unable to fetch records from multiple tables using join - php

I am using Yii framework. i am wonder how i can get records from multiple tables i did research but couldn't find any usefull link i am using following code for this please let me know where i am missing
my model Task.php
public function relations()
{
// NOTE: you may need to adjust the relation name and the related
// class name for the relations automatically generated below.
return array(
'prj_user' => array(self::BELONGS_TO, 'User', 'id'),
);
}
model User.php
public function relations()
{
// NOTE: you may need to adjust the relation name and the related
// class name for the relations automatically generated below.
return array(
array('task', self::HAS_MANY, 'Task','project_id')
);
}
and this is my main controller
$criteria = new CDbCriteria;
$criteria->compare('t.id', 1);
$criteria->with = array( 'prj_user' => array('select' => 'username,title,roles', 'joinType'=>'inner join'));
$rows = Task::model()->findAll( $criteria );
but still i am getting columns only from task table but i need more three columns from users table please help me

Let Yii worry about joining your tables. Your relations looks fine so you should be able to access them directly
For example, what does this return?
foreach ($rows as $task)
{
if ( isset($task->prj_user) )
echo $task->prj_user->username . "<br>";
}
Or this?
this->widget('zii.widgets.grid.CGridView', array(
'dataProvider'=>new CActiveDataProvider('Task'),
'columns'=>array(
'id',
'prj_user.username',
'prj_user.title',
'prj_user.roles',
)
));
->with() is used for eager loading, so at this point you probably don't need it. In fact, unless I misread you completely, you can remove your criteria all together.

Related

How to filter associated HABTM data with FriendsOfCake Search for CakePHP 3

Plugin: FriendsOfCake/Search
CakePHP: 3.1.4
I'm using the plugin to filter my index.ctp view data with a form.
This similar question:
How to Filter on Associated Data
is about a belongsTo association. My question is specifically about associated HABTM data where my associated table is linked through a joinTable and not directly. The normal setup in the Model like the following is not working in this case:
->value('painting', [
field' => $this->Paintings->target()->aliasField('id')
)]
My tables are set up like:
Tickets belongsToMany Paintings
Paintings belongsToMany Tickets
with joinTable tickets_paintings
Here is the main setup:
class TicketsTable extends Table
{
public function initialize(array $config)
{
...
$this->belongsToMany('Paintings', [
'foreignKey' => 'ticket_id',
'targetForeignKey' => 'painting_id',
'joinTable' => 'tickets_paintings'
]);
}
public function searchConfiguration()
{
$search = new Manager($this);
$search->value('status', [
'field' => $this->aliasField('active'),
])->like('member_name', [
'field' => $this->Members->target()->aliasField('surname'),
'filterEmpty' => true
])->value('painting', [
'field' => $this->Paintings->target()->aliasField('id'), // not working
]);
return $search;
}
class TicketsController extends AppController
{
public function index()
{
$query = $this->Tickets
->find('search',
$this->Tickets->filterParams($this->request->query))
->contain(['Members', 'Paintings', 'Appointments']);
...
}
Everything else is working and the parameters are added to the URL when I filter etc., so I only put in the parts where sth has to be wrong.
After filtering I get an error:
SQLSTATE[42S22]: Column not found: 1054 Unknown column 'Paintings.id' in 'where clause'
The contain works properly when just displaying data from the Paintings table in the Tickets view.
But in the code from the SQL query I can see, that all contained tables (Members, Appoinments) are joined for the query except the Paintings table, so obviously it can not find the column...And I guess it can't really join it directly anyway since they are only connected through the joinTable.
I'm new to CakePHP and I can't really figure out what I'm doing wrong here, so hopefully someone can help me out a bit.
Do I have to use a different syntax in the plugin settings? Do I have to set up my Tables differently? Or how exactly can I tell the query to incorporate the habtm related table in the search?
Thanks!
The available search methods rely on the field being available in the main query (hasMany and belongsToMany associations are being being retrieved in separate queries).
While you could join it in manually in the controller, using a callback- or a finder-filter is probably the better approach, that way you can modify the query in the model layer, and you could easily utilize Query::matching() to filter by associated data.
Here's an (untested) example that should give you a hint:
use Cake\ORM\Query;
use Search\Type\Callback; // This changed in master recently
// now it's Search\Model\Filter\Callback
// ...
public function searchConfiguration()
{
$search = new Manager($this);
$search
// ...
->callback('painting', [
'callback' => function (Query $query, array $args, Callback $type) {
return $query
->distinct($this->aliasField('id'))
->matching('Paintings', function (Query $query) use ($args) {
return $query
->where([
$this->Paintings->target()->aliasField('id') => $args['painting']
]);
});
}
]);
return $search;
}
See also
https://github.com/FriendsOfCake/search/blob/9e12117404f824847b2d1aa093f3d52736b658b4/README.md#types
https://github.com/FriendsOfCake/search/blob/master/README.md#filters
Cookbook > Database Access & ORM > Retrieving Data & Results Sets > Filtering by Associated Data

How to display value from other table using primary key

I have implemented my project in Yii. I displaying search results in view part.
I wrote a search query for fetching the results from one table which is Recipe.
In this table name, course_id, cuisinename,type, colorie_count respectively, course_id,cuisinename, type are columns respectively.
In my controller i write code like this:
$result="SELECT * FROM recipe WHERE name LIKE '%$name%' AND `cuisinename` LIKE '$cuisine1%' AND course_id LIKE '%$course1%' AND `type` LIKE '%$type1%' AND `calorie_count` LIKE '%$calorie1%' ORDER BY recipe_id DESC LIMIT 15";
values are getting. if i give condition based to display the search result text. not displaying all name.
but those are displaying based on names.
I added below my view part condition and code:
$query= Course::model()->find("course_id=$as1");
$course2=$query->course_name;
$query1= Cuisine::model()->find("id=$as4");
$cuisine2=$query1->cuisinename;
$query3= RecipeType::model()->find("id=$as3");
$type2=$query3->recipeType_name;
<?php echo '<p align="center"> Showing results for&nbsp:&nbsp'.'Name'.$getval.',&nbsp'.'Course-'.$course2.',&nbsp'.'Cuisine-'.$cuisine2.',&nbsp'.'Type-'.$type2;',&nbsp';'</p>';
echo ',&nbsp'.'Calories-'.$calorie;
?>
You need to create relations between tables look there. For Recipe model it should be
public function relations()
{
return array(
'cuisine'=>array(self::BELONGS_TO, 'Cuisine', 'cuisine_id'),
'type'=>array(self::BELONGS_TO, 'RecipeType', 'type_id'),
);
}
Then you can get values as $model->cuisine->name. If you don't understand creating relations, generate models (it tables must be correct foreign keys) with gii.
check this article: http://www.yiiframework.com/doc/guide/1.1/en/database.arr about relations in AR
class Recipe extends CActiveRecord
{
......
public function relations()
{
return array(
'course'=>array(self::BELONGS_TO, 'Course', 'course_id'),
'cuisine'=>array(self::BELONGS_TO, 'Cuisine', 'cuisine_id'),
'type'=>array(self::BELONGS_TO, 'RecipeType', 'type_id'),
);
}
}
and related Models
class RecipeType extends CActiveRecord
{
......
public function relations()
{
return array(
'recipes'=>array(self::HAS_MANY, 'Recipe ', 'type_id'),
);
}
}
and your search query will be smth like this in controller file:
$criteria=new CDbCriteria;
$criteria->with=array(
'course',
'cuisine',
'type',
);
$criteria->addCondition('course.course_id = :filter_course'); // for ID compares
$criteria->addSearchCondition('cuisine.name', $cuisinename) //for LIKE compares
...
$criteria->params = array(':filter_course' => intval($course1));
$searchResults = Receipe::model()->findAll($criteria);
and in your view you can get related tables values:
foreach ($searchResults as $result){
echo $result->cuisine->name;
}
check also http://www.yiiframework.com/doc/api/1.1/CDbCriteria for details
you can also use this $criteria to create DataProdier for CListView or CGridView helpers in your view file
$dataProvider=new CActiveDataProvider( Receipe::model()->cache(5000),
array (
'criteria' => $criteria,
'pagination' => array (
'pageSize' => 10,
)
)
);
$this->render('search',array(
'dataProvider'=>$dataProvider
));
http://www.yiiframework.com/doc/api/1.1/CListView/
http://www.yiiframework.com/doc/api/1.1/CGridView

querying relational models in Yii

In my Web Application I have three models. Namely- items,Manufacturers,items_manufacturers
This is the query I need to perform
SELECT items.id,item_desc,manufacturers.id,manufacturers.name FROM items_manufacturers,items,manufacturers WHERE items_manufacturers.item_id=item.id AND items_manufacturers.manufacturer_id=manufacturers.id
The relation between the models is
public function relations()
{
// NOTE: you may need to adjust the relation name and the related
// class name for the relations automatically generated below.
return array(
'item' => array(self::BELONGS_TO, 'Items', 'item_id'),
'manufacturer' => array(self::BELONGS_TO, 'Manufacturers', 'manufacturer_id'),
'itemsManufacturersLocations' => array(self::HAS_MANY, 'ItemsManufacturersLocations', 'items_manufacturer_id'),
);
}
I am unable to write this query using the conventions in Yii framework.
This is what I tried
$im=new CDbCriteria ;
$im->with= array(
'items_manufacturers.item_id'
'items_manufacturers.manufacturer_id'
'items.item_desc'
'manufacturers.manufacturer_name'
'condition'=>'items_manufacturers.manufacturer_id=manufacturers.id
items_manufacturer.item_id=items.id'
);
))->findAll();
Any body kindly help me with this, since I am new to this framework.I am stuck up with this.I tried this in the items_manufacturers Controller.
You're assigning 'with' property with db columns, while you should do something like:
$im = new CDbCriteria;
$im->with = array('items','manufacturers'); // you put 'relation names' here, not db columns
$imf = ItemsManufacturers::model()->findAll($im);
You could do this without criteria:
$imf = ItemsManufacturers::model()->with('items','manufacturers')->findAll();

Change yii crud generated page

I have 2 models: taxiDrivers and taxiOrders. In taxiOrders I have a field driver_id, but instead of just an id, I want to output driver's name (which is located in taxiDrivers). Both models are generated via gii, and crud tools are also generated. The page which is needed to be changed is taxiOrders/admin (view: admin.php, models: TaxiOrders.php, TaxiDrivers.php and respective controllers)
2 DCoder: Thanks dude! but one more query I have and hope you can clearify: I have a standart generated admin.php view page with following code:
<?php $this->widget('zii.widgets.grid.CGridView', array(
'id'=>'taxi-orders-grid',
'dataProvider'=>$model->search(),
'filter'=>$model,
'columns'=>array(
'id',
'uid',
'did',
'type',
'notes',
//'or_lat',
//'or_lng',
//'des_lat',
//'des_lng',
'cost',
'rating',
'date',
'time',
'status',
array(
'class'=>'CButtonColumn',
),
),
)); ?>
and below code is for controller:public function actionAdmin()
{
$model=new TaxiOrders('search');
$model->unsetAttributes(); // clear any default values
if(isset($_GET['TaxiOrders']))
$model->attributes=$_GET['TaxiOrders'];
$this->render('admin',array(
'model'=>$model,
));
}
So can u please show me where I could put your manipulations.
The Yii way would be to define a Relation between the two model classes (and enforce it with a Foreign Key). Then Yii would know how the two classes are related and you would have an easier time loading the related data.
In the TaxiOrders model class, a relation would look like this:
/**
* #property TaxiDrivers $Driver
*/
class TaxiOrders extends CActiveRecord {
// ...
public function relations() {
return array(
'Driver' => array(self::BELONGS_TO, 'TaxiDrivers', 'driver_id'),
);
}
// ...
}
In the controller, when you load the order data, you can prefetch the associated driver data like this:
public function actionOrderInfo($orderID) {
$order = TaxiOrders::model()->with('Driver')->findByPk($orderID);
// render it
}
with('Driver') will make sure that each returned order has its driver info already loaded, no matter if you need to find one record or a lot of records. It is a lot more efficient than trying to load that related data yourself.
In the view, you can output the driver info like this:
echo CHtml::encode($order->Driver->Name);
Unless you have a foreign key to ensure data integrity, it is possible that the Driver has been deleted without clearing his existing orders... In that case $order->Driver will be NULL and the line above will cause an error. Figuring out how to avoid it should be obvious.
In TaxiOrders admin use this to display driver name
TaxiDrivers::getName($data->driver_id);
Now in the TaxiDrivers Model write a function with sql query to get the driver name like this...
public function getName($getid) {
$sql = "SELECT name from `taxi_drivers` where `driver_id`='$getid'";
$command=yii::app()->db->createCommand($sql);
$rs = $command->queryScalar();
return $rs;
}
I Hope it will help you..
I always prefer Query Builder approach instead of Active record approach in joined scenarios. Like that
First Get Data through Query Builder
public function getTaxtOrder($id) {
$select = Yii::app()->db->createCommand()
->select('to.*, td.name as driver_name')
->from('TaxiOrders to')
->join('TaxiDriver td', 'td.id = to.driver_id')
->where('to.id = :id', array(':id' => $id));
return $select->queryRow();
}
Then Pass through controller
$data = TaxiOrders::model()->getTaxtOrder($id);
$this->render('view',array(
'data' => $data
));
Last use this into views
$this->widget('zii.widgets.CDetailView', array(
'data'=>$data,
'attributes'=>array(
array('label' => 'Order No', 'value' =>$model['order_no']),
array('label' => 'Driver Name', 'value' =>$model['driver_name']),
array('label' => 'Date', 'value' =>$model['order_date']),
),
));
This approach easily and flexibly work with multiple joined tables than Active Record Approach.

Yii framework: Using data from related Active Record models for searching

Yii 1.1 application development Cookbook explain a method for using data from related Active Record Models for searching the related models as well. This method is explained in page number 193 and 194. i have tried to integrate this method in to my application but it does not work. could anybody explain me whether this feature is still available in Yii framework version 1.1.8
At this location also i could find comments for searching data form related active record models. But it also does not work.
http://www.yiiframework.com/doc/api/1.1/CDbCriteria
I have order table and user table
Order table and User table has One to many Relation.
User has many orders and order has exactly one user.
So , i am editing following CDbCriterial to include user tables name and email field in to Order tables search entries.
Order table has following relations
public function relations()
{
// NOTE: you may need to adjust the relation name and the related
// class name for the relations automatically generated below.
return array(
'comments' => array(self::HAS_MANY, 'Comment', 'order_id'),
'user' => array(self::BELONGS_TO, 'User', 'user_id'),
'orderstatus' => array(self::BELONGS_TO, 'Orderstatus', 'orderstatus_id'),
'commentCount' => array(self::STAT, 'Comment' , 'order_id')
);
}
This is the search/filter conditions with user table's name filed included
public function search()
{
// Warning: Please modify the following code to remove attributes that
// should not be searched.
$criteria=new CDbCriteria;
$criteria->compare('id',$this->id);
$criteria->compare('order_create_date',$this->order_create_date,true);
$criteria->compare('price',$this->price,true);
$criteria->compare('bank_account_number',$this->bank_account_number,true);
$criteria->compare('hardwaredetail_Id',$this->hardwaredetail_Id);
$criteria->compare('user_id',$this->user_id);
$criteria->compare('order_update_date',$this->order_update_date,true);
$criteria->compare('is_received',$this->is_received);
$criteria->compare('order_received_date',$this->order_received_date,true);
$criteria->compare('is_notify_by_email',$this->is_notify_by_email);
$criteria->compare('warehouse_offered_price',$this->warehouse_offered_price,true);
$criteria->compare('warehouse_offered_price_date',$this->warehouse_offered_price_date,true);
$criteria->compare('orderstatus_id',$this->orderstatus_id);
$criteria->together = true;
$criteria->with = array('user');
$criteria->compare('user.name',$this->user,true);
//$criteria->compare('user.name',$this->user->name);
return new CActiveDataProvider($this, array(
'criteria'=>$criteria,
));
}
and Order admin page is edited to display the name filed as follows
<?php $this->widget('zii.widgets.grid.CGridView', array(
'id'=>'order-grid',
'dataProvider'=>$model->search(),
//'filter'=>$model,
'columns'=>array(
'id',
'order_create_date',
'price',
'bank_account_number',
array(
'name'=>'user',
'value'=>'$data->user->name'
),
),
));
Error message returned
After solving the id column ambiguity problem by applying the solution that thaddeusmt gave i have faced with the following error message.
Thanks in advance for any help
I could find the answer. This is all i did.
Following are the two tables i have. Order and User
I have Order/Admin page, Default generated code provide searching order table data only. i want to relate user tables name field in the search criteria.
This is the initial look of the search page.
I want to integrated user name filed from other table in to this search. then final look will be as follows.
so these are the steps i did.
first in the Order model i have following relations
public function relations()
{
// NOTE: you may need to adjust the relation name and the related
// class name for the relations automatically generated below.
return array(
'user' => array(self::BELONGS_TO, 'User', 'user_id'),
);
}
This is generated by Yii framework , i did nothing :)
Then , i changed the search method as follows
public function search()
{
// Warning: Please modify the following code to remove attributes that
// should not be searched.
$criteria=new CDbCriteria;
$criteria->compare('t.order_create_date',$this->order_create_date,true);
$criteria->compare('t.price',$this->price,true);
$criteria->compare('t.bank_account_number',$this->bank_account_number,true);
$criteria->compare('t.hardwaredetail_Id',$this->hardwaredetail_Id);
//$criteria->compare('user_id',$this->user_id);
$criteria->compare('t.order_update_date',$this->order_update_date,true);
$criteria->compare('t.is_received',$this->is_received);
$criteria->compare('t.order_received_date',$this->order_received_date,true);
$criteria->compare('t.is_notify_by_email',$this->is_notify_by_email);
$criteria->compare('t.warehouse_offered_price',$this->warehouse_offered_price,true);
$criteria->compare('t.warehouse_offered_price_date',$this->warehouse_offered_price_date,true);
$criteria->compare('t.orderstatus_id',$this->orderstatus_id);
$criteria->together = true;
$criteria->compare('t.id',$this->id,true);
$criteria->with = array('user');
$criteria->compare('name',$this->user,true,"OR");
return new CActiveDataProvider($this, array(
'criteria'=>$criteria,
));
}
it is important to put t in-front of the t if your Order table primary key field if both have save name. in my case it is id and id, so i had to put t.
Other thing is the order of the elements
$criterial->togeter = true; should come before the relational elements.
then u updated to rules method in Order table. i added user filed and name filed to safe attributes.
public function rules()
{
// NOTE: you should only define rules for those attributes that
// will receive user inputs.
return array(
//array(' orderstatus_id', 'required'),
array('hardwaredetail_Id, user_id, is_received, is_notify_by_email, orderstatus_id', 'numerical', 'integerOnly'=>true),
array('price, warehouse_offered_price', 'length', 'max'=>10),
array('bank_account_number', 'length', 'max'=>100),
array('order_create_date, order_update_date, order_received_date, warehouse_offered_price_date, user,name', 'safe'),
// The following rule is used by search().
// Please remove those attributes that should not be searched.
array('id, order_create_date, price, bank_account_number, hardwaredetail_Id, user_id, order_update_date, is_received, order_received_date, is_notify_by_email, warehouse_offered_price, warehouse_offered_price_date, orderstatus_id', 'safe', 'on'=>'search'),
);
}
Finally update your UI code.
<?php $this->widget('zii.widgets.grid.CGridView', array(
'id'=>'order-grid',
'dataProvider'=>$model->search(),
'filter'=>$model,
'columns'=>array(
'id',
'order_create_date',
'price',
'bank_account_number',
array(
'name'=>'user',
'value'=>'$data->user->name'
)
)); ?>
i updated the order admin with the
array(
'name'=>'user',
'value'=>'$data->user->name'
)
That is what i did and it worked for me. ask me if you need any help. Thanks every one looking in to this issue.
It looks like both the user and order have columns named id. And your criteria uses them both in the WHERE clause, which is giving the "ambiguous" mySql error message.
When using with criteria (which does a SQL JOIN of the tables), if two of your tables have columns with the same name you need to use the mySql "dot" prefix on conditions, like so:
$criteria->compare('t.id',$this->id); // the default table prefix in Yii is "t"
When I JOIN a table using $criteria->with I prefix all of the column names (in my compare and condition criteria, etc)., like so:
$criteria->compare('t.id',$this->id); // t
$criteria->compare('t.order_create_date',$this->order_create_date,true); // t
$criteria->with = array('user');
$criteria->compare('user.name',$this->user_id,true); // user (the filter will set user_id)
Your gridview will need to look like this:
array(
'name'=>'user_id',
'header'=>'User',
'sortable'=>false,
'value'=>'$data->user->name'
),
Also, I think there is a larger problem, as you point out with your edit:
Your search function is set up like this: user.name',$this->user - but $this->user is going to return the current user object via the relation, not the search criteria. The column filter will set the user_id, property.
EDIT: Nope, you can $this->user as your column name so long as you set it as a safe attribute.
The way I am getting around this is shown in more detail here:
Search in BELONGS_TO model column with CGridView, Yii
Sorting will not work with that though - just the filtering.
Here is good post in the Yii forum that might give you more clues, too:
http://www.yiiframework.com/forum/index.php?/topic/9083-search-filter-of-a-relations-field-through-cgridview/
Sadly, sorting and filter CGridViews on relations is not really default functionality. YOu can easily display related info with a column name like user.name, but it won't sort or filter. Good luck!

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