table1: Proid email password verify
12345 john#xx.com xxxxxxx xxxx
45678 lee#xx.com xxxxxxx xxxx
// some more tables here
table2: Proid fname lname gender dofbirth
13456 rey aj male xxxxx
12345 john paul male xxxxx
47812 murray dj male xxxxx
45678 lee mah female xxxxx
Note this tables dont have duplicates of Proid
now here Proid is common for both the tables what i wanted is, to fetch an array simple as this
$result = mysql_query("SELECT table1.verify,table1.Email,table2.* FROM table1,table2 WHERE table2.Pro_ID='$pro_id' LIMIT 1");
$row = mysql_fetch_array($result, MYSQL_ASSOC);
// and I expect $row variable now has this values
$row['email'],$row['verify'],$row['fname'],row['lname'],row['table2*']
but no matter what its taking the first entry. How coud I fix this. is this the way to do it? Could anyone post or suggest me a good way to do it. Thanks
change this:
SELECT table1.verify,table1.Email,table2.* FROM table1,table2
WHERE table2.Pro_ID='$pro_id' LIMIT 1
to:
SELECT table1.verify,table1.Email,table2.* FROM table1
left join table2 on table1.Proid=table2.Proid
where table2.Proid in not null LIMIT 1
What happens with your query:
SELECT table1.verify, table1.Email, table2.*
//means: In each row include columns 'verify' and 'email'
// from table1 and all columns from table2.
FROM table1, table2
//means: Combine EACH row of table1 with EACH row of table2.
WHERE table2.Pro_ID='$pro_id'
//means: Fetch only rows where the 'pro_id' column
// of table2 has the specified value.
LIMIT 1
//means: Fetch only the first row.
So, what actually happens is that you combine each row of table1 with the row of table2 that has Pro_ID='$pro_id' (resulting in 4 rows for your example tables above) and then return the 1st row (which always contains the values of the 1st row of table1).
The problem is that there is no contsraint that forces the matching of rows from table1 and table2 only when their pro_id values are the same.
You can fix this in several ways.
1.) Add an additional condition in your WHERE clause:
...
WHERE table1.Pro_ID = table2.Pro_ID
AND table2.Pro_ID = '$pro_id'
...
2.) Joining the tables on column 'Pro_ID':
...
FROM table1 INNER JOIN table2
ON table1.Pro_ID = table2.Pro_ID
...
(More info on SQL joins.)
Related
I need to find matchs between two tables, but also need to display when there is no match.
Table1: id, dni_number, name, business_id
Table2: id, dni, business_id
I need to form a table like this:
id
dni
name
business_id
is_match
1
12365478
John Doe
15451
1
1
22365478
Karen Doe
23451
0
is_match meaning 1: it found the dni in table1 and also in table2, 0 for not match
The query should have a where condition to find matchs from certain business_id
Any help will be much appreciated. Thanks in advance
SELECT
tblA.id,
1 as is_match
FROM tblA, tblB
WHERE tblA.id = tblB.id
UNION ALL
SELECT
tblA.id,
0 as is_match
FROM tblA, tblB
WHERE tblA.id != tblB.id
SELECT *, (table2.dnu = table1.dnu) AS is_match
FROM table1
LEFT JOIN table2 ON table1.business_id = table2.business_id
WHERE table1.business_id = xxx;
I am having 2 tables :
1.internal_employee_master
id employee_name unique_id
1 Noah ABCD
2 Liam ABCD
3 William ABCD
4 Benjamin ABCD
5 Jacob EFGH
2.external_employee_master
id name unique_id
1 Elijah ABCD
2 Ethan ABCD
3 Alexander EFGH
I am using UNION query to get both tables data into single table and display this data into html table.
select id
, employee_name
, unique_id
from internal_employee_master
where unique_id = 'ABCD'
union
select id
, employee_name
, unique_id
from external_employee_master
where unique_id = 'ABCD'
I want to store payslips of both employees into single table.
I have one table payslips with emp_id and emp_type columns.
I am storing data into payslips data like:
id pay_slip emp_id emp_type
1 Noah_payslip.pdf 1 internal
2 Liam_payslip.pdf 2 internal
3 Lia_payslip.pdf 1 External
as you can see in above table i am storing emp_id and emp_type of
both the tables in single columns each.
Now, i dont undestand how to split data of internal employee and
external employee from pay_slip table and show data in html table.
Currently, i am writing below sql joins to get employee_names of
internal and external employee tables but it doesnt work for me.
$id = $_GET['id];
SELECT ps.id,ps.pdf,ps.emp_id,ps.emp_type,external_employee.name as comemp,
internal_employee.comp_empl_name as comemp
FROM pay_slip as ps
INNER JOIN internal_employee_master as internal_employee ON internal_employee.comp_trad_id = ps.trade_id
INNER JOIN external_employee_master as external_employee ON external_employee.trad_id = ps.trade_id
where ps.is_deleted = 1 AND ps.id = '".$id."'"
Please help me to join query to get name and employee_name with respect to emp_type form pay_slip table.
How about using UNION again?
SELECT
ps.id,
ps.pdf,
ps.emp_id,
ps.emp_type,
external_employee.name AS comemp,
internal_employee.comp_empl_name AS comemp
FROM
pay_slip AS ps
INNER JOIN
internal_employee_master AS internal_employee ON internal_employee.comp_trad_id = ps.trade_id
WHERE
ps.is_deleted = 1 AND ps.id = '".$id."'
AND ps.type = 'internal'
UNION ALL
SELECT
ps.id,
ps.pdf,
ps.emp_id,
ps.emp_type,
external_employee.name AS comemp,
internal_employee.comp_empl_name AS comemp
FROM
pay_slip AS ps
INNER JOIN
external_employee_master AS external_employee ON external_employee.trad_id = ps.trade_id
WHERE
ps.is_deleted = 1 AND ps.id = '".$id."'
AND ps.type = 'external'
You could try this
SELECT ps.id, ps.pay_slip, ps.emp_type, COALESCE(i.employee_name, e.name) AS name
FROM payslips ps
LEFT JOIN internal_employee_master i ON i.id = ps.emp_id AND ps.emp_type = 'internal'
LEFT JOIN external_employee_master e ON e.id = ps.emp_id AND ps.emp_type = 'External'
AND ps.id = :ID
You can see this in action here http://sqlfiddle.com/#!9/53a195/7/0
I would mention that there are a number of issues in your included tables and queries. For example, irregular column names between tables (name vs. employee_name), you've missed the is_deleted column from your example schema, and you have capitalised and non-capitalised values in the emp_type column which is confusing.
I have two tables.
first datatable structure has nine columns but the important three are:
code | name | value
2D3 | name test | 0.12
the second table has the same three columns.
Now I want to update all rows of the first table with the values of table two where code AND name are the same as in table two.
So my current idea is to do a select of all rows of table 1 with the code and name columns, than check if a row with the same code and name exists in table 2, if yes get that value and do a UPDATE query in table 1 with value of table 2.
The problem is that the two tables are hugh and I am sure that I am not using the fastest method.
anyone an idea for the fastest method to do this? Thank you very much!
EDIT: the query:
$getall = "SELECT code, name, value FROM table2";
$query = mysqli_query($conn, $getall );
while($result = mysqli_fetch_array($query))
{
$UpdateAll = "UPDATE table1 SET value = '".mysqli_real_escape_string($conn,$result["value"])."' WHERE name = '".mysqli_real_escape_string($conn,$result["name"])."' AND code = '".mysqli_real_escape_string($conn,$result["code"])."'";
$result2 = mysqli_query($conn, $UpdateAll); }
You speak of two databases but really mean two tables, don't you? In this case, you can do it with one update using a join, like this:
update table1 t1
inner join table2 t2 on t2.code = t1.code and t2.name = t1.name
set t1.value = t2.value;
I have two tables first and second.
first Table:
ID NAME ADDRESS
1 test testing address
2 test1 testing address
3 test2 testing address
4 test3 testing address
second Table:
T_ID Partner_id date
1 2 12345678
3 4 32164584
If input T_id is given. Then corresponding Partner_id is taken and it is compared with the ID from first table and corresponding row should be selected.
Can you please tell me.
In php I can write this with two queries but I want it to be in a single query.
Queries in php:
$q=mysqli_query($conn, "SELECT Partner_id from second where T_ID=1");
$qa=mysqli_fetch_array($q);
$w=mysqli_query($conn, "SELECT * from first where ID=$qa[0]");
But, how to combine this two statements?
The specified result can be returned using a query with a join operation.
SELECT f.*
FROM first f
JOIN second s
ON s.Partner_id = f.ID
WHERE s.T_ID=1
Note that there is a potential for this to return more rows that the original, if the first query returns more than one row. (That is, we don't assume that T_ID is unique in second, or that every row with a given T_ID value will have identical values for Partner_id.)
There are other query patterns that will return an equivalent result, but the join operation is the normative pattern.
try to use union ,see this this link
where The SQL UNION operator combines the result of two or more SELECT statements.
SELECT * FROM first WHERE ID IN( SELECT Parent_id FROM second WHERE T_ID = 1 )
or
SELECT * FROM first WHERE ID = ( SELECT Parent_id FROM second WHERE T_ID = 1 )
SELECT * FORM first_table AS f
JOIN second_table AS s
ON s.parent_id =f.id
WHERE s.T_ID = $id
I'm very new with SQL and need assistance on how I can accomplish this task using the correct query.
I have 2 tables that I need to use. Table "TB1" has:
id Name
1 bob
2 blow
3 joe
table "TB2" has:
compid property
1 bob
2 blow
I am trying to get which compid is missing in "TB2" and insert it from "TB1"
the query I am doing is:
SELECT id, name from TB1, TB2 where id <> compid
what I get is 2 ouputs of Id 1, and 2, and 3 outputs from id 3. by using php:
for($i=0;$i <= mysql_num_rows($comp)-1; $i++)
{
echo mysql_result($comp, $i, 0)."<br>";
}
and I expected the ouput 3 but instead got this:
1
1
2
2
3
3
3
I understand its comparing all the rows within the table but is there a way to achieve what I am looking for?
Thanks for your time.
You are performing an implicit Cartesian JOIN which results in every row against every other row. You need to specify what attribute JOINs the two tables.
Using implicit syntax (not recommended):
SELECT id, name
FROM TB1, TB2
WHERE id <> compid
AND TB1.Name = TB2.property <-- Column join
Using explicit syntax:
SELECT id, name
FROM TB1
JOIN TB2
ON TB2.property = TB1.Name <-- Column join
WHERE id <> compid
To accomplish your goal you would need something along the lines of:
SELECT TB1.id, TB1.name
FROM TB1
LEFT JOIN TB2
ON TB2.property = TB1.Name
WHERE TB2.compid IS NULL
See it in action
It's best practice to always alias the columns you select to prevent ambiguity.
To select it you can do:
SELECT *
FROM TB1
WHERE id NOT IN (
SELECT compid
FROM TB2
);