I have 2 models: taxiDrivers and taxiOrders. In taxiOrders I have a field driver_id, but instead of just an id, I want to output driver's name (which is located in taxiDrivers). Both models are generated via gii, and crud tools are also generated. The page which is needed to be changed is taxiOrders/admin (view: admin.php, models: TaxiOrders.php, TaxiDrivers.php and respective controllers)
2 DCoder: Thanks dude! but one more query I have and hope you can clearify: I have a standart generated admin.php view page with following code:
<?php $this->widget('zii.widgets.grid.CGridView', array(
'id'=>'taxi-orders-grid',
'dataProvider'=>$model->search(),
'filter'=>$model,
'columns'=>array(
'id',
'uid',
'did',
'type',
'notes',
//'or_lat',
//'or_lng',
//'des_lat',
//'des_lng',
'cost',
'rating',
'date',
'time',
'status',
array(
'class'=>'CButtonColumn',
),
),
)); ?>
and below code is for controller:public function actionAdmin()
{
$model=new TaxiOrders('search');
$model->unsetAttributes(); // clear any default values
if(isset($_GET['TaxiOrders']))
$model->attributes=$_GET['TaxiOrders'];
$this->render('admin',array(
'model'=>$model,
));
}
So can u please show me where I could put your manipulations.
The Yii way would be to define a Relation between the two model classes (and enforce it with a Foreign Key). Then Yii would know how the two classes are related and you would have an easier time loading the related data.
In the TaxiOrders model class, a relation would look like this:
/**
* #property TaxiDrivers $Driver
*/
class TaxiOrders extends CActiveRecord {
// ...
public function relations() {
return array(
'Driver' => array(self::BELONGS_TO, 'TaxiDrivers', 'driver_id'),
);
}
// ...
}
In the controller, when you load the order data, you can prefetch the associated driver data like this:
public function actionOrderInfo($orderID) {
$order = TaxiOrders::model()->with('Driver')->findByPk($orderID);
// render it
}
with('Driver') will make sure that each returned order has its driver info already loaded, no matter if you need to find one record or a lot of records. It is a lot more efficient than trying to load that related data yourself.
In the view, you can output the driver info like this:
echo CHtml::encode($order->Driver->Name);
Unless you have a foreign key to ensure data integrity, it is possible that the Driver has been deleted without clearing his existing orders... In that case $order->Driver will be NULL and the line above will cause an error. Figuring out how to avoid it should be obvious.
In TaxiOrders admin use this to display driver name
TaxiDrivers::getName($data->driver_id);
Now in the TaxiDrivers Model write a function with sql query to get the driver name like this...
public function getName($getid) {
$sql = "SELECT name from `taxi_drivers` where `driver_id`='$getid'";
$command=yii::app()->db->createCommand($sql);
$rs = $command->queryScalar();
return $rs;
}
I Hope it will help you..
I always prefer Query Builder approach instead of Active record approach in joined scenarios. Like that
First Get Data through Query Builder
public function getTaxtOrder($id) {
$select = Yii::app()->db->createCommand()
->select('to.*, td.name as driver_name')
->from('TaxiOrders to')
->join('TaxiDriver td', 'td.id = to.driver_id')
->where('to.id = :id', array(':id' => $id));
return $select->queryRow();
}
Then Pass through controller
$data = TaxiOrders::model()->getTaxtOrder($id);
$this->render('view',array(
'data' => $data
));
Last use this into views
$this->widget('zii.widgets.CDetailView', array(
'data'=>$data,
'attributes'=>array(
array('label' => 'Order No', 'value' =>$model['order_no']),
array('label' => 'Driver Name', 'value' =>$model['driver_name']),
array('label' => 'Date', 'value' =>$model['order_date']),
),
));
This approach easily and flexibly work with multiple joined tables than Active Record Approach.
Related
Plugin: FriendsOfCake/Search
CakePHP: 3.1.4
I'm using the plugin to filter my index.ctp view data with a form.
This similar question:
How to Filter on Associated Data
is about a belongsTo association. My question is specifically about associated HABTM data where my associated table is linked through a joinTable and not directly. The normal setup in the Model like the following is not working in this case:
->value('painting', [
field' => $this->Paintings->target()->aliasField('id')
)]
My tables are set up like:
Tickets belongsToMany Paintings
Paintings belongsToMany Tickets
with joinTable tickets_paintings
Here is the main setup:
class TicketsTable extends Table
{
public function initialize(array $config)
{
...
$this->belongsToMany('Paintings', [
'foreignKey' => 'ticket_id',
'targetForeignKey' => 'painting_id',
'joinTable' => 'tickets_paintings'
]);
}
public function searchConfiguration()
{
$search = new Manager($this);
$search->value('status', [
'field' => $this->aliasField('active'),
])->like('member_name', [
'field' => $this->Members->target()->aliasField('surname'),
'filterEmpty' => true
])->value('painting', [
'field' => $this->Paintings->target()->aliasField('id'), // not working
]);
return $search;
}
class TicketsController extends AppController
{
public function index()
{
$query = $this->Tickets
->find('search',
$this->Tickets->filterParams($this->request->query))
->contain(['Members', 'Paintings', 'Appointments']);
...
}
Everything else is working and the parameters are added to the URL when I filter etc., so I only put in the parts where sth has to be wrong.
After filtering I get an error:
SQLSTATE[42S22]: Column not found: 1054 Unknown column 'Paintings.id' in 'where clause'
The contain works properly when just displaying data from the Paintings table in the Tickets view.
But in the code from the SQL query I can see, that all contained tables (Members, Appoinments) are joined for the query except the Paintings table, so obviously it can not find the column...And I guess it can't really join it directly anyway since they are only connected through the joinTable.
I'm new to CakePHP and I can't really figure out what I'm doing wrong here, so hopefully someone can help me out a bit.
Do I have to use a different syntax in the plugin settings? Do I have to set up my Tables differently? Or how exactly can I tell the query to incorporate the habtm related table in the search?
Thanks!
The available search methods rely on the field being available in the main query (hasMany and belongsToMany associations are being being retrieved in separate queries).
While you could join it in manually in the controller, using a callback- or a finder-filter is probably the better approach, that way you can modify the query in the model layer, and you could easily utilize Query::matching() to filter by associated data.
Here's an (untested) example that should give you a hint:
use Cake\ORM\Query;
use Search\Type\Callback; // This changed in master recently
// now it's Search\Model\Filter\Callback
// ...
public function searchConfiguration()
{
$search = new Manager($this);
$search
// ...
->callback('painting', [
'callback' => function (Query $query, array $args, Callback $type) {
return $query
->distinct($this->aliasField('id'))
->matching('Paintings', function (Query $query) use ($args) {
return $query
->where([
$this->Paintings->target()->aliasField('id') => $args['painting']
]);
});
}
]);
return $search;
}
See also
https://github.com/FriendsOfCake/search/blob/9e12117404f824847b2d1aa093f3d52736b658b4/README.md#types
https://github.com/FriendsOfCake/search/blob/master/README.md#filters
Cookbook > Database Access & ORM > Retrieving Data & Results Sets > Filtering by Associated Data
I have a relatively simple setup using Yii application but I'm struggling to access data across tables in the following scenario:
Two tables:
payments_info (id, data): where id is the primary auto increment key, model class name PaymentInfo
payments (id, payment_id, other_columns): here id is again a primary key and payment_id is foreign key pointing to one of the records in the payment_info table, model class name Payment
In the relations array inside the Payment model class I have the following:
'payment_id'=>array(self::BELONGS_TO, 'PaymentInfo', 'id'),
I haven't added anything in the PaymentInfo model's relations as technically it doesn't know anything about the other table.
I have a controller creating a CActiveDataProvider from the Payments model and showing all the records. In it, I'd like to have a field which would be showing the 'data' column from the PaymentInfo model but I have no idea how to get there.
In the cdbcriteria in the controller, used to create the data provider I tried using:
$criteria->with = array('payment_id');
And then in the view, inside the columns variable of the CGridView which displays the data provider I added:
array(
'name'=>'payment_id',
'visible'=>true,
'value'=> $data->payment_id->data,
),
I also tried different combinations of adding ' or " around the $data variable but with no success so far. I manage to get the correct payment_id displayed but I can't figure out how to display the 'data' value from the other table. Any tips appreciated!
you can use below method to Get Data From Another Relational Table in YII
Payment Model In Relation Function
public function relations()
{
return array(
'pinfos' => array(self::BELONGS_TO, 'PaymentInfo', 'payment_id'),
);
}
PaymentInfo Model In Relation Function
public function relations()
{
return array(
'payments' => array(self::HAS_MANY, 'Payment', 'payment_id'),
);
}
And In zii.widgets.grid.CGridView put this
<?php $this->widget('zii.widgets.grid.CGridView', array(
'id'=>'post-grid',
'dataProvider'=>$model->search(),
'filter'=>$model,
'columns'=>array(
'pinfos.data',
/* other fields goes here*/
array(
'class'=>'CButtonColumn',
),
),
)); ?>
No need to do anything else.
In my Web Application I have three models. Namely- items,Manufacturers,items_manufacturers
This is the query I need to perform
SELECT items.id,item_desc,manufacturers.id,manufacturers.name FROM items_manufacturers,items,manufacturers WHERE items_manufacturers.item_id=item.id AND items_manufacturers.manufacturer_id=manufacturers.id
The relation between the models is
public function relations()
{
// NOTE: you may need to adjust the relation name and the related
// class name for the relations automatically generated below.
return array(
'item' => array(self::BELONGS_TO, 'Items', 'item_id'),
'manufacturer' => array(self::BELONGS_TO, 'Manufacturers', 'manufacturer_id'),
'itemsManufacturersLocations' => array(self::HAS_MANY, 'ItemsManufacturersLocations', 'items_manufacturer_id'),
);
}
I am unable to write this query using the conventions in Yii framework.
This is what I tried
$im=new CDbCriteria ;
$im->with= array(
'items_manufacturers.item_id'
'items_manufacturers.manufacturer_id'
'items.item_desc'
'manufacturers.manufacturer_name'
'condition'=>'items_manufacturers.manufacturer_id=manufacturers.id
items_manufacturer.item_id=items.id'
);
))->findAll();
Any body kindly help me with this, since I am new to this framework.I am stuck up with this.I tried this in the items_manufacturers Controller.
You're assigning 'with' property with db columns, while you should do something like:
$im = new CDbCriteria;
$im->with = array('items','manufacturers'); // you put 'relation names' here, not db columns
$imf = ItemsManufacturers::model()->findAll($im);
You could do this without criteria:
$imf = ItemsManufacturers::model()->with('items','manufacturers')->findAll();
I am using Yii framework. i am wonder how i can get records from multiple tables i did research but couldn't find any usefull link i am using following code for this please let me know where i am missing
my model Task.php
public function relations()
{
// NOTE: you may need to adjust the relation name and the related
// class name for the relations automatically generated below.
return array(
'prj_user' => array(self::BELONGS_TO, 'User', 'id'),
);
}
model User.php
public function relations()
{
// NOTE: you may need to adjust the relation name and the related
// class name for the relations automatically generated below.
return array(
array('task', self::HAS_MANY, 'Task','project_id')
);
}
and this is my main controller
$criteria = new CDbCriteria;
$criteria->compare('t.id', 1);
$criteria->with = array( 'prj_user' => array('select' => 'username,title,roles', 'joinType'=>'inner join'));
$rows = Task::model()->findAll( $criteria );
but still i am getting columns only from task table but i need more three columns from users table please help me
Let Yii worry about joining your tables. Your relations looks fine so you should be able to access them directly
For example, what does this return?
foreach ($rows as $task)
{
if ( isset($task->prj_user) )
echo $task->prj_user->username . "<br>";
}
Or this?
this->widget('zii.widgets.grid.CGridView', array(
'dataProvider'=>new CActiveDataProvider('Task'),
'columns'=>array(
'id',
'prj_user.username',
'prj_user.title',
'prj_user.roles',
)
));
->with() is used for eager loading, so at this point you probably don't need it. In fact, unless I misread you completely, you can remove your criteria all together.
Please consider this:
class User extends CActiveRecord
{
...
public function relations()
{
return array(
...
'articleCount' => array(self::STAT, 'Article', 'userid'),
...
);
}
...
}
Now, I need to create a $dataProvider = new CActiveDataProvider(...) to feed a CListView widget to which I want add articleCount to the property sortableAttributes so that I can sort User records according to the number of articles the user is the author for.
What are the most convenient method? what are the other alternatives?
Well, it took me a while, but I finally got it figured out. ;)
First, make sure you still have the same STAT relation you mention in your question.
Then, in your search() method where you are building your CDbCriteria for the CActiveDataProvider, do something like this:
public function search() {
$criteria=new CDbCriteria;
$criteria->select = 't.*, IFNULL( count(article.id), 0) as articleCount';
$criteria->join = 'LEFT JOIN article ON article.userid = t.id';
$criteria->group = 't.id';
// other $criteria->compare conditions
$sort = new CSort();
$sort->attributes = array(
'articleCount'=>array(
'asc'=>'articleCountASC',
'desc'=>'articleCountDESC',
),
'*', // add all of the other columns as sortable
);
return new CActiveDataProvider(get_class($this), array(
'criteria'=>$criteria,
'sort'=>$sort,
'pagination'=> array(
'pageSize'=>20,
),
));
}
Then, in your View where you output your CGridView, do this like so:
<?php $this->widget('zii.widgets.grid.CGridView', array(
'dataProvider'=>$model->search(),
'columns'=>array(
'articleCount',
// other columns here
)
)); ?>
This works, I tested it (although I did not use the exact same names, like 'article', but the basic idea should work :) I did add some bonus features so it works better (like the IFNULL magic) but most of the credit goes to this Yii forum post:
http://www.yiiframework.com/forum/index.php?/topic/7061-csort-and-selfstat-to-sort-by-count/
I hope this helps! They should add better support for this though, so you don't need to make these tricky SELECT statements. Seems like something that should 'just work', I would file an 'enhancement' request in the Yii bug tracker.