1 ORDER BY date LIMIT 5, 45
Try this
SELECT id FROM (SELECT id FROM (SELECT id FROM table ORDER BY id ASC LIMIT 50) AS tbl ORDER BY id DESC LIMIT 5) as tbldata ORDER BY id ASC
this works:
SELECT id FROM (SELECT id,date FROM table ORDER BY date LIMIT 50) AS
temptable ORDER BY date DESC LIMIT 5
Is possible, and how to ask MySQL for
SELECT * FROM my_table ORDER by row_id DESC LIMIT 8
get the last 8, newest record from my table, with randomized order for PHP showing method
$results = $mysqli->query($query);
while($row = $results->fetch_assoc()) {
echo $row['my_col_name'];
}
Colud I, and where put the rand() in my SQL query?
Without randomize I get last 8 rows ORDERED 10,9,8,7,6,5,4,3
I want to get in the following order:
9,7,5,4,6,10,3,8;
8,7,3,6,10,9,5,4
...
You can place it inside another select:
SELECT * FROM (SELECT * FROM my_table ORDER by row_id DESC LIMIT 8) t ORDER BY RAND()
Use a subquery:
SELECT t.*
FROM (SELECT t.*
FROM my_table t
ORDER by row_id DESC
LIMIT 8
) t
ORDER BY rand();
I have a question about how to select the second, third, fourth, and fifth largest number in a table. To select the biggest row I use:
$max = SELECT max(money) FROM table
Right now I want to specify $second_max, $third_max, $fourth_max and $fifth_max.
Does someone know how to change my previous SQL select max() easy to specify second max, third max etc...?
I do not want to use:
select money from table order by money desc limit 5;
Because I want them all in different variables.
select money from table order by money desc LIMIT 5
Probably the easiest way is to get them on separate rows:
select t.money
from table t
group by t.money
order by money desc
limit 5;
The next easiest thing is to put them in a comma-separated list:
select group_concat(money order by money desc) as monies
from (select t.money
from table t
group by t.money
order by money desc
limit 5
) T
Just this:
SELECT money
FROM yourtable
ORDER BY money DESC
LIMIT 5
You'll get a 5-record result set, ordered by the top money values - assuming you actually have 5+ records in the table.
USE SQL
select money from table order by money desc limit 5;
The five rows are there as max, secondary,... value of money.
In ORACLE you could do the following :
SELECT *
FROM (
SELECT ADRESSID,
ROW_NUMBER() OVER (ORDER BY ADRESSID DESC) AS ROW_NUM
FROM ADRESSTABLE
) t
WHERE ROW_NUM = 1
OR ROW_NUM = 3
OR ROW_NUM = 5;
with this code I select the first 30 row of the table:
SELECT * FROM `table` LIMIT 0 , 30
But how to select the last 30, without changing the order?
It looks like everyone is missing this part:
But how to select the last 30, without changing the order?
First of all, clearly there is no order in the query provided. Assuming the order is ascending on some field this would be the query #DannyFox meant:
SELECT * FROM T
ORDER BY val
LIMIT 0 , 30
Now imagine we have simplified data, such as a, b, c, d, e and that we want only 3 rows instead of 30:
SELECT * FROM T
ORDER BY val
LIMIT 3
If this returns: a, b, c, d, e in each row, then he would expect to get c, d, e in that order. The query everyone is providing:
SELECT * FROM T
ORDER BY val desc
LIMIT 3
Would return e, d, c. The problem with this is that it's actually changing the original order, and the OP say he didn't want to change the order. So technically, the query that would result in c, d, e is:
select * from (
select * from t
order by val desc
limit 3
) s
order by val
Which actually changes the order twice, getting the original order back.
Since you are trying to avoid ordering, then the solution would be to apply it twice.
SELECT *
FROM (
SELECT *
FROM `table_name`
ORDER BY `column_name` DESC -- maybe id?
LIMIT 0, 30
) `table_aliase`
ORDER BY `column_name` ASC
First you need to specify an order:
SELECT * FROM table
ORDER BY some_id ASC -- ascending order
LIMIT 30
If that query returns the first 30 columns, this one will return the last 30:
SELECT * FROM table
ORDER BY some_id DESC -- descending order
LIMIT 30
If you have an auto incremental key/column, say id then here's an example
SELECT * FROM `table` ORDER BY id DESC LIMIT 0 , 30;
Maybe this will work: select * from table WHERE id > ((SELECT MAX(id) from table) - 30);
Nothing is said about an order, so you can not use ORDER BY.
There is a way to get records from a given point, but for that you need to know how many records there are, then use this counted value to provide the limits
SELECT COUNT(*) AS counted FROM table
SELECT * FROM table LIMIT (counted-30),30
Here's my method used with PHP:
$query = "SELECT * FROM table ORDER BY id DESC LIMIT 3";
$res = mysql_query($query);
$results = array();
while($row = mysql_fetch_assoc($res)){
$results = $row[field];
}
// Back to original order based from DB
$results = array_reverse(results);